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JEE • PHYSICS • ELECTRIC FIELDS AND CHARGES

Electric fields and charges practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 385 questions

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151 Medium
151 of 385
Understanding +4 | -1
If a point charge q\mathrm{q} is placed at the centre of a cube what is the flux linked with the cube?
View answer and explanation
Correct option: A
ϕ=1ϵ0q\phi=\frac{1}{\epsilon_0} q
Option A (ϕ=1ϵ0q\phi=\frac{1}{\epsilon_0} q) is correct because Gauss's law states that the electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space.
152 Medium
152 of 385
Analyzing +4 | -1
Assertion: Electric and gravitational fields are acting along same line. When proton and α\alpha-particle are projected up veritically along that line, the time of flights is less for proton.

Reason: In the given electric field acceleration of a charged particle is directly proportional to specific charge.
View answer and explanation
Correct option: A
Both Assertion & Reason are true. Reason is the correct explanation for assertion
Option A (Both Assertion & Reason are true. Reason is the correct explanation for assertion) is correct because the acceleration is directly proportional to the specific charge (charge/mass), leading to a shorter time of flight for the proton.
153 Medium
153 of 385
Remembering +4 | -1
Charge on α\alpha particle is
View answer and explanation
Correct option: C
3.2×10−19C3.2 \times {10^{ - 19}}C
Option C (3.2×10−19C3.2 \times {10^{ - 19}}C) is correct because an alpha particle has a charge of +2e, where e is the elementary charge.
154 Medium
154 of 385
Understanding +4 | -1
A,B,CA,B,C, are three points on a circle of radius 1  cm1\,\,cm. These points from the corners of an equilateral triangle. A charge 2C2C is placed at the centre of the circle. The work done in carrying a charge of 0.1 μC0.1\,\mu C from AA to BB is
View answer and explanation
Correct option: A
zero
Option A (zero) is correct because the work done in moving a charge between two points on an equipotential surface is zero.
155 Medium
155 of 385
Understanding +4 | -1
Statement-1: A uniformly charged dise has a pin hole at its centre. The electric field at the centre of the disc is zero.
Statement-2: Disc can be supposed to be made up of many rings. Also electric field at the centre of uniformly charged ring is zero.
View answer and explanation
Correct option: A
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
Option A (Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1) is correct because the electric field at the center of a charged ring is zero, and the disc can be considered as a collection of such rings.
156 Medium
156 of 385
Understanding +4 | -1
Plastic rod rubbed with fur and glass rod rubbed with silk
View answer and explanation
Correct option: C
attract each other
Option C (attract each other) is correct because the plastic rod becomes negatively charged and the glass rod becomes positively charged, and opposite charges attract.
157 Medium
157 of 385
Understanding +4 | -1
Assertion: Vehicle carrying highly inflammable materials having hanging chains, slightly touching the ground.

Reason: The body of a vechicle gets charged when moving through air at high speed.
View answer and explanation
Correct option: A
Both Assertion & Reason are true. Reason is the correct explanation for assertion
Option A (Both Assertion & Reason are true. Reason is the correct explanation for assertion) is correct because the hanging chains discharge static electricity buildup, preventing sparks near flammable materials.
158 Medium
158 of 385
Application +4 | -1
The distance between a proton and electron both having a charge 1.6×10−19coulomb,1.6 \times {10^{ - 19}}coulomb, , of a hydrogen atom is 10−10metre.{10^{ - 10}}metre.. The value of intensity of electric field produced on electron due to proton will be
View answer and explanation
Correct option: D
1.44×1011N/C1.44 \times {10^{11}}N/C
Option D (1.44imes1011N/C1.44 imes {10^{11}}N/C) is correct because it's the electric field intensity calculated using Coulomb's law at the given distance.
159 Medium
159 of 385
Remembering +4 | -1
The dimensional formula of electric charge is:
View answer and explanation
Correct option: A
[M0L0T1A1]\left[\mathrm{M}^0 \mathrm{L}^0 \mathrm{T}^1 \mathrm{A}^1\right]
Option A ([M⁰ L⁰ T¹ A¹]) is correct because electric charge is the product of current and time, leading to the given dimensional formula.
160 Medium
160 of 385
Remembering +4 | -1
One of the following is not a property of field lines
View answer and explanation
Correct option: D
They form closed loop
Option D (They form closed loop) is correct because electric field lines do not form closed loops; they originate from positive charges and terminate at negative charges.
161 Medium
161 of 385
Understanding +4 | -1
Two identical conductors of copper and aluminum are placed in an identical electric fields. The magnitude of induced charge in the aluminum will be
View answer and explanation
Correct option: C
Equal to that in copper
Option C is correct because in electrostatic equilibrium, the induced charge on conductors depends only on the applied electric field and geometry, not the material.
162 Medium
162 of 385
Understanding +4 | -1
Mark the incorrect statement among the following.
View answer and explanation
Correct option: C
A given conducting sphere can be charged to any extent
Option C (A given conducting sphere can be charged to any extent) is the incorrect statement because a conducting sphere has a limit to the amount of charge it can hold before dielectric breakdown occurs.
163 Medium
163 of 385
Application +4 | -1
Two charged particles of same specific charge (i.e. charge per unit mass) are projected in same uniform magnetic field with projection velocities, perpendicular to the magnetic field. If the speeds of charged particles are vv and 2v2 v, then the ratio of angular speeds of the path of the particles in magnetic field will be
View answer and explanation
Correct option: A
1:11: 1
Option A (1:11: 1) is correct because the angular speed of a charged particle in a magnetic field depends only on the charge, magnetic field strength, and mass, not on the speed.
164 Medium
164 of 385
Analyzing +4 | -1
Assertion: A point charge is brought in an electric field. The field at a nearby point will increase, whatever be the nature of the charge.

