Skip to main content
Back to STRAIGHT LINES

Your Progress

0 / 408 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • STRAIGHT LINES

Straight lines practice · Easy

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 331-360 of 408 questions

Preparing practice and saved progress…

331 Easy
331 of 408
Application +4 | -1
If A(2,3)A(2,3) and B(−2,1)B(-2,1) are two vertices of aa triangle and third vertex moves on the line 2x+3y=92 x+3 y=9, then the locus of the centroid of the triangle is
View answer and explanation
Correct option: A
2x+3y=12 x+3 y=1
The correct answer is A (2x+3y=12 x+3 y=1) because it represents the locus of the centroid of the triangle, derived by substituting the coordinates of the third vertex on the given line into the centroid formula.
332 Easy
332 of 408
Application +4 | -1
Reduce the equation 3x+y−8=0\sqrt{3} x+y-8=0 into normal form. The value of pp is
View answer and explanation
Correct option: A
4
Option A (4) is correct because after normalizing the equation, the constant term on the right-hand side represents the perpendicular distance (p) from the origin.
333 Easy
333 of 408
Application +4 | -1
One possible condition for the three points (a,b),(b,a)(a, b),(b, a) and (a2,−b2)\left(a^2,-b^2\right) to be collinear is
View answer and explanation
Correct option: C
a=1+ba=1+b
Option C (a=1+b) is correct because the collinearity condition leads to the factor (a-b)(a+b)(1-a+b) = 0, which gives a = 1+b as a possible condition.
334 Easy
334 of 408
Analyzing +4 | -1
If the lines ax+2  y+1=0,  bx+3  y+1=0,  cx+4  y+1=0ax + 2\;y + 1 = 0,\;bx + 3\;y + 1 = 0,\;cx + 4\;y + 1 = 0 are concurrent, then a,b,c are in
View answer and explanation
Correct option: A
AP
Option A (AP) is correct because the given condition leads to a, b, and c forming an arithmetic progression.
335 Easy
335 of 408
Application +4 | -1
The point on the line 3x+4y=53x + 4y = 5, which is equidistant from (1, 2) and (3, 4) is
View answer and explanation
Correct option: B
(15,  −10)\left( {15,\; - 10} \right)
Option B ((15, -10)) is correct because it satisfies both the equation of the line and the equidistant condition from the two given points.
336 Easy
336 of 408
Analyzing +4 | -1
If the roots of the equation ax2+bx+10=0a x^2+b x+10=0 are not real and distinct where a,b∈Ra, b \in R and α\alpha and β\beta are the values of aa and bb for which 5a+b5 a+b is minimum, then the family of lines α(4x+2y+3)+β(x−y−1)=0\alpha(4 x+2 y+3)+\beta(x-y-1)=0 are concurrent at
View answer and explanation
Correct option: C
(−1/6,−7/6)(-1 / 6,-7 / 6)
Option C ((−1/6,−7/6)(-1 / 6,-7 / 6)) is correct because it is the intersection point of the family of lines derived from the minimum value condition.
337 Easy
337 of 408
Application +4 | -1
If the points (1,1),(−1,−1),(−3,3)\left( {1,1} \right),\left( { - 1, - 1} \right),\left( { - \sqrt 3 ,\sqrt 3 } \right) are the vertices of a triangle, then this triangle is
View answer and explanation
Correct option: C
Equilateral
Option C (Equilateral) is correct because all three sides of the triangle have equal lengths, which is 222\sqrt{2}.
338 Easy
338 of 408
Application +4 | -1
The equation of the image of the lines y=∣x∣y = \left| x \right| in the line mirror x=2x = 2 is
View answer and explanation
Correct option: A
y=∣x−4∣y = \left| {x - 4} \right|
Option A (y=∣x−4∣y = \left| {x - 4} \right|) is correct because the reflection of y=∣x∣y = |x| across the line x=2x = 2 results in a horizontal shift of 4 units.
339 Easy
339 of 408
Application +4 | -1
If the straight line ax+by+c=0ax + by + c = 0 always passes through (1,-2), then a,b,c are
View answer and explanation
Correct option: A
in AP
Option A ((0,am)\left( {0,\frac{a}{m}} \right)) is correct because it represents the coordinates of the foot of the perpendicular from (a,0) on the given line.
340 Easy
340 of 408
Application +4 | -1
If the sum of distances of a point from two perpendicular lines is unity, then its locus is
View answer and explanation
Correct option: D
none of these
Option D (none of these) is correct because the locus is a square, not a circle, ellipse, or hyperbola.
341 Easy
341 of 408
Analyzing +4 | -1
The points P(a,b),Q(c,d),R(a,d)P(a, b), Q(c, d), R(a, d) and S(c,b),S(c, b), where a,b,c,da, b, c, d are distinct real numbers, are
View answer and explanation
Correct option: B
Vertices of a square
The correct answer is Vertices of a rectangle. The slopes of the lines PS and QR are 0, and the slopes of PR and QS are infinite, indicating that the points form a rectangle.
342 Easy
342 of 408
Application +4 | -1
The equation of the line passing through the intersection of x−3  y+3−1=0x - \sqrt 3 \;y + \sqrt 3 - 1 = 0 and x+y−2=0x + y - 2 = 0 and making an angle of 15∘{15^ \circ } with the first line is
View answer and explanation
Correct option: A
x−y=0x - y = 0
Option A (x−y=0x - y = 0) is correct because it represents a line passing through the intersection of the given lines and making a 15-degree angle with the first line.
343 Easy
343 of 408
Application +4 | -1
The distance between the parallel lines 3x−4y+7=03 x-4 y+7=0 and 3x−4y+5=03 {x}-4 {y}+5=0 is ab\frac{{a}}{{b}}. Value of a+b{a}+{b} is
View answer and explanation
Correct option: A
7
Option A (7) is correct because the distance between parallel lines is calculated using the formula, and the sum of the numerator and denominator of the simplified distance is 7.
344 Easy
344 of 408
Application +4 | -1
If P=(1,0),Q=(−1,0)P = \left( {1,0} \right),Q = \left( { - 1,0} \right) and R=(2,0)R = \left( {2,0} \right) are three given points, then the locus of the point S(x,y)S\left( {x,y} \right) satisfying the relation SQ2++SR2=2SP2S{Q^2} + + S{R^2} = 2S{P^2} is
View answer and explanation
Correct option: D
A straight line parallel to yy-axis
Option D (A straight line parallel to yy-axis) is correct because the equation simplifies to a linear equation in x, indicating a vertical line.
345 Easy
345 of 408
Application +4 | -1
The line L given by x5+yb=1\frac{x}{5} + \frac{y}{b} = 1 passes through the point (13, 32). The line K is parallel to L and has the equation xc+y3−1\frac{x}{c} + \frac{y}{3} - 1. Then, the distance between L and K is
View answer and explanation
Correct option: D
2317\frac{{23}}{{\sqrt {17} }}
Option D (2317\frac{{23}}{{\sqrt {17} }}) is correct because it represents the distance between the two parallel lines L and K after finding their equations and applying the distance formula.
346 Easy
346 of 408
Application +4 | -1
If area of triangle with vertices (0, 0), (0, 6) and (α,  β)\left( {\mathrm{\alpha },\mathrm{\;\beta }} \right) is 15 sq unit, then
View answer and explanation
Correct option: D
α=±5,  β  \mathrm{\alpha } = \pm 5,\mathrm{\;\beta \;} can take any real value
Option D (α=±5\alpha = \pm 5, β\beta can take any real value) is correct because the area of the triangle depends only on the x-coordinate of the third vertex, and the y-coordinate can be any real number.
347 Easy
347 of 408
Application +4 | -1
If a straight line L is perpendicular to the line 5x−y=15x - y = 1 such that the area of the Δ\Delta formed by the line L and the coordinate axes is 5, then the equation of the line L is
View answer and explanation
Correct option: D
x+5  y±52=0x + 5\;y \pm 5\sqrt 2 = 0
Option D (x+5  y±52=0x + 5\;y \pm 5\sqrt 2 = 0) is correct because it represents the equation of a line perpendicular to the given line and forms a triangle with the coordinate axes with an area of 5.
348 Easy
348 of 408
Understanding +4 | -1
Consider the following statements.

