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JEE • PHYSICS • MAGNETISM AND MATTER

Magnetism and matter practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 323 questions

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181 Medium
181 of 323
Application +4 | -1
A magnet of 10 cm10 \mathrm{~cm} long and having a pole strength 2 amp m2 \mathrm{~amp} \mathrm{~m} is deflected through 30∘30^{\circ} from the magnetic meridian. The horizontal component of earth's induction is 0.32×10−4 T0.32 \times 10^{-4} \mathrm{~T}, then the value of deflecting couple is
View answer and explanation
Correct option: D
32×10−7 Nm32 \times 10^{-7} \mathrm{~Nm}
Option D (32×10−7 Nm32 \times 10^{-7} \mathrm{~Nm}) is correct because the deflecting couple is calculated using the formula τ=mBsin⁡θ\tau = mB \sin \theta, where mm is the magnetic moment.
182 Medium
182 of 323
Remembering +4 | -1
The product of magnetic susceptibility (χ)(\chi) and absolute temperature ( TT ) is constant for a
View answer and explanation
Correct option: B
paramagnetic material
Option B (paramagnetic material) is correct because the Curie law states that the magnetic susceptibility of a paramagnetic material is inversely proportional to its absolute temperature.
183 Medium
183 of 323
Understanding +4 | -1
A material is placed in a magnetic field and it is
thrown out of it. Then the material is ______
View answer and explanation
Correct option: B
diamagnetic
Option B (diamagnetic) is correct because diamagnetic materials are repelled by magnetic fields.
184 Medium
184 of 323
Application +4 | -1
A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20×10−6J/T20 \times {10^{ - 6}}J\mathrm{/}T when a magnetic intensity of 60×103A/m60 \times {10^3}A\mathrm{/}m is applied. Its magnetic susceptibility is
View answer and explanation
Correct option: A
3.3×10−43.3 \times {10^{ - 4}}
Option A (3.3×10−43.3 \times {10^{ - 4}}) is correct because it is the magnetic susceptibility calculated using the given magnetic dipole moment and magnetic intensity.
185 Medium
185 of 323
Understanding +4 | -1
Magnetic field strength due to a short bar magnet on its axial line at a distance x is B. Its value at the same distance on the equatorial line is
View answer and explanation
Correct option: D
B/2
Option D (B/2) is correct because the magnetic field on the equatorial line is half the magnetic field on the axial line at the same distance for a short bar magnet.
186 Medium
186 of 323
Application +4 | -1
A magnet when placed at an angle of 30∘30^\circ to a uniform field of strength 10−4   wb m−2{10^{ - 4}}\,\,\,wb\,{m^{ - 2}} experiences a couple of moment 4×10−5  Nm4 \times {10^{ - 5}}\,\,Nm. What is the magnetic moment of the magnet?
View answer and explanation
Correct option: C
0.8   Am20.8\,\,\,{\text{A}}{{\text{m}}^2}
Option C (0.8   Am20.8 \,\,\,{\text{A}}{{\text{m}}^2}) is correct because it is calculated directly from the torque equation τ=MBsin⁡θ\tau = MB\sin \theta given the magnetic field strength and the angle.
187 Medium
187 of 323
Understanding +4 | -1
Consider a short magnetic dipole of magnetic length 10 cm. Its geometric length is
View answer and explanation
Correct option: A
12 cm
Option A (12 cm) is correct because the geometric length of a magnet is approximately 6/5 times its magnetic length.
188 Medium
188 of 323
Understanding +4 | -1
Magnetic potential at any point on equatorial line of the magnetic dipole is
View answer and explanation
Correct option: D
0
Option D (0) is correct because the magnetic potential at any point on the equatorial line of a magnetic dipole is zero due to the angle being 90 degrees.
189 Medium
189 of 323
Understanding +4 | -1
A magnetic dipole of moment mm is in a uniform magnetic field of induction BB. If it is in stable equilibrium position in the field, the torque acting on it and potential energy are respectivley
View answer and explanation
Correct option: D
zero, −mB-mB
Option D (zero, −mB-mB) is correct because in stable equilibrium, the angle between the magnetic moment and the magnetic field is 0, resulting in zero torque and potential energy of −mB-mB.
190 Medium
190 of 323
Application +4 | -1
An inductor of 10 mH shows 50 mH when operate with a core mad e of ferrite. The susceptibility of ferrite is
View answer and explanation
Correct option: B
4
Option B (45) is correct because the current in a tangent galvanometer is proportional to the tangent of the deflection angle, allowing us to calculate the new deflection angle.
