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JEE • MATHEMATICS • TRANSFORMATION OF AXES

Transformation of axes practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Medium
1 of 10
Application +4 | -1
The pedal points of a perpendicular drawn from origin on the line 3x+4y−5=03 x+4 y-5=0, is
View answer and explanation
Correct option: B
(35,45)\left(\frac{3}{5}, \frac{4}{5}\right)
Option B ((3/5), (4/5)) is correct because it represents the coordinates of the foot of the perpendicular from the origin to the line.
2 Medium
2 of 10
Application +4 | -1
If the origin is shifted to the point (ab/(a−b),0)(a b /(a-b), 0) without rotation, then the equation (a−b)(x2+y2)−2abx−0(a-b)\left(x^2+y^2\right)-2 a b x-0 becomes -
View answer and explanation
Correct option: D
(a−b)2(x2+y2)−a2b2(a-b)^2\left(x^2+y^2\right)-a^2 b^2
Option D ((a−b)2(x2+y2)−a2b2(a-b)^2(x^2+y^2)-a^2 b^2) is correct because shifting the origin and substituting into the equation leads to this result after simplification.
3 Medium
3 of 10
Application +4 | -1
The point (4,1)(4,1) undergoes the following two successive transformation

(i) Reflection about the line y=xy=x

(ii) Translation through a distance 2 units along the positive xx-axis

Then the final coordinates of the point are
View answer and explanation
Correct option: B
(3,4)(3,4)
Option B ((3,4)) is correct because after reflection about y=x, (4,1) becomes (1,4), and then translation by 2 units along the x-axis results in (3,4).
4 Medium
4 of 10
Understanding +4 | -1
If by rotating the coordinate axes without translating the origin, the expression a1x2+2h1xy+b1y2a_1 x^2+2 h_1 x y+b_1 y^2 becomes a2X2+2h2XY+b2Y2a_2 X^2+2 h_2 X Y+b_2 Y^2, then
View answer and explanation
Correct option: B
a1+b1=a2+b2a_1+b_1=a_2+b_2
Option B is correct because a1+b1a_1 + b_1 is invariant under rotation of axes.
5 Medium
5 of 10
Application +4 | -1
If the coordinates of two points AA and BB are (3,4)(3,4) and (5,−2)(5,-2) respectively. Then, the coordinates of any point PP, if PA=PBP A=P B and area of △PAB=10\triangle P A B=10, are
View answer and explanation
Correct option: B
(7,2),(1,0)(7,2),(1,0)
Option B ((7,2),(1,0)) is correct because these points satisfy both the condition PA=PB and the area condition of the triangle PAB.
6 Medium
6 of 10
Analyzing +4 | -1
If by rotating the coordinate axes without translating the origin, the expression a1x2+2h1xy+b1y2a_1 x^2+2 h_1 x y+b_1 y^2 becomes a2X2+2h2XY+b2Y2a_2 X^2+2 h_2 X Y+b_2 Y^2, then
View answer and explanation
Correct option: A
(a1−b1)2+4h12=(a2−b2)2+4h22\left(a_1-b_1\right)^2+4 h_1^2=\left(a_2-b_2\right)^2+4 h_2^2
Option A ((a1−b1)2+4h12=(a2−b2)2+4h22)\left((a_1 - b_1)^2 + 4h_1^2 = (a_2 - b_2)^2 + 4h_2^2\right) is correct because it represents an invariant under rotation of coordinate axes.
7 Medium
7 of 10
Application +4 | -1
ABCA B C is a variable triangle with the fixed vertex C(1,2)C(1,2) and A,BA, B having the coordinates (cos⁡t,sin⁡t),(sin⁡t,−cos⁡t)(\cos t, \sin t),(\sin t,-\cos t) respectively, where tt is a parameter. The locus of centroid of the △ABC\triangle A B C is
View answer and explanation
Correct option: B
3(x2+y2)−2x−4y+1=03\left(x^2+y^2\right)-2 x-4 y+1=0
Option B (3(x2+y2)−2x−4y+1=03(x^2+y^2)-2x-4y+1=0) is correct because it represents the locus of the centroid of the triangle ABC, derived by eliminating the parameter t.
8 Medium
8 of 10
Application +4 | -1
The transformed equation of x2+6xy+8y2=10{x^2} + 6xy + 8{y^2} = 10 when the axes are rotated through an angle π4\frac{\pi }{4} is
View answer and explanation
Correct option: C
15x2+14xy+3y2=2015{x^2} + 14xy + 3{y^2} = 20
Option C (15x2+14xy+3y2=2015{x^2} + 14xy + 3{y^2} = 20) is correct because after rotating the axes by π4\frac{\pi}{4}, the transformed equation is 15x2+14xy+3y2=2015{x^2} + 14xy + 3{y^2} = 20.
9 Medium
9 of 10
Analyzing +4 | -1
If x=Xcos⁡θ−Ysin⁡θ,y=Xsin⁡θ+Ycos⁡θx = X\cos \theta - Y\sin \theta ,y = X\sin \theta + Y\cos \theta and x2+4xy+y2=AX2+BY2,0≤θ≤π2,{x^2} + 4xy + {y^2} = A{X^2} + B{Y^2},0 \le \theta \le \frac{\pi }{2}, then
View answer and explanation
Correct option: B
θ=π4\theta = \frac{\pi }{4}
Option B (θ=π4\theta = \frac{\pi }{4}) is correct because substituting the given transformations into the equation and comparing coefficients leads to the condition that θ=π4\theta = \frac{\pi}{4}.
10 Medium
10 of 10
Application +4 | -1
If the equation 2x2+y2−4x−4y=02{x^2} + {y^2} - 4x - 4y = 0 is transformed to the equation 2X2+Y2−8X−8Y+18=02{X^2} + {Y^2} - 8X - 8Y + 18 = 0 by shifting the origin at a point PP without rotating the coordinates axes, then the coordinates of PP are
View answer and explanation
Correct option: D
(−1,−2)\left( { - 1, - 2} \right)
Option D ((-1,-2)) is correct because it represents the shift in origin that transforms the first equation into the second.
Revision notes and key takeaways

Review TRANSFORMATION OF AXES in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 10 single-correct-answer MCQs on TRANSFORMATION OF AXES.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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