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JEE • PHYSICS • ELECTRIC FIELDS AND CHARGES

Electric fields and charges practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 420 questions

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301 Medium
301 of 420
Application +4 | -1
If a charge on the body is 1 nC,1 \mathrm{~nC}, then how many electrons are present on the body?
View answer and explanation
Correct option: B
6.25×1096.25 \times 10^9
Option B (6.25×1096.25 \times 10^9) is correct because it is the number of electrons calculated using the quantization of charge formula.
302 Medium
302 of 420
Application +4 | -1
Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 18×10−22 Cm−218 \times 10^{-22} \mathrm{~Cm}^{-2}. The electric field between the plates is:
View answer and explanation
Correct option: A
2.03×10−10 NC−12.03 \times 10^{-10} \mathrm{~NC}^{-1}
Option A (2.03×10−10 NC−12.03 \times 10^{-10} \mathrm{~NC}^{-1}) is correct because the electric field between two large, thin metal plates with opposite surface charge densities is given by σε0\frac{\sigma}{\varepsilon_0}.
303 Medium
303 of 420
Understanding +4 | -1
A cube of side aa is placed in a uniform electric field E=E0i^+E0j^+E0k^{E}=E_0 \hat{{i}}+E_0 \hat{{j}}+E_0 \hat{{k}}. Total electric flux passing through the cube would be
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the net electric flux through a closed surface in a uniform electric field is always zero.
304 Medium
304 of 420
Understanding +4 | -1
The electrostatic field due to a charged
conductor just outside the conductor is:
View answer and explanation
Correct option: D
Normal to the surface at every point and zero
inside the conductor
Option D (Normal to the surface at every point and zero inside the conductor) is correct because the electric field inside a conductor is zero, and the electric field just outside is normal to the surface.
305 Medium
305 of 420
Understanding +4 | -1
There are two types of electric charges positive charges and negative charges. The property which differentiates the two types of charges is:
View answer and explanation
Correct option: B
Polarity of charge
Option B is correct because the polarity of charge distinguishes positive and negative charges.
306 Medium
306 of 420
Application +4 | -1
A current in a wire is given by the equation I=2t2−3t+1I = 2{t^2} - 3t + 1 . The charge through cross section of wire in time interval t=3 s   t0t=5st = 3\,s\,\,\,{t_0}t = 5s is
View answer and explanation
Correct option: B
43.34 L
Option B (43.34 L) is correct because it is the charge calculated by integrating the current function over the given time interval.
307 Medium
307 of 420
Application +4 | -1
An infinite number of electric charges each equal to 5  nano−coulomb5\;nano - coulomb (magnitude) are placed along XX-axis at x=1  cm,    x=2  cm,    x=4  cm    x=8  cm………x = 1\;cm,\;\;x = 2\;cm,\;\;x = 4\;cm\;\;x = 8\;cm \ldots \ldots \ldots and so on. In the setup if the consecutive charges have opposite sign, then the electric field in Newton/CoulombNewton/Coulomb at X=0X = 0 is

[14πε0=9×109N−m2/c2]\left[ {\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}N - {m^2}/{c^2}} \right]
View answer and explanation
Correct option: C
36×10436 \times {10^4}
Option C (36×10436 \times {10^4}) is correct because the electric field is calculated by summing the contributions of all charges, considering their alternating signs and positions.
308 Medium
308 of 420
Application +4 | -1
Two similarly equally charged identical metal spheres AA and BB repel each other with a force of 2.0×10−5 N2.0 \times 10^{-5} \mathrm{~N}. AA third identical uncharged sphere CC is touched to AA, then placed at the midpoint between AA and BB. Calculate the net electrostatic force on CC.
View answer and explanation
Correct option: B
2.0×10−5 N2.0 \times 10^{-5} \mathrm{~N}
Option B (2.0×10−5 N2.0 \times 10^{-5} \mathrm{~N}) is correct because it is the net electrostatic force on sphere C, calculated by considering the forces due to spheres A and B.
309 Medium
309 of 420
Application +4 | -1
Two particles, each having a mass of 5 g5 \mathrm{~g} and charge 1.0×10−7C1.0 \times 10^{-7} \mathrm{C}, stay in limiting equilibrium on a horizontal table with a separation of 10 cm10 \mathrm{~cm} between them. The coefficient of friction between each particle and the table is the same. Find the value of this coefficient
View answer and explanation
Correct option: B
0.18
Option B (0.18) is correct because the coefficient of friction is found by equating the electric force and the frictional force in limiting equilibrium.
310 Easy
310 of 420
Remembering +4 | -1
The electrostatic force (F→1)\left(\overrightarrow{\mathrm{F}}_1\right) and magnetic force (F→2)\left(\overrightarrow{\mathrm{F}}_2\right) acting on a charge q\mathrm{q} moving with velocity v\mathrm{v} can be written:
View answer and explanation
Correct option: C
F→1=qE→,F→2=q(V→×B→)\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})
Option C (F→1=qE→,F→2=q(V→×B→)\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})) is correct because the electrostatic force is given by qEqE and the magnetic force by q(v×B)q(v \times B).
311 Easy
311 of 420
Understanding +4 | -1
Assertion (A): Some charge is put at the centre of a conducting sphere. It will move to the surface of the sphere.

