Skip to main content
Back to MAGNETISM AND MATTER

Your Progress

0 / 335 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • MAGNETISM AND MATTER

Magnetism and matter practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 301-330 of 335 questions

Preparing practice and saved progress…

301 Medium
301 of 335
Application +4 | -1
The period of oscillation of a magnet at a place is 2 seconds. When it is remagnetised, so that the pole strength becomes 4 times the initial value. The period of oscillation in second is
View answer and explanation
Correct option: B
11
Option B (1) is correct because the time period is inversely proportional to the square root of the magnetic moment, which is proportional to the pole strength.
302 Medium
302 of 335
Understanding +4 | -1
For an isotropic medium B,  μ,  HB,\;\mu ,\;H and MM are related as (where B,  μ0,  HB,\;{\mu _0},\;H and MM have their usual meanings in the context of magnetic material)
View answer and explanation
Correct option: D
B=μ0(H+M)B = {\mu _0}\left( {H + M} \right)
Option D (B=μ0(H+M)B = {\mu _0}(H + M)) is correct because it represents the relationship between magnetic induction (B), magnetic field intensity (H), and magnetization (M) in an isotropic medium.
303 Medium
303 of 335
Understanding +4 | -1
Assertion: Super conductors can be easily levitated in strong magnetic field.
Reason: Magnetic susceptibility of super conductor is extremely positive.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because superconductors can be levitated, but their magnetic susceptibility is extremely negative (not positive).
304 Medium
304 of 335
Remembering +4 | -1
Substances, when placed in a magnetic field
acquire feeble magnetization in the direction
opposite to that of the applied field are called
View answer and explanation
Correct option: A
Diamagnetic substances
Option A (Diamagnetic substances) is correct because diamagnetic materials are repelled by a magnetic field, acquiring feeble magnetization in the opposite direction.
305 Medium
305 of 335
Application +4 | -1
The needle of a dip circle shows an apparent dip of 45∘45^{\circ} in a particular position and 53∘53^{\circ} when the circle is rotated through 90∘90^{\circ}. Find the true dip.
View answer and explanation
Correct option: C
39∘39^{\circ}
Option C (39∘39^{\circ}) is correct because the true dip is calculated using the formula involving the apparent dips in two perpendicular positions.
306 Medium
306 of 335
Application +4 | -1
The magnetic susceptibility of a material of a rod is 499. The absolute permeability of vacuum is 4π×10−7  Hm−14\pi \times {10^{ - 7}}\;\mathrm{H}{\mathrm{m}^{ - 1}}. The absolute permeability of the material of a rod is
View answer and explanation
Correct option: B
2π×10−4  Hm−12\pi \times {10^{ - 4}}\;\mathrm{H}{\mathrm{m}^{ - 1}}
Option B (2π×10−4  Hm−12\pi \times {10^{ - 4}}\;\mathrm{H}{\mathrm{m}^{ - 1}}) is correct because it is calculated using the formula for absolute permeability, considering the magnetic susceptibility and permeability of vacuum.
307 Medium
307 of 335
Remembering +4 | -1
The magnetic moment of a diamagnetic atoms is:
View answer and explanation
Correct option: D
Equal to zero
Option D (Equal to zero) is correct because diamagnetic atoms have no permanent magnetic dipole moment.
308 Medium
308 of 335
Application +4 | -1
A magnet of distance moment 2 J T−1{\mathrm{T}^{ - 1}} is aligned in the direction of magnetic field of 0.1 T. What is the net work done to bring, the magnet normal to the magnetic field?
View answer and explanation
Correct option: B
0.2 J
Option B (0.2 J) is correct because it is calculated by finding the difference in potential energy of the magnet in the initial and final positions.
309 Medium
309 of 335
Application +4 | -1
The magnetic susceptibility of a paramagnetic material is 1.0×10−51.0 \times 10^{-5} at 270C27^0 \mathrm{C} Temperature. Then, at what temperature its magnetic susceptibility would be 1.5×10−51.5 \times 10^{-5} ?
View answer and explanation
Correct option: C
−73∘C-73^{\circ} \mathrm{C}
Option C (−73∘C-73^{\circ} \mathrm{C}) is correct because the magnetic susceptibility of a paramagnetic material is inversely proportional to its absolute temperature.
310 Medium
310 of 335
Understanding +4 | -1
Which of the following properties is 'False' for
a bar magnet ?
View answer and explanation
Correct option: A
It doesn't produce magnetic field
Option A (It doesn't produce magnetic field) is correct because a bar magnet inherently produces a magnetic field.
311 Medium
311 of 335
Understanding +4 | -1
The oscillating electric and magnetic field vectors of electromagnetic wave are oriented along
View answer and explanation
Correct option: C
mutually perpendicular directions and are in same phase
Option C (mutually perpendicular directions and are in same phase) is correct because the electric and magnetic fields in an electromagnetic wave are perpendicular to each other and oscillate in phase.