Reason: The electric field is independent of the nature of charge.
View answer and explanation
Correct option: D
If both Assertion and Reason are false.
Option D (If both Assertion and Reason are false) is correct because the electric field at a nearby point can either increase or decrease depending on the nature and position of the charge, and the electric field does depend on the nature of the charge.
165 Medium
165 of 385
Application +4 | -1
Two particles of masses in the ratio 1:21: 2, with charges in the ratio 1:11: 1, are placed at rest in a uniform electric field. They are released and allowed to move for the same time. The ratio of their kinetic energies will be finally
View answer and explanation
Correct option: A
2:12: 1
Option A (2:12: 1) is correct because the ratio of kinetic energies is inversely proportional to the ratio of their masses, given that they experience the same force for the same time.
166 Medium
166 of 385
Understanding +4 | -1
If the electric flux entering and leaving an enclosed surface respectively are ϕ1{\phi _1} and ϕ2{\phi _2}, the electric charge inside the surface will be
View answer and explanation
Correct option: A
(ϕ2−ϕ1)ε0\left( {{\phi _2} - {\phi _1}} \right){\mathrm{\varepsilon }_0}
Option A ((ϕ2−ϕ1)ε0\left( {{\phi _2} - {\phi _1}} \right){\mathrm{\varepsilon }_0}) is correct because Gauss's law relates the net electric flux through a closed surface to the enclosed charge.
167 Medium
167 of 385
Understanding +4 | -1
Assertion: Coulomb force between charges is central force.

Reason: Coulomb force depends on medium between charges.
View answer and explanation
Correct option: B
Both Assertion & Reason are true. Reason is not the correct explanation for assertion
Option B (Both Assertion & Reason are true. Reason is not the correct explanation for assertion) is correct because both statements are true, but the medium's influence doesn't explain why the force is central.
168 Medium
168 of 385
Application +4 | -1
The electric field in a certain region is given by E⃗=5i^−3j^kV/m.\vec{E}=5 \hat{i}-3 \hat{j} k V / m. The potential difference VB−VAV_B-V_A between points AA and B,B, having coordinates (4,0,3) m(4,0,3) \,\mathrm{m} and (10,3,0) m(10,3,0) \,\mathrm{m} respectively, is equal to
View answer and explanation
Correct option: B
−21 kV-21 \,\mathrm{kV}
Option B (−21 kV-21 \,\mathrm{kV}) is correct because the potential difference is calculated by integrating the electric field along the path between the two points.
169 Medium
169 of 385
Application +4 | -1
A circular loop of radius a carries a total charge QQ distributed uniformly over its circumference. A small length dL{dL} of the wire is cut off. The magnitude of electric field at the center due to remaining wire will be [K=14πε0]\left[K=\frac{1}{4 \pi \varepsilon_0}\right]
View answer and explanation
Correct option: C
KQdL2πa3\frac{K Q d L}{2 \pi a^3}
Option D (KQdLa3\frac{{K Q d L}}{{a^3}}) is incorrect. The correct answer is C (KQdL2πa3\frac{{K Q d L}}{{2 \pi a^3}}) because it calculates the electric field due to the missing charge element.
170 Medium
170 of 385
Understanding +4 | -1
Assertion: Electrostatic field lines start at positive charges and end at negative charges.
Reason: Field lines are continuous curves without any breaks and they form closed loop.
View answer and explanation
Correct option: C
If assertion is true but reason is false
If assertion is true but reason is false is correct because field lines start at positive charges and end at negative charges, but they do not form closed loops.
171 Medium
171 of 385
Understanding +4 | -1
Electrical force is acting between two charges kept in vacuum. A copper plate is placed between the charges, the force now is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because a copper plate, being a conductor, effectively shields the charges, making the electric field inside zero.
172 Medium
172 of 385
Analyzing +4 | -1
Assertion: Induced charge does not contribute to electric field or potential at a given point.

