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JEE • PHYSICS • ALTERNATING CURRENT

Alternating current practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 279 questions

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181 Medium
181 of 279
Application +4 | -1
An alternating current is given by the following equation: I=32sin⁡(100πt+π/4)I=3 \sqrt{2} \sin (100 \pi t+\pi / 4). Give the frequency and rms value of the current.
View answer and explanation
Correct option: A
3 A3 \mathrm{~A}
Option A (3 A) is correct because the RMS value of the current is calculated by dividing the peak current by the square root of 2.
182 Medium
182 of 279
Application +4 | -1
The primary and secondary coils of a transformer have 50\mathrm{50} and 1500\mathrm{1500} turns respectively. If the magnetic flux ϕ\phi linked with the primary coil is given by ϕ=ϕ0+4t\phi = {\phi _0} + 4\mathrm{t}, where ϕ\phi is in weber, tt is time in second and ϕ0{\phi _0} is a constant, the output voltage across the secondary coil is
View answer and explanation
Correct option: B
120  V\mathrm{120}\,\,\mathrm{V}
Option B (120 V\mathrm{120}\,\mathrm{V}) is correct because it calculates the output voltage using the transformer turns ratio.
183 Medium
183 of 279
Understanding +4 | -1
Statement (A): An inductor, capacitor and resistance connected in series. The combination is connected across AC source. Peak current through each remains same.

Statement (B): Average power delivered by source is equal to average power consumed by resistance.
View answer and explanation
Correct option: A
Both (A) and (B) are true
Option A (Both (A) and (B) are true) is correct because in a series LCR circuit, the peak current is the same through each element, and the average power delivered by the source is consumed only by the resistance.
184 Medium
184 of 279
Understanding +4 | -1
If E0{E_0} is the peak emf, I0{I_0} is the peak current and ϕ\phi is the phase difference between them, then the average power dissipation in the circuit is
View answer and explanation
Correct option: D
12E0I0cos⁡ϕ\frac{1}{2}{E_0}{I_0}\cos \phi
Option D is correct because the average power dissipation in an AC circuit is given by 12E0I0cos⁡ϕ\frac{1}{2}E_0 I_0 \cos \phi, where ϕ\phi is the phase difference between voltage and current.
185 Medium
185 of 279
Application +4 | -1
A generator at a utility company produces 100A\mathrm{100 A} of current at 4000  V\mathrm{4000}\,\,\mathrm{V}. The voltage is stepped up to 240000  V\mathrm{240000}\,\,\mathrm{V} by a transformer before it is sent on a high voltage transmission line. The current in transmission line is
View answer and explanation
Correct option: C
1.67A\mathrm{1}\mathrm{.67 A}
Option C (1.67 A) is correct because the power remains constant in an ideal transformer, so the current is inversely proportional to the voltage.
186 Medium
186 of 279
Understanding +4 | -1
Assertion: An electric lamp connected in series with a variable capacitor and ac source, its brightness increases with increase in capacitance.