191 Medium
191 of 323
Remembering +4 | -1
The example of diamagnetic, paramagnetic and
ferromagnetic materials are respectively:
View answer and explanation
Correct option: A
copper, aluminium, iron
Option A (copper, aluminium, iron) is correct because copper is diamagnetic, aluminium is paramagnetic, and iron is ferromagnetic.
192 Medium
192 of 323
Remembering +4 | -1
Which among the following is correct regarding diamagnetic materials?
View answer and explanation
Correct option: D
They are feebly repelled by magnets
The correct answer is D (They are feebly repelled by magnets) because diamagnetic materials exhibit a weak repulsion to magnetic fields.
193 Medium
193 of 323
Understanding +4 | -1
At temperature T1,{T_1}, the magnetic susceptibility of a diamagnetic material is χ1{\chi _1} and at temperature T2,{T_2}, it is χ2.{\chi _2}. Then
View answer and explanation
Correct option: D
χ1=χ2{\chi _1} = {\chi _2}
Option D (χ1=χ2\chi_1 = \chi_2) is correct because the magnetic susceptibility of a diamagnetic material is independent of temperature.
194 Medium
194 of 323
Application +4 | -1
A magnet of length 0.1 m and pole strength 10−4{10^{ - 4}} A-m is kept in a magnetic field of 30 Wb m−2{\mathrm{m}^{ - 2}} at an angle 30∘.30^\circ . The couple acting on it is ……..×10−4\times {10^{ - 4}} Nm.
View answer and explanation
Correct option: D
1.5
Option D (1.5) is correct because the torque is calculated using the formula τ=MBsin⁡θ\tau = MB\sin{\theta}, where M is the magnetic moment, B is the magnetic field, and θ\theta is the angle.
195 Medium
195 of 323
Understanding +4 | -1
A vertical pillar of soft iron partially embedded in earth, at south pole, is found to be magnetized by the earth's magnetic field. The polarity at the top end of the pillar will be
View answer and explanation
Correct option: B
North pole
Option B is correct because at the South Pole, the Earth's magnetic field lines exit the Earth, magnetizing the iron pillar with a North Pole at the top.
196 Medium
196 of 323
Remembering +4 | -1
If a diamagnetic substance is brought near north or south pole of a bar magnet, it is
View answer and explanation
Correct option: B
Repelled by the poles
Option B (Repelled by the poles) is correct because diamagnetic substances are repelled by magnetic fields due to the induction of opposing magnetic dipoles.
197 Medium
197 of 323
Understanding +4 | -1
The property possessed by only ferromagnetic substance is
View answer and explanation
Correct option: A
Hysteresis
Option A (Hysteresis) is correct because hysteresis is a property unique to ferromagnetic substances, describing the lagging of magnetization behind the magnetizing field.
198 Medium
198 of 323
Remembering +4 | -1
The relation connecting magnetic susceptibility χm\chi_{\mathrm{m}} and relative permeability μr\mu_{\mathrm{r}} is
View answer and explanation
Correct option: B
χm=μr−1\chi_{\mathrm{m}}=\mu_{\mathrm{r}}-1
Option B (χm=μr−1\chi_{\mathrm{m}}=\mu_{\mathrm{r}}-1) is correct because the relationship between magnetic susceptibility and relative permeability is given by μr=1+χm\mu_r = 1 + \chi_m, which rearranges to χm=μr−1\chi_m = \mu_r - 1.
199 Medium
199 of 323
Application +4 | -1
A bar magnet of magnetic moment 4.0 A−m24.0 \mathrm{~A}-\mathrm{m} 2 is free to rotate about a vertical axis through its center. The magnet is released from rest from east-west position. Kinetic energy of the magnet in north-south position will be (H=25μT)(\mathrm{H}=25 \mu \mathrm{T})
View answer and explanation
Correct option: B
10−4 J10^{-4} \mathrm{~J}
Option B (10−4 J10^{-4} \mathrm{~J}) is correct because the kinetic energy gained is equal to the loss in potential energy as the magnet rotates from the east-west to the north-south position.
200 Medium
200 of 323
Remembering +4 | -1
Curie temperature is the temperature above which
View answer and explanation
Correct option: B
A ferromagnetic material becomes paramagnetic
Option B (A ferromagnetic material becomes paramagnetic) is correct because the Curie temperature is the temperature above which a ferromagnetic material loses its ferromagnetism and becomes paramagnetic.
201 Medium
201 of 323
Application +4 | -1
The radius of the coil of a tangent galvanometer which has 10 turns is 0.1 m. The current required to produce a deflection of 60∘  (BH=4×10−5  T)60^\circ \;\left( {{B_H} = 4 \times {{10}^{ - 5}}\mathrm{\;T}} \right) is
