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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 276 questions

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91 Medium
91 of 276
Understanding +4 | -1
The magnetic flux linked with a coil of N turns of area of cross section A held with its plane parallel to the field B is
View answer and explanation
Correct option: D
0
Option D (0) is correct because the magnetic flux is zero when the plane of the coil is parallel to the magnetic field.
92 Medium
92 of 276
Understanding +4 | -1
The coil of dynamo is rotating in a magnetic field. The developed induced e.m.f. changes and the number of magnetic lines of force also changes. Which of the following conditions is correct
View answer and explanation
Correct option: B
Lines of force maximum but induced e.m.f. is zero
Option B (Lines of force maximum but induced e.m.f. is zero) is correct because the induced EMF is proportional to the rate of change of magnetic flux, which is zero when the flux is at its maximum.
93 Medium
93 of 276
Understanding +4 | -1
The total charge, induced in a conducting loop, when it is moved in a magnetic field depends on
View answer and explanation
Correct option: C
Total change in magnetic flux and resistance
Option C (Total change in magnetic flux and resistance) is correct because the induced charge depends on the total change in magnetic flux and the resistance of the loop, as given by Q=ΔΦRQ = \frac{{\Delta \Phi}}{R}.
94 Medium
94 of 276
Understanding +4 | -1
When a bar magnet falls through a long hollow metal cylinder fixed with its axis vertical, the final acceleration of the magnet is
View answer and explanation
Correct option: A
Equal to zero
Option A (Equal to zero) is correct because as the bar magnet falls, eddy currents are induced in the metal cylinder, creating a retarding force that eventually balances the weight of the magnet, resulting in zero net acceleration.
95 Medium
95 of 276
Application +4 | -1
Self inductance of primary and secondary of a perfectly coupled coils are 4 mH4 \mathrm{~mH} and 9 mH9 \mathrm{~mH} respectively. The coefficient of mutual inductance between them is
View answer and explanation
Correct option: D
6 mH6 \mathrm{~mH}
Option D (6 mH) is correct because the mutual inductance between perfectly coupled coils is given by the square root of the product of their self-inductances.
96 Medium
96 of 276
Remembering +4 | -1
The direction of magnetic lines of force produced by passing a direct current in a conductor is given by
View answer and explanation
Correct option: C
Right hand palm rule
The correct answer is C (Right hand palm rule) because the right-hand palm rule is used to determine the direction of the magnetic field around a current-carrying conductor.
97 Medium
97 of 276
Application +4 | -1
Two concentric circular coils, one of small radius r\mathrm{r} and the other of large radius R\mathrm{R} are placed co-axially with centers coinciding. If the radius r\mathrm{r} is changed by 2%2 \%, then the change in mutual inductance of the arrangement is (Assume, r<<R\mathrm{r} << \mathrm{R})
View answer and explanation
Correct option: C
4%4 \%
Option C (4%) is correct because the mutual inductance is proportional to the square of the radius, so a 2% change in radius results in a 4% change in mutual inductance.
98 Medium
98 of 276
Understanding +4 | -1
Assertion: Induced electric field lines form closed loops in space.