Reason (R): Conducting sphere has no free electrons at the centre.
View answer and explanation
Correct option: A
Both A and R are true and R is the correct
explanation of A
Option A is correct because charges in a conductor redistribute to the surface, and the absence of free electrons at the center facilitates this movement.
312 Medium
312 of 420
Application +4 | -1
Calculate the net charge on a substance consisting of a combination of 7×10137 \times 10^{13} protons and 4×10134 \times 10^{13} electrons.
View answer and explanation
Correct option: A
+4.8 μC+4.8\,\mu \mathrm{C}
Option A (+4.8 μC) is correct because it is calculated by finding the difference between the total positive charge of protons and the total negative charge of electrons.
313 Medium
313 of 420
Understanding +4 | -1
Assertion: Force between two point charges at rest is not changed by the presence of third point charge between them.

Reason: Force depends on the magnitude of the first two charges and seperation between them.
View answer and explanation
Correct option: A
Both Assertion & Reason are true. Reason is the correct explanation for assertion
Option A (Both Assertion & Reason are true. Reason is the correct explanation for assertion) is correct because the force between two point charges depends only on their magnitudes and the separation between them, as described by Coulomb's law.
314 Medium
314 of 420
Application +4 | -1
Two charges of equal magnitudes and at a distance rr exert a force FF on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is
View answer and explanation
Correct option: D
F/16F/16
Option D (F/16F/16) is correct because the force is proportional to the square of the charge and inversely proportional to the square of the distance.
315 Hard
315 of 420
Understanding +4 | -1
Statement-1: E→\overrightarrow{{E}} in outside velocity of a conductor depends only on the local charge density α\alpha.
Statement-2: E→\overrightarrow{{E}} in outside vicinity of a conductor is given by σε0\frac{\sigma}{\varepsilon_0}.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D (Statement-1 is false, Statement-2 is true) is correct because the electric field outside a conductor depends on the overall charge distribution, and Statement-2 correctly gives the electric field near the surface.
316 Medium
316 of 420
Understanding +4 | -1
A point charge + q+\,q, is placed at a distance d from an isolated conducting plane. The field at a point PP on the other side of the plane is
View answer and explanation
Correct option: A
directed perpendicular to the plane and away from the plane.
Option A (directed perpendicular to the plane and away from the plane) is correct because the electric field lines from the charge induce an opposite charge on the conducting plane, resulting in a field perpendicular and away from the plane on the other side.
317 Medium
317 of 420
Understanding +4 | -1
Two bodies are charged by rubbing one against the other. During the process, one becomes positively charged while the other becomes negatively charged. Then
View answer and explanation
Correct option: D
Mass of each body changes slightly but the total mass remains the same.
Option D (Mass of each body changes slightly but the total mass remains the same) is correct because electrons are transferred, changing individual masses, but the total mass is conserved.
318 Medium
318 of 420
Application +4 | -1
A point charge placed at any point on the axis of an electric dipole at some large distance experiences a force FF. Find the force acting on the point charge when it's distance from the dipole is doubled.
View answer and explanation
Correct option: C
F′=F8F^{\prime}=\frac{F}{8}
Option C (F′=F8F^{\prime}=\frac{F}{8}) is correct because the force on a point charge due to an electric dipole varies inversely with the cube of the distance.
319 Medium
319 of 420
Application +4 | -1
An electron of mass Me,  {M_e},\; initially at rest, moves through a certain distance in a uniform electric field in time t1.  {t_1}.\; A proton of mass Mp{M_p} also initially at rest, takes time t2{t_2} to move through an equal distance in this uniform electric field, neglecting the effect of gravity, the ratio t1/t2  {t_1}/{t_{2\;}} is nearly equal to
View answer and explanation
Correct option: B
Mp/Me\sqrt {{M_p}/{M_e}}
Option B (Mp/Me\sqrt {{M_p}/{M_e}}) is correct because it is derived from the relationship between time, distance, mass, and acceleration in a uniform electric field.
320 Medium
320 of 420
Understanding +4 | -1
An electric charge does not have which of the
following properties?
View answer and explanation
Correct option: D
Circular line of force
Option D (Circular line of force) is correct because electric field lines originate from positive charges and terminate at negative charges, and they are not circular.
321 Easy
321 of 420
Understanding +4 | -1
A neutral body is charged positively by rubbing it, its weight
View answer and explanation
Correct option: B
Decreases slightly
Option B (Decreases slightly) is correct because when a neutral body is charged positively, it loses electrons, thus reducing its mass and weight slightly.
322 Medium
322 of 420
Application +4 | -1
A charged particle of mass 0.003 g0.003 \mathrm{~g} is held stationary is space by placing it in a downward direction of electric field of 6×104 N/C6 \times 10^4 \mathrm{~N} / \mathrm{C}. Then the magnitude of the charge is
View answer and explanation
Correct option: B
5×10−10C5 \times 10^{-10} \mathrm{C}
Option B (5×10−10C5 \times 10^{-10} \mathrm{C}) is correct because the charge is calculated by equating the electric force to the gravitational force.
323 Medium
323 of 420
Understanding +4 | -1
When we touch a pith ball with an electrified plastic rod, some of the negative charges on the rod are transferred to the pith ball and it also gets charged. Thus, pith ball is charged by
View answer and explanation
Correct option: B
Contact
Option B (Contact) is correct because the pith ball acquires charge through direct physical contact with the charged rod.
324 Medium
324 of 420
Understanding +4 | -1
In nature, the electric charge of any system is always equal to
View answer and explanation
Correct option: D
Integral multiple of the least amount of charge
Option D is correct because electric charge is quantized, meaning it exists only in integer multiples of the elementary charge.
325 Medium
325 of 420
Application +4 | -1
A charge of 1 μ\mathrm{\mu }C is divided into two parts such that their charges are in the ratio of 2:3. These two charges are kept at a distance 1 m apart in vacuum. Then, the electric force between them (in N) is
View answer and explanation
Correct option: B
0.00216
Option B (0.00216) is correct because the electric force is calculated using Coulomb's law with the given charges and distance.
326 Medium
326 of 420
Application +4 | -1
Two conducting spheres have radii R1=0.5 mR_1=0.5 \mathrm{~m} and R2=1 mR_2=1 \mathrm{~m}. Each of them has 300 μC300 ~\mu \mathrm{C} charge on its surface. If the spheres are joined by a conducting wire then the amount of charge transferred from one body to the other is
View answer and explanation
Correct option: A
100 μC100 ~\mu \mathrm{C}
Option A (100 μC100 ~\mu \mathrm{C}) is correct because it is the amount of charge transferred to equalize the potential after connecting the spheres.
327 Medium
327 of 420
Understanding +4 | -1
Assertion: Two particles of same charge projected with different velocity normal to electric field experience same force.

