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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 489 questions

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91 Medium
91 of 489
Analyzing +4 | -1
If A+B=C{A}+{B}={C} and that C{C} is perpendicular to A{A}. What is the angle between A{A} and B{B}, if ∣A∣=∣C∣?|{A}|=|{C}|?
View answer and explanation
Correct option: C
3π4 rad\frac{3 \pi}{4} \, \mathrm{rad}
Option C is correct because the angle between A and B is 3π/4 rad, derived using vector addition and the cosine rule.
92 Hard
92 of 489
Understanding +4 | -1
(a⋅i^)i^+(a⋅j^)j^+(a⋅k^)k^(\mathbf{a} \cdot \hat{\mathbf{i}}) \hat{\mathbf{i}}+(\mathbf{a} \cdot \hat{\mathbf{j}}) \hat{\mathbf{j}}+(\mathbf{a} \cdot \hat{\mathbf{k}}) \hat{\mathbf{k}} is equal to
View answer and explanation
Correct option: A
a\mathbf{a}
Option A (a\mathbf{a}) is correct because the expression represents the vector a\mathbf{a} resolved along the i, j, and k axes, which sums back to the original vector.
93 Medium
93 of 489
Understanding +4 | -1
If a body is in equilibrium under a set of non-collinear forces, then the minimum number of forces has to be
View answer and explanation
Correct option: B
three
Option B (three) is correct because at least three non-collinear forces are needed to achieve equilibrium, forming a closed vector triangle.
94 Medium
94 of 489
Understanding +4 | -1
Choose the correct statement(s) from the following.
I. If speed of a body in a curved path is constant it has zero acceleration
II. When a body moves on a curved path with a constant speed, it has acceleration perpendicular to the direction of motion
View answer and explanation
Correct option: B
II only
Option B (II only) is correct because a body moving on a curved path with constant speed has centripetal acceleration perpendicular to the motion.
95 Medium
95 of 489
Analyzing +4 | -1
If the angle between two non-zero vectors A\mathbf{A} and B\mathbf{B} is 120∘120^{\circ}, its resultant CC will be
View answer and explanation
Correct option: C
C>∣A−B∣C>|\mathbf{A}-\mathbf{B}|
Option C is correct. The magnitude of the resultant vector C is greater than the magnitude of the difference between vectors A and B when the angle between them is 120 degrees.
96 Medium
96 of 489
Application +4 | -1
Two bodies are thrown with the same initial velocity of 30 m/s. One at 17∘17^\circ, other at 73∘73^\circ to the horizontal. The sum of the maximum heights reached by them is [g=10  m/s2][g = 10\,\,m\mathrm{/}{s^2}]
View answer and explanation
Correct option: A
45 m
Option A (45 m) is correct because the sum of maximum heights for complementary angles of projection is independent of the angle and depends only on initial velocity.
97 Medium
97 of 489
Analyzing +4 | -1
The minimum number of vectors having different planes which can be added to give zero resultant is
View answer and explanation
Correct option: C
4
Option C (4) is correct because a minimum of four vectors in different planes are required to achieve a zero resultant.
98 Medium
98 of 489
Application +4 | -1
If a^+2b^\hat{a}+2 \hat{b} and 5a^−4b^5 \hat{a}-4 \hat{b} are perpendicular to each other, find angle between a^\hat{a} and b^\hat{b} :-
View answer and explanation
Correct option: A
60∘60^{\circ}
Option A (60∘60^{\circ}) is correct because the dot product of the two perpendicular vectors is zero, leading to cos⁡θ=12\cos \theta = \frac{1}{2}.
99 Medium
99 of 489
Understanding +4 | -1
Statement-I: The cross product of a vector with itself is a null vector.
Statement-II: The cross product of two vectors results is a vector quantity.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A is correct because the cross product of a vector with itself is indeed a null vector, and the cross product of two vectors always results in a vector quantity.
100 Medium
100 of 489
Analyzing +4 | -1
If A⃗+B⃗=C⃗\vec{A}+\vec{B}=\vec{C} and A2+B2=C2A^2+B^2=C^2, then A⃗\vec{A} and B⃗\vec{B} are perpendicular to each other.
View answer and explanation
Correct option: A
90∘90^{\circ}
Option A is correct because if A⃗+B⃗=C⃗\vec{A} + \vec{B} = \vec{C} and A2+B2=C2A^2 + B^2 = C^2, then the angle between A⃗\vec{A} and B⃗\vec{B} must be 90 degrees.
101 Medium
101 of 489
Analyzing +4 | -1
Assertion: In a projectile motion the projectile hits the ground with the same velocity with which it was thrown.
Reason: In a projectile motion horizontal velocity remains same but vertical velocity continuously changes and particle strikes the ground with same vertical velocity with which the particle was thrown in vertical direction.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because in projectile motion, the final velocity's vertical component is reversed, and the horizontal component remains constant, assuming no air resistance.
