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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 421-450 of 489 questions

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421 Medium
421 of 489
Application +4 | -1
If A^=3i^+4j^\hat{A}=3 \hat{i}+4 \hat{j} and B=7i^+24j^B=7 \hat{i}+24 \hat{j} then a vector having same magnitude as B⃗\vec{B} and parallel to vector A⃗\vec{A} will be
View answer and explanation
Correct option: B
15i^+20j^15 \hat{i}+20 \hat{j}
Option B (15i^+20j^15 \hat{i}+20 \hat{j}) is correct because it has the same magnitude as B⃗\vec{B} and is parallel to A⃗\vec{A}.
422 Easy
422 of 489
Understanding +4 | -1
At the top of the trajectory of a projectile, the acceleration is
View answer and explanation
Correct option: D
gg
Option D (gg) is correct because the acceleration at the top of the trajectory of a projectile is due to gravity, which is constant throughout the motion.
423 Medium
423 of 489
Application +4 | -1
The angle between A=i+jA = i + j and B=i−jB = i - j is
View answer and explanation
Correct option: B
90∘90^\circ
Option B (90∘90^\circ) is correct because the dot product of the two vectors is zero, indicating they are perpendicular.
424 Hard
424 of 489
Analyzing +4 | -1
If a,b,c\mathbf{a}, \mathbf{b}, \mathbf{c} be non-zero vectors such that a\mathbf{a} is perpendicular to b\mathbf{b} and c\mathbf{c} and ∣a∣=1,∣b∣=2,∣c∣=1,b⋅c=1|\mathbf{a}|=1,|\mathbf{b}|=2,|\mathbf{c}|=1, \mathbf{b} \cdot \mathbf{c}=1 and there is a non-zero vector d\mathrm{d} coplanar with a+b\mathbf{a}+\mathbf{b} and 2b−c2 \mathbf{b}-\mathbf{c} and d⋅a=1\mathbf{d} \cdot \mathbf{a}=1, then minimum value of ∣d∣|\mathbf{d}| is
View answer and explanation
Correct option: D
413\frac{4}{\sqrt{13}}
Option D (413\frac{4}{\sqrt{13}}) is correct because it represents the minimum magnitude of vector d\mathbf{d} found by minimizing the quadratic expression obtained from the given conditions.
425 Medium
425 of 489
Understanding +4 | -1
Assertion: The magnitude of the resultant of two vectors P⃗\vec{P} and Q⃗\vec{Q} is maximum (P+Q)(P+Q), when the two vectors act in the same direction and minimum (P−Q)(P-Q), when they act in opposite directions.

Reason: The resultant of two vectors can be found by using the relation

R=P2+Q2+2PQcos⁡θR=\sqrt{P^2+Q^2+2 P Q \cos \theta}
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not
correct explanation of the assertion.
Option B is correct because both the assertion and the reason are true, but the reason doesn't directly explain why the resultant is maximum or minimum in the specified directions.
426 Medium
426 of 489
Application +4 | -1
Among the following the set that cannot represent the three sides of a triangle is
View answer and explanation
Correct option: B
5,7,13
Option B (5,7,13) is correct because the sum of the two smaller sides (5+7=12) is not greater than the longest side (13), violating the triangle inequality theorem.
427 Medium
427 of 489
Analyzing +4 | -1
Statement-I: a⃗=i^+pj^+2k^\vec{a}=\hat{i}+p \hat{j}+2 \hat{k} and b⃗=2i^+3j^+qk^\vec{b}=2 \hat{i}+3 \hat{j}+q \hat{k} are parallel vectors if p=32,q=4p=\frac{3}{2}, q=4.
Statement-II: If a⃗=a1i^+a2j^+a3k^\vec{a}=a_1 \hat{i}+a_2 \hat{j}+a_3 \hat{k} and b⃗=b1i^+b2j^+b3k^\vec{b}=b_1 \hat{i}+b_2 \hat{j}+b_3 \hat{k} are parallel, then a1b1=a2b2−a3b3\frac{a_1}{b_1}=\frac{a_2}{b_2}-\frac{a_3}{b_3}
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option D (Statement-I is true and statement-II is true) is correct because both the given statements are correct about parallel vectors.
428 Medium
428 of 489
Understanding +4 | -1
Which of the following statements are correct ?
I. Centripetal acceleration is always directed towards the centre.
II. Magnitude of the centripetal acceleration is v2R\frac{{{v^2}}}{R}.
III. Direction of centripetal acceleration changes pointing always towards the centre.
View answer and explanation
Correct option: D
I, II and III
Option D (I, II and III) is correct because all three statements about centripetal acceleration are accurate.
429 Medium
429 of 489
Analyzing +4 | -1
The resultant of the two vectors A⃗\vec{A} and B⃗\vec{B} makes angle α\alpha with A⃗\vec{A} and β\beta with B⃗\vec{B}.

