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JEE • PHYSICS • ALTERNATING CURRENT

Alternating current practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 279 questions
241 Medium
241 of 279
Application +4 | -1
An electric bulb and a capacitor are connected in series with an AC source. On increasing the frequency of the source, the brightness of the bulb:
View answer and explanation
Correct option: B
Increases
Option B (Increases) is correct because increasing the frequency decreases the capacitive reactance, leading to increased current and brightness.
242 Medium
242 of 279
Understanding +4 | -1
Maximum power is dissipated in an LCR circuit at resonance
View answer and explanation
Correct option: B
Through R\mathrm{R}
Option B (Through R) is correct because in an LCR circuit at resonance, the impedance is minimized and equal to the resistance, so maximum power is dissipated through the resistor.
243 Easy
243 of 279
Remembering +4 | -1
In L – C – R series circuit the resonance condition in terms of capacitive reactance (XC)\left( {{X_C}} \right) and inductive reactance (XL)\left( {{X_L}} \right) is
View answer and explanation
Correct option: D
XC−XL=0{X_C} - {X_L} = 0
Option D (XC−XL=0{X_C} - {X_L} = 0) is correct because at resonance in an LCR series circuit, the capacitive reactance equals the inductive reactance, making their difference zero.
244 Medium
244 of 279
Understanding +4 | -1
For a given AC source the average emf during the positive half cycle
View answer and explanation
Correct option: C
both 1 and 2
Option C (both 1 and 2) is correct because the average emf depends on both the peak value (E0E_0) and the shape of the wave.
245 Medium
245 of 279
Application +4 | -1
A coil of inductance 0.50 H0.50 \mathrm{~H} and resistance 100Ω100 \Omega is connected to a 240 V,50 Hz240 \mathrm{~V}, 50 \mathrm{~Hz} ac supply. What are the maximum current in the coil and the time lag between voltage maximum and current maximum?
View answer and explanation
Correct option: A
3.2×10−3 s3.2 \times 10^{-3} \mathrm{~s}
Option A (3.2×10−3 s3.2 \times 10^{-3} \mathrm{~s}) is correct because it is calculated using the impedance of the coil and the phase difference between voltage and current.
246 Medium
246 of 279
Understanding +4 | -1
Average power in the L-C-R circuit depends upon
View answer and explanation
Correct option: D
Current, emf and phase difference
Option D (Current, emf and phase difference) is correct because average power in an LCR circuit depends on voltage, current, and the phase angle between them.
247 Medium
247 of 279
Understanding +4 | -1
In a series L-R circuit, under which condition the power loss will be least for an a.c. voltage source?
View answer and explanation
Correct option: C
low resistance and high inductance
Option C (low resistance and high inductance) is correct because low resistance minimizes power loss, and high inductance causes a larger phase difference, reducing power factor.
248 Medium
248 of 279
Understanding +4 | -1
The primary coil of an ideal transformer has 100 turns and secondary coil has 200 turns. Then select the correct option.
View answer and explanation
Correct option: D
The Voltage in secondary coil is two times than primary coil
Option D (The Voltage in secondary coil is two times than primary coil) is correct because the voltage ratio is equal to the turns ratio in an ideal transformer.
249 Medium
249 of 279
Application +4 | -1
The peak power consumed by a resistive coil when connected to an AC source is 80 W. Find the energy consumed by the coil in 100 seconds which is many times larger than the time period of the source.
View answer and explanation
Correct option: A
4.0 kJ
Option A (4.0 kJ) is correct because the energy consumed is calculated by multiplying the average power by the time.
250 Medium
250 of 279
Analyzing +4 | -1
The phase difference between the alternating current and emf is π/2\pi / 2. Which of the following cannot be the constituent of the circuit?
View answer and explanation
Correct option: B
R,LR, L
Option C (L, C) is correct because in an L-C circuit, the phase difference between current and voltage can have a value of 0 or π/2 depending on the values of L and C.
251 Medium
251 of 279
Application +4 | -1
A transformer has an efficiency of 80%80 \%. It works at 4 kW4 \mathrm{~kW} and 100 V100 \mathrm{~V}. If secondary voltage is 240 V240 \mathrm{~V}, the current in primary coil is
View answer and explanation
Correct option: D
40 A40 \mathrm{~A}
Option D (40 A) is correct because the primary current is calculated using the transformer efficiency and power equation.
252 Medium
252 of 279
Application +4 | -1
The electric current in a circuit is given by [i=3sin⁡ωt+4cos⁡ωt][i=3 \sin \omega t+4 \cos \omega t]. The value of rmsrms current is:
View answer and explanation
Correct option: A
52\frac{5}{\sqrt{2}}
Option A (52\frac{5}{\sqrt{2}}) is correct because it is calculated using the RMS value formula for sinusoidal currents.
253 Medium
253 of 279
Understanding +4 | -1
Assertion: In series LCR circuit resonance can take place.

