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JEE • MATHEMATICS • STRAIGHT LINES

Straight lines practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 408 questions
61 Easy
61 of 408
Application +4 | -1
If the lines x=a+m,y=−2x=a+m, y=-2 and y=mxy=m x are concurrent, the least value of ∣a∣|a| is :
View answer and explanation
Correct option: C
222 \sqrt{2}
Option C (222 \sqrt{2}) is correct because the condition for concurrency leads to a quadratic equation in 'm' which must have real roots, thus giving the least value of |a| as 222 \sqrt{2}.
62 Easy
62 of 408
Application +4 | -1
The line passing through (1,1)(1,1) and parallel to the line 2x−3y+5=02 x-3 y+5=0 is
View answer and explanation
Correct option: B
2x−3y+1=02 x-3 y+1=0
Option B (2x−3y+1=02 x-3 y+1=0) is correct because it has the same slope as the given line and passes through the point (1,1).
63 Easy
63 of 408
Application +4 | -1
The distance of the line 2x−3y=42x - 3y = 4 from the point (1, 1) measured parallel to the line x+y=1x + y = 1, is
View answer and explanation
Correct option: A
2\sqrt 2
Option A (2\sqrt 2) is correct because it represents the distance calculated by finding the intersection point of the two lines and using the given angle.
64 Easy
64 of 408
Application +4 | -1
The set of all values of k\mathrm{k} for which lines kx+2y+2=0,2x+ky+3=0,3x+3y+k=0k x+2 y+2=0,2 x+k y+3=0,3 x+3 y+k=0 are concurrent is
View answer and explanation
Correct option: B
{2,3,−5}\{2,3,-5\}
Option B ({2,3,-5}) is correct because these are the values of k for which the determinant of the coefficient matrix is zero, indicating concurrency, but k=2 makes the first two lines parallel.
65 Easy
65 of 408
Application +4 | -1
The angle between the lines whose joint equation is 2x2−3xy−6y2=02 x^2-3 x y-6 y^2=0, is
View answer and explanation
Correct option: B
θ=tan⁡−1(−574)\theta=\tan ^{-1}\left(-\frac{\sqrt{57}}{4}\right)
Option B (θ=tan⁡−1(−574)\theta=\tan ^{-1}\left(-\frac{\sqrt{57}}{4}\right)) is correct because it is the angle calculated using the formula for the angle between two lines represented by a homogeneous equation.
66 Easy
66 of 408
Application +4 | -1
The equation of the bisector of that angle between the lines x+y=3x+y=3 and 2x−y=22 x-y=2 which contains the point (1,1)(1,1) is
View answer and explanation
Correct option: A
(5−22)x+(5+2)y−35+22=0(\sqrt{5}-2 \sqrt{2}) x+(\sqrt{5}+\sqrt{2}) y-3 \sqrt{5}+2 \sqrt{2}=0
Option A (5−22)x+(5+2)y−35+22=0\sqrt{5}-2 \sqrt{2}) x+(\sqrt{5}+\sqrt{2}) y-3 \sqrt{5}+2 \sqrt{2}=0) is correct because it represents the angle bisector that contains the point (1,1) after proper normalization.
67 Easy
67 of 408
Analyzing +4 | -1
Equation of the straight line which belongs to the system of straight lines a(2x+y−3)+b(3x+2y−5)=0a(2 x+y-3)+b(3 x+2 y-5)=0 and is farthest from the point (4,−3)(4,-3) is
View answer and explanation
Correct option: B
3x−4y+1=03 x-4 y+1=0
Option B (3x−4y+1=03x - 4y + 1 = 0) is correct because it represents the line in the system farthest from the point (4, -3), which is perpendicular to the line joining (1,1) and (4,-3).
68 Easy
68 of 408
Application +4 | -1
The angle between the lines represented by the equation x2−2pxy+y2=0x^2-2 p x y+y^2=0, is
View answer and explanation
Correct option: A
sec⁡−1p\sec ^{-1} p
Option A (sec⁡−1p\sec ^{-1} p) is correct because it is calculated using the formula for the angle between the lines and trigonometric identities.
