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JEE • PHYSICS • MAGNETIC EFFECT OF CURRENT

Magnetic effect of current practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-385 of 385 questions
361 Medium
361 of 385
Application +4 | -1
A charged particle has acceleration a⃗=2i^+xj^\vec{\mathrm{a}}=2 \hat{\mathrm{i}}+x \hat{j} in the magnetic field B⃗=−3i^+2j^−4k^\vec{B}=-3 \hat{i}+2 \hat{j}-4 \hat{k}. Find the value of xx.
View answer and explanation
Correct option: A
3
Option A (3) is correct because the acceleration and magnetic field are perpendicular, implying their dot product is zero.
362 Medium
362 of 385
Understanding +4 | -1
A charge is moving in a circular path in uniform magnetic field. The path of charge is
View answer and explanation
Correct option: B
Uniformly accelerated motion
Option B (Uniformly accelerated motion) is correct because the magnetic force provides centripetal acceleration, causing the charge to move in a circle with constant speed but changing velocity direction.
363 Medium
363 of 385
Understanding +4 | -1
The path of a charged particle entering in a uniform magnetic field making an angle 60∘60^{\circ} with the field is
View answer and explanation
Correct option: D
Helical
Option D is correct because when a charged particle enters a uniform magnetic field at an angle, its path becomes helical due to the combined effects of the magnetic force and the particle's velocity components.
364 Medium
364 of 385
Understanding +4 | -1
An electron enters a region where magnetic
field (B) and electric field (E) are mutually
perpendicular, then
View answer and explanation
Correct option: D
it can go undeflected also
The correct answer is D (it can go undeflected also) because if the electric and magnetic forces are balanced, the electron will experience no net force and continue in a straight line.
365 Medium
365 of 385
Application +4 | -1
A positive charge of 1.5μC1.5 \mu \mathrm{C} is moving with a speed of 2×106 ms−12 \times 10^6 \mathrm{~ms}^{-1} along the positive X\mathrm{X}-axis. A magnetic field, B⃗=(0.2j^+0.4k^)\vec{B}=(0.2 \hat{j}+0.4 \hat{k}) tesla acts in space. Find the magnetic force acting on the charge.
View answer and explanation
Correct option: A
(0.6k^−1.2j^)N(0.6 \hat{k}-1.2 \hat{j}) \mathrm{N}
Option A (16) is correct because the focal length is calculated using the lens formula and the condition that the images are in the same plane.
366 Medium
366 of 385
Understanding +4 | -1
In using Ampere’s law to find the magnetic
field of a straight, long solenoid, the loop
(Amperian loop) that is taken is
View answer and explanation
Correct option: D
A rectangular loop in a plane containing the
axis of the solenoid, the loop being partly
inside the solenoid, and partly outside it
Option D (A rectangular loop in a plane containing the axis of the solenoid, the loop being partly inside the solenoid, and partly outside it) is correct because this configuration allows for the application of Ampere's law to relate the magnetic field to the current.
367 Medium
367 of 385
Application +4 | -1
The cyclotron frequency of an electron grating in a magnetic field of 1 T is approximately
View answer and explanation
Correct option: D
28 GHz
Option D (28 GHz) is correct because it calculates the cyclotron frequency using the formula f=Bq2πmf = \frac{{Bq}}{{2\pi m}} with the given magnetic field and electron properties.
368 Medium
368 of 385
Application +4 | -1
If a current of 200μA200 \mu \mathrm{A} deflects the coil of moving coil galvanometer through 60∘60^{\circ}, then the current required to cause deflection through π10\frac{\pi}{10} radians is
View answer and explanation
Correct option: A
60μA60 \mu \mathrm{A}
Option A (60μA60 \mu \mathrm{A}) is correct because the current is directly proportional to the deflection angle in a moving coil galvanometer.
369 Medium
369 of 385
Remembering +4 | -1
Magnetic field at a distance rr from an infinitely long straight conductor carrying a steady current varies as:
View answer and explanation
Correct option: C
1r\frac{1}{\mathrm{r}}
Option C (1r\frac{{1}}{{\mathrm{{r}}}}) is correct because the magnetic field due to an infinitely long straight conductor is inversely proportional to the distance r.
