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JEE • PHYSICS • MECHANICAL PROPERTIES OF FLUIDS

Mechanical properties of fluids practice · Medium

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Showing 121-150 of 390 questions

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121 Medium
121 of 390
Application +4 | -1
A tank is filled to a height HH. The range of water coming out of a hole which is a depth H/4H / 4 from the surface of water level is
View answer and explanation
Correct option: B
3H2\frac{\sqrt{3} H}{2}
Option B (3H2\frac{\sqrt{3} H}{2}) is correct because the range is calculated using the formula for the range of a projectile launched from a height.
122 Medium
122 of 390
Understanding +4 | -1
A waterproofing agent changes the angle of contact
View answer and explanation
Correct option: B
from acute to obtuse.
Option B (from acute to obtuse) is correct because waterproofing agents increase the contact angle, making it obtuse and preventing wetting.
123 Medium
123 of 390
Application +4 | -1
A body weighs 160g160g in air, 130g130g in water and in oil. The specific gravity of oil is
View answer and explanation
Correct option: A
0.8
The correct answer is A (0.8) because specific gravity is calculated as the ratio of the loss of weight in oil to the loss of weight in water.
124 Medium
124 of 390
Understanding +4 | -1
A small sphere is falling in a viscous liquid with terminal speed. The work done by viscous force on the body in taking it through a finite displacement is;
View answer and explanation
Correct option: C
Negative
Option C (Negative) is correct because the viscous force opposes the motion, resulting in negative work done.
125 Medium
125 of 390
Application +4 | -1
A solid sphere of radius RR acquires a terminal velocity v1{v_1} when falling (due to gravity) through a viscous fluid having a coefficient of viscosity η\eta. The sphere is broken into 27 identical solid spheres. If each of these spheres acquires a terminal velocity, v2{v_2} when falling through the same fluid, the ratio (v1/v2)\left( {{v_1}/{v_2}} \right) equals
View answer and explanation
Correct option: A
9
Option A (9) is correct because the terminal velocity is proportional to the square of the radius, and the radius changes by a factor of 3 when the sphere is divided into 27 smaller spheres.
126 Medium
126 of 390
Remembering +4 | -1
If Reynold's number is greater than 3000, the flow of liquid is:
View answer and explanation
Correct option: B
Turbulent
Option B (Turbulent) is correct because Reynolds number greater than 3000 indicates turbulent flow.
127 Medium
127 of 390
Application +4 | -1
The water flows from a tap of diameter 1.25cm1.25cm with a rate of 5×10−5m3s−15 \times {10^{ - 5}}{m^3}{s^{ - 1}}. The density and coefficient of viscosity of water are 103kgm−3{10^3}kg{m^{ - 3}} and 10−3{10^{ - 3}} Pas, respectively. The flow of water is
View answer and explanation
Correct option: B
Turbulent with Reynolds number 5100
Option B (Turbulent with Reynolds number 5100) is correct because the calculated Reynolds number is greater than 3000, indicating turbulent flow.
128 Medium
128 of 390
Application +4 | -1
What is the maximum height (in m\mathrm{m} ) of a brick column of uniform cross section for which column deformation due to its own weight is within the elastic limit? [Patmospheric =100kPa,ρ=1.8×103\left[\mathrm{P}_{\text {atmospheric }}=100 \mathrm{kPa}, \rho=1.8 \times 10^3\right. kg/m3\mathrm{kg} / \mathrm{m}^3. Elastic limit, σ=3.7MPa\sigma=3.7 \mathrm{MPa}.]
View answer and explanation
Correct option: A
200
Option D (200) is correct because it is calculated by setting the pressure due to the column's weight equal to the elastic limit and solving for the height.
129 Medium
129 of 390
Application +4 | -1
The work done in blowing a soap bubble of radius 0.2 m is (Surface tension of water is 0.06 N/m )
View answer and explanation
Correct option: A
192π×10−4J192\pi \times {10^{ - 4}}J
Option A (192π×10−4J192\pi \times {10^{ - 4}}J) is correct because it is the work done calculated using the surface tension and the change in surface area of the soap bubble.
130 Medium
130 of 390
Understanding +4 | -1
Two stretched membranes of area2cm22\mathrm{c}{\mathrm{m}^2} and3cm23\mathrm{c}{\mathrm{m}^2} are placed in a liquid at the same depth. The ratio of pressure on them is
