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JEE • PHYSICS • ALTERNATING CURRENT

Alternating current practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 246 questions

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151 Medium
151 of 246
Remembering +4 | -1
Transformer is based upon the principle of
View answer and explanation
Correct option: B
mutual induction
Option B is correct because a transformer operates based on the principle of mutual induction between two coils.
152 Medium
152 of 246
Analyzing +4 | -1
A series R-C circuit is connected to AC Voltage source. Consider two cases: (A) when C is without a dielectric medium and (B) when C is filled with dielectric of constant 4. The current IR{I_R} through the resistor and voltage Vc{V_c} across the capacitor are compared in the two cases. Which of the following is/are true?
View answer and explanation
Correct option: B
IRA<IRBI_R^A < I_R^B
Option B is correct because when the dielectric is filled, the capacitance increases, impedance decreases, and thus the current through the resistor increases.
153 Medium
153 of 246
Understanding +4 | -1
The peak value of house hold line voltage is
View answer and explanation
Correct option: B
311 V311 \mathrm{~V}
Option B (311 V311 \mathrm{~V}) is correct because the peak voltage is calculated using the formula Vm=2Vrms V_m = \sqrt{2} V_{\text {rms }} where Vrms V_{\text {rms }} is 220 V220 \mathrm{~V}.
154 Medium
154 of 246
Application +4 | -1
Find the output voltage of an ideal transformer connected to a 220 V220 \mathrm{~V} A.C and number of turns in primary coil and secondary coil of transformer are 100 and 10 respectively.
View answer and explanation
Correct option: A
22 V
Option A (22 V) is correct because it is calculated using the transformer equation relating the voltage ratio to the turns ratio.
155 Medium
155 of 246
Analyzing +4 | -1
An ac source of angular frequency ω\omega is fed across a resistor rr and a capacitor CC in series. The current in the circuit measured is ll. If now the frequency of source is changed to ω/3\omega / 3 (but maintaining the same voltage), the current in the circuit is found to reduce by a factor of three. The power factor of the circuit at the original frequency ω\omega is
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because the resistance R is found to be zero, leading to a power factor of zero in the circuit.
156 Medium
156 of 246
Understanding +4 | -1
When capacitor is connected to the circuit, the current, when key is pressed, is
View answer and explanation
Correct option: B
maximum
Option B (maximum) is correct because initially, the capacitor acts as a short circuit, allowing maximum current to flow.
157 Medium
157 of 246
Understanding +4 | -1
Statement I : In a series L−CL-C - RR circuit, the resonance can take place.