312 Easy
312 of 335
Understanding +4 | -1
The dimensions of B is
View answer and explanation
Correct option: A
[M1T−2A−1]\left[ {{M^1}{T^{ - 2}}{A^{ - 1}}} \right]
Option A, [M1T−2A−1]\left[ {{M^1}{T^{ - 2}}{A^{ - 1}}} \right], is the correct dimension for magnetic field B, derived from the Lorentz force equation.
313 Easy
313 of 335
Application +4 | -1
A dip needle vibrates in the vertical plane perpendicular to magnetic meridian. The time period of vibration is found to be 2 s. The same needle is then allowed to vibrate in the horizontal plane and time period is again found to be 2s. Then the angle of dip is
View answer and explanation
Correct option: C
45∘^ \circ
Option C (45∘^ \circ) is correct because the time periods are equal, implying the horizontal and vertical components of the magnetic field are equal.
314 Medium
314 of 335
Understanding +4 | -1
If there is no torsion in the suspension thread, then the time period of a magnet executing SHM\mathrm{SHM} is :
View answer and explanation
Correct option: A
T=2πIMB\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{I}}{\mathrm{MB}}}
Option A (T=2πIMB\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{I}}{\mathrm{MB}}}) is correct because it represents the standard formula for the time period of a magnet in SHM without torsion.
315 Medium
315 of 335
Remembering +4 | -1
Meissner effect is related to
View answer and explanation
Correct option: B
Superconductors
Option B (Superconductors) is correct because the Meissner effect is a characteristic property of superconductors.
316 Medium
316 of 335
Understanding +4 | -1
The relation between total magnetic field (B), magnetic intensity (H)(\mathrm{H}), permeability of free space (μ0)\left(\mu_0\right) and susceptibility (χ)(\chi) is
View answer and explanation
Correct option: B
BH=μ0(1+χ)\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1+\chi)
Option B (BH=μ0(1+χ)\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1+\chi)) is correct because it represents the relationship between magnetic field, magnetic intensity, permeability, and susceptibility.
317 Medium
317 of 335
Understanding +4 | -1
Nickel shows ferromagnetic property at room temperature. If the temperature is increased beyond Curie temperature, then it will show
View answer and explanation
Correct option: A
Paramagnetism
Option A (Paramagnetism) is correct because above the Curie temperature, ferromagnetic materials lose their long-range order and become paramagnetic, where atomic magnetic moments align weakly with an external field.
318 Medium
318 of 335
Application +4 | -1
A 3 cm×10 cm3 {~cm} \times 10 {~cm} rectangular coil with number of turns 300 is placed in uniform magnetic field of strength 0.2 T0.2 {~T}. The maximum magnetic torque acting on it when a current of 10−4 A10^{-4} {~A} is passed through it; 
View answer and explanation
Correct option: D
1.8×10−5Nm1.8 \times 10^{-5} {Nm}
Option D (1.8×10−5Nm1.8 \times 10^{-5} {Nm}) is correct because it is the maximum torque calculated using the formula τ=NIBAsin⁡θ\tau = NIBA \sin \theta with θ=90∘\theta = 90^{\circ}.
319 Medium
319 of 335
Understanding +4 | -1
Due to the earth’s magnetic field, charged cosmic ray particles
View answer and explanation
Correct option: C
Can never reach the equator
Option A (Require greater kinetic energy to reach the equator than the poles) is correct because charged particles are deflected more strongly near the equator due to the Earth's magnetic field, requiring more energy to overcome this deflection.
320 Medium
320 of 335
Understanding +4 | -1
A bar magnet is characterized by
View answer and explanation
Correct option: D
all of these
Option D (all of these) is correct because a bar magnet exhibits directional properties, attracts magnetic materials, and induces magnetism in other materials.
321 Easy
321 of 335
Analyzing +4 | -1
Assertion: If a unit north pole rotates around a current carrying wire then work has to be done.
Reason: Magnetic field produced by current is always non - conservative in nature.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because the work done is non-zero due to the non-conservative nature of the magnetic field produced by the current-carrying wire.
322 Medium
322 of 335
Application +4 | -1
A magnet placed in the magnetic meridian with its north pole pointing north of the earth produces a neutral point at a distance of 0.15 m0.15 \mathrm{~m} from either pole. It is then broken into two equal pieces and one such piece is placed in a similar position. Find the position of the neutral point.
View answer and explanation
Correct option: A
0.119 m
Option A (0.119 m) is correct because when the magnet is broken, its magnetic moment changes, and the new distance to the neutral point can be calculated using the relationship between magnetic field and distance.
323 Medium
323 of 335
Understanding +4 | -1
Assertion (A): Electromagnets are made of soft iron.