View answer and explanation
Correct option: A
1:11\mathrm{ }:\mathrm{ }1
Option A (1:11\mathrm{ }:\mathrm{ }1) is correct because pressure at a given depth in a liquid depends only on the depth and the density of the liquid, not the area.
131 Medium
131 of 390
Application +4 | -1
A straw 6 cm6\,cm long floats on water. The water film on one side has surface tension of 50 dyne/cm50\,dyne/cm on the other side camphor reduces the surface tension to 40 dyne/cm40\,dyne/cm.The force is
View answer and explanation
Correct option: A
(50×6−40×6)dyne\left( {50 \times 6 - 40 \times 6} \right)dyne
Option A ((50×6−40×6)dyne\left( {50 \times 6 - 40 \times 6} \right)dyne) is correct because the net force is the difference in surface tension multiplied by the length of the straw.
132 Medium
132 of 390
Understanding +4 | -1
Sudden fall of pressure at a place indicates:
View answer and explanation
Correct option: A
Storm
Option A (Storm) is correct because a sudden fall in pressure indicates the approach of a storm due to the rapid influx of air.
133 Medium
133 of 390
Application +4 | -1
An object is located at 2 km beneath the surface of the water. If the fractional compression ΔVV\frac{{\Delta V}}{V} is 1.36%, the ratio of hydraulic stress to the corresponding hydraulic strain will be………
(Take, density of water is 1000 kg m−31000\,\mathrm{ }kg\mathrm{ }\,{m^{ - 3}} and g=9.81 m s−2g = 9.81\,\mathrm{ m}\,{\mathrm{s}^{ - 2}} )
View answer and explanation
Correct option: D
1.44×109Nm−21.44 \times {10^9}\mathrm{N}{m^{ - 2}}
Option D (tan⁡−1(43)\tan ^{-1}\left(\frac{4}{3}\right)) is correct because the phase angle is calculated using the inductive reactance and resistance.
134 Medium
134 of 390
Application +4 | -1
A tube of length 3 m3 \mathrm{~m} is filled completely with an incompressible liquid of mass 2 kg2 \mathrm{~kg} and closed at both ends. The tube is rotated in horizontal plane about one of its ends with angular speed of 1 rad/s1 \mathrm{~rad} / \mathrm{s}. The force exerted by liquid at other end is
View answer and explanation
Correct option: C
3 N3 \mathrm{~N}
Option C (3 N) is correct because the force exerted by the liquid is calculated using integration and the given parameters.
135 Medium
135 of 390
Understanding +4 | -1
With an increase in temperature, surface tension of liquid (except molten copper and cadmium)
View answer and explanation
Correct option: C
decreases
Option C is correct because the surface tension of most liquids decreases as temperature increases due to increased molecular kinetic energy.
136 Medium
136 of 390
Understanding +4 | -1
Assertion: The contact angle between water and glass is acute.
Reason: The surface of water in the capillary is convex.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct because the contact angle between water and glass is acute, but the surface of water in a capillary is concave, not convex.
137 Medium
137 of 390
Application +4 | -1
A square frame of side LL is dipped in a liquid. On taking out, a membrane is formed. If the surface tension of the liquid is TT, the force acting on one side of the frame will be
View answer and explanation
Correct option: A
2TL2 T L
Option A (2TL2 T L) is correct because the force acting on one side of the frame is twice the surface tension times the length due to the two surfaces of the membrane.
138 Medium
138 of 390
Application +4 | -1
A soap bubble of diameter aa is produced using the soap solution of surface tension TT. Find the energy required to double the radius of the bubble without change of temperature.
View answer and explanation
Correct option: A
2πa2T2 \pi a^2 T
Option A (2πa2T2 \pi a^2 T) is correct because the energy required is calculated considering the two surfaces of the soap bubble.
139 Medium
139 of 390
Understanding +4 | -1
In a streamline flow if the gravitational head is hh. The kinetic and pressure heads are
View answer and explanation
Correct option: B
v2/2g{v^2}/2\mathrm{g} and p/ρp/\rho g
Option B (v2/2g{v^2}/2\mathrm{g} and p/ρp/\rho g) is correct because these are the standard expressions for kinetic and pressure heads in fluid dynamics.
140 Medium
140 of 390
Understanding +4 | -1
Wax is coated on the inner wall of a capillary tube and the tube is then dipped in water. Then, compared to the unwaxed capillary, the angle of contact θ\theta and the height hh upto which water rises change. These changes are :