Reason: A point chagre q0q_0 is kept outside a solid metallic sphere, the elcetric field inside the sphere is Zero.
View answer and explanation
Correct option: D
Assertion is false and Reason is false
Option D is correct because both Assertion and Reason are false. Induced charges do contribute to the electric field and potential, and the electric field inside a metallic sphere is zero due to the superposition of fields.
173 Medium
173 of 385
Understanding +4 | -1
Statement I: The electrostatic field lines cannot form a closed path

Statement II: The magnetic field lines form a continuous closed path
View answer and explanation
Correct option: A
Statement I and statement II are true
Option A is correct because electrostatic field lines originate from positive charges and terminate at negative charges, never forming closed loops, while magnetic field lines always form closed loops.
174 Medium
174 of 385
Understanding +4 | -1
Consider a neutral conducting sphere. A positive point charge is placed outside the sphere. The net charge on the sphere is then
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the net charge on a neutral conducting sphere remains zero even when a charge is placed outside; charges are induced but the total remains neutral.
175 Medium
175 of 385
Understanding +4 | -1
When a number of charged liquid drops coalesce, which of the following quantity does not change?
View answer and explanation
Correct option: A
Charge
Option A (Charge) is correct because charge is a conserved quantity and remains constant when liquid drops coalesce.
176 Medium
176 of 385
Understanding +4 | -1
Assertion : Work done in moving a charge between any two points in an electric field is independent of the path followed by the charge, between these points.

Reason: Electrostatic force is a non conservative force.
View answer and explanation
Correct option: C
Assertion is true but reason is false
Option C (Assertion is true but reason is false) is correct because the work done is path-independent due to the conservative nature of electrostatic force, making the assertion true, while the reason incorrectly states that electrostatic force is non-conservative.
177 Medium
177 of 385
Understanding +4 | -1
The Gaussian surface for calculating the electric field due to a charge distribution is
View answer and explanation
Correct option: C
A symmetrical closed surface containing the charge distribution, at every point of which electric field has a single fixed value
Option C (A symmetrical closed surface containing the charge distribution, at every point of which electric field has a single fixed value) is correct because a Gaussian surface must be closed and symmetrical to simplify the calculation of the electric field using Gauss's law.
178 Medium
178 of 385
Understanding +4 | -1
Statement-I: Flux through a closed surface is zero

Statement-II: Total charge inside the surface must be zero
View answer and explanation
Correct option: A
Statement-I is True, statement-II is True
Option A (Statement-I is True, statement-II is True) is correct because Gauss's law states that the flux through a closed surface is proportional to the enclosed charge, so zero flux implies zero enclosed charge.
179 Medium
179 of 385
Understanding +4 | -1
Consider the following two statements
a) Electric field is always conservative in nature.
b) In electromagnetic waves the phase difference between oscillating electric and magnetic field is 90o{90^\mathrm{o}}
The corerct statement (s) is/are
View answer and explanation
Correct option: D
Neither (a) nor (b)
Option D (Neither (a) nor (b)) is correct because electric fields are not always conservative (e.g., induced electric fields), and the electric and magnetic fields in EM waves are in phase.
180 Medium
180 of 385
Analyzing +4 | -1
An infinite number of charges, each of magnitude q\mathrm{q}, are placed along X\mathrm{X}-axis at x=1 m,2 m,4 m,8 m,16 m\mathrm{x}=1 \mathrm{~m}, 2 \mathrm{~m}, 4 \mathrm{~m}, 8 \mathrm{~m}, 16 \mathrm{~m} and so on but the consecutive charges are of opposite sign starting with +q+\mathrm{q} at x=1 m\mathrm{x}=1 \mathrm{~m}. A point charge q0\mathrm{q}_0, kept at the origin, experiences a force of magnitude:
View answer and explanation
Correct option: B
qq05πε0\frac{\mathrm{q q}_0}{5 \pi \varepsilon_0}
Option B (qq05πε0\frac{\mathrm{q q}_0}{5 \pi \varepsilon_0}) is correct because the electric field due to the infinite series of charges converges to this value.
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