370 Medium
370 of 385
Analyzing +4 | -1
Choose the wrong statement
View answer and explanation
Correct option: D
while passing through a given place, the path of electron remains straight line. It can be definitely said that the magnetic field is not present at that place
Option D (while passing through a given place, the path of electron remains straight line. It can be definitely said that the magnetic field is not present at that place) is the wrong statement because the electron could be moving parallel to the magnetic field.
371 Medium
371 of 385
Application +4 | -1
Current sensitivity of a moving coil galvanometer is 5  div / mA\mathrm{5}{\mkern 1mu} {\mkern 1mu} \mathrm{div}{\mkern 1mu} \mathrm{/}{\mkern 1mu} m\mathrm{A} and its voltage sensitivity (angular deflection per unit voltage applied) is 20  div / V\mathrm{20}\,\,\mathrm{div}\,\mathrm{/}\,\mathrm{V}. The resistance of the galvanometer is
View answer and explanation
Correct option: C
 250  Ω\,250\,\,\Omega
Option C (250 Ω\Omega) is correct because the resistance is calculated by dividing the voltage sensitivity by the current sensitivity.
372 Medium
372 of 385
Application +4 | -1
A proton and an α\alpha-particle are projected normally with the same speed into a magnetic field. What will be the ratio of radii of the trajectories of the proton and α\alpha - particle?
View answer and explanation
Correct option: B
1:21:2
Option B (1:2) is correct because the radius of the trajectory is proportional to the mass and inversely proportional to the charge, leading to the ratio 1:2.
373 Medium
373 of 385
Understanding +4 | -1
The magnetic moment of current (I) carrying circular coil of radius ( rr ) and number of turns (n) varies as:
View answer and explanation
Correct option: D
r2\mathrm{r}^2
The correct answer is D (r²) because the magnetic moment is directly proportional to the area of the coil, which is proportional to r².
374 Medium
374 of 385
Application +4 | -1
A galvanometer with a coil resistance of 100  Ω100\,\,\Omega gives a full-scale deflection when a current of 1  mA1\,\,mA is passed through it. The resistance of the shunt needed in ohm to convert this galvanometer into an ammeter of range 10 A10\,A is nearly.
View answer and explanation
Correct option: A
0.01
Option D (0.099\mathrm{0}\mathrm{.099}) is correct because it is the shunt resistance value needed to convert the galvanometer into an ammeter of the specified range.
375 Medium
375 of 385
Analyzing +4 | -1
Statement I: When radius of a circular wire carrying current is doubled, its magnetic moment becomes four times.
Statement II: Magnetic moment is directly proportional to area of the loop.
Which of the following statement(s) is/are correct?
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct because the magnetic moment is proportional to the area of the loop, and doubling the radius makes the area four times larger.
376 Medium
376 of 385
Application +4 | -1
Two straight parallel wires carry currents of 200   mA   and    1A200\,\,{\mkern 1mu} mA\,\,{\mkern 1mu} \mathrm{and}\,\,\,{\mkern 1mu} 1A in opposite directions. If the wires are 20 cm apart, the distance of the neutral point from the 1A1A wire is (in cm)
View answer and explanation
Correct option: D
25
Option A (5) is incorrect. Option B (15) is incorrect. Option C (20) is incorrect. Option D (25) is correct because the neutral point is located at a distance where the magnetic fields due to both wires cancel each other out. The distance from the smaller current wire is calculated, then added to the distance between the wires to find the distance from the 1A wire.
377 Medium
377 of 385
Understanding +4 | -1
Statement-1: A charged particle can never move along a magnetic field line in absence of any other force.
Statement-2: Force due to magnetic field is given by F→=q(v⃗×B→)\overrightarrow{{F}}=q(\vec{v} \times \overrightarrow{{B}})
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option C (Statement-I is false and statement-II is true) is correct because a man in a lift moving with uniform velocity will feel his normal weight, and in downward accelerated motion, the apparent weight decreases.