69 Easy
69 of 408
Application +4 | -1
The line parallel to the XX-axis and passing through the intersection of the lines ax+2by+3b=0a x+2 b y+3 b=0 and bx−2ay−3a=0,b x-2 a y-3 a=0, where (a,b)≠(0,0)(a, b) \neq(0,0) is
View answer and explanation
Correct option: A
Below the XX-axis at a distance of 32\frac{3}{2} from it
Option A Below the XX-axis at a distance of 32\frac{3}{2} from it is correct because the line parallel to the X-axis is found to be y = -3/2.
70 Easy
70 of 408
Analyzing +4 | -1
The points (0,83),(1,3)\left(0, \frac{8}{3}\right),(1,3) and (82,30)(82,30) :
View answer and explanation
Correct option: C
lie on a straight line.
Option C (lie on a straight line) is correct because the slope between any two pairs of points is the same, indicating collinearity.
71 Easy
71 of 408
Application +4 | -1
The line joining the points (2,x)(2, x) and (3,1)(3,1) is perpendicular to the line joining the points (x,4)(x, 4) and (7,5)(7,5). The value of xx is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the product of the slopes of two perpendicular lines is -1, which leads to the equation (1-x)/(3-2) * (5-4)/(7-x) = -1, solving for x gives x=4.
72 Easy
72 of 408
Analyzing +4 | -1
Let equation of the side BCBC of a Δ  ABC\Delta \;ABC be x+y+2=0.x + y + 2 = 0. If coordinates of its orthocentre and circumcentre are (1, 1) and (2, 0) respectively, then radius of the circumcircle of Δ  ABC\Delta \;ABC is
View answer and explanation
Correct option: B
10\sqrt {10}
Option B (10\sqrt {10}) is correct because the radius of the circumcircle is calculated using the distance between the circumcenter and a point on the circumcircle, which is the reflection of the orthocenter in side BC.
73 Easy
73 of 408
Application +4 | -1
The orthocentre of the triangle formed by (0,0),(8,0),(4,6)\left( {0,0} \right),\left( {8,0} \right),\left( {4,6} \right) is
View answer and explanation
Correct option: A
(4,  8/3)\left( {4,\;8/3} \right)
Option A ((4,  8/3)\left( {4,\;8/3} \right)) is correct because it represents the intersection of the altitudes of the triangle.
74 Easy
74 of 408
Application +4 | -1
The acute angle between the lines joining the origin to the points of intersection of the line 3x+y=2\sqrt 3 x + y = 2 and the circle x2+y2=4{x^2} + {y^2} = 4 is
View answer and explanation
Correct option: B
π/3\mathrm{\pi }/3
Option B (π/3\mathrm{\pi }/3) is correct because the acute angle is calculated by finding the intersection points and their respective angles with the origin.
75 Easy
75 of 408
Application +4 | -1
The range of values of θ\theta in the interval (0,π)(0, \pi) such that the points (3,2)(3,2) and (cos⁡θ,sin⁡θ)(\cos \theta, \sin \theta) lie on the same side of the line x+y−1=0x+y-1=0, is
View answer and explanation
Correct option: A
(0,π2)\left(0, \frac{\pi}{2}\right)
Option A (0,π2)\left(0, \frac{\pi}{2}\right) is correct because the values of θ\theta in this interval ensure that both points lie on the same side of the line x+y-1=0.
76 Easy
76 of 408
Analyzing +4 | -1
Equation of straight line belonging to families of straight lines (x+2y)+λ(3x+2y+1)=0\left( {x + 2y} \right) + \lambda \left( {3x + 2y + 1} \right) = 0 and (x−2y)+μ(x−y+1)=0\left( {x - 2y} \right) + \mathrm{\mu }\left( {x - y + 1} \right) = 0 is
View answer and explanation
Correct option: B
5x−6y+4=05x - 6y + 4 = 0
Option B (5x−6y+4=05x - 6y + 4 = 0) is correct because it represents the equation of the straight line passing through the intersection points of the two families of lines.