Reason : Induced electric field lines do not originate & terminate at charged particle.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A is correct because induced electric fields are non-conservative and form closed loops, originating from changing magnetic fields, not charges.
99 Medium
99 of 276
Remembering +4 | -1
Which of the following is constructed on the principle of electromagnetic induction
View answer and explanation
Correct option: C
Generator
Option C (Generator) is correct because generators operate on the principle of electromagnetic induction, converting mechanical energy into electrical energy.
100 Medium
100 of 276
Application +4 | -1
A solenoid of radius 4 cm4 \mathrm{~cm} and 1000 turns, carries a current of 8 A8 \mathrm{~A}. If it is equivalent to a magnet of same size and magnetization M⃗\vec{M} (Magnetic moment/Volume) of 2000 Am−12000 \, \mathrm{Am}^{-1}, then the length of the solenoid is
View answer and explanation
Correct option: D
40 cm40 \mathrm{~cm}
Option D (40 cm40 \mathrm{~cm}) is correct because it is the length of the solenoid calculated by equating its magnetic moment to that of an equivalent magnet.
101 Medium
101 of 276
Application +4 | -1
A conducting rod of length L\mathrm{L} is moving in a uniform magnetic field (B)(\mathrm{B}) with a velocity v\mathrm{v} without rotation. The velocity of the rod is perpendicular to the rod, and the motion of the rod is confined to a plane perpendicular to the magnetic field. What is the induced emf developed across the rod?
View answer and explanation
Correct option: A
BLv\mathrm{BLv}
The correct answer is A (BLv) because the induced emf in a moving conductor is given by the formula emf = BLv when the magnetic field, length, and velocity are mutually perpendicular.
102 Medium
102 of 276
Application +4 | -1
A wheel with ten metallic spokes each 0.5 m long is rotated with a speed of 120 rev/min in a plane normal to the earths magnetic field at the place. If the magnitude of the field is 0.4 gauss, the induced e.m.f between the axle and the rim of the wheel is equal to
View answer and explanation
Correct option: D
6.28×10−5 V6.28 \times {10^{ - 5}}\,V
Option D (6.28×10−5 V6.28 \times {10^{ - 5}}\,V) is correct because it correctly applies the formula for induced EMF in a rotating rod within a magnetic field.
103 Medium
103 of 276
Application +4 | -1
A primary coil and secondary coil are placed close to each other. A current, which changes at the rate of 25 A25 \mathrm{~A} in a millisecond, is present in the primary coil. If the mutual inductance is 92×10−6 H{92}\times 10^{-6} \mathrm{~H}, then the value of induced emf in the secondary coil is
View answer and explanation
Correct option: B
2.3 V2.3 \mathrm{~V}
Option C (L/R  sec⁡L/R\,\,\sec) is correct because it represents the time constant for an LR circuit, which determines how quickly the current decays.
104 Medium
104 of 276
Application +4 | -1
A small coil of radius rr is placed at the centre of a large coil of radius RR, where R>>rR > > r. The two coils are coplanar. The mutual induction between the coils is proportional to
View answer and explanation
Correct option: B
r2/Rr^2 / R
Option B (r2/Rr^2 / R) is correct because the mutual inductance between two coplanar coils, where one is much smaller than the other, is proportional to the area of the smaller coil divided by the radius of the larger coil.
105 Medium
105 of 276
Remembering +4 | -1
Which of the following phenomena is utilised in the construction of mouth piece of a telephone now a days?
View answer and explanation
Correct option: C
Change of resistance with pressure
Option C (Change of resistance with pressure) is correct because modern telephone mouthpieces use a carbon microphone, which relies on the change in resistance of carbon granules due to the pressure of sound waves.
106 Medium
106 of 276
Understanding +4 | -1
Two identical induction coils each of inductance LL joined in series are placed very close to each other such that the winding direction of one is exactly opposite to that of the other, what is the net inductance?
View answer and explanation
Correct option: D
Zero
Option D is correct because when two identical coils are wound in opposite directions, their magnetic fields cancel each other, resulting in zero net inductance.
107 Medium
107 of 276
Understanding +4 | -1
The approximate formula expressing the formula of mutual inductance of two thin coaxial loops of the same radius aa when their centers are separated by a distance ll with l≫al \gg a is
View answer and explanation
Correct option: A
12μ0πa4l3\frac{1}{2} \frac{\mu_0 \pi a^4}{l^3}
Option A (12μ0πa4l3\frac{1}{2} \frac{\mu_0 \pi a^4}{l^3}) is correct because it is the approximate formula for mutual inductance of two coaxial loops when their centers are separated by a large distance.
108 Medium
108 of 276
Application +4 | -1
The mutual inductance of a pair of coils is 0.75 H0.75\,\mathrm{H}. If current in the primary coil changes from 0.5 A0.5 \mathrm{~A} to zero in 0.01 s0.01 \mathrm{~s} find average induced e.m.f. in secondary coil.
View answer and explanation
Correct option: A
37.5 V
Option A (37.5 V) is correct because it's calculated using the formula for induced EMF in terms of mutual inductance and the rate of change of current.
109 Medium
109 of 276
Application +4 | -1
A wire loop that encloses an area of 20 cm220 \mathrm{~cm}^2 has a resistance of 10Ω10 \Omega. The loop is placed in a magnetic field of 2.4T2.4 T with its plane perpendicular to the field. The loop is suddenly removed from the field. How much charge flows pass a given point in the wire?
View answer and explanation
Correct option: C
4.8×10−4C4.8 \times 10^{-4} \mathrm{C}
Option C (4.8×10−4C4.8 \times 10^{-4} \mathrm{C}) is correct because the induced charge is calculated using the formula q=BARq = \frac{BA}{R}, where BB is the magnetic field, AA is the area, and RR is the resistance.
110 Medium
110 of 276
Application +4 | -1
Two coil A\mathrm{A} and B\mathrm{B} have mutual inductance 2×10−22 \times 10^{-2} henry. If the current in the primary is I=5sin⁡(10πt)\mathrm{I}=5 \sin (10 \pi \mathrm{t}) then the maximum value of e.m.f. induced in coil B\mathrm{B} is
View answer and explanation
Correct option: A
π\pi volt
Option A (π\pi volt) is correct because it is the maximum induced emf calculated using the mutual inductance and the rate of change of current.
111 Medium
111 of 276
Remembering +4 | -1
The phenomenon called electromagnetic induction was first investigated by
View answer and explanation
Correct option: C
Faraday
Option C (Faraday) is correct because Michael Faraday first investigated the phenomenon of electromagnetic induction.
112 Medium
112 of 276
Understanding +4 | -1
Assertion(A): L/RL/R and CRCR both have same dimensions.

