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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 489 questions

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211 Medium
211 of 489
Application +4 | -1
For a projectile thrown into space with a speed v, the horizontal range is 3v22g.\frac{{\sqrt 3 {v^2}}}{{2\mathrm{g}}}. The vertical range is v28g\frac{{{v^2}}}{{8\mathrm{g}}}. The angle which the projectile makes with the horizontal initially is
View answer and explanation
Correct option: B
300{30^0}
Option B (150{15^0}) is correct because the angle of projection is calculated using the given horizontal and vertical ranges.
212 Medium
212 of 489
Application +4 | -1
If ∣A×B∣=3A⋅B|{A} \times {B}|=\sqrt{3} {A} \cdot {B}, then the value of ∣A+B∣|{A}+{B}| is
View answer and explanation
Correct option: D
(A2+B2+AB)1/2\left(A^2+B^2+A B\right)^{1 / 2}
Option D ((A2+B2+AB)1/2\left(A^2+B^2+A B\right)^{1 / 2}) is correct because it is derived from the law of cosines after finding the angle between the vectors A and B.
213 Medium
213 of 489
Application +4 | -1
The two vectors have magnitudes 3 and 5 . If angle between them is 60∘60^{\circ}, then the dot product of two vectors will be :-
View answer and explanation
Correct option: A
7.57.5
Option A (7.57.5) is correct because the dot product is calculated using the formula A⋅B=ABcos⁡θA \cdot B = AB \cos \theta.
214 Medium
214 of 489
Analyzing +4 | -1
Given that A⃗+B⃗+C⃗=0\mathrm{\vec A} + \mathrm{\vec B} + \mathrm{\vec C} = 0. Out of three vectors, two are equal in magnitude and the magnitude of third vector is 2\sqrt 2 times that of either of the two having equal magnitude. Then the angles between vectors are given by
View answer and explanation
Correct option: B
90∘,135∘,135∘90^\circ ,135^\circ ,135^\circ
Option B (90∘,135∘,135∘90^\circ ,135^\circ ,135^\circ) is correct because it satisfies the vector addition condition with the given magnitudes.
215 Hard
215 of 489
Application +4 | -1
The unit vector in ZOX plane making angles 45∘45^{\circ} and 60∘60^{\circ} respectively, with a=2i^+2j^−k^a=2 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}} and b=j^−k^\mathbf{b}=\hat{\mathbf{j}}-\hat{\mathbf{k}}, is
View answer and explanation
Correct option: B
12(i^−k^)\frac{1}{\sqrt{2}}(\hat{i}-\hat{k})
Option B (12(i^−k^)\frac{1}{\sqrt{2}}(\hat{i}-\hat{k})) is correct because it satisfies the conditions of being a unit vector in the ZOX plane and making the specified angles with vectors a and b.
216 Medium
216 of 489
Understanding +4 | -1
(A⃗−B⃗)×(A⃗+B⃗)=(\vec{A}-\vec{B}) \times(\vec{A}+\vec{B})=
View answer and explanation
Correct option: A
2(A⃗×B⃗)2(\vec{A} \times \vec{B})
Option A is correct because the cross product (A⃗−B⃗)×(A⃗+B⃗)(\vec{A}-\vec{B}) \times (\vec{A}+\vec{B}) simplifies to 2(A⃗×B⃗)2(\vec{A} \times \vec{B}) using the properties of cross products.
217 Medium
217 of 489
Application +4 | -1
A particle is projected with speed 20 ms−120 \mathrm{~ms}^{-1} at an angle 30∘30^{\circ} with horizontal. After how much time the angle between velocity and acceleration will be 90∘90^{\circ}
View answer and explanation
Correct option: A
1 s1 \mathrm{~s}
Option A (1 s1 \mathrm{~s}) is correct because the time at which the angle between velocity and acceleration is 90 degrees is when the vertical component of velocity becomes zero.
218 Medium
218 of 489
Analyzing +4 | -1
Which of the following sets of vectors given below may have zero resultant?
View answer and explanation
Correct option: C
11,22,1711,22,17
Option C (11, 22, 17) is correct because the sum of two vectors (11 + 17 = 28) can be equal or greater than the third vector (22), allowing for a zero resultant.
219 Hard
219 of 489
Application +4 | -1
If ∣a∣=3,∣b∣=4|\mathbf{a}|=3,|\mathbf{b}|=4, then a value of λ\lambda for which a+λb\mathbf{a}+\lambda \mathbf{b} is perpendicular to a−λb\mathbf{a}-\lambda \mathbf{b}.
View answer and explanation
Correct option: B
3/43 / 4
Option B (3/43 / 4) is correct because it satisfies the condition for perpendicularity between the vectors a+λb\mathbf{a}+\lambda \mathbf{b} and a−λb\mathbf{a}-\lambda \mathbf{b}.
220 Medium
220 of 489
Application +4 | -1
The range RR of projectile is same when its maximum heights are h1h_1 and h2h_2. What is the relation between RR and h1h_1 and h2h_2
View answer and explanation
Correct option: D
R=4h1h2R=4 \sqrt{h_1 h_2}
Option D (R=4h1h2R=4 \sqrt{h_1 h_2}) is correct because it relates the range to the product of the two maximum heights achieved at complementary projection angles.
221 Medium
221 of 489
Analyzing +4 | -1
Assertion: The trajectory of an object moving under constant acceleration due to gravity can be a straight line or parabola.
Reason: Initial conditions affect the motion of the object.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because both the assertion and reason are true, and the reason correctly explains why the trajectory can be a straight line or parabola depending on initial conditions.
222 Medium
222 of 489
Understanding +4 | -1
I. Pressure
II. Temperature
III. Momentum
IV. Work
Which of the following physical quantities are scalars?
View answer and explanation
Correct option: C
I, II and IV
Option C (I, II and IV) is correct because pressure, temperature, and work are scalar quantities, while momentum is a vector quantity.
223 Medium
223 of 489
Understanding +4 | -1
From the top of a tower, a ball A is dropped and another ball B is thrown horizontally at the same time. Which ball strikes the ground first?
View answer and explanation
Correct option: C
Simultaneously
Option C is correct because the vertical motion of both balls is identical, so they will hit the ground simultaneously.
224 Easy
224 of 489
Understanding +4 | -1
Assertion At highest point of a projectile, dot product of velocity and acceleration is zero.