Statement (A) : α<β\alpha<\beta if ∣A⃗∣<∣B⃗∣|\vec{A}|<|\vec{B}|

Statement (B) : α<β\alpha<\boldsymbol{\beta} if ∣A→∣>∣B⃗∣|\overrightarrow{{A}}|>|\vec{B}|

Statement (C) : α=β\alpha=\beta if ∣A⃗∣=∣B⃗∣|\vec{A}|=|\vec{B}|
View answer and explanation
Correct option: C
(B) and (C) are true
Option C is correct because the angle a vector makes with the resultant depends on the magnitudes of the vectors; if |A| > |B|, then α < β, and if |A| = |B|, then α = β.
430 Hard
430 of 489
Analyzing +4 | -1
If a=3i^−j^+5k^\mathbf{a}=3 \hat{\mathbf{i}}-\hat{\mathbf{j}}+5 \hat{\mathbf{k}} and b=i^+2j^−3k^\mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}} are given vector. A vector c\mathbf{c} which is perpendicular to ZZ-axis satisfying c⋅a=9\mathbf{c} \cdot \mathbf{a}=9 and c⋅b=−4\mathbf{c} \cdot \mathbf{b}=-4. If inclination of c\mathbf{c} with XX-axis and γ\gamma-axis is α\alpha and β\beta respectively, then which of the following is not true?
View answer and explanation
Correct option: C
α>π2\alpha>\frac{\pi}{2}
Option C (α>π2\alpha > \frac{\pi}{2}) is correct because by finding the vector c and its components, we determine the angle it makes with the x-axis, which is less than π2\frac{\pi}{2}.
431 Medium
431 of 489
Application +4 | -1
Two vectors are given by A⃗=i^+2j^+2k^\vec{A}=\hat{i}+2 \hat{j}+2 \hat{k} and B⃗=3i^+6j^+2k^\vec{B}=3 \hat{i}+6 \hat{j}+2 \hat{k}. Another vector C⃗\vec{C} has the same magnitude as B⃗\vec{B} but has the same direction as A⃗\vec{A}. Then which of the following vectors represent C⃗\vec{C}
View answer and explanation
Correct option: A
73(i^+2j^+2k^)\frac{7}{3}(\hat{i}+2 \hat{j}+2 \hat{k})
Option A (73(i^+2j^+2k^)\frac{7}{3}(\hat{i}+2 \hat{j}+2 \hat{k})) is correct because it represents a vector with the same magnitude as B⃗\vec{B} but in the direction of A⃗\vec{A}.
432 Medium
432 of 489
Application +4 | -1
The angle between two vectors of magnitude 12 and 18 units when their resultant is 24 units, will be:
View answer and explanation
Correct option: C
75.52∘75.52^{\circ}
Option C (75.52∘75.52^{\circ}) is correct because it is the angle calculated using the law of cosines with the given magnitudes of the two vectors and their resultant.
433 Medium
433 of 489
Application +4 | -1
The vectors from origin to the points AA and BB are A=3i^−6j^+2k^{A}=3 \hat{{i}}-6 \hat{{j}}+2 \hat{{k}} and B=2i^+j^−2k^{B}=2 \hat{{i}}+\hat{{j}}-2 \hat{{k}}, respectively. The area of the △OAB\triangle O A B be
View answer and explanation
Correct option: A
5217\frac{5}{2} \sqrt{17} sq units
Option A (5217\frac{5}{2} \sqrt{17} sq units) is correct because it is the result of calculating half the magnitude of the cross product of the position vectors.
434 Medium
434 of 489
Analyzing +4 | -1
There are NN coplanar vectors each of magnitude VV. Each vector is inclined to the preceding vector at angle 2πN\frac{2 \pi}{N}. What is the magnitude of their resultant?
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because the vectors form a closed polygon, resulting in a net resultant of zero.
435 Medium
435 of 489
Analyzing +4 | -1
Assertion: Vector (i^+j^+k^)(\hat{i}+\hat{j}+\hat{k}) is perpendicular to (i^−2j^+k^)(\hat{i}-2 \hat{j}+\hat{k})
Reason: Two non-zero vectors are perpendicular if their dot product is zero.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Assertion & Reason are True & the Reason is a correct explanation of the Assertion because the dot product of the two vectors is zero, indicating they are perpendicular, and the reason correctly states the condition for perpendicularity.
436 Medium
436 of 489
Application +4 | -1
The friction of the air causes a vertical retardation equal to 10%10 \% of the acceleration due to gravity. (Take g=10 ms−2\mathrm{g}=10 \mathrm{~ms}^{-2} ). The maximum height will be decreased by in projectile motion -
View answer and explanation
Correct option: C
9%9 \%
Option C (9%9 \%) is correct because the percentage decrease in maximum height is calculated by considering the vertical retardation due to air friction.
437 Medium
437 of 489
Application +4 | -1
Statement I : Rain is falling vertically downwards with a velocity of 3 kmh−13 \mathrm{~kmh}^{-1}. A man walks with a velocity of 4kmh−14 \mathrm{kmh}^{-1}. Relative velocity of rain w.r.t. man is 5 kmh−15 \mathrm{~kmh}^{-1}.