Reason: Resonance takes place if inductance and capacitive reactances are equal and opposite.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because resonance occurs in a series LCR circuit when the inductive and capacitive reactances are equal, leading to maximum current.
254 Medium
254 of 279
Application +4 | -1
An emf E=4cos⁡1000tE=4 \cos 1000 \mathrm{t} volt is applied to an L-R circuit of inductance 3mH3 \mathrm{mH} and resistance 4Ω4 \Omega. The amplitude of the current in the circuit is
View answer and explanation
Correct option: A
0.8 A0.8 \mathrm{~A}
Option A (0.8 A0.8 \mathrm{~A}) is correct because it is the amplitude of the current calculated using the formula i0=ε0Zi_0 = \frac{\varepsilon_0}{Z}, where Z is the impedance of the L-R circuit.
255 Hard
255 of 279
Analyzing +4 | -1
An ac source of angular frequency ω is fed across a resistor r and a capctior C in series. The current registered is II. If the frequency of source is changed to ω/3 (maintaining the same voltage), the current in the circuit is found to be halved. Calculate the ratio of reactance to resistance at the original frequency ω
View answer and explanation
Correct option: A
35\sqrt {\frac{3}{5}}
The ratio of reactance to resistance at the original frequency is 35\sqrt{\frac{3}{5}} (Option A) because it is derived from the given current and frequency changes in the RC circuit.
256 Medium
256 of 279
Understanding +4 | -1
When the current in an ac circuit is wattles, the phase difference between the applied voltage and circuit current will be
View answer and explanation
Correct option: C
90∘90^\circ
Option C is correct because in a wattless current, the phase difference between voltage and current is 90 degrees, resulting in zero power consumption.
257 Medium
257 of 279
Understanding +4 | -1
Given below are two statements.

Statement I: In an ac circuit, the current through a capacitor
leads the voltage across it.

Statement II: In a.c circuits containing pure capacitance only,
the phase difference between the current and
the voltage is π.\pi.

In the light of the above statements, choose the
most appropriate answer from the options
given below.
View answer and explanation
Correct option: D
Statement I is correct but Statement II is
incorrect
Option D is correct. Statement I is correct because in an AC circuit, the current through a capacitor leads the voltage. Statement II is incorrect because the phase difference is \π2\frac{\pi}{2} not \π\pi.
258 Medium
258 of 279
Understanding +4 | -1
A particle oscillating under a force F→=−kx→−bv→\overrightarrow F = - k\overrightarrow x - b\overrightarrow v is a [K and b are constants] :
View answer and explanation
Correct option: C
Damped oscillator
Option C (Damped oscillator) is correct because the force includes a term proportional to velocity (−bv→-b\overrightarrow{v}), which represents damping.
259 Medium
259 of 279
Analyzing +4 | -1
Assertion (A) : In series L−C⋅RL-C \cdot R circuit, if a ferromagnetic rod is inserted inside an inductor, current in the circuit may increase or decrease.

