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JEE • PHYSICS • ELECTRIC FIELDS AND CHARGES

Electric fields and charges practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 420 questions

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181 Medium
181 of 420
Analyzing +4 | -1
Assertion: A point charge is brought in an electric field. The field at a nearby point will increase, whatever be the nature of the charge.

Reason: The electric field is independent of the nature of charge.
View answer and explanation
Correct option: D
If both Assertion and Reason are false.
Option D (If both Assertion and Reason are false) is correct because the electric field at a nearby point can either increase or decrease depending on the nature and position of the charge, and the electric field does depend on the nature of the charge.
182 Medium
182 of 420
Application +4 | -1
Two particles of masses in the ratio 1:21: 2, with charges in the ratio 1:11: 1, are placed at rest in a uniform electric field. They are released and allowed to move for the same time. The ratio of their kinetic energies will be finally
View answer and explanation
Correct option: A
2:12: 1
Option A (2:12: 1) is correct because the ratio of kinetic energies is inversely proportional to the ratio of their masses, given that they experience the same force for the same time.
183 Medium
183 of 420
Understanding +4 | -1
If the electric flux entering and leaving an enclosed surface respectively are ϕ1{\phi _1} and ϕ2{\phi _2}, the electric charge inside the surface will be
View answer and explanation
Correct option: A
(ϕ2−ϕ1)ε0\left( {{\phi _2} - {\phi _1}} \right){\mathrm{\varepsilon }_0}
Option A ((ϕ2−ϕ1)ε0\left( {{\phi _2} - {\phi _1}} \right){\mathrm{\varepsilon }_0}) is correct because Gauss's law relates the net electric flux through a closed surface to the enclosed charge.
184 Medium
184 of 420
Understanding +4 | -1
Assertion: Coulomb force between charges is central force.

Reason: Coulomb force depends on medium between charges.
View answer and explanation
Correct option: B
Both Assertion & Reason are true. Reason is not the correct explanation for assertion
Option B (Both Assertion & Reason are true. Reason is not the correct explanation for assertion) is correct because both statements are true, but the medium's influence doesn't explain why the force is central.
185 Medium
185 of 420
Application +4 | -1
The electric field in a certain region is given by E⃗=5i^−3j^kV/m.\vec{E}=5 \hat{i}-3 \hat{j} k V / m. The potential difference VB−VAV_B-V_A between points AA and B,B, having coordinates (4,0,3) m(4,0,3) \,\mathrm{m} and (10,3,0) m(10,3,0) \,\mathrm{m} respectively, is equal to
View answer and explanation
Correct option: B
−21 kV-21 \,\mathrm{kV}
Option B (−21 kV-21 \,\mathrm{kV}) is correct because the potential difference is calculated by integrating the electric field along the path between the two points.
186 Medium
186 of 420
Application +4 | -1
A circular loop of radius a carries a total charge QQ distributed uniformly over its circumference. A small length dL{dL} of the wire is cut off. The magnitude of electric field at the center due to remaining wire will be [K=14πε0]\left[K=\frac{1}{4 \pi \varepsilon_0}\right]
View answer and explanation
Correct option: C
KQdL2πa3\frac{K Q d L}{2 \pi a^3}
Option D (KQdLa3\frac{{K Q d L}}{{a^3}}) is incorrect. The correct answer is C (KQdL2πa3\frac{{K Q d L}}{{2 \pi a^3}}) because it calculates the electric field due to the missing charge element.
187 Medium
187 of 420
Understanding +4 | -1
Assertion: Electrostatic field lines start at positive charges and end at negative charges.
Reason: Field lines are continuous curves without any breaks and they form closed loop.
View answer and explanation
Correct option: C
If assertion is true but reason is false
If assertion is true but reason is false is correct because field lines start at positive charges and end at negative charges, but they do not form closed loops.
188 Medium
188 of 420
Understanding +4 | -1
Electrical force is acting between two charges kept in vacuum. A copper plate is placed between the charges, the force now is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because a copper plate, being a conductor, effectively shields the charges, making the electric field inside zero.
189 Medium
189 of 420
Analyzing +4 | -1
Assertion: Induced charge does not contribute to electric field or potential at a given point.

Reason: A point chagre q0q_0 is kept outside a solid metallic sphere, the elcetric field inside the sphere is Zero.
View answer and explanation
Correct option: D
Assertion is false and Reason is false
Option D is correct because both Assertion and Reason are false. Induced charges do contribute to the electric field and potential, and the electric field inside a metallic sphere is zero due to the superposition of fields.
190 Medium
190 of 420
Understanding +4 | -1
Statement I: The electrostatic field lines cannot form a closed path

Statement II: The magnetic field lines form a continuous closed path
View answer and explanation
Correct option: A
Statement I and statement II are true
Option A is correct because electrostatic field lines originate from positive charges and terminate at negative charges, never forming closed loops, while magnetic field lines always form closed loops.
191 Medium
191 of 420
Understanding +4 | -1
Consider a neutral conducting sphere. A positive point charge is placed outside the sphere. The net charge on the sphere is then
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the net charge on a neutral conducting sphere remains zero even when a charge is placed outside; charges are induced but the total remains neutral.
192 Medium
192 of 420
Understanding +4 | -1
When a number of charged liquid drops coalesce, which of the following quantity does not change?
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Correct option: A
Charge
Option A (Charge) is correct because charge is a conserved quantity and remains constant when liquid drops coalesce.
193 Medium
193 of 420
Understanding +4 | -1
Assertion : Work done in moving a charge between any two points in an electric field is independent of the path followed by the charge, between these points.