Reason: Capacitive reactance decrease with increase in capacitance of capacitor.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because increasing capacitance decreases capacitive reactance, leading to increased brightness.
187 Medium
187 of 279
Understanding +4 | -1
In an LRLR-circuit time constant is that time in which current grows from zero to the value (where I0{I_0} is the steady state current)
View answer and explanation
Correct option: A
0.63  I00.63\,\,{I_0}
Option A is correct because the time constant in an LR circuit represents the time it takes for the current to reach approximately 63% of its steady-state value.
188 Easy
188 of 279
Application +4 | -1
In an AC circuit, the instantaneous values of emf and current are e=200sin⁡314t volt and I=sin⁡(314t+π3) ampI = \sin \left( {314t + \frac{\pi }{3}} \right)\,amp , The average power consumed in watt is
View answer and explanation
Correct option: C
50
Option C (50) is correct because the average power consumed is calculated using P = Vrms * Irms * cos(phi).
189 Medium
189 of 279
Application +4 | -1
The impedance of a circuit consists of 3 ohm resistance and 4 ohm reactance. The power factor of the circuit is
View answer and explanation
Correct option: B
0.6
Option B (0.6) is correct because the power factor is the ratio of resistance to impedance, and the impedance is calculated using the Pythagorean theorem.
190 Medium
190 of 279
Understanding +4 | -1
The current and emf through an inductance differ in phase by.
View answer and explanation
Correct option: B
π2\frac{\pi}{2}
Option B (π2\frac{\pi}{2}) is correct because in a purely inductive circuit, the voltage leads the current by 90 degrees, or π2\frac{\pi}{2} radians.
191 Medium
191 of 279
Application +4 | -1
When 100 volt DC source is applied across a coil, a current of 1 A flows through it. When 100 V AC source of 50 Hz is applied to the same coil, only 0.5 A current flows. Calculate the inductance of the coil
View answer and explanation
Correct option: B
(3/π)H(\sqrt{3} / \pi) \mathrm{H}
Option B (3π\frac{\sqrt{3}}{\pi} H) is correct because the inductance is calculated using the difference between DC and AC current behavior in the coil.
192 Medium
192 of 279
Remembering +4 | -1
The hysteresis cycle for the material of a transformer core is
View answer and explanation
Correct option: B
Tall and narrow
Option D (Short and narrow) is correct because the material of a transformer core should have low hysteresis loss, which is achieved with a short and narrow hysteresis loop.
193 Medium
193 of 279
Understanding +4 | -1
The turn ratio of a transformer is 1:2\mathrm{1:2}. An electrolytic DC cell of emf 2V\mathrm{2 V} is connected to its primary. The output voltage across transformer is
View answer and explanation
Correct option: A
Zero
Option A is correct because transformers only work with alternating current (AC). A DC voltage applied to the primary will not induce a voltage in the secondary.
194 Easy
194 of 279
Understanding +4 | -1
The instantaneous values of current and emf in an ac circuit are I=1/2I = 1/\sqrt 2 sin⁡314  t  amp\sin 314\;t\;amp and E=2sin⁡(314  t−π/6)VE = \sqrt 2 \sin \left( {314\;t - \pi /6} \right)V respectively. The phase difference between E and I will be
View answer and explanation
Correct option: A
−π/6  rad- \pi /6\;rad
Option A (−π/6  rad- \pi /6\;rad) is correct because the phase difference is the difference between the phase angles of the voltage and current.
195 Easy
195 of 279
Understanding +4 | -1
In an AC series circuit, the instantaneous current is maximum when the instantaneous voltage is maximum. The circuit element connected to the source will be
View answer and explanation
Correct option: C
Pure resistor
Option C (Pure resistor) is correct because in a purely resistive AC circuit, the voltage and current are in phase, meaning they reach their maximum values simultaneously.
196 Medium
196 of 279
Application +4 | -1
A coil has an inductance of 1H1 H. (i) At what frequency will it have a reactance of 3142Ω3142 \Omega ? (ii) What should be the capacity of a capacitor which has the same reactance at that frequency?
View answer and explanation
Correct option: A
500 Hz500 \mathrm{~Hz} , 0.11 μF0.11 ~\mu \mathrm{F}
Option A (500 Hz500 \mathrm{~Hz} , 0.11 μF0.11 ~\mu \mathrm{F}) is correct because it accurately calculates the frequency and capacitance based on the given inductance and reactance.
197 Medium
197 of 279
Understanding +4 | -1
In an AC generator, a coil with N turns, all of the same area A and total resistance R, rotates with frequency ω \omega \, in a magnetic field B. The maximum value of emf generated in the coils is
View answer and explanation
Correct option: D
N A B ω \omega \,
Option D (N A B ω\omega) is correct because the maximum induced EMF in an AC generator is given by the formula NABω\omega.
198 Medium
198 of 279
Application +4 | -1
An emf of 20 V is applied at time t=0t = 0 to a circuit containing in series 10 mH inductor and 5 Ω5\,\Omega resistor. The ratio of the currents at time t = ∞t\, = \,\infty and at t = 40 st\, = \,40\,s is close to (Take, e2 = 7.389{e^2}\, = \,7.389)
View answer and explanation
Correct option: A
1.06
Option A (1.06) is correct because it represents the ratio of currents at t=infinity and t=40s, calculated using the formula for current growth in an L-R circuit.
199 Easy
199 of 279
Understanding +4 | -1
An alternating e.m.f. is applied to purely capacitive circuit. The phase relation between e.m.f. and current flowing in the circuit is or
In a circuit containing capacitance only
View answer and explanation
Correct option: B
Current is ahead of e.m.f. by π/2\pi /2
Option B (Current is ahead of e.m.f. by π/2\pi /2) is correct because in a purely capacitive circuit, the current leads the voltage by 90 degrees.
200 Medium
200 of 279
Application +4 | -1
A 0.7 henry inductor is connected a cross a 120 V- 60 Hz ac source. The current in the inductor will be very nearly (in amp)
View answer and explanation
Correct option: C
0.455
Option C (0.455) is correct because the current is calculated using the formula I = V/X_L, where X_L is the inductive reactance.
201 Medium
201 of 279
Analyzing +4 | -1
Assertion: Average power loss in series LC circuit is always zero.