Reason: A charged particle experiences force, independent of velocity in electric field.
View answer and explanation
Correct option: A
Both Assertion & Reason are true. Reason is the correct explanation for assertion
Option A (Both Assertion & Reason are true. Reason is the correct explanation for assertion) is correct because the force on a charged particle in an electric field is independent of its velocity, and this explains why particles with the same charge experience the same force.
328 Hard
328 of 420
Analyzing +4 | -1
Given below are two statements: one is labelled
as Assertion (A) and the other is labelled as
Reason (R).

Assertion (A): Net dipole moment of a polar
linear isotropic dielectric substance is not zero
even in the absence of an external electric field.

Reason (R): In absence of an external electric
field, the different permanent dipoles of a polar
dielectric substance are oriented in random
directions.

In the light of the above statements, choose the
most appropriate answer from the options given
below:
View answer and explanation
Correct option: D
(A) is not correct but (R) is correct
Option D ((A) is not correct but (R) is correct) is correct. A polar dielectric substance has randomly oriented dipoles resulting in a net dipole moment of zero in the absence of an external electric field, and the reason correctly states this random orientation.
329 Medium
329 of 420
Analyzing +4 | -1
Assertion : When we rub a glass rod with silk, the rod gets negatively charged and the silk gets positively charged.

Reason : On rubbing, electrons from silk cloth move to the glass rod.
View answer and explanation
Correct option: D
Both assertion and reason are false
Option D (Both assertion and reason are false) is correct because when a glass rod is rubbed with silk, the rod becomes positively charged and the silk becomes negatively charged due to electron transfer from the glass to the silk.
330 Medium
330 of 420
Analyzing +4 | -1
Two conducting charged spheres having different radii (Solid or Hollow) are connected by a conducting wire. Then which of the following is true
View answer and explanation
Correct option: B
Finally bigger sphere has more charge than smaller sphere
Option B (Finally bigger sphere has more charge than smaller sphere) is correct because when connected by a wire, the spheres will have the same potential, and charge is proportional to radius.
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