102 Medium
102 of 489
Analyzing +4 | -1
The sum of two vectors A⃗ and B⃗\mathrm{\vec A}\,and\,\mathrm{\vec B} is at right angles to their difference. Then
View answer and explanation
Correct option: A
A=BA = B
Option A is correct because if the sum of two vectors is at right angles to their difference, it implies that the magnitudes of the two vectors are equal.
103 Hard
103 of 489
Analyzing +4 | -1
Statement I Two forces (P+Q) and (P-Q) where P⊥QP \bot Q, when act at an angle θ1{\theta _1} to each other, the magnitude of their resultant is 3(P2+Q2),\sqrt {3({P^2} + {Q^2})} , when they act at an angle θ2,{\theta _2}, the magnitude of their resultant becomes 2(P2+Q2)\sqrt {2({P^2} + {Q^2})}. This is possible only when θ1<θ2.{\theta _1} < {\theta _2}.
Statement II In the situation given above. θ1=60∘  and  θ2=90∘{\theta _1} = {60^ \circ }\,\,\mathrm{and}\,\,{\theta _2} = {90^ \circ }
In the light of the above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: B
Both Statement I and Statement II are true
Option B (Both Statement I and Statement II are true) is correct because solving the equations for the resultant forces with the given angles confirms that both statements are true.
104 Medium
104 of 489
Application +4 | -1
The resultant of Pˉ{\bar P} and Qˉ{\bar Q} is perpendicular to Pˉ{\bar P}. The angle between Pˉ{\bar P} and Qˉ{\bar Q} is
View answer and explanation
Correct option: B
Cos⁡−1(−PQ){\operatorname{Cos} ^{ - 1}}\left( {\frac{{ - P}}{Q}} \right)
Option B (Cos⁡−1(−PQ){\operatorname{Cos} ^{ - 1}}\left( {\frac{{ - P}}{Q}} \right)) is correct because the resultant being perpendicular to Pˉ\bar P implies that P+Qcos⁡θ=0P + Q \cos \theta = 0.
105 Easy
105 of 489
Analyzing +4 | -1
I.Inprojectilemotion,theanglebetwee instantaneousvelocityvectorandacceleration vector can be anything between 0 to π\pi (excluding the limiting case.)

II. In projectile motion, acceleration vector is always pointing vertically downwards. (Neglect air friction).

Which of the following statement(s) is/are correct?
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct. In projectile motion, the angle between instantaneous velocity and acceleration varies from 0 to π\pi, and the acceleration vector always points downwards (neglecting air friction).
106 Medium
106 of 489
Application +4 | -1
Find the vector for which when added to the resultant of P⃗=2i^+7j^−10k^\vec{P}=2 \hat{i}+7 \hat{j}-10 \hat{k} and Q⃗=i^+2j^+3k^\vec{Q}=\hat{i}+2 \hat{j}+3 \hat{k} gives a unit vector along X\mathrm{X}-axis.
View answer and explanation
Correct option: C
−2i^−9j^+7k^-2 \hat{i}-9 \hat{j}+7 \hat{k}
Option C (−2i^−9j^+7k^-2 \hat{i}-9 \hat{j}+7 \hat{k}) is correct because it is the vector that, when added to the resultant of the given vectors, yields a unit vector along the X-axis.
107 Medium
107 of 489
Understanding +4 | -1
For the resultant of two vectors A⃗\vec{A} and B⃗\vec{B} to maximum. The angle between them should be
View answer and explanation
Correct option: B
0∘0^{\circ}
Option B is correct because the resultant of two vectors is maximum when the angle between them is 0 degrees, resulting in their direct addition.
108 Medium
108 of 489
Application +4 | -1
An aeroplane moving horizontally at a speed of 200 m/s and at a height of 8.0×103  m8.0 \times {10^3}\;m is to drop a bomb on a target. At what horizontal distance from the target should the bomb be released
View answer and explanation
Correct option: B
8.081 km
Option B (8.081 km) is correct because it is the horizontal distance calculated using projectile motion principles, considering the time it takes for the bomb to fall from the given height.
109 Medium
109 of 489
Analyzing +4 | -1
The plane which can be formed with the vectors a→=3i→−4j→+2k→\overrightarrow a = 3\overrightarrow i - 4\overrightarrow j + 2\overrightarrow k,b→=2i→−j→−6k→,c→=5i→−5j→−4k→\overrightarrow b = 2\overrightarrow i - \overrightarrow j - 6\overrightarrow k ,\overrightarrow c = 5\overrightarrow i - \overrightarrow {5j} - 4\overrightarrow k IS
View answer and explanation
Correct option: B
triangle
Option B (triangle) is correct because the vectors satisfy the condition a→+b→+c→=0\overrightarrow a + \overrightarrow b + \overrightarrow c = 0, indicating they form a triangle.
