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JEE • PHYSICS • GRAVITATION

Gravitation practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 392 questions

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211 Medium
211 of 392
Analyzing +4 | -1
Assertion: Comets move around the Sun in elliptical orbits. The gravitational force on the comet due to Sun is not normal to the comet? Velocity but the work done by the gravitational force over every complete orbit of the comet is zero.
Reason: Gravitational force is a non-conservative force.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct because the assertion is true, comets move in elliptical orbits and the gravitational force does zero work over a complete orbit, but the reason is false, as gravitational force is a conservative force.
212 Medium
212 of 392
Understanding +4 | -1
Select the correct statement from the following
View answer and explanation
Correct option: D
The orbital velocity is inversely proportional to the square root of the radius of the orbit
Option D (The orbital velocity is inversely proportional to the square root of the radius of the orbit) is correct because v=GM/rv = \sqrt{{GM/r}}.
213 Medium
213 of 392
Understanding +4 | -1
An astronaut orbiting the earth in a circular orbit 120 km above the surface of earth, gently drops a spoon out of space-ship. The spoon will
View answer and explanation
Correct option: C
Will move along with space-ship
Option C (Will move along with space-ship) is correct because the spoon has the same initial velocity as the spaceship and will continue to orbit with it.
214 Medium
214 of 392
Application +4 | -1
The escape velocity from the earth is 11  km/s11\,\,km/s . The escape velocity from a planet having twice the radius and same density as that of the earth is (in km/skm/s )
View answer and explanation
Correct option: A
22
Option A (22 km/s) is correct because the escape velocity is proportional to the radius when the density is constant.
215 Medium
215 of 392
Application +4 | -1
A planet of mass of 16\frac{1}{6} th of earth's mass, radius of 13\frac{1}{3} rd of earth's radius. If escape speed for earth is 11.2 km/s11.2 \mathrm{~km} / \mathrm{s}, then escape speed for the planet shall be km/s\mathrm{km} / \mathrm{s} (nearest integer).
View answer and explanation
Correct option: D
8
Option D (8) is correct because the escape speed is proportional to Mr\sqrt{\frac{M}{r}}, so ve′=veM′Mrr′=11.21/61/3=11.2/2≈8 km/sv_e' = v_e \sqrt{\frac{M'}{M} \frac{r}{r'}} = 11.2 \sqrt{\frac{1/6}{1/3}} = 11.2/\sqrt{2} \approx 8 \text{ km/s}.
216 Medium
216 of 392
Analyzing +4 | -1
Assertion: When two masses come closer, their gravitational potential energy decreases.

Reason: Two masses attract each other.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion
Option B is correct because both the assertion and reason are true, but the reason is not the correct explanation for the assertion. The decrease in potential energy is due to the inverse relationship between potential energy and distance, not simply the attraction.
217 Medium
217 of 392
Application +4 | -1
If the mass and radius of the planet are doubled
then acceleration due to gravity on its surface will
become (density of the planet remains same)
View answer and explanation
Correct option: B
One half
Option B (One half) is correct because if mass and radius are doubled while density remains constant, the acceleration due to gravity becomes half of its original value.
218 Medium
218 of 392
Understanding +4 | -1
Assertion: Even when orbit of a satellite is elliptical, its plane of rotation passes through the centre of earth.
Reason: According to law of conservation of angular momentum, the plane of rotation of satellite always remains same.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (If both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because the conservation of angular momentum dictates that the orbital plane remains constant.
219 Medium
219 of 392
Application +4 | -1
If a new planet is discovered rotating around the sum with the orbital radius double that of earth, then what will be its time period (in earth’s days)?
View answer and explanation
Correct option: A
1032
Option A (1032) is correct because, according to Kepler's third law, the square of the period is proportional to the cube of the orbital radius. Doubling the radius results in a period of approximately 1032 days.
220 Medium
220 of 392
Understanding +4 | -1
Given below are two statements:
Statement I: In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (E1)\left( {{E_1}} \right) to higher energy orbit (E2),\left( {{E_2}} \right), is given as hf=E1−E2.hf = {E_1} - {E_2}.
Statement II: The jumping of electron from higher energy orbit (E2)\left( {{E_2}} \right) to lower energy orbit (E1)\left( {{E_1}} \right) is associated with frequency of radiation given as f=(E2−E1)h.f = \frac {{\left( {{E_2} - {E_1}} \right)}}{h}.
This condition is Bohr’s frequency condition.
In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: D
Statement I is incorrect but statement II is true
Option D is correct because radiation is emitted when an electron jumps from a higher to a lower energy level, and the frequency is given by f=(E2−E1)hf = \frac{{(E_2 - E_1)}}{{h}}.
221 Medium
221 of 392
Understanding +4 | -1
A missile is launched with a velocity less than the escape velocity. The sum of its kinetic and potential energy is
View answer and explanation
Correct option: B
negative
Option B (negative) is correct because if the missile's velocity is less than the escape velocity, it is still bound by Earth's gravity, resulting in negative total energy.
222 Medium
222 of 392
Remembering +4 | -1
LANDSAT series of satellites move in near polar orbits at an altitude of
View answer and explanation
Correct option: C
918 km
Option C (918 km) is correct because LANDSAT satellites typically orbit at an altitude around 918 km.
223 Medium
223 of 392
Application +4 | -1
Two planets of radii in the ratio 2:32:3 are made from the material of density in the ratio 3:23:2. Then, the ratio of acceleration due to gravity g1g2\frac{{{g_1}}}{{{g_2}}} at the surface of the two planets will be
View answer and explanation
Correct option: A
1
Option A (1) is correct because the ratio of acceleration due to gravity is directly proportional to the product of density and radius, and these factors cancel out in this case.
224 Medium
224 of 392
Understanding +4 | -1
Escape speed of a body from the earth depend on
View answer and explanation
Correct option: D
The height of launching location
Option D (The height of launching location) is correct because the escape speed depends on the gravitational potential at the launching location, which is determined by the height above the Earth's surface.
225 Medium
225 of 392
Application +4 | -1
Two spheres of radius r and 2rr\,and\,2r are touching each other. The fore of attraction between them is proportional to
View answer and explanation
Correct option: D
r−2{r^{ - 2}}
Option C (r2{r^2}) is incorrect. The correct answer is B (r4{r^4}) because the force of attraction is proportional to the product of the masses and inversely proportional to the square of the distance between their centers. Since mass is proportional to r3r^3, the force is proportional to r6/r2=r4r^6/r^2 = r^4.
226 Medium
226 of 392
Analyzing +4 | -1
Assertion: At pole value of acceleration due to gravity (g)(g) is greater than that of equator.

