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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 489 questions

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151 Easy
151 of 489
Understanding +4 | -1
As a rocket is accelerating vertically upwards at 9.8 ms−29.8 \mathrm{~ms}^{-2} near the earth's surface, it releases a projectile with zero speed relative to rocket. Immediately after release, the acceleration (in ms−2\mathrm{ms}^{-2} ) of the projectile is [take, g=9.8 ms−2g=9.8 \mathrm{~ms}^{-2} ]
View answer and explanation
Correct option: C
9.8 ms−29.8 \mathrm{~ms}^{-2}, down
Option C is correct because immediately after release, the projectile is only under the influence of gravity, resulting in a downward acceleration of 9.8 m/s².
152 Medium
152 of 489
Application +4 | -1
A particle is projected in XY plane with Y-axis along vertical, the point of projection is origin. The equation of the path is y= 3×−g2×2\sqrt 3 \times - \frac{g}{2}{ \times ^2}. Where X and Y are in metres. The speed of
projection in ms−1m{s^{ - 1}} is
View answer and explanation
Correct option: A
2
Option A (2) is correct because comparing the given equation with the standard trajectory equation allows us to determine the initial velocity.
153 Medium
153 of 489
Application +4 | -1
A force of 8 N8 {~N} makes an angle 30∘30^{\circ} with XX-axis. Find the xx and yy components of the force.
View answer and explanation
Correct option: A
Fx=43N,Fy=4NF_x=4 \sqrt{3} N, F_y=4 N
Option A (Fx=43N,Fy=4NF_x=4 \sqrt{3} N, F_y=4 N) is correct because it correctly calculates the x and y components using cosine and sine functions respectively.
154 Easy
154 of 489
Understanding +4 | -1
If a vector P⃗\vec P make angles α, β,\alpha ,\,\beta , and γ\gamma respectively with the X,  YX,\,\,Y and ZZ axes. Then sin⁡2α  +  sin⁡2β  +  sin⁡2γ  ={\sin ^2}\alpha \,\, + \,\,{\sin ^2}\beta \,\, + \,\,{\sin ^2}\gamma \,\, =
View answer and explanation
Correct option: C
2
Option C (2) is correct because the sum of the squares of the sines of the angles is equal to 2.
155 Medium
155 of 489
Understanding +4 | -1
A bomb is dropped by fighter plane flying horizontally. To an observer sitting in the plane, the trajectory of the bomb is a
View answer and explanation
Correct option: C
Straight line vertically down the plane
Option C (Straight line vertically down the plane) is correct because, relative to the observer in the plane, the bomb has no initial horizontal velocity and falls straight down due to gravity.
156 Medium
156 of 489
Application +4 | -1
Find a vector whose length is 7 and which is perpendicular to each of the vectors: A⃗=2i^−3j^+6k^ and B⃗=i^+j^−k^\vec{A}=2 \hat{i}-3 \hat{j}+6 \hat{k} \text { and } \vec{B}=\hat{i}+\hat{j}-\hat{k}
View answer and explanation
Correct option: A
12(−3i^+8j^+5k^)\frac{1}{\sqrt{2}}(-3 \hat{i}+8 \hat{j}+5 \hat{k})
The correct answer is A (12(−3i^+8j^+5k^)\frac{1}{\sqrt{2}}(-3 \hat{i}+8 \hat{j}+5 \hat{k})) because it is a vector of length 7 that is perpendicular to both given vectors, found using the cross product.
157 Medium
157 of 489
Application +4 | -1
The resultant of two forces acting at an angle of 150∘150^{\circ} is 10 N10 {~N} and is perpendicular to one of the forces. One of the two other forces is
View answer and explanation
Correct option: C
20 N20 {~N}
Option C (75.52∘75.52^{\circ}) is correct because the angle between the two vectors is calculated using the law of cosines.