77 Easy
77 of 408
Application +4 | -1
If x1,    x2,    x3{x_1},\;\;{x_2},\;\;{x_3} and y1,    y2,    y3{y_1},\;\;{y_2},\;\;{y_3} are both in GP with the same common ratio, then the points (x1,  y1),  (x2,  y2),  (x3,  y3)\left( {{x_1},\;{y_1}} \right),\;\left( {{x_2},\;{y_2}} \right),\;\left( {{x_3},\;{y_3}} \right)
View answer and explanation
Correct option: A
Lie on a straight line
Option A (Lie on a straight line) is correct because the area of the triangle formed by the points is zero, indicating collinearity.
78 Easy
78 of 408
Application +4 | -1
The equation of the line equidistant from the lines 2x+3y+5=02x + 3y + 5 = 0 and 4x+6y=114x + 6y = 11 is
View answer and explanation
Correct option: C
8x+12y−1=08x + 12y - 1 = 0
The correct answer is C (8x + 12y - 1 = 0) because it represents a line equidistant from the two given parallel lines, found by averaging their constant terms.
79 Easy
79 of 408
Application +4 | -1
The point (2,1)(2,1) is translated parallel to the line L:x−y=4L: x-y=4 by 232 \sqrt{3} units. If the new point QQ lies in the third quadrant, then the equation of the line passing through QQ and perpendicular to LL, is
View answer and explanation
Correct option: D
x+y=3−26x+y=3-2 \sqrt{6}
Option D (x+y=3−26x+y=3-2 \sqrt{6}) is correct because it is the equation of the line passing through the translated point Q in the third quadrant and perpendicular to the given line L.
80 Easy
80 of 408
Application +4 | -1
A(3,−1),B(1,3),C(2,4)A(3,-1), B(1,3), C(2,4) are vertices of △ABC\triangle A B C. If DD is the centroid of △ABC\triangle A B C and PP is the point of intersection of lines x+3y−1=0x+3 y-1=0 and 3x−y+1=03 x-y+1=0, then which of the following points lies on the line joining DD and PP.
View answer and explanation
Correct option: B
(−9,−6)(-9,-6)
Option B ((-9,-6)) is correct because the point lies on the line formed by the centroid and the intersection point of the given lines.
81 Easy
81 of 408
Application +4 | -1
The vertices of a triangle are (ab,1ab)\left(a b, \frac{1}{a b}\right), (bc,1bc)\left(b c, \frac{1}{b c}\right) and (ca,1ca)\left(c a, \frac{1}{c a}\right) where a,b,ca, b, c are the roots of the equation x3−3x2+6x+1=0x^3-3 x^2+6 x+1=0. The coordinates of its centroid are
View answer and explanation
Correct option: B
(2,−1)(2,-1)
Option B ((2,-1)) is correct because the centroid coordinates are found by averaging the x and y coordinates of the vertices, and using Vieta's formulas.
82 Easy
82 of 408
Application +4 | -1
The line (λ+1)2x+λy−2λ2−2=0(\lambda+1)^2 x+\lambda y-2 \lambda^2-2=0 passes through a point regardless of the value λ\lambda. Which of the following is the line with slope 2 passing through the point?
View answer and explanation
Correct option: A
y=2x−8y=2 x-8
Option A y=2x−8y=2 x-8 is correct because it is the equation of the line with slope 2 that passes through the fixed point of the given family of lines.
83 Easy
83 of 408
Application +4 | -1
Area of square having two sides y=x+1y=x+1 and y=x+2y=x+2 is
View answer and explanation
Correct option: A
12\frac{1}{2}
Option A, 12\frac{{1}}{{2}}, is correct because the area of the square is calculated by finding the distance between the parallel lines and squaring it.