Reason (R) : By doing so XLX_L will increase.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because while inserting a ferromagnetic rod increases X_L, the current's behavior depends on the relative values of X_L and X_C.
260 Medium
260 of 279
Application +4 | -1
The primary winding of a transformer has 200 turns and its secondary winding has 50 turns. If the current in the secondary winding is 40 A, the current in the primary is
View answer and explanation
Correct option: A
10A
Option A (10A) is correct because the current in the primary winding is inversely proportional to the number of turns, calculated using the transformer equation.
261 Medium
261 of 279
Application +4 | -1
In a series LCR circuit, the voltages across an inductor, a capacitor, and a resistor are 30 V,30 V30{~V}, 30{~V} and 60 V60{~V} respectively. The phase difference between the applied voltage and the current in the circuit is
View answer and explanation
Correct option: D
0∘0^\circ
Option D (0∘0^\circ) is correct because in a series LCR circuit, when the voltage across the inductor and capacitor are equal, the circuit is in resonance, and the phase difference is zero.
262 Medium
262 of 279
Application +4 | -1
An a.c current is given by i=3sin⁡wt+4cos⁡wti=3 \sin w t+4 \cos w t amp. Its rms value is
View answer and explanation
Correct option: C
52\frac{5}{\sqrt{2}}
The correct answer is C (52\frac{5}{\sqrt{2}}). The RMS value of the current is calculated by finding the square root of the average of the square of the current over one cycle.
263 Medium
263 of 279
Application +4 | -1
An L−CL-C circuit is in a state of resonance. If C=0.1μFC=0.1 \mu \mathrm{F} and L=0.25HL=0.25 \mathrm{H}, then neglecting the ohmic resistance of the circuit, find the frequency of oscillations.
View answer and explanation
Correct option: A
1007 Hz1007 \mathrm{~Hz}
Option A (1007 Hz1007 \mathrm{~Hz}) is correct because it is the resonant frequency calculated using the formula v=12πLCv=\frac{1}{2 \pi \sqrt{L C}}.
264 Medium
264 of 279
Analyzing +4 | -1
A series R−CR-C circuit is connected to ACA C voltage source. Consider two cases; (A)(A) When CC is without a dielectric medium and (B)(B) When CC is filled with dielectric of constant 4 . The current IRI_R through the resistor and voltage VCV_C across the capacitor are compared in two cases. Which of the following is true?
View answer and explanation
Correct option: B
IRA<IRBI_R^A < I_R^B
Option B (IRA<IRBI_R^A < I_R^B) is correct because adding a dielectric increases capacitance, decreases impedance, and increases current.
265 Medium
265 of 279
Understanding +4 | -1
The core of any transformer is laminated so as to
View answer and explanation
Correct option: A
reduce the energy loss due to eddy currents
Option A is correct because laminating the core increases the resistance to eddy currents, thereby reducing energy loss.
266 Medium
266 of 279
Application +4 | -1
A resistor of resistance 400 Ω400 ~\Omega, and a capacitor of reactance 200 Ω200 ~\Omega, are connected in series to a 220 V,50 Hz220 \mathrm{~V}, 50 \mathrm{~Hz}, a.c. source. If the current in the circuit is 0.49 ampere, find the (i) voltage across the resistor and capacitor (ii) value of inductance required so that voltage and current are in phase.
View answer and explanation
Correct option: C
98 V98 \mathrm{~V} , 0.64 H0.64 \mathrm{~H}
Option C (98 V98 \mathrm{~V} , 0.64 H0.64 \mathrm{~H}) is correct because it calculates the voltage across the capacitor and resistor using Ohm's law and finds the inductance required for resonance.
267 Easy
267 of 279
Understanding +4 | -1
In an ac circuit with voltage V and current I, the power dissipated is
View answer and explanation
Correct option: D
Depends on the phases between V and I
Option D (Depends on the phases between V and I) is correct because the power dissipated in an AC circuit depends on the phase angle between voltage and current, as given by P=VIcos⁡ϕP = VI\cos\phi.
268 Medium
268 of 279
Application +4 | -1
In an AC circuit the instantaneous values of emf and current are e=200sin⁡300  t  volte = 200\sin 300\;t\;\mathrm{volt} and i=2sin⁡(300t+π3)i = 2\sin \left( {300t + \frac{\pi }{3}} \right) amp. The average power consumed in watt is
View answer and explanation
Correct option: B
100
Option B (100) is correct because the average power consumed is calculated using P = (V0*I0/2) * cos(phi).
269 Medium
269 of 279
Application +4 | -1
A current of 2 A2 \mathrm{~A} is flowing at 220 V220 \mathrm{~V} in the primary coil of a transformer. If current in the secondary coil is 1 A1 \mathrm{~A} and efficiency of the transformer is 80%80 \% then the voltage produced in the secondary coil will be
View answer and explanation
Correct option: B
352 V352 \mathrm{~V}
Option B (352 V352 \mathrm{~V}) is correct because it's calculated by using the transformer efficiency formula and the given currents and primary voltage.
270 Medium
270 of 279
Understanding +4 | -1
Which is not true for series LCR circuit in resonance:
View answer and explanation
Correct option: B
Maximum impedance
Option B (Maximum impedance) is correct because at resonance, the impedance of a series LCR circuit is minimum and equal to the resistance, leading to maximum current.
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