Reason At highest point, velocity and acceleration are mutually perpendicular.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A (If both Assertion and Reason are correct and Reason is the correct explanation of Assertion) is correct because at the highest point, the velocity is horizontal and the acceleration due to gravity is vertical, making them perpendicular and their dot product zero.
225 Hard
225 of 489
Analyzing +4 | -1
Let a, b,c, be vectors of length 3, 4, 5 respectively and a\mathbf{a} be perpendicular to (b+c),b(\mathbf{b}+\mathbf{c}), \mathbf{b} to (c+a)(\mathbf{c}+\mathbf{a}) and c\mathbf{c} to (a+b)(\mathbf{a}+\mathbf{b}), then the value of (a+b+c)(\mathbf{a}+\mathbf{b}+\mathbf{c}) is
View answer and explanation
Correct option: D
525 \sqrt{2}
The correct answer is D (525 \sqrt{2}) because by using the given perpendicularity conditions and vector algebra, we find the magnitude of the sum of the vectors.
226 Medium
226 of 489
Understanding +4 | -1
Statement I : In order to hit a target, a man should point his rifle in the same direction as the target.

Statement II : The horizontal range of bullet is dependent on the angle of projection with the horizontal.
View answer and explanation
Correct option: D
Statement I is false; Statement II is true
Option D (Statement I is false; Statement II is true) is correct because to hit a target, one must aim higher to compensate for gravity, and the horizontal range indeed depends on the projection angle.
227 Medium
227 of 489
Application +4 | -1
If a1→\overrightarrow {{a_1}} and a2→\overrightarrow {{a_2}} are two non collinear unit vectors inclined at 600{60^0} to each other then the value of (a1→−a2→).(2a1→+a2→)\left( {\overrightarrow {{a_1}} - \overrightarrow {{a_2}} } \right).\left( {\overrightarrow {2{a_1}} + \overrightarrow {{a_2}} } \right)
View answer and explanation
Correct option: A
12\frac{1}{2}
Option A (1/2) is correct because the dot product of the two vectors simplifies to 1/2 after using the given angle and unit vector properties.
228 Medium
228 of 489
Application +4 | -1
The resultant of forces F1→=4i^−3j^\overrightarrow {{F_1}} = 4\hat i - 3\hat j and F2→=6i^+8j^ \overrightarrow {{F_2}} = 6\hat i + 8\hat j\, is
View answer and explanation
Correct option: A
555\sqrt 5
Option A (555\sqrt 5) is correct because it is the magnitude of the resultant vector obtained by adding the two force vectors.
229 Medium
229 of 489
Understanding +4 | -1
Assertion: The maximum possible height attained by the projected body is u22g\frac{{{u^2}}}{{2g}} where uu is the velocity of projection
Reason : To attain the maximum height, body is thrown vertically upwards.
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct explanation for assertion.
Option A (Assertion is correct, reason is correct; reason is a correct explanation for assertion) is correct because the maximum height is achieved when the body is projected vertically upwards.
230 Medium
230 of 489
Understanding +4 | -1
A bomb is dropped from an aeroplane moving horizontally at constant speed. If air resistance is neglected, then the bomb
View answer and explanation
Correct option: A
Falls on the earth exactly below the aeroplane
Option A is correct because the bomb has the same initial horizontal velocity as the airplane, and neglecting air resistance, it will remain directly below the airplane as it falls.
231 Medium
231 of 489
Application +4 | -1
A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of 3 ms−23 \mathrm{~m} \mathrm{s}^{-2} for 0.5 minutes. If the maximum height reached by it is 80 m80 \mathrm{~m}, then the angle of projection is
(Take g=10 ms−2g=10 \mathrm{~m} \mathrm{s}^{-2} )
View answer and explanation
Correct option: C
tan⁡−1(49)\tan ^{-1}\left(\frac{4}{9}\right)
Option C (tan⁡−1(49)\tan ^{-1}(\frac{4}{9})) is correct because it's derived by relating the horizontal and vertical components of the projectile's initial velocity using the given maximum height and horizontal velocity information.
232 Hard
232 of 489
Analyzing +4 | -1
If OABCO A B C is a tetrahedron such that OA2+BC2\mathrm{OA}^2+\mathrm{BC}^2 =OB2+CA2=OC2+AB2=\mathrm{OB}^2+\mathrm{CA}^2=\mathrm{OC}^2+\mathrm{AB}^2, then which of the following is not true?
View answer and explanation
Correct option: D
AB⊥ACA B \perp A C
Option D (AB⊥ACA B \perp A C) is correct because the given conditions imply that OA⊥BCOA \perp BC, OB⊥ACOB \perp AC, and OC⊥ABOC \perp AB, but not necessarily that AB⊥ACAB \perp AC.
233 Medium
233 of 489
Analyzing +4 | -1
Two projectiles A and B are thrown with the same speed such that A makes angle q\mathrm{q} with the horizontal and B makes angle qq with the vertical, then
View answer and explanation
Correct option: D
Both may have same time of flight
Option D (Both may have same time of flight) is correct because the time of flight depends on the angle of projection, and they will be the same only if the angle is 45 degrees.
234 Medium
234 of 489
Analyzing +4 | -1
Consider the following statements about three vectors a→,b→\overrightarrow{{a}}, \overrightarrow{{b}} and c→\overrightarrow{{c}} that have non-zero magnitudes. It follows b→=c→\overrightarrow{{b}}=\overrightarrow{{c}}