The three given points A,B,CA, B, C are collinear i.e., lie on the same straight line, if

I. area of △ABC\triangle A B C is zero.

II. slope of AB=A B= Slope of BCB C.

III. any one of the three points lie on the straight line joining the other two points.

Choose the correct option.
View answer and explanation
Correct option: D
All are true
Option D is correct because all three statements are valid conditions for three points to be collinear.
349 Easy
349 of 408
Application +4 | -1
The image of a point A(3,8)A(3,8) in the line x+3y−7=0x+3 y-7=0, is (a,b)(a, b). Find a−ba-b.
View answer and explanation
Correct option: A
3
Option A (3) is correct because the image of the point A(3,8) in the given line is (-1,-4), and a-b = -1 - (-4) = 3.
350 Easy
350 of 408
Application +4 | -1
The area of triangle formed by the points (a,  b+c),  (b,  c+a),  (c,  a+b)\left( {a,\;b + c} \right),\;\left( {b,\;c + a} \right),\;\left( {c,\;a + b} \right) is equal to
View answer and explanation
Correct option: D
0
Option B (11.11) is correct because the weight percentage of deuterium in heavy water (D2O) is calculated as (2*2 / 20) * 100 = 20%.
351 Easy
351 of 408
Application +4 | -1
Equation of the straight line making equal intercepts on the axes and passing through the point (2, 4), is
View answer and explanation
Correct option: C
x+y-6=0
Option C (x+y-6=0) is correct because it represents a line with equal intercepts that passes through the point (2, 4).
352 Easy
352 of 408
Application +4 | -1
Equation of the straight line cutting off an intercept 2 from the negative direction of the axis of y and inclined at 30∘{30^ \circ } to the positive direction of x-axis, is
View answer and explanation
Correct option: D
3y−x+23=0\sqrt 3 y - x + 2\sqrt 3 = 0
Option D (3y−x+23=0\sqrt 3 y - x + 2\sqrt 3 = 0) is correct because it represents the equation of a line with a slope of 13\frac{1}{{\sqrt 3 }} and a y-intercept of -2.
353 Easy
353 of 408
Remembering +4 | -1
Consider the following statements.