Reason (R): Coercivity of soft iron is small.
View answer and explanation
Correct option: A
If both (A) and (R) are true and the (R) is a correct explanation of the (A)
Option A (If both (A) and (R) are true and the (R) is a correct explanation of the (A)) is correct because electromagnets need to be easily magnetized and demagnetized, which is facilitated by the low coercivity of soft iron.
324 Medium
324 of 335
Understanding +4 | -1
If the susceptibility of dia, para and ferro magnetic materials are χd,χp,χf\chi_{\mathrm{d}}, \chi_{\mathrm{p}}, \chi_{\mathrm{f}} respectively, then
View answer and explanation
Correct option: A
χd<χp<χf\chi_{\mathrm{d}} < \chi_{\mathrm{p}} < \chi_{\mathrm{f}}
Option C (The velocity at the highest point is directed along the horizontal) is correct because at the highest point, the vertical component of velocity is zero, leaving only the horizontal component.
325 Medium
325 of 335
Application +4 | -1
In the magnetic meridian of a certain place, the horizontal component of the Earth's magnetic field is 86.6 G86.6 \mathrm{~G} (Gauss) and the magnetic field of earth is 100 G100 \mathrm{~G} (Gauss). Then the dip angle is
View answer and explanation
Correct option: C
30∘30^{\circ}
Option C (30∘30^{\circ}) is correct because the dip angle is calculated using the horizontal component and the Earth's magnetic field.
326 Medium
326 of 335
Understanding +4 | -1
χ1\chi_1 and χ2\chi_2 are susceptibility of a paramagnetic material at temperatures T1 KT_1\,K and T2 KT_2\,K respectively, then :
View answer and explanation
Correct option: B
χ1 T1=χ2 T2\chi_1 \mathrm{~T}_1=\chi_2 \mathrm{~T}_2
Option C is correct because, according to Curie's law, the magnetic susceptibility of a paramagnetic material is inversely proportional to its temperature.
327 Medium
327 of 335
Understanding +4 | -1
A hydrogen atom is paramagnetic. A hydrogen molecule is
View answer and explanation
Correct option: A
Diamagnetic
Option A (Diamagnetic) is correct because the hydrogen molecule has no unpaired electrons, resulting in a net magnetic moment of zero.
328 Medium
328 of 335
Understanding +4 | -1
The unit of μ04π\frac{\mu_{0}}{4 \pi} is
View answer and explanation
Correct option: B
NA−2N A^{-2}
Option B is correct because the unit of μ04π\frac{{\mu_{0}}}{{4 \pi}} is NA−2N A^{{-2}}, derived from the Biot-Savart law or Ampere's law.
329 Medium
329 of 335
Application +4 | -1
A thin magnetic needle oscillates in a horizontal plane with a period T\mathrm{T}. It is broken into nn equals parts. The time period of each part will be
View answer and explanation
Correct option: D
T/n\mathrm{T} / \mathrm{n}
Option D (T/n\mathrm{T} / \mathrm{n}) is correct because the time period is inversely proportional to the number of parts the needle is broken into.
330 Medium
330 of 335
Remembering +4 | -1
The hysteresis cycle for the material of permanent magnet is
View answer and explanation
Correct option: C
Tall and wide
Option C (Tall and wide) is correct because a permanent magnet needs high coercivity and retentivity, resulting in a tall and wide hysteresis cycle.
Revision notes and key takeaways

Review MAGNETISM AND MATTER in your textbook or class notes, then use this set to check your understanding.

Showing 301-330 of 335 questions

Your practice

0 / 335 answered · 335 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.