View answer and explanation
Correct option: C
θ\theta increases and hh decreases
Option C (θ\theta increases and hh decreases) is correct because waxing the capillary tube increases the contact angle and reduces the capillary rise.
141 Medium
141 of 390
Remembering +4 | -1
An air foil has:
View answer and explanation
Correct option: A
Convex shape
Option A (Convex shape) is correct because an airfoil is designed with a convex shape on its upper surface to create lift.
142 Medium
142 of 390
Application +4 | -1
A water drop is divided into eight equal droplets. The pressure difference between the inner and outer side of the big drop will be
View answer and explanation
Correct option: B
1/21 / 2 of that for smaller droplet
Option B (1/21 / 2 of that for smaller droplet) is correct because the pressure difference is inversely proportional to the radius, and the radius of the big drop is twice that of the smaller droplets.
143 Medium
143 of 390
Application +4 | -1
A drop of radius RR is split under isothermal conditions into nn droplets, each of radius rr the ratio of surface energies of big and each small drop is
View answer and explanation
Correct option: B
n2/3:1{n^{2/3}}:1
Option B (n2/3:1{n^{2/3}}:1) is correct because the ratio of surface energies is proportional to the ratio of surface areas, which depends on the number of droplets.
144 Medium
144 of 390
Understanding +4 | -1
Select the correct statements from the following.
View answer and explanation
Correct option: D
All are correct
Option D is correct because all the statements are applications of Bernoulli's principle and atmospheric pressure.
145 Medium
145 of 390
Application +4 | -1
A body of density ρ\rho is dropped from rest from height hh (from the surface of water) into a lake of density of water σ(σ>ρ)\sigma(\sigma>\rho). Neglecting all dissipative effects, the acceleration of body while it is in the lake is
View answer and explanation
Correct option: A
g(σρ−1)g\left(\frac{\sigma}{\rho}-1\right) upwards
Option A (g(σρ−1)g\left(\frac{\sigma}{\rho}-1\right) upwards) is correct because the net acceleration is the difference between the buoyant force and the weight, divided by the mass, acting upwards.
146 Medium
146 of 390
Application +4 | -1
A cubical block of steel of each side equal to ll is floating on mercury in a vessel. The densities of steel and mercury are ρs\rho_s and ρm\rho_m. The height of the block above the mercury level is given by
View answer and explanation
Correct option: B
l(1−ρsρm)l\left(1-\frac{\rho_s}{\rho_m}\right)
Option B (l(1−ρsρm)l\left(1-\frac{\rho_s}{\rho_m}\right)) is correct because it represents the height of the block above the mercury level, calculated using the principle of floatation.
147 Medium
147 of 390
Application +4 | -1
A ball whose density is0.4×103kgm−30.4 \times {10^3}\mathrm{kg}{\mathrm{m}^{ - 3}} falls into water from a height of 9 cm. To what depth does the ball sink?
View answer and explanation
Correct option: B
6 cm
Option B (6 cm) is correct because the depth the ball sinks is calculated to be 6 cm by considering the buoyant force and the ball's density.
148 Medium
148 of 390
Application +4 | -1
A boat having a length 3 m3 \mathrm{~m} and breadth 2 m2 \mathrm{~m} is floating on a lake. The boat sinks by 1 cm1 \mathrm{~cm} when a man gets on it. The mass of the man is
View answer and explanation
Correct option: A
60 kg60 \mathrm{~kg}
Option A (60 kg60 \text{ kg}) is correct because it's calculated by equating the weight of the man to the extra upthrust experienced by the boat when it sinks by 1 cm.
149 Medium
149 of 390
Application +4 | -1
A sample of metal weight 300 gm300 \mathrm{~gm} in air, 270 gm270 \mathrm{~gm} liquid. Then find:

(1) Relative density of metal

(2) Relative density of unknown liquid.
View answer and explanation
Correct option: A
10,310,3
Option A (10, 3) is correct because it is calculated using the formulas for relative density.
150 Medium
150 of 390
Application +4 | -1
The pressure on a swimmer 20 m below the surface of water at sea level is
View answer and explanation
Correct option: D
3.0 atm
Option D (3.0 atm) is correct because it is the total pressure calculated by adding atmospheric pressure to the pressure due to the water column.
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