View answer and explanation
Correct option: B
1.1 A
Option B (1.1 A) is correct because the current is calculated using the tangent galvanometer formula with the given magnetic field, radius, number of turns, and deflection angle.
202 Medium
202 of 323
Application +4 | -1
A short bar magnet placed with its axis at 30∘30^{\circ} experiences a torque of 0.016 Nm0.016\,\mathrm{Nm} in an external field of 800G800 \mathrm{G}. (a) What is the magnetic moment of the magnet? (b) What is the work done by an external force in moving it from its most stable to most unstable position?
View answer and explanation
Correct option: A
0.40 Am2; 0.064 J0.40\,\mathrm{Am}^2;\,0.064 \mathrm{~J}
Option A (0.40 Am2; 0.064 J0.40\,\mathrm{Am}^2;\,0.064 \mathrm{~J}) is correct because it correctly calculates the magnetic moment and work done.
203 Medium
203 of 323
Remembering +4 | -1
Hysteresis loss is minimized by using
View answer and explanation
Correct option: D
Mu metal
Option D (Mu metal) is correct because Mu-metal is a nickel-iron alloy with very high permeability, which minimizes hysteresis loss in magnetic cores.
204 Medium
204 of 323
Understanding +4 | -1
The vertical component of earth’s magnetic field is zero or The earth’s magnetic field always has a vertical component except at the
View answer and explanation
Correct option: D
Magnetic equator
Option D (Magnetic equator) is correct because the vertical component of Earth's magnetic field is zero at the magnetic equator.
205 Medium
205 of 323
Understanding +4 | -1
At a point on the right bisector of a magnetic dipole magnetic
View answer and explanation
Correct option: A
Potential varies as 1r2\frac{1}{{{r^2}}}
Option A (Potential varies as 1r2\frac{1}{{{r^2}}}) is correct because the magnetic potential at a point on the right bisector of a magnetic dipole varies inversely with the square of the distance.
206 Medium
206 of 323
Understanding +4 | -1
Magnetic materials used for making permanent magnets (P)(P) and magnets in a transformer (T)(T) have different properties, of the following, which property best matches for the type of magnet required?
View answer and explanation
Correct option: B
P: Large retentivity, large coercivity
Option B (P: Large retentivity, large coercivity) is correct because permanent magnets need to retain their magnetism (large retentivity) and resist demagnetization (large coercivity).
207 Medium
207 of 323
Understanding +4 | -1
Assertion: Ferro-magnetic substances become paramagnetic below Curie temp.
Reason : Domains are destroyed at high temperature
View answer and explanation
Correct option: D
If the Assertion is incorrect and Reason is correct
Option D is correct because ferromagnetic substances become paramagnetic *above* the Curie temperature, and the reason correctly states that domains are destroyed at high temperatures.
208 Medium
208 of 323
Remembering +4 | -1
The unit of permeability of Vacuum (μ0)\left(\mu_0\right) is ______
View answer and explanation
Correct option: B
NA2\frac{\mathrm{N}}{\mathrm{A}^2}
Option B (NA2\frac{\mathrm{N}}{\mathrm{A}^2}) is correct because the unit of permeability of vacuum (μ0\mu_0) is Henry per meter (H/m), which is equivalent to Newton per Ampere squared (N/A²).
209 Medium
209 of 323
Understanding +4 | -1
Given below are two statements; one is labeled as Assertion A and the other is labeled as Reason R.

Assertion (A) : Electromagnets are made of soft iron.

Reason (R) : soft iron has high permeability and low retentivity.

In the light of above, statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: B
Both A and R are correct and R is the correct explanation of A
Option B (Both A and R are correct and R is the correct explanation of A) is correct because soft iron's high permeability allows easy magnetization, and low retentivity allows easy demagnetization, making it ideal for electromagnets.
210 Medium
210 of 323
Application +4 | -1
The values of the apparent angles of dip in two planes at right angles to each other are 30∘30^{\circ} and 45∘45^{\circ}. Calculate the true value of the angle of dip at the place.
View answer and explanation
Correct option: A
26.6∘26.6^{\circ}
Option A (26.6∘26.6^{\circ}) is correct because the true angle of dip is calculated using the formula relating it to the apparent angles of dip in two perpendicular planes.
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