158 Easy
158 of 489
Understanding +4 | -1
Four bodies P, Q, RP,\,Q,\,R and SS are projected with equal velocities having angles of projection 15∘, 30∘, 45∘15^\circ ,\,30^\circ ,\,45^\circ and 60∘60^\circ with the horizontal respectively. The body having shortest range is
View answer and explanation
Correct option: A
PP
Option A is correct. The range of a projectile is shortest when the angle of projection is farthest from 45 degrees, and 15 degrees is the farthest from 45 degrees among the given options.
159 Medium
159 of 489
Application +4 | -1
A ball is projected horizontally from the top of a building 80 m high. If the line joining the point of projection to the point where it hits the ground makes an angle of 45∘45^{\circ} to the horizontal, the initial velocity of the ball is
View answer and explanation
Correct option: A
20 ms−120 \mathrm{~ms}^{-1}
Option A (20 ms−120 \mathrm{~ms}^{-1}) is correct because it is the initial velocity calculated using projectile motion principles and the given angle.
160 Medium
160 of 489
Understanding +4 | -1
Assertion: A projectile that traverses a parabolic path shows deviation from its idealized trajectory in the presence of air resistance.

Reason: Air resistance affects the motion of the projectile.
View answer and explanation
Correct option: A
Both Assertion and Reason are true, and Reason is the correct explanation for Assertion
Option A is correct because air resistance, a dissipative force, affects the trajectory of a projectile, causing it to deviate from its ideal parabolic path.
161 Hard
161 of 489
Analyzing +4 | -1
If a,b and c are unit vectors, then ∣a−b∣2+∣b−c∣2+∣c−a∣2|\mathbf{a}-\mathbf{b}|^2+|\mathbf{b}-\mathbf{c}|^2+|\mathbf{c}-\mathbf{a}|^2 does not exceed
View answer and explanation
Correct option: B
9
Option B (9) is correct because by expanding the expression and using the fact that the vectors are unit vectors, we can find an upper bound for the given expression.
162 Medium
162 of 489
Application +4 | -1
The magnitude of i^+j^\hat{i}+\hat{{j}} is
View answer and explanation
Correct option: C
2\sqrt{2}
Option C (2\sqrt{2}) is correct because the magnitude of a vector is calculated using the square root of the sum of the squares of its components.
163 Medium
163 of 489
Application +4 | -1
The equation of trajectory of an oblique projectile is y=x−12x2y=x-\frac{1}{2} x^2. The time of flight of projectile will be.
View answer and explanation
Correct option: A
2g\frac{2}{\sqrt{g}}
Option A (2g\frac{2}{\sqrt{g}}) is correct because it is the time of flight calculated by comparing the given trajectory equation with the standard equation and using the formula for time of flight.
164 Medium
164 of 489
Analyzing +4 | -1
Statement-I: If a⃗⋅b⃗=b⃗⋅c⃗\vec{a} \cdot \vec{b}=\vec{b} \cdot \vec{c}, then a⃗\vec{a} may not always be equal to c⃗\vec{{c}}.
Statement-II: The dot product of two vectors involves cosine of the angle between the two vectors.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A is correct. Statement-I is true because the dot product doesn't guarantee vector equality, and Statement-II is true because the dot product involves the cosine of the angle between the vectors.
165 Medium
165 of 489
Understanding +4 | -1
Statement-I: If dot product and cross product of a⃗\vec{a} and b⃗\vec{b} are zero, it implies that one of the vector a⃗\vec{a} and b⃗\vec{b} must be a null vector.
Statement-II: Null vector is a vector with zero magnitude.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because both statements are factually accurate and logically consistent.
166 Medium
166 of 489
Analyzing +4 | -1
Two boys PP and QQ are playing on a river bank. PP plans to swim across the river directly and come back. QQ plans to swim downstream by a length equal to the width of the river and then come back. Both of them bet each other, claiming that the boy succeeding in less time will win. Assuming the swimming rate of both PP and QQ to the same, it can be concluded that
View answer and explanation
Correct option: A
PP wins
Option A (PP wins) is correct because the time taken by P to swim across and back is less than the time taken by Q.
