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JEE • MATHEMATICS • TRIGONOMETRY RATIOS

Trigonometry ratios practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 391-394 of 394 questions
391 Easy
391 of 394
Application +4 | -1
If sec θ  + tan θ=1\mathrm{sec}\,\mathrm{\theta \; + }\,\mathrm{tan}\,\mathrm{\theta } = 1, then root of the equation (a−2b+c)x2  +  (b−2c+a)x  +  (c−2a+b)=0\left( {a - 2b + c} \right){x^2}\,\, + \,\,\left( {b - 2c + a} \right)x\,\, + \,\,\left( {c - 2a + b} \right) = 0 is
View answer and explanation
Correct option: A
sec⁡  θ\sec \,\,\mathrm{\theta }
Option A (sec⁡θ\sec \theta) is correct because one root of the quadratic equation is 1, and given the condition sec⁡θ+tan⁡θ=1\sec \theta + \tan \theta = 1, it follows that sec⁡θ=1\sec \theta = 1.
392 Medium
392 of 394
Analyzing +4 | -1
The value of cos⁡2A  (3−4  cos⁡2A)2+sin⁡2A  (3−4  sin⁡2 A)2{\cos ^2}A\;{\left( {3 - 4\,\,{{\cos }^2}A} \right)^2} + {\sin ^2}A\;{\left( {3 - 4\,\,{{\sin }^2}\,A} \right)^2} is equal to
View answer and explanation
Correct option: C
1\mathrm{1}
Option C (1) is correct because the expression simplifies to 1 after applying trigonometric identities and algebraic manipulation.
393 Easy
393 of 394
Understanding +4 | -1
If α,β,γ\alpha, \beta, \gamma are the angles which a half ray makes with the positive directions of the axes, then sin⁡2α+sin⁡2β+sin⁡2γ\sin ^2 \alpha+\sin ^2 \beta+\sin ^2 \gamma is equal to
View answer and explanation
Correct option: B
2
Option B (2) is correct because sin⁡2α+sin⁡2β+sin⁡2γ=2\sin^2 \alpha + \sin^2 \beta + \sin^2 \gamma = 2 when α,β,γ\alpha, \beta, \gamma are the angles a half ray makes with the positive directions of the axes.
394 Medium
394 of 394
Application +4 | -1
If   tan⁡  θ,  2tan⁡θ+2,   3tan⁡θ+3  \;\tan \,\,\mathrm{\theta },\,\,2\tan \mathrm{\theta } + 2,\;\,3\tan \mathrm{\theta } + 3\; are in GP, then the value of 7−5 cot⁡θ9−4 sec⁡2θ−1\frac{{7 - 5\,\cot \mathrm{\theta }}}{{9 - 4\,\sqrt {{{\sec }^2}\mathrm{\theta } - 1} }} is
View answer and explanation
Correct option: C
33100\frac{{33}}{{100}}
Option C (33/100) is the correct answer because it is obtained by solving the given GP condition for tan θ and substituting it into the expression.
Revision notes and key takeaways

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