Statement II : Resonance takes place, if the inductive and capacitive reactances are equal and opposite.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
Option A is correct because resonance in a series L-C-R circuit occurs when inductive and capacitive reactances are equal and opposite, leading to minimum impedance.
158 Medium
158 of 246
Application +4 | -1
A 100μF100 \mu \mathrm{F} capacitor in series with a 40 Ω40 ~\Omega resistance is connected to a 110 V,60 Hz110 \mathrm{~V}, 60 \mathrm{~Hz} supply. What is the maximum current in the circuit?
View answer and explanation
Correct option: A
3.24 A3.24 \mathrm{~A}
Option A (3.24 A3.24 \mathrm{~A}) is correct because it is calculated by finding the peak voltage, impedance, and then the maximum current in the R-C circuit.
159 Medium
159 of 246
Application +4 | -1
In a series LRL R circuit XL=RX_L=R and power factor of the circuit is P1P_1. When capacitor with capacitance CC such that XL=XCX_L=X_C is put in series, the power factor becomes P2P_2. The ratio P1P2\frac{P_1}{P_2} is
View answer and explanation
Correct option: B
12\frac{1}{\sqrt{2}}
Option B (12\frac{1}{\sqrt{2}}) is correct because the power factor changes from 12\frac{1}{\sqrt{2}} to 1 when resonance occurs.
160 Medium
160 of 246
Application +4 | -1
An ideal choke takes a current of 10 ampere when connected to an A.C. supply of 125 volt and 50 Hz50 \mathrm{~Hz}. A pure resistor under the same conditions takes a current of 12.5 ampere. If the two are connected to an A.C. supply of 1002100 \sqrt{2} volt and 40 hertz, then find the current in a series combination of the above resistor and inductor.
View answer and explanation
Correct option: A
0.416666667
The correct answer is 10:00 AM because the current in the series combination of the resistor and inductor is calculated to be 10 A using the given parameters.
161 Medium
161 of 246
Understanding +4 | -1
QQ-factor can be increased by having a coil of:
View answer and explanation
Correct option: A
Large inductance, small ohmic resistance
Option A (Large inductance, small ohmic resistance) is correct because the Q-factor of a coil is given by Q=ωLRQ = \frac{{\omega L}}{R}, so a large inductance and small resistance will increase the Q-factor.
162 Medium
162 of 246
Understanding +4 | -1
A choke coil has negligible resistance. The alternating potential drop across it is 220 volt and the current is 5mA. The power consumed is.
View answer and explanation
Correct option: C
zero
Option C (zero) is correct because the average power consumed by a purely inductive choke coil in an AC circuit is zero.
163 Medium
163 of 246
Application +4 | -1
An alternating current is given by the following equation: I=32sin⁡(100πt+π/4)I=3 \sqrt{2} \sin (100 \pi t+\pi / 4). Give the frequency and rms value of the current.
View answer and explanation
Correct option: A
3 A3 \mathrm{~A}
Option A (3 A) is correct because the RMS value of the current is calculated by dividing the peak current by the square root of 2.
164 Medium
164 of 246
Application +4 | -1
The primary and secondary coils of a transformer have 50\mathrm{50} and 1500\mathrm{1500} turns respectively. If the magnetic flux ϕ\phi linked with the primary coil is given by ϕ=ϕ0+4t\phi = {\phi _0} + 4\mathrm{t}, where ϕ\phi is in weber, tt is time in second and ϕ0{\phi _0} is a constant, the output voltage across the secondary coil is
View answer and explanation
Correct option: B
120  V\mathrm{120}\,\,\mathrm{V}
Option B (120 V\mathrm{120}\,\mathrm{V}) is correct because it calculates the output voltage using the transformer turns ratio.
165 Medium
165 of 246
Understanding +4 | -1
Statement (A): An inductor, capacitor and resistance connected in series. The combination is connected across AC source. Peak current through each remains same.

Statement (B): Average power delivered by source is equal to average power consumed by resistance.
View answer and explanation
Correct option: A
Both (A) and (B) are true
Option A (Both (A) and (B) are true) is correct because in a series LCR circuit, the peak current is the same through each element, and the average power delivered by the source is consumed only by the resistance.
166 Medium
166 of 246
Understanding +4 | -1
If E0{E_0} is the peak emf, I0{I_0} is the peak current and ϕ\phi is the phase difference between them, then the average power dissipation in the circuit is
View answer and explanation
Correct option: D
12E0I0cos⁡ϕ\frac{1}{2}{E_0}{I_0}\cos \phi
Option D is correct because the average power dissipation in an AC circuit is given by 12E0I0cos⁡ϕ\frac{1}{2}E_0 I_0 \cos \phi, where ϕ\phi is the phase difference between voltage and current.
167 Medium
167 of 246
Application +4 | -1
A generator at a utility company produces 100A\mathrm{100 A} of current at 4000  V\mathrm{4000}\,\,\mathrm{V}. The voltage is stepped up to 240000  V\mathrm{240000}\,\,\mathrm{V} by a transformer before it is sent on a high voltage transmission line. The current in transmission line is
View answer and explanation
Correct option: C
1.67A\mathrm{1}\mathrm{.67 A}
Option C (1.67 A) is correct because the power remains constant in an ideal transformer, so the current is inversely proportional to the voltage.
168 Medium
168 of 246
Understanding +4 | -1
Assertion: An electric lamp connected in series with a variable capacitor and ac source, its brightness increases with increase in capacitance.