378 Medium
378 of 385
Application +4 | -1
A wire in the form of a square of side a carries a current i\mathrm{i}. Then, the magnetic induction at the centre of the square is (magnetic permeability of free space =μ0=\mu_0)
View answer and explanation
Correct option: C
22μ0iπa\frac{2 \sqrt{2} \mu_0 \mathrm{i}}{\pi \mathrm{a}}
Option C (22μ0iπa\frac{{2 \sqrt{2} \mu_0 \mathrm{i}}}{{\pi \mathrm{a}}}) is correct because the magnetic field at the center of the square is the sum of the fields due to each side, calculated using the Biot-Savart law.
379 Medium
379 of 385
Application +4 | -1
An electron beam moving with a velocity of 106 ms−110^6 \mathrm{~ms}^{-1} through a uniform magnetic field of 0.1 T0.1\,T, which is perpendicular to the direction of the beam. Calculate the force on an electron if the electron charge is 1.6×10−19C1.6 \times 10^{-19} \mathrm{C}.
View answer and explanation
Correct option: A
1.6×10−14 N1.6 \times 10^{-14} \mathrm{~N}
Option A (1.6×10−14 N1.6 \times 10^{-14} \mathrm{~N}) is correct because it is calculated using the Lorentz force formula, considering the electron's charge, velocity, and the magnetic field strength.
380 Medium
380 of 385
Remembering +4 | -1
The source of magnetic field is ____ & source
of electric field is _____.
View answer and explanation
Correct option: A
vector, vector
Option D (vector, scalar) is correct because magnetic field is a vector quantity and electric field is a scalar quantity.
381 Medium
381 of 385
Application +4 | -1
For full scale deflection of total 50 divisions, 50mV voltage is required in galvanometer. The resistance of galvanometer if its current sensitivity is 2 div/mA will be
View answer and explanation
Correct option: D
2 Ω2\,\Omega
Option A (−6.22×107 J kg−1-6.22 \times 10^7 \mathrm{~J} \mathrm{~kg}^{-1}) is correct because it is the gravitational potential calculated using the given values for radius, density, and gravitational constant.
382 Medium
382 of 385
Application +4 | -1
The coercivity of a bar magnet is 120 A/m120 {~A} / {m}. It is to be demagnetised by placing it inside a solenoid having number of turns per unit length 60 m−160 {~m}^{-1}. The current flowing through the solenoid is
View answer and explanation
Correct option: C
2.0 A2.0 {~A}
Option C (2.0 A2.0 {~A}) is correct because it's the current required to demagnetize the magnet, calculated using the coercivity and number of turns per unit length.
383 Medium
383 of 385
Application +4 | -1
The magnetic field due to a current carrying circular loop of radius 3 cm at a point on the axis at a distance of 4 cm from the centre is 54 μT54\,\mu T. What will be its value at the centre of loop?
View answer and explanation
Correct option: C
250 μT250\,\mu T
Option C (250 μT250\,\mu T) is correct because the magnetic field at the center of the loop is calculated using the formula and the given magnetic field at a point on the axis.
384 Medium
384 of 385
Remembering +4 | -1
The magnetic field at the origin due to a current element i.dli . d l placed at a point with vector position r\mathbf{r}
The correct Biot-Savart law in vector form is :
View answer and explanation
Correct option: A
μ04πdl×r→r3\frac{\mu_0}{4 \pi} \frac{\mathrm{d} l \times \overrightarrow{\mathrm{r}}}{\mathrm{r}^3}
Option A (μ04πdl×r→r3\frac{\mu_0}{4 \pi} \frac{\mathrm{d} l \times \overrightarrow{\mathrm{r}}}{\mathrm{r}^3}) is correct because it represents the Biot-Savart law in vector form, showing the relationship between the magnetic field, current element, and position vector.
385 Medium
385 of 385
Understanding +4 | -1
Assertion (A): No net force acts on a rectangular coil carrying a steady current when suspended freely in a uniform magnetic field.

Reason (R): Forces acting on each pair of the opposite sides of the coil are equal and opposite.
View answer and explanation
Correct option: A
(A) and (R) are true and (R) is the correct explanation of (A)
Option A ((A) and (R) are true and (R) is the correct explanation of (A)) is correct because the net force is zero due to equal and opposite forces on opposite sides of the coil.
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