110 Hard
110 of 489
Application +4 | -1
If ∣a∣=5,∣a−b∣=8|\mathbf{a}|=5,|\mathbf{a}-\mathbf{b}|=8 and ∣a+b∣=10|\mathbf{a}+\mathbf{b}|=10, then ∣b∣|\mathbf{b}| is equal to
View answer and explanation
Correct option: B
57\sqrt{57}
Option B (57\sqrt{57}) is correct because it is derived from the vector identity relating the magnitudes of the sum and difference of two vectors to their individual magnitudes.
111 Medium
111 of 489
Application +4 | -1
In the projectile motion of an object, the object reaches its maximum height where its speed is half of initial speed. Then the ratio between range and maximum height of projectile is
View answer and explanation
Correct option: C
43\frac{4}{\sqrt{3}}
Option C (43\frac{4}{\sqrt{3}}) is correct because it represents the ratio of range to maximum height calculated using the given condition that the speed at maximum height is half the initial speed.
112 Medium
112 of 489
Analyzing +4 | -1
Assertion : Two balls of different masses are thrown vertically upward with same speed. They will pass through their point of projection in the downward direction with the same speed.
Reason : The maximum height and downward velocity attained at the point of projection are independent of the mass of the ball.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B is correct. The assertion is correct because the equations of motion are independent of mass, and the reason is also correct, but it doesn't fully explain the assertion.
113 Medium
113 of 489
Application +4 | -1
A stone is projected from the ground with velocity 50  ms−150\mathrm{\;m}{\mathrm{s}^{ - 1}} and angle of 300{30^0}. It crosses a wall after 3 s. How far beyond the wall the stone will strike the ground?
View answer and explanation
Correct option: C
86.6 m
Option C (86.6 m) is correct because it represents the horizontal distance traveled by the stone after it crosses the wall, calculated using projectile motion principles.
114 Medium
114 of 489
Application +4 | -1
The vectors&nbsp;2i^+3j^−2k^,  5i^+aj^+k^   and−i^+2j^+3k^\mathrm{2\hat i} + 3\mathrm{\hat j} - 2\mathrm{\hat k},\mathrm{\;}5\mathrm{\hat i} + \mathrm{a\hat j} + \mathrm{\hat k}\,\,\,\mathrm{ and } - \mathrm{\hat i} + 2\mathrm{\hat j} + 3\mathrm{\hat k} are coplanar when a is
View answer and explanation
Correct option: D
18
Option D (18) is correct because, for the vectors to be coplanar, their scalar triple product must be zero, which leads to a = 18.
115 Medium
115 of 489
Analyzing +4 | -1
Statement-1: If we want to throw a bottle from a moving train so that danger of being broken on hitting ground is least. We should throw bottle in forward direcrion.
Statement-2: While jumping out from side of a moving carriage it is safer to jump in forwards direction.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because Statement-1 is false (bottle should be thrown backwards) and Statement-2 is true (jumping forward is safer).
116 Medium
116 of 489
Remembering +4 | -1
Position of a particle in a rectangular coordinate system is (3,2,5)(3,2,5). Then, its position vector will be:
View answer and explanation
Correct option: B
3i^+2j^+5k^3 \hat{i}+2 \hat{j}+5 \hat{k}
Option B (3i^+2j^+5k^3 \hat{i}+2 \hat{j}+5 \hat{k}) is correct because it correctly represents the position vector given the coordinates (3, 2, 5).
117 Medium
117 of 489
Application +4 | -1
A body of mass m is thrown upwards at an angle θ\theta with the horizontal with velocity v. While rising up the velocity of the mass after t seconds will be
View answer and explanation
Correct option: C
v2+g2t2−(2vsin⁡θ)gt\sqrt {{v^2} + {g^2}{t^2} - \left( {2v\sin \theta } \right)gt}
Option C (v2+g2t2−(2vsin⁡θ)gt\sqrt {{v^2} + {g^2}{t^2} - \left( {2v\sin \theta } \right)gt}) is correct because it represents the magnitude of the velocity vector after time t, considering both horizontal and vertical components of motion under gravity.
118 Medium
118 of 489
Application +4 | -1
The sum of magnitude of two forces acting at a point is 16N16N and their resultant&nbsp;83  N8\sqrt 3 \,\,N is at 900{90^0} with the force of smaller magnitude. The two forces (in  N)\left( {in\,\,N} \right) are
View answer and explanation
Correct option: D
2,14
Option D (2,14) is correct because solving the force equations derived from the given conditions yields these values for the two forces.
119 Medium
119 of 489
Analyzing +4 | -1
Eighteen forces each equal to 10 N act on a particle simultaneously, at an angle 20∘20^{\circ} with the next one. If one force is removed, then the resultant of remaining forces is
View answer and explanation
Correct option: C
10
Option C (10) is correct because when one force is removed from a system of equally spaced forces summing to zero, the resultant is equal to the removed force.
120 Medium
120 of 489
Understanding +4 | -1
Which of the following is constant in a projectile motion?
View answer and explanation
Correct option: B
Horizontal component of the velocity
Option B (Horizontal component of the velocity) is correct because in projectile motion, only gravity acts vertically, leaving the horizontal component of velocity constant.
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