Reason: Capacitive reactance decrease with increase in capacitance of capacitor.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because increasing capacitance decreases capacitive reactance, leading to increased brightness.
169 Medium
169 of 246
Understanding +4 | -1
In an LRLR-circuit time constant is that time in which current grows from zero to the value (where I0{I_0} is the steady state current)
View answer and explanation
Correct option: A
0.63  I00.63\,\,{I_0}
Option A is correct because the time constant in an LR circuit represents the time it takes for the current to reach approximately 63% of its steady-state value.
170 Medium
170 of 246
Application +4 | -1
The impedance of a circuit consists of 3 ohm resistance and 4 ohm reactance. The power factor of the circuit is
View answer and explanation
Correct option: B
0.6
Option B (0.6) is correct because the power factor is the ratio of resistance to impedance, and the impedance is calculated using the Pythagorean theorem.
171 Medium
171 of 246
Understanding +4 | -1
The current and emf through an inductance differ in phase by.
View answer and explanation
Correct option: B
π2\frac{\pi}{2}
Option B (π2\frac{\pi}{2}) is correct because in a purely inductive circuit, the voltage leads the current by 90 degrees, or π2\frac{\pi}{2} radians.
172 Medium
172 of 246
Application +4 | -1
When 100 volt DC source is applied across a coil, a current of 1 A flows through it. When 100 V AC source of 50 Hz is applied to the same coil, only 0.5 A current flows. Calculate the inductance of the coil
View answer and explanation
Correct option: B
(3/π)H(\sqrt{3} / \pi) \mathrm{H}
Option B (3π\frac{\sqrt{3}}{\pi} H) is correct because the inductance is calculated using the difference between DC and AC current behavior in the coil.
173 Medium
173 of 246
Remembering +4 | -1
The hysteresis cycle for the material of a transformer core is
View answer and explanation
Correct option: B
Tall and narrow
Option D (Short and narrow) is correct because the material of a transformer core should have low hysteresis loss, which is achieved with a short and narrow hysteresis loop.
174 Medium
174 of 246
Understanding +4 | -1
The turn ratio of a transformer is 1:2\mathrm{1:2}. An electrolytic DC cell of emf 2V\mathrm{2 V} is connected to its primary. The output voltage across transformer is
View answer and explanation
Correct option: A
Zero
Option A is correct because transformers only work with alternating current (AC). A DC voltage applied to the primary will not induce a voltage in the secondary.
175 Medium
175 of 246
Application +4 | -1
A coil has an inductance of 1H1 H. (i) At what frequency will it have a reactance of 3142Ω3142 \Omega ? (ii) What should be the capacity of a capacitor which has the same reactance at that frequency?
View answer and explanation
Correct option: A
500 Hz500 \mathrm{~Hz} , 0.11 μF0.11 ~\mu \mathrm{F}
Option A (500 Hz500 \mathrm{~Hz} , 0.11 μF0.11 ~\mu \mathrm{F}) is correct because it accurately calculates the frequency and capacitance based on the given inductance and reactance.
176 Medium
176 of 246
Understanding +4 | -1
In an AC generator, a coil with N turns, all of the same area A and total resistance R, rotates with frequency ω \omega \, in a magnetic field B. The maximum value of emf generated in the coils is
View answer and explanation
Correct option: D
N A B ω \omega \,
Option D (N A B ω\omega) is correct because the maximum induced EMF in an AC generator is given by the formula NABω\omega.
177 Medium
177 of 246
Application +4 | -1
An emf of 20 V is applied at time t=0t = 0 to a circuit containing in series 10 mH inductor and 5 Ω5\,\Omega resistor. The ratio of the currents at time t = ∞t\, = \,\infty and at t = 40 st\, = \,40\,s is close to (Take, e2 = 7.389{e^2}\, = \,7.389)
View answer and explanation
Correct option: A
1.06
Option A (1.06) is correct because it represents the ratio of currents at t=infinity and t=40s, calculated using the formula for current growth in an L-R circuit.
178 Medium
178 of 246
Application +4 | -1
A 0.7 henry inductor is connected a cross a 120 V- 60 Hz ac source. The current in the inductor will be very nearly (in amp)
View answer and explanation
Correct option: C
0.455
Option C (0.455) is correct because the current is calculated using the formula I = V/X_L, where X_L is the inductive reactance.
179 Medium
179 of 246
Analyzing +4 | -1
Assertion: Average power loss in series LC circuit is always zero.

Reason: Average values of voltage and current in A. C. is zero.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because the average power loss is zero due to the phase difference between voltage and current, not because the average voltage and current are zero.
180 Medium
180 of 246
Application +4 | -1
A transformer with efficiency 80%80 \% works at 4 kW4 \mathrm{~kW} and 100 V100 \mathrm{~V}. If the secondary voltage is 200 V200 \mathrm{~V}, then the primary and secondary currents are respectively-
View answer and explanation
Correct option: A
40 A,16 A40 \mathrm{~A}, 16 \mathrm{~A}
Option A (40 A,16 A40 \mathrm{~A}, 16 \mathrm{~A}) is correct because the primary and secondary currents are calculated using the transformer efficiency and power equations.
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