84 Easy
84 of 408
Application +4 | -1
The co-ordinates of the foot of perpendicular from the point (2,3)(2,3) on the line x+y−11=0x+y-11=0 are (x,y)(x, y). Find x+yx+y
View answer and explanation
Correct option: A
11
The correct answer is A (11) because it is the sum of the coordinates of the foot of the perpendicular from the point (2,3) on the line x+y-11=0.
85 Easy
85 of 408
Analyzing +4 | -1
Consider three points P=(−sin⁡(β−α),−cos⁡β)P=(-\sin (\beta-\alpha),-\cos \beta), Q=(cos⁡(β−α),sin⁡β)Q=(\cos (\beta-\alpha), \sin \beta) and R(cos⁡(β−α+θ),sin⁡(β−θ))R(\cos (\beta-\alpha+\theta), \sin (\beta-\theta)), where 0<θ,α,β<π40 < \theta, \alpha, \beta < \frac{\pi}{4}. Then,
View answer and explanation
Correct option: D
P,Q,RP, Q, R are non-collinear
Option D (P,Q,RP, Q, R are non-collinear) is correct because point R can be expressed as a linear combination of the coordinates of P and Q, but it doesn't lie on the line segment PQ.
86 Easy
86 of 408
Understanding +4 | -1
Consider the following statements.

I. Equation of the line passing through (0,0)(0,0) with slope m{m} is y=mx{y}={mx}

II. Equation of the x{x}-axis is x=0{x}=0.
Choose the correct option.
View answer and explanation
Correct option: A
Only I is true
Option A is correct because only statement I is true; statement II incorrectly states the equation of the x-axis.
87 Easy
87 of 408
Analyzing +4 | -1
Given four lines with equations x+2y−3=0,  2x+3y−4=0,  3x+4y−5=0,  x + 2y - 3 = 0,\;2x + 3y - 4 = 0,\;3x + 4y - 5 = 0,\; 4x+5y−6=04x + 5y - 6 = 0 These lines are
View answer and explanation
Correct option: A
Concurrent
Option A (Concurrent) is correct because all four lines intersect at a single point.
88 Easy
88 of 408
Application +4 | -1
A straight line LL through the point (3,−2)(3,-2) is inclined at an angle of 60∘60^{\circ} to the line 3x+y=1\sqrt{3} x+y=1. If L also intersects the xx-axis, then the equation of LL, is
View answer and explanation
Correct option: B
y−3x+2+33=0y-\sqrt{3} x+2+3 \sqrt{3}=0
Option B (y−3x+2+33=0y-\sqrt{3} x+2+3 \sqrt{3}=0) is correct because it represents a line passing through (3, -2) and inclined at 60 degrees to the given line, and it also intersects the x-axis.
89 Easy
89 of 408
Understanding +4 | -1
If u=a1x+b1y+c1=0,v=a2x+b2y+c2=0u=a_1 x+b_1 y+c_1=0, v=a_2 x+b_2 y+c_2=0 and a1a2=b1b2≠c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2} \neq \frac{c_1}{c_2}, then u+kv=0u+k v=0 represents
View answer and explanation
Correct option: B
a family of parallel line
Option B (a family of parallel line) is correct because the condition a1a2=b1b2≠c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2} \neq \frac{c_1}{c_2} indicates that the lines are parallel, and u+kv=0u+kv=0 represents a family of lines parallel to them.
90 Easy
90 of 408
Application +4 | -1
Assertion: The distance between the parallel lines
3x−4y+9=0 and 6x−8y−15=0 is 33103 x-4 y+9=0 \text { and } 6 x-8 y-15=0 \text { is } \frac{33}{10}

Reason: Distance between the parallel lines Ax+By+C1=0{Ax}+{By}+{C}_1=0 and Ax+By+C2=0{Ax}+{By}+{C}_2=0, is given by d=∣C1−C2∣A2+B2{d}=\frac{\left|{C}_1-{C}_2\right|}{\sqrt{{A}^2+{B}^2}}
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct
explanation for assertion
Option A is correct because the assertion is true, the reason is true, and the reason correctly explains the assertion, as shown by calculating the distance between the parallel lines.
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