Reason : Earth rotates on its axis in addition to revolving round the sun.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion.) is correct because the Earth's rotation causes the value of g to be minimum at the equator and maximum at the poles.
227 Medium
227 of 392
Application +4 | -1
Ve{V_e} and Vp{V_p} denotes the escape velocity from the earth and another planet having half the radius and the same mean density as the earth then
View answer and explanation
Correct option: B
Ve=Vp2{V_e} = \frac{{{V_p}}}{2}
Option B (Ve=Vp2{V_e} = \frac{{{V_p}}}{2}) is correct because the escape velocity is proportional to the radius, and the planet has half the radius of the Earth.
228 Medium
228 of 392
Application +4 | -1
The maximum horizontal range of a projectile on the earth is R. Then for the same velocity of projection, its maximum range on another plant is 5R4\frac{{5R}}{4}. Then the ratio of acceleration due to gravity on that planet and on the earth is
View answer and explanation
Correct option: B
4:54:5
Option B (4:5) is correct because the maximum range is inversely proportional to the acceleration due to gravity, so the ratio of gravities is the inverse ratio of the ranges.
229 Medium
229 of 392
Application +4 | -1
A satellite in a circular orbit of radius RR has a period of 4h4h. Another satellite with orbital radius 3R3R around the same planet will have a period (in hour)
View answer and explanation
Correct option: C
4274\sqrt {27}
Option C (4274\sqrt {27}) is correct because it is derived from Kepler's third law, which relates the period and orbital radius of a satellite.
230 Medium
230 of 392
Understanding +4 | -1
The period of a satellite in a circular orbit around a planet is independent of
View answer and explanation
Correct option: C
The mass of the satellite
Option C (The mass of the satellite) is correct because the period of a satellite's orbit depends on the mass of the planet and the orbital radius, but not the mass of the satellite.
231 Medium
231 of 392
Analyzing +4 | -1
Assertion: Angular momentum of a satellite remains conserved.
Reason: Conservation of linear momentum leads to conservation of angular momentum.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct. Angular momentum of a satellite is conserved because there is no external torque acting on it, but conservation of linear momentum does not directly lead to conservation of angular momentum.
232 Medium
232 of 392
Application +4 | -1
The weight of a body on surface of earth is 12.6 N. When it is raised to a height half the radius of earth its weight will be
View answer and explanation
Correct option: B
5.6 N
Option B (5.6 N) is correct because the weight decreases as the distance from the Earth's center increases, following an inverse square relationship.
233 Medium
233 of 392
Understanding +4 | -1
Every planet revolves around the sun in an elliptical
orbit:

A. The force acting on a planet is inversely
proportional to square of distance from sun.

B. Force acting on planet is inversely proportional
to product of the masses of the planet and the
sun.

C. The Centripetal force acting on the planet is
directed away from the sun.

D. The square of time period of revolution of
planet around sun is directly proportional to
cube of semi-major axis of elliptical orbit.