Reason: Average values of voltage and current in A. C. is zero.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because the average power loss is zero due to the phase difference between voltage and current, not because the average voltage and current are zero.
202 Medium
202 of 279
Application +4 | -1
A transformer with efficiency 80%80 \% works at 4 kW4 \mathrm{~kW} and 100 V100 \mathrm{~V}. If the secondary voltage is 200 V200 \mathrm{~V}, then the primary and secondary currents are respectively-
View answer and explanation
Correct option: A
40 A,16 A40 \mathrm{~A}, 16 \mathrm{~A}
Option A (40 A,16 A40 \mathrm{~A}, 16 \mathrm{~A}) is correct because the primary and secondary currents are calculated using the transformer efficiency and power equations.
203 Medium
203 of 279
Analyzing +4 | -1
Statement (A): An electric lamp is connected in series with a long solenoid of copper with air core and then connected to AC source. If an iron rod is inserted in solenoid the lamp will become dim.

Statement (B): If iron rod is inserted in solenoid, the induction of solenoid increases.
View answer and explanation
Correct option: A
Both (A) and (B) are true
Both (A) and (B) are true because inserting an iron rod increases the inductance of the solenoid, which increases the impedance and reduces the current, dimming the lamp.
204 Hard
204 of 279
Application +4 | -1
What is the value of inductance L for which the current is a maximum in a series L-C-R circuit with C=10μFC = 10\mu \mathrm{F} and ω=1000  s−1?\omega = 1000\;{\mathrm{s}^{ - 1}}?
View answer and explanation
Correct option: A
100 mH
Option A (100 mH) is correct because the current is maximum at resonance, where the inductive reactance equals the capacitive reactance, leading to L = 1/(ω2\omega^2C).
205 Medium
205 of 279
Understanding +4 | -1
Alternating current cannot be measured by DC ammeter because
View answer and explanation
Correct option: C
Average value of current for complete cycle is zero
Option C is correct because the average value of AC over a complete cycle is zero, so a DC ammeter, which measures average current, will not register any current.
206 Hard
206 of 279
Understanding +4 | -1
For a series R-L-C circuit:

(a) Voltage across L and C differ by π\pi phase

(b) Current through L and R are in same phase

(c) Voltage across R and L differ by π/2\pi/2 phase

(d) Voltage across L and current through C differ by π/2\pi/2 phase
View answer and explanation
Correct option: D
All are correct
Option D (All are correct) is correct because it accurately describes the phase relationships between voltage and current in a series RLC circuit.
207 Medium
207 of 279
Understanding +4 | -1
An AC source rated 100 V100 \mathrm{~V} (rms) supplies a current of 10 A10 \mathrm{~A} (rms) to a circuit. The average power delivered by the source:
View answer and explanation
Correct option: C
May be less than 1000 W1000 \mathrm{~W}
Option C is correct because the average power delivered by an AC source is given by P=VrmsIrmscos⁡ϕP = V_{rms} I_{rms} \cos{\phi}, where cos⁡ϕ\cos{\phi} is the power factor, which can be less than 1.
208 Medium
208 of 279
Application +4 | -1
A 100 Ω100\,\Omega resistance and a capacitor of 100 Ω100\,\Omega reactance are connected in series across a 200  V200\,{\mkern 1mu} V source. When the capacitor is 50% charged, the peak value of the displacement current is
View answer and explanation
Correct option: B
2.2 A
The correct answer is 2.2 A because the peak current is calculated using the peak voltage and impedance of the series RC circuit.
209 Medium
209 of 279
Application +4 | -1
Impedance of a coil having inductance 0.4 H at frequency of 50 Hz will be
View answer and explanation
Correct option: B
40 π  Ω40\,\pi \,\,\Omega
Option B (40π,Ω40\pi \\,\Omega) is correct because it accurately calculates the impedance of the coil using the formula XL=2πfLX_L = 2\pi fL.
210 Easy
210 of 279
Understanding +4 | -1
In an ac circuit, the instantaneous current is zero, when the instantaneous voltage is maximum. In this case, the source may be connected to:
A. pure inductor.
B. pure capacitor.
C. pure resistor.
D. combination of an inductor and capacitor.
Choose the correct answer from the options given below:
View answer and explanation
Correct option: D
A, B and D only
Option D (A, B and D only) is correct because in a pure inductor, pure capacitor, or a combination of inductor and capacitor, the instantaneous current can be zero when the instantaneous voltage is maximum due to a phase difference of π2\frac{\pi}{2}.
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