I. The equation of a straight line passing through the point (x1,y1)\left(x_1, y_1\right) and having slope m{m} is given by y−y1=m(x−x1)y-y_1=m\left(x-x_1\right)

II. Equation of the yy-axis is x=0x=0.

Choose the correct option.
View answer and explanation
Correct option: C
Both are true
Option C (Both are true) is correct because the point-slope form of a line and the equation of the y-axis are correctly stated.
354 Easy
354 of 408
Application +4 | -1
A(−5,0)A\left( { - 5,0} \right) and B(3,0)B\left( {3,0} \right) are two of the vertices of a triangle ABC. Its area is 20 square cms. The vertex C lies on the line x−y=2.x - y = 2.. The coordinates of C are
View answer and explanation
Correct option: D
(−3,−5)\left( { - 3, - 5} \right) or (7,5)\left( {7,5} \right)
Option D ((−3,−5)\left( { - 3, - 5} \right) or (7,5)\left( {7,5} \right)) is correct because these coordinates satisfy both the area condition and the line equation.
355 Easy
355 of 408
Application +4 | -1
A line passes through the point of intersection of the lines 3x+y+1=03x + y + 1 = 0 and 2x−y+3=02x - y + 3 = 0 and makes equal intercepts with axes. Then, equation of the line is
View answer and explanation
Correct option: A
5x+5y−3=05x + 5y - 3 = 0
Option D (5x+5y+3=05x + 5y + 3 = 0) is correct because it passes through the intersection point and has equal intercepts.
356 Easy
356 of 408
Application +4 | -1
The point (4,1)(4,1) undergoes the following two successive transformation
(i) Reflection about the line y=xy=x
(ii) Translation through a distance 2 units along the positive xx-axis
Then the final coordinates of the point are (x,y)(x, y). Find x+yx+y.
View answer and explanation
Correct option: A
7
The correct answer is A (7) because it is the sum of the final coordinates after performing the given transformations.
357 Easy
357 of 408
Analyzing +4 | -1
If the lines x+ay+a=0,bx+y+b=0x+a y+a=0, b x+y+b=0 and cx+cy+1=0 (a,b,cc x+c y+1=0\,(a, b, c being distinct ≠1)\neq 1) are concurrent, then the value of aa−1+bb−1+cc−1,\frac{a}{a-1}+\frac{b}{b-1}+\frac{c}{c-1}, is
View answer and explanation
Correct option: C
1
Option C (1) is correct because the concurrency condition leads to a relationship between a, b, and c, which simplifies the given expression to 1.
358 Easy
358 of 408
Application +4 | -1
The area of the triangle formed by the points (2, 2), (5, 5), (6, 7) is equal to (in square unit)
View answer and explanation
Correct option: D
32\frac{3}{2}
Option D (3/2) is correct because using the determinant formula for the area of a triangle with given vertices yields 3/2.
359 Easy
359 of 408
Application +4 | -1
The equation of one side of a rectangle is 3x−4y−10=03x - 4y - 10 = 0 and the coordinates of two its vertices are (-2,1) and (2,4). Then, the area of the rectangle is
View answer and explanation
Correct option: A
20 sq. units
Option B ((2, 2)) is correct because it is the point that satisfies the condition where the sum of the intercepts is equal to half of the product of the intercepts.
360 Easy
360 of 408
Application +4 | -1
The values of kk for which the line (k−3)x−(4−k2)y+k2−7k+6=0(k-3) x-\left(4-k^2\right) y+k^2-7 k+6=0 is parallel to the xx-axis, is
View answer and explanation
Correct option: A
3
Option A (3) is correct because a line parallel to the x-axis has the form y = constant, meaning the coefficient of x must be zero.
Revision notes and key takeaways

Review STRAIGHT LINES in your textbook or class notes, then use this set to check your understanding.

Showing 331-360 of 408 questions

Your practice

0 / 408 answered · 408 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.