Choose the correct answer from the options given
below:
View answer and explanation
Correct option: D
A and D only
Option D (A and D only) is correct because Kepler's laws state that the force is inversely proportional to the square of the distance and the square of the period is proportional to the cube of the semi-major axis.
234 Medium
234 of 392
Analyzing +4 | -1
Two identical satellites are at RR and 7R7R away from earth surface, the wrong statement is
View answer and explanation
Correct option: D
Ratio of total energy will be 4 but ratio of potential and kinetic energies will be 2.
Option D is the wrong statement because the ratio of potential and kinetic energies should also be 4, similar to the total energy ratio.
235 Medium
235 of 392
Understanding +4 | -1
Assertion: For circular orbits, the law of periods is T2∝r3{T}^2 \propto {r}^3, where M{M} is the mass of sun and rr is the radius of orbit.
Reason: The square of the period TT of any planet about the sun is proportional to the cube of the semi-major axis aa of the orbit.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because Kepler's Third Law states that the square of the period is proportional to the cube of the semi-major axis, which applies to circular orbits as well.
236 Medium
236 of 392
Application +4 | -1
A satellite of mass 200 kg is orbiting around the earth at a height of 400 km above its surface. The energy required to send it out of the earth’s gravitational influence is (Mass of earth =6×1024kg= 6 \times {10^{24}}kg, Radius of earth = 6000 km, G=6.67×10−11 Nm2 kg−2G = 6.67 \times {10^{ - 11}}\,N{m^2}\,k{g^{ - 2}})
View answer and explanation
Correct option: C
4×109J4 \times {10^9}J
Option C (4×109J4 \times {10^9}J) is correct because it is the energy required to escape Earth's gravitational influence, calculated using the gravitational potential energy formula.
237 Medium
237 of 392
Application +4 | -1
The masses and radii of the earth and moon are M1,R1{M_{1,}}{R_1} and M2,R2{M_{2,}}{R_2} respectively, their centres are distance dd apart. The minimum velocity with which a particle of mass mm should be projected from a point midway between their centres so that it escapes to infinity is
View answer and explanation
Correct option: A
2Gd(M1+M2)2\sqrt {\frac{G}{d}({M_1} + {M_2})}
Option A is correct because it calculates the escape velocity based on the gravitational potential at the midpoint between the Earth and Moon.
238 Medium
238 of 392
Application +4 | -1
Two bodies of masses m1 and m2{m_1}\,and\,{m_2} are initially at rest at infinite distance apart. They are then allowed to move towards each other under mutual gravitational attraction. Their relative velocity of approach at a separation distance rr between them is
View answer and explanation
Correct option: B
[2Gr(m1+m2)]1/2{\left[ {\frac{{2G}}{r}\left( {{m_1} + {m_2}} \right)} \right]^{1/2}}
Option B ({\left[ {\frac{{2G}}{r}\left( {{{m_1} + {m_2}} \right)} \right]^{1/2}}{\left[ {\frac{{2G}}{r}\left( {{{m_1} + {m_2}} \right)} \right]^{1/2}}) is correct because it represents the relative velocity derived from conservation of energy and momentum for two masses approaching each other under gravitational attraction.
239 Medium
239 of 392
Analyzing +4 | -1
In the following four periods
(i) Time of revolution of a satellite just above the earth’s surface (Tst)\left( {{T_{st}}} \right) , (ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth (Tma)\left( {{T_{ma}}} \right) , (iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8N/kg(Tsp)9.8N/kg\left( {{T_{sp}}} \right) , (iv) Period of an infinite length simple pendulum in the earth’s real gravitational filed (Tis)\left( {{T_{is}}} \right)
View answer and explanation
Correct option: C
Tsp>Tis{T_{sp}} > {T_{is}}
Option C (Tsp>Tis{T_{sp}} > {T_{is}}) is correct because the period of a simple pendulum with length equal to Earth's radius in a uniform field is less than that of an infinite length simple pendulum in Earth's real gravitational field.
240 Medium
240 of 392
Understanding +4 | -1
The ratio of orbital velocity of an earth's satellite to the escape velocity of the same earth's satellite is very nearly equal to
View answer and explanation
Correct option: D
12\frac{1}{\sqrt{2}}
Option D (12\frac{1}{\sqrt{2}}) is correct because the ratio of orbital velocity to escape velocity is derived from their respective formulas and simplifies to 12\frac{1}{\sqrt{2}}.
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