167 Medium
167 of 489
Analyzing +4 | -1
A river flows with a speed more than the maximum speed with which a person can swim in still water. He intends to cross the river by the shortest possible path (i.e., he wants to reach the point on the opposite bank which directly opposite to the starting point). Which of the following is correct?
View answer and explanation
Correct option: D
The man cannot cross the river in that way.
Option D (The man cannot cross the river in that way) is correct because the swimmer's speed is less than the river's speed, making it impossible to swim directly across.
168 Medium
168 of 489
Application +4 | -1
If a⃗+b⃗\vec{a}+\vec{b} is perpendicular to a⃗\vec{a} and 2a⃗+b⃗2 \vec{a}+\vec{b} is perpendicular to b⃗\vec{b}. Then ∣b⃗∣∣a⃗∣\frac{|\vec{b}|}{|\vec{a}|} is
View answer and explanation
Correct option: B
2\sqrt{2}
Option B (2\sqrt{2}) is correct because it is derived from the dot product conditions given, leading to the ratio of magnitudes.
169 Medium
169 of 489
Application +4 | -1
The position of a particle is given by r⃗=3.0ti^+2.0t2j^+5.0k^\vec{r}=3.0 t \hat{i}+2.0 t^2 \hat{j}+5.0 \hat{k} where tt is in seconds and the coefficients have the proper units for rr to be in metres. Find v(t)v(t) and a(t)a(t) of the particle.
View answer and explanation
Correct option: A
3.0i^+4.0tj^,+4.0j^3.0 \hat{i}+4.0 t \hat{j}, +4.0 \hat{j}
Option A (3.0i^+4.0tj^,+4.0j^3.0 \hat{i}+4.0 t \hat{j}, +4.0 \hat{j}) is correct because it is found by taking the first and second derivatives of the position vector with respect to time.
170 Medium
170 of 489
Understanding +4 | -1
If the angle between the vectors A⃗\vec{A} and B⃗\vec{B} is θ\theta, the value of the product (B→×A→)⋅A→(\overrightarrow{{B}} \times \overrightarrow{{A}}) \cdot \overrightarrow{{A}} is equal:
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the scalar triple product of vectors where one vector is repeated is always zero, as the cross product results in a vector orthogonal to A, and the dot product of orthogonal vectors is zero.
171 Medium
171 of 489
Application +4 | -1
A body is projected with speed v  ms−1v\;\mathrm{m}{\mathrm{s}^{ - 1}} at angle θ\theta. The kinetic energy at the highest point is half of the initial kinetic energy. The value of θ\theta is
View answer and explanation
Correct option: B
450{45^0}
Option B (450{45^0}) is correct because at the highest point, the kinetic energy is half the initial kinetic energy, implying cos⁡2θ=12\cos^2 \theta = \frac{1}{2}, thus θ=45∘\theta = 45^\circ.
172 Medium
172 of 489
Application +4 | -1
A large number of bullets are fired in all directions with same speed v. What is the maximum area on the ground on which these bullets will spread
View answer and explanation
Correct option: B
πv4g2\pi \frac{{{v^4}}}{{{g^2}}}
Option B (πv4g2\pi \frac{{{v^4}}}{{{g^2}}}) is correct because the maximum area is determined by the maximum range of the projectiles, which occurs at an angle of 45 degrees.
173 Medium
173 of 489
Understanding +4 | -1
Three balls are projected from the top of a building with equal speeds but at different angles. Balls strike the ground with velocities v1{v} 1, v2v2 and v3{v} 3 respectively, then
View answer and explanation
Correct option: C
v1=v2=v3{v} 1={v} 2={v} 3
Option C (v1=v2=v3{v} 1={v} 2={v} 3) is correct because the speed at which the balls strike the ground depends only on the initial speed and the height, not the angle of projection.