Statement II : Relative velocity of rain w.r.t. man is given by vmm=vr−vm\quad \mathbf{v}_{m m}=\mathbf{v}_r-\mathbf{v}_m
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
Option A (Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I) is correct because the relative velocity calculation and its magnitude are accurate, and the formula used is correct.
438 Medium
438 of 489
Application +4 | -1
What is the component of 3i^+4j^3 \hat{i}+4 \hat{j} along i^+j^\hat{i}+\hat{j} ?
View answer and explanation
Correct option: D
72(i^+j^)\frac{7}{2}(\hat{i}+\hat{j})
Option D (72(i^+j^)\frac{7}{2}(\hat{i}+\hat{j})) is correct because it is the projection of the vector 3i^+4j^3\hat{i}+4\hat{j} onto the vector i^+j^\hat{i}+\hat{j}.
439 Medium
439 of 489
Understanding +4 | -1
Statement-I: The vector product of a force F⃗\vec{F} and displacement r⃗\vec{r} is equal to the work done.
Statement-II: Work done is not a vector.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option C is correct because work done is a scalar quantity, and it is calculated as the dot product (scalar product) of force and displacement, not the vector product.
440 Medium
440 of 489
Understanding +4 | -1
Statement-I: If θ\theta be the angle between a⃗\vec{a} and b→\overrightarrow{\mathrm{b}}, then tan⁡θ=∣a⃗×b⃗∣a⃗⋅b⃗\tan \theta=\frac{|\vec{a} \times \vec{b}|}{\vec{a} \cdot \vec{b}}
Statement-II: a⃗×b⃗\vec{a} \times \vec{b} is perpendicular to a⃗.b⃗\vec{a} . \vec{b}
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option B is correct because the magnitude of the cross product divided by the dot product equals the tangent of the angle between the vectors, but the cross product is a vector while the dot product is a scalar.
441 Medium
441 of 489
Understanding +4 | -1
Which of the following is not the vector quantity?
View answer and explanation
Correct option: D
Electric flux
Option D (Electric flux) is correct because electric flux is a scalar quantity, while torque, displacement, and dipole moment are vector quantities.
442 Medium
442 of 489
Analyzing +4 | -1
Two projectiles are thrown with different velocities and at different angles so as to cover the same maximum height. Show that the sum of the times taken by each to reach the highest point is equal to the total time taken by either of the projectiles.
View answer and explanation
Correct option: A
2u1sin⁡θ1g or 2u2sin⁡θ2g\frac{2 u_1 \sin \theta_1}{g} \text { or } \frac{2 u_2 \sin \theta_2}{g}
The correct answer is A (2u1sin⁡θ1g or 2u2sin⁡θ2g\frac{{2 u_1 \sin \theta_1}}{{g}} \text {{ or }} \frac{{2 u_2 \sin \theta_2}}{{g}}) because the sum of the times to reach the highest point equals the time of flight for either projectile, given equal maximum heights.
443 Medium
443 of 489
Understanding +4 | -1
Which of the following is not true about vectors A⃗,B⃗\vec{A}, \vec{B} and C⃗\vec{C} ?
View answer and explanation
Correct option: C
(A→×C→)×(B→×C→)(\overrightarrow{\mathrm{A}} \times \overrightarrow{\mathrm{C}}) \times(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}}) is a scalar value.