(i) if a→⋅b→=a→⋅c→\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{b}}=\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{c}}

(ii) if a⃗×b⃗=a⃗×c⃗b⃗\vec{a} \times \vec{b}=\vec{a} \times \vec{c} \quad \vec{b} must be perpendicular to c→\overrightarrow{\mathrm{c}}
View answer and explanation
Correct option: C
(i) only
Option B is correct because neither statement (i) nor (ii) necessarily implies that b→=c→\overrightarrow{{b}}=\overrightarrow{{c}} when dealing with dot and cross products of vectors.
235 Medium
235 of 489
Analyzing +4 | -1
Statement-I: Two bodies thrown with same speed from the same point at the same instants but at different angles never collide in air.
Statement-II: xx and yy co-ordinates of the two projectiles always differ
View answer and explanation
Correct option: A
Both statements are true
The correct answer is D because both statements are false. The resistivity of a semiconductor decreases with temperature, and the reason is incorrect.
236 Medium
236 of 489
Understanding +4 | -1
Statement-I: Minimum number of non-equal vectors in a plane required to give zero resultant is three.
Statement-II: If a⃗+b⃗+c⃗=0\vec{a}+\vec{b}+\vec{c}=0, then they must lie in one plane
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct. Three non-equal vectors are needed for a zero resultant in a plane, and if the sum of vectors is zero, they must be coplanar.
237 Medium
237 of 489
Analyzing +4 | -1
Assertion: Two projectiles of masses mm and 4m4m when projected with same initial velocity vector have different ranges.
Reason: The horizontal range of a projectile depends on mass of the body.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct. The range of a projectile depends on initial velocity and angle of projection, not mass. Therefore, both the assertion and reason are false.
238 Medium
238 of 489
Understanding +4 | -1
The component of a vector r along X-axis will
have a maximum value, if :
View answer and explanation
Correct option: A
r is along positive X-axis
Option A (r is along positive X-axis) is correct because the component of a vector along the X-axis is maximized when the vector is aligned with the X-axis.
239 Medium
239 of 489
Application +4 | -1
A body constrained to move along the zz-axis of a co-ordinate system is subjected to a constant force F⃗\vec{F} given by F⃗=−i^+2j^+3k^\vec{F}=-\hat{i}+2 \hat{j}+3 \hat{k} newton where i^,j^\hat{i}, \hat{j} and k^\hat{k} represent unit vectors along x,yx,y and zz-axis of the system respectively. Calculate the work done by the force in displacing the body through a distance of 4 m4 \mathrm{~m} along the zz-axis.
View answer and explanation
Correct option: A
12 joule12 \text { joule}
Option A (12 joule12 \text { joule}) is correct because only the force component along the z-axis contributes to the work done when the displacement is along the z-axis.
240 Easy
240 of 489
Application +4 | -1
A\mathbf{A} and B\mathbf{B} are two vectors given by A=2i^+3j^\mathbf{A}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}} and B=2i^+4j^\mathbf{B}=2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}. The magnitude of the component of A\mathbf{A} along B\mathbf{B} is
View answer and explanation
Correct option: C
85\frac{8}{\sqrt{5}}
Option C (85\frac{8}{\sqrt{5}}) is correct because it is calculated by finding the dot product of the two vectors and dividing by the magnitude of vector B.
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