Reason: Electrostatic force is a non conservative force.
View answer and explanation
Correct option: C
Assertion is true but reason is false
Option C (Assertion is true but reason is false) is correct because the work done is path-independent due to the conservative nature of electrostatic force, making the assertion true, while the reason incorrectly states that electrostatic force is non-conservative.
194 Medium
194 of 420
Understanding +4 | -1
The Gaussian surface for calculating the electric field due to a charge distribution is
View answer and explanation
Correct option: C
A symmetrical closed surface containing the charge distribution, at every point of which electric field has a single fixed value
Option C (A symmetrical closed surface containing the charge distribution, at every point of which electric field has a single fixed value) is correct because a Gaussian surface must be closed and symmetrical to simplify the calculation of the electric field using Gauss's law.
195 Medium
195 of 420
Understanding +4 | -1
Statement-I: Flux through a closed surface is zero

Statement-II: Total charge inside the surface must be zero
View answer and explanation
Correct option: A
Statement-I is True, statement-II is True
Option A (Statement-I is True, statement-II is True) is correct because Gauss's law states that the flux through a closed surface is proportional to the enclosed charge, so zero flux implies zero enclosed charge.
196 Medium
196 of 420
Understanding +4 | -1
Consider the following two statements
a) Electric field is always conservative in nature.
b) In electromagnetic waves the phase difference between oscillating electric and magnetic field is 90o{90^\mathrm{o}}
The corerct statement (s) is/are
View answer and explanation
Correct option: D
Neither (a) nor (b)
Option D (Neither (a) nor (b)) is correct because electric fields are not always conservative (e.g., induced electric fields), and the electric and magnetic fields in EM waves are in phase.
197 Medium
197 of 420
Analyzing +4 | -1
An infinite number of charges, each of magnitude q\mathrm{q}, are placed along X\mathrm{X}-axis at x=1 m,2 m,4 m,8 m,16 m\mathrm{x}=1 \mathrm{~m}, 2 \mathrm{~m}, 4 \mathrm{~m}, 8 \mathrm{~m}, 16 \mathrm{~m} and so on but the consecutive charges are of opposite sign starting with +q+\mathrm{q} at x=1 m\mathrm{x}=1 \mathrm{~m}. A point charge q0\mathrm{q}_0, kept at the origin, experiences a force of magnitude:
View answer and explanation
Correct option: B
qq05πε0\frac{\mathrm{q q}_0}{5 \pi \varepsilon_0}
Option B (qq05πε0\frac{\mathrm{q q}_0}{5 \pi \varepsilon_0}) is correct because the electric field due to the infinite series of charges converges to this value.
198 Medium
198 of 420
Application +4 | -1
Two point charges +3μC+ 3\mu C and +8μC+ 8\mu C repel each other with a force of 40NN. If a charge of −5μC- 5\mu C is added to each of them, then the force between them will become
View answer and explanation
Correct option: B
+10N+ 10N
Option B (+10N+ 10N) is correct because the force is proportional to the product of the charges, and adding the same charge to both changes the magnitude and sign of the force.
199 Medium
199 of 420
Application +4 | -1
An electron moves a distance of 6 cm6 \mathrm{~cm} when accelerated from rest by an electric field of strength 2×104 NC−12 \times 10^4 \mathrm{~NC}^{-1}. Calculate the time of travel. The mass and charge of electron are 9×10−31 kg9 \times 10^{-31} \mathrm{~kg} and 1.6×10−19C1.6 \times 10^{-19} \mathrm{C} respectively.
View answer and explanation
Correct option: C
0.585×10−8 s0.585 \times 10^{-8} \mathrm{~s}
Option C (0.585×10−8 s0.585 \times 10^{-8} \mathrm{~s}) is correct because it is calculated using kinematics equations with the acceleration derived from the electric field force.
200 Medium
200 of 420
Application +4 | -1
Electric charge is uniformly distributed along a long straight wire of radius 1mm. The charge per cm length of the wire is Q{\cal Q} coulomb. Another cylindrical surface of radius 50 cm and length 1m symmetrically encloses the wire. The total electric flux passing through the cylindrical surface is
View answer and explanation
Correct option: B
100Qε0\frac{{100{\cal Q}}}{{{\varepsilon _0}}}
Option B (100Qε0\frac{{100{\cal Q}}}{{{\varepsilon _0}}}) is correct because it applies Gauss's law to find the electric flux through the cylindrical surface, considering the charge enclosed within the 1-meter length.
201 Medium
201 of 420
Application +4 | -1
Calculate the ratio of electric to gravitational force between two electrons.
View answer and explanation
Correct option: A
4.17×10424.17 \times 10^{42}
Option A (4.17×10424.17 \times 10^{42}) is correct because it is calculated by dividing the electric force by the gravitational force between two electrons, using the respective formulas.
202 Medium
202 of 420
Application +4 | -1
A negatively charged oil drop is prevented from falling under gravity by applying a vertical electric field 100V  m−1.100V\;{m^{ - 1}}. If the mass of the drop is 1.6×10−3g,1.6 \times {10^{ - 3}}g, the number of electrons carried by the drop is (g=10ms−2)\left( {g = 10m{s^{ - 2}}} \right)
View answer and explanation
Correct option: D
1012{10^{12}}
Option D (1012{10^{12}}) is correct because the number of electrons is determined by equating the electric force to the gravitational force and then dividing the charge by the elementary charge.
203 Medium
203 of 420
Application +4 | -1
Two charges of 50 μc50\,\mu c and 100 μc100\,\mu c are separated by a distance of 0.6 m0.6\,m. The intensity of electric field of a point midway between them is ….×106vm\times {10^6}\frac{v}{m}
View answer and explanation
Correct option: B
2
Option B (2) is correct because it is the correct calculation of the electric field intensity at the midpoint between the two charges.
204 Medium
204 of 420
Analyzing +4 | -1
Statement-1: Total work done by non-uniform electric field on a charged particle starting from rest till any time is non-negative. (assume no other forces act on the charged particle).
Statement-2: The angle between electrostatic force an velocity of the charged particle released from rest in non-uniform electric field is always acute. (assume no other forces act on the charged particle).
View answer and explanation
Correct option: C
Statement-1 is true, Statement-2 is false
Option C is correct because Statement-1 is true (work done is non-negative), but Statement-2 is false (the angle can be obtuse).
205 Medium
205 of 420
Application +4 | -1
If the electrostatic force on a small sphere of charge 0.4μC0.4 \mu \mathrm{C} due to another small sphere of charge −0.8μC-0.8 \mu \mathrm{C} in air is 0.2 N.0.2 \mathrm{~N}. The separation of the spheres is (k=9×109 N m2/C2)\left(\mathrm{k}=9 \times 10^9 \mathrm{~N} \mathrm{~m}^2 / \mathrm{C}^2\right)
View answer and explanation
Correct option: D
12 cm12 \mathrm{~cm}
Option D (12 cm12 \mathrm{~cm}) is correct because it is the calculated separation using Coulomb's law with the given charges and force.
206 Medium
206 of 420
Analyzing +4 | -1
Assertion: Two charges q1{q}_1 and q2{q}_2 are placed at separation rr. Then magnitude of force on each charge is FF.