Option C is the correct answer because (A→×C→)×(B→×C→)(\overrightarrow{\mathrm{A}} \times \overrightarrow{\mathrm{C}}) \times(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}}) results in a vector, not a scalar, due to the cross product operation.
444 Medium
444 of 489
Application +4 | -1
A stone is thrown vertically at a speed of 30 ms−130 \mathrm{~ms}^{-1} taking an angle of 45∘45^{\circ} with the horizontal. What is the maximum height reached by the stone? Take g=10 ms−2\mathrm{g}=10 \mathrm{~ms}^{-2}.
View answer and explanation
Correct option: B
22.5 m22.5 \mathrm{~m}
Option B (22.5 m22.5 \mathrm{~m}) is correct because it is the maximum height calculated using the projectile motion formula, considering the initial velocity and launch angle.
445 Medium
445 of 489
Analyzing +4 | -1
Following forces start acting on a particle at rest at the origin of the co-ordinate system simultaneously F⃗1=5i^−5j^+5k^,      F2=2i^+8j^+6k^,F3=−6i^+4j^−7k^,F4=−i^−3j^−2k^.{\mathrm{\vec F}_1} = 5\hat i - 5\hat j + 5\hat k,\mathrm{\;\;\;}{\mathrm{F}_2} = 2\hat i + 8\hat j + 6\hat k,{\mathrm{F}_3} = - 6\hat i + 4\hat j - 7\hat k,{\mathrm{F}_4} = - \hat i - 3\hat j - 2\hat k. The particle will move
View answer and explanation
Correct option: B
in y-z plane
Option B (in y-z plane) is correct because the resultant force vector has no component along the y-axis, indicating motion in the y-z plane.
446 Medium
446 of 489
Understanding +4 | -1
A projectile is projected at an angle of 47∘47^{\circ} relative to the horizontal. The range of the projectile could be increased by
View answer and explanation
Correct option: B
increasing the initial speed
Option B is correct because increasing the initial speed will increase the range of the projectile, given the fixed angle.
447 Medium
447 of 489
Application +4 | -1
A bullet is fired from a cannon with velocity 500 m/s . If the angle of projection is 15∘15^\circ and g=10  m/s2g = 10\;m/{s^2}. Then the range is
View answer and explanation
Correct option: B
12.5×103  m12.5 \times {10^3}\;m
Option B (12.5×103;m12.5 \times {10^3}\\;m) is correct because it is calculated using the range formula for projectile motion.
448 Easy
448 of 489
Application +4 | -1
Consider a vector F=4i^−3j^\mathbf{F}=4 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}. Another vector perpendicular to F\mathbf{F} is
View answer and explanation
Correct option: C
7k^7 \hat{\mathbf{k}}
Option C (7k^7 \hat{\mathbf{k}}) is correct because it is perpendicular to the XY-plane where F\mathbf{F} lies, thus their dot product is zero.
449 Medium
449 of 489
Application +4 | -1
The vectors A⃗=i^+2j^+3k^\vec{A}=\hat{i}+2 \hat{j}+3 \hat{k} and B⃗=2i^−j^\vec{B}=2 \hat{i}-\hat{j} are ___ to each other.
View answer and explanation
Correct option: A
A⃗⊥B⃗\vec{A} \perp \vec{B}
Option A (A⃗⊥B⃗\vec{A} \perp \vec{B}) is correct because the dot product of the two vectors is zero, indicating they are perpendicular.
450 Medium
450 of 489
Understanding +4 | -1
The shape of trajectory of the motion of an object is determined by
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because the trajectory of an object's motion depends on its initial position, initial velocity, and acceleration.
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