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JEE • MATHEMATICS • TRIGONOMETRY RATIOS

Trigonometry ratios practice · Medium

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Showing 151-157 of 157 questions
151 Medium
151 of 157
Application +4 | -1
The value of sin⁡  π16  sin⁡  3π16  sin⁡  5π16  sin⁡  7π16\sin \,\,\frac{\pi }{{16}}\,\,\sin \,\,\frac{{3\pi }}{{16}}\,\,\sin \,\,\frac{{5\pi }}{{16}}\,\,\sin \,\,\frac{{7\pi }}{{16}} is
View answer and explanation
Correct option: A
216\frac{{\sqrt 2 }}{{16}}
Option A (216\frac{{\sqrt 2 }}{{16}}) is correct because the product of the sines can be simplified using trigonometric identities to obtain this value.
152 Medium
152 of 157
Remembering +4 | -1
∑n=124sin⁡(π2)\sum_{n=12}^4 \sin \left(\frac{\pi}{2}\right) is equal to
View answer and explanation
Correct option: D
3+2+22\frac{\sqrt{3}+\sqrt{2}+2}{2}
Option D (3+2+22\frac{\sqrt{3}+ \sqrt{2}+2}{2}) is correct because it is the sum of sin⁡π1\sin{\frac{\pi}{1}}, sin⁡π2\sin{\frac{\pi}{2}}, sin⁡π3\sin{\frac{\pi}{3}}, and sin⁡π4\sin{\frac{\pi}{4}}.
153 Medium
153 of 157
Application +4 | -1
If tan⁡A,tan⁡B,tan⁡C\tan A, \tan B, \tan C are the roots of the cubic equation x3−7x2+11x−7=0x^3-7 x^2+11 x-7=0 then A+B+C=A+B+C=
View answer and explanation
Correct option: B
π\pi
Option B (π\pi) is correct because the sum of the roots of the cubic equation gives the tangent of the sum of the angles, which equals zero, implying the sum of the angles is π\pi.
154 Medium
154 of 157
Analyzing +4 | -1
In a △ABC,cos⁡B⋅cos⁡C+sin⁡B⋅sin⁡C⋅sin⁡2A=1\triangle A B C, \cos B \cdot \cos C+\sin B \cdot \sin C \cdot \sin ^2 A=1 Then, the triangle is
View answer and explanation
Correct option: A
right angled isosceles
Option A (right angled isosceles) is correct because the given equation implies that B=CB=C and A=π2A = \frac{\pi}{2}, making the triangle right-angled and isosceles.
155 Medium
155 of 157
Application +4 | -1
If sin⁡θ=1213(0<θ<π2)\sin \theta=\frac{12}{13}\left(0 < \theta < \frac{\pi}{2}\right) and cos⁡ϕ=−35,(π<ϕ<3π2)\cos \phi=-\frac{3}{5},\left(\pi < \phi < \frac{3 \pi}{2}\right) Then sin⁡(θ+ϕ)\sin (\theta+\phi) will be
View answer and explanation
Correct option: B
−5665\frac{-56}{65}
Option B (−5665\frac{{-56}}{{65}}) is correct because it is obtained by correctly applying the sine addition formula and considering the quadrant of ϕ\phi.
156 Medium
156 of 157
Analyzing +4 | -1
The value of cos⁡2A  (3−4  cos⁡2A)2+sin⁡2A  (3−4  sin⁡2 A)2{\cos ^2}A\;{\left( {3 - 4\,\,{{\cos }^2}A} \right)^2} + {\sin ^2}A\;{\left( {3 - 4\,\,{{\sin }^2}\,A} \right)^2} is equal to
View answer and explanation
Correct option: C
1\mathrm{1}
Option C (1) is correct because the expression simplifies to 1 after applying trigonometric identities and algebraic manipulation.
157 Medium
157 of 157
Application +4 | -1
If   tan⁡  θ,  2tan⁡θ+2,   3tan⁡θ+3  \;\tan \,\,\mathrm{\theta },\,\,2\tan \mathrm{\theta } + 2,\;\,3\tan \mathrm{\theta } + 3\; are in GP, then the value of 7−5 cot⁡θ9−4 sec⁡2θ−1\frac{{7 - 5\,\cot \mathrm{\theta }}}{{9 - 4\,\sqrt {{{\sec }^2}\mathrm{\theta } - 1} }} is
View answer and explanation
Correct option: C
33100\frac{{33}}{{100}}
Option C (33/100) is the correct answer because it is obtained by solving the given GP condition for tan θ and substituting it into the expression.
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