174 Medium
174 of 489
Analyzing +4 | -1
Of the vectors given below, the parallel vectors are,

A⃗=6i^+8j^B⃗=210i^+280k^C⃗=5.1i^+6.8j^D⃗=3.6i^+6j^+48k^\begin{aligned} & \vec{A}=6 \hat{i}+8 \hat{j} \\ & \vec{B}=210 \hat{i}+280 \hat{k} \\ & \vec{C}=5.1 \hat{i}+6.8 \hat{j} \\ & \vec{D}=3.6 \hat{i}+6 \hat{j}+48 \hat{k} \end{aligned}
View answer and explanation
Correct option: B
A→\overrightarrow{\mathrm{A}} and C→\overrightarrow{\mathrm{C}}
Option B is correct because vectors A and C have proportional components, indicating they are parallel.
175 Medium
175 of 489
Analyzing +4 | -1
If a2+b2+c2=1a^2+b^2+c^2=1 where a,b,c∈Ra, b, c \in R, then the maximum value of (4a−3b)2+(5b−4c)2+(3c−5a)2(4 a-3 b)^2+(5 b-4 c)^2+(3 c-5 a)^2 is
View answer and explanation
Correct option: B
50
Option B (50) is correct because the maximum value is found using vector properties and the Cauchy-Schwarz inequality.
176 Medium
176 of 489
Analyzing +4 | -1
Statement-I: If a⃗\vec{a} is perpendicular to b⃗\vec{b} and c→\overrightarrow{{c}}, then a→×(b→×c→)=0\overrightarrow{{a}} \times(\overrightarrow{{b}} \times \overrightarrow{{c}})=0
Statement-II: If b→\overrightarrow{{b}} is perpendicular to c→\overrightarrow{{c}}, then b→×c→=0\overrightarrow{{b}} \times \overrightarrow{{c}}=0
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option B is correct because if a⃗\vec{a} is perpendicular to both b⃗\vec{b} and c⃗\vec{c}, then b⃗×c⃗\vec{b} \times \vec{c} will not be zero, and a⃗×(b⃗×c⃗)\vec{a} \times (\vec{b} \times \vec{c}) will be non-zero, and b⃗\vec{b} being perpendicular to c⃗\vec{c} does not mean their cross product is zero.
177 Medium
177 of 489
Application +4 | -1
Two objects are projected with same velocity ' uu ' however at different angles α\alpha and β\beta with the horizontal. If α+β=90∘\alpha+\beta=90^{\circ}, the ratio of horizontal range of the first object to the 2nd object will be :
View answer and explanation
Correct option: D
1:11: 1
Option D (1:11:1) is correct because the horizontal range is the same for complementary angles of projection.
178 Medium
178 of 489
Understanding +4 | -1
A football is kicked into the air vertically upwards with velocity u.u. The velocity of the ball at the highest point is
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because at the highest point of its trajectory, the football momentarily stops moving upwards before it starts falling back down, hence its vertical velocity is zero.
179 Medium
179 of 489
Understanding +4 | -1
If vectors i^−3j^+5k^\hat{i}-3 \hat{j}+5 \hat{k} and i^−3j^−ak^\hat{i}-3 \hat{j}-a \hat{k} are equal vectors, then the value of aa is
View answer and explanation
Correct option: D
-5
Option D (-5) is correct because for two vectors to be equal, their corresponding components must be equal.
180 Medium
180 of 489
Understanding +4 | -1
Assertion: Angle between i^+j^\hat{i}+\hat{j} and i^\hat{i} is 45∘45^{\circ}.
Reason: i^+j^\hat{i}+\hat{j} is equally inclined to both i^\hat{i} and j^\hat{j} the angle between i^\hat{i} and j^\hat{j} is 90∘90^{\circ}.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A is correct because both the assertion and reason are true, and the reason correctly explains why the angle is 45 degrees.
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