Reason(R): L/R{L}/{R} and CR{CR} are time constants.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because both L/R and CR represent time constants and therefore have the same dimensions of time.
113 Medium
113 of 276
Understanding +4 | -1
Assertion: Magnetic flux is a vector qunatity

Reason: Value of magnetic flux can be positive, negative or zero.
View answer and explanation
Correct option: D
Assertion is false but reason is true.
Option D (Assertion is false but reason is true) is correct because magnetic flux is a scalar quantity, and its value can be positive, negative, or zero.
114 Medium
114 of 276
Understanding +4 | -1
Two coils are placed close to each other. The mutual inductance of the pair of coils depends upon

I. relative position and orientation of the two coils

II. the materials of the wires of the coils

III. the rates at which currents are changing in the two coils

Which of the above statements is/are correct?
View answer and explanation
Correct option: A
I only
Option A is correct because the mutual inductance between two coils depends on their relative position and orientation, affecting the magnetic flux linkage.
115 Medium
115 of 276
Application +4 | -1
A 10 m long horizontal wire extends from North-East to South-West. It is falling with a speed of 5.0   ms−15.0\,\,\,m{s^{ - 1}} at right angles to the horizontal component of the earth’s magnetic field of 0.3×10−4 Wb/m2.0.3 \times {10^{ - 4}}\,Wb/{m^2}. The value of the induced emf in wire is
View answer and explanation
Correct option: A
1.5×10−3 V1.5 \times {10^{ - 3}}\,V
Option A (1.5×10−3 V1.5 \times {10^{ - 3}}\,V) is correct because the induced emf is calculated using the formula ε=Blv\varepsilon = Blv with the given values.
116 Medium
116 of 276
Understanding +4 | -1
A closed surface SS encloses a magnet of magnetic moment 2 ml2 \mathrm{~ml}. The magnetic flux emerging from the surface is
View answer and explanation
Correct option: B
Zero
Option B is correct because, according to Gauss's law for magnetism, the net magnetic flux through any closed surface is always zero due to the absence of magnetic monopoles.
117 Medium
117 of 276
Analyzing +4 | -1
A magnet is dropped down an infinitely long vertical copper tube
View answer and explanation
Correct option: A
The magnet moves with continuously increasing velocity and ultimately acquires a constant terminal velocity
The correct answer is that the magnet moves with continuously increasing velocity and ultimately acquires a constant terminal velocity because of the opposing force due to eddy currents.
118 Medium
118 of 276
Analyzing +4 | -1
Assertion (A): Electromagnetic force is enormously strong as compared to gravitational force. Yet, gravity dominates in the large-scale phenomena (e.g. formation of galaxies).
Reason (R): Existence of positive and negative charges make matter mostly electrically neutral.
Which of the following is true?
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A is correct because the electromagnetic force is stronger than gravity, but the existence of positive and negative charges makes matter mostly electrically neutral, leading to gravity dominating large-scale phenomena.
119 Medium
119 of 276
Application +4 | -1
A gold rod of length ll is accelerated in the horizontal direction with an acceleration a0a_0. The rod is held between two perfectly insulating clamps. Calculate the electric field set up in the rod. Take the mass of electron as mm.
View answer and explanation
Correct option: A
E=ma0eE=\frac{m a_0}{e}
Option A. πr2IB\pi r^2 I B is correct because it is the net torque on the coil calculated using the formula τ⃗=M⃗×B⃗\vec{\tau} =\vec{M} \times \vec{B}
120 Medium
120 of 276
Application +4 | -1
The magnetic potential energy stored in a certain induction is 25   mJ\mathrm{25}{\mkern 1mu} {\mkern 1mu} \,mJ, when the current in the inductors is 60  mA\mathrm{60}{\mkern 1mu} {\mkern 1mu} mA. This inductors is of inductance
View answer and explanation
Correct option: A
13.89  H\mathrm{13}\mathrm{.89}\,\,\mathrm{H}
Option A (98 cm\mathrm{98 }\,\mathrm{cm}) is correct because the distance between the lenses in a Galilean telescope in normal adjustment is the difference between the focal lengths of the objective and eyepiece.
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