Reason: Now a third charge q3{q}_3 is placed near q1{q}_1 and q2{q}_2 Then force on q1{q}_1 due to q2{q}_2 remains F{F}.
View answer and explanation
Correct option: B
Both Assertion & Reason are true. Reason is not the correct explanation for assertion
Option B (Both Assertion & Reason are true. Reason is not the correct explanation for assertion) is correct because the force between two charges is independent of the presence of other charges, although the net force on a charge will be affected.
207 Medium
207 of 420
Understanding +4 | -1
The electric field at a distance 3R2\frac{{3R}}{2} from the centre of a charged conducting spherical shell of radius R  is  ER\;\mathrm{is}\;E. The electric field at a distance R2\frac{R}{2} from the centre of the sphere is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because the electric field inside a charged conducting spherical shell is always zero.
208 Medium
208 of 420
Understanding +4 | -1
Select the correct statements from the following
(i) inside a charged or neutral conductor, electrostatic field is zero
(ii) the electrostatic field at the surface of the charged conductor must be tangential to the surface at any point
(iii) there is no net charge at any point inside the conductor
View answer and explanation
Correct option: B
(i) and (iii)
Option B ((i) and (iii)) is correct because inside a charged or neutral conductor, the electrostatic field is zero, and there is no net charge at any point inside the conductor.
209 Medium
209 of 420
Application +4 | -1
Two identical conducting balls AA and BB have positive charges q1{q_1} and q2{q_2} respectively but q1≠q2.{q_1} \ne {q_2}. The balls are brought together so that they touch each other and then kept in their original positions. The force between them is
View answer and explanation
Correct option: B
Greater than that before the balls touched
Option B (Greater than that before the balls touched) is correct because after touching, the charges redistribute, resulting in a larger product of charges and thus a greater force.
210 Medium
210 of 420
Application +4 | -1
A 10 μC10\,\mu C charge is divided into two equal parts and kept at 1 cm distance. Find repulsion between charges.
View answer and explanation
Correct option: C
2250 N
Option C (2250 N) is correct because it is calculated using Coulomb's law with the given charge and distance.
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