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JEE • MATHEMATICS • STRAIGHT LINES

Straight lines practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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121 Easy
121 of 555
Application +4 | -1
Area of square having two sides y=x+1y=x+1 and y=x+2y=x+2 is
View answer and explanation
Correct option: A
12\frac{1}{2}
Option A, 12\frac{{1}}{{2}}, is correct because the area of the square is calculated by finding the distance between the parallel lines and squaring it.
122 Easy
122 of 555
Application +4 | -1
The co-ordinates of the foot of perpendicular from the point (2,3)(2,3) on the line x+y−11=0x+y-11=0 are (x,y)(x, y). Find x+yx+y
View answer and explanation
Correct option: A
11
The correct answer is A (11) because it is the sum of the coordinates of the foot of the perpendicular from the point (2,3) on the line x+y-11=0.
123 Easy
123 of 555
Analyzing +4 | -1
Consider three points P=(−sin⁡(β−α),−cos⁡β)P=(-\sin (\beta-\alpha),-\cos \beta), Q=(cos⁡(β−α),sin⁡β)Q=(\cos (\beta-\alpha), \sin \beta) and R(cos⁡(β−α+θ),sin⁡(β−θ))R(\cos (\beta-\alpha+\theta), \sin (\beta-\theta)), where 0<θ,α,β<π40 < \theta, \alpha, \beta < \frac{\pi}{4}. Then,
View answer and explanation
Correct option: D
P,Q,RP, Q, R are non-collinear
Option D (P,Q,RP, Q, R are non-collinear) is correct because point R can be expressed as a linear combination of the coordinates of P and Q, but it doesn't lie on the line segment PQ.
124 Easy
124 of 555
Understanding +4 | -1
Consider the following statements.

I. Equation of the line passing through (0,0)(0,0) with slope m{m} is y=mx{y}={mx}

II. Equation of the x{x}-axis is x=0{x}=0.
Choose the correct option.
View answer and explanation
Correct option: A
Only I is true
Option A is correct because only statement I is true; statement II incorrectly states the equation of the x-axis.
125 Easy
125 of 555
Analyzing +4 | -1
Given four lines with equations x+2y−3=0,  2x+3y−4=0,  3x+4y−5=0,  x + 2y - 3 = 0,\;2x + 3y - 4 = 0,\;3x + 4y - 5 = 0,\; 4x+5y−6=04x + 5y - 6 = 0 These lines are
View answer and explanation
Correct option: A
Concurrent
Option A (Concurrent) is correct because all four lines intersect at a single point.
126 Easy
126 of 555
Application +4 | -1
A straight line LL through the point (3,−2)(3,-2) is inclined at an angle of 60∘60^{\circ} to the line 3x+y=1\sqrt{3} x+y=1. If L also intersects the xx-axis, then the equation of LL, is
View answer and explanation
Correct option: B
y−3x+2+33=0y-\sqrt{3} x+2+3 \sqrt{3}=0
Option B (y−3x+2+33=0y-\sqrt{3} x+2+3 \sqrt{3}=0) is correct because it represents a line passing through (3, -2) and inclined at 60 degrees to the given line, and it also intersects the x-axis.
127 Easy
127 of 555
Understanding +4 | -1
If u=a1x+b1y+c1=0,v=a2x+b2y+c2=0u=a_1 x+b_1 y+c_1=0, v=a_2 x+b_2 y+c_2=0 and a1a2=b1b2≠c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2} \neq \frac{c_1}{c_2}, then u+kv=0u+k v=0 represents
View answer and explanation
Correct option: B
a family of parallel line
Option B (a family of parallel line) is correct because the condition a1a2=b1b2≠c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2} \neq \frac{c_1}{c_2} indicates that the lines are parallel, and u+kv=0u+kv=0 represents a family of lines parallel to them.
128 Easy
128 of 555
Application +4 | -1
Assertion: The distance between the parallel lines
3x−4y+9=0 and 6x−8y−15=0 is 33103 x-4 y+9=0 \text { and } 6 x-8 y-15=0 \text { is } \frac{33}{10}

Reason: Distance between the parallel lines Ax+By+C1=0{Ax}+{By}+{C}_1=0 and Ax+By+C2=0{Ax}+{By}+{C}_2=0, is given by d=∣C1−C2∣A2+B2{d}=\frac{\left|{C}_1-{C}_2\right|}{\sqrt{{A}^2+{B}^2}}
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct
explanation for assertion
Option A is correct because the assertion is true, the reason is true, and the reason correctly explains the assertion, as shown by calculating the distance between the parallel lines.
129 Medium
129 of 555
Application +4 | -1
The equation of the bisector of the obtuse angle between the lines 3x−4y+7=03x - 4y + 7 = 0 and −12x−5y+2=0,- 12x - 5y + 2 = 0, is
View answer and explanation
Correct option: A
21x+77y−101=021x + 77y - 101 = 0
The correct answer is A (21x + 77y - 101 = 0) because it represents the bisector of the obtuse angle between the two lines, determined by checking the sign of a1a2 + b1b2.
130 Medium
130 of 555
Application +4 | -1
The equation of straight line passing through (−a,0)(-a, 0) and making the triangle with axes of area 'TT' is
View answer and explanation
Correct option: B
2Tx−a2y+2aT=02 T x-a^2 y+2 a T=0
Option B (2Tx−a2y+2aT=02 T x-a^2 y+2 a T=0) is correct because it represents the equation of the line passing through (-a, 0) and forming a triangle of area T with the axes.
131 Easy
131 of 555
Application +4 | -1
The harmonic conjugate of (4,−2)\left( {4, - 2} \right) with respect to (2,−4)\left( {2, - 4} \right) and (7,1)\left( {7,1} \right) is
View answer and explanation
Correct option: A
(−8,−14)\left( { - 8, - 14} \right)
Option A ((−8,−14)\left( { - 8, - 14} \right)) is correct because it represents the harmonic conjugate of the given point with respect to the other two points, calculated using the section formula.
132 Medium
132 of 555
Application +4 | -1
The two points on the line x+y=4x+y=4 that lie at aa unit distance from the line 4x+3y=104 x+3 y=10, are
View answer and explanation
Correct option: B
(3,1),(−7,11)(3,1),(-7,11)
Option B ((3,1),(−7,11)(3,1),(-7,11)) is correct because these points lie on the line x+y=4x+y=4 and are at a unit distance from the line 4x+3y=104x+3y=10.
133 Easy
133 of 555
Understanding +4 | -1
Consider the equation y−y1=m(x−x1)y-y_1=m\left(x-x_1\right). In this equation, if mm and x1x_1 are fixed and different lines are drawn for different values of y1y_1, then
View answer and explanation
Correct option: C
There will be a set of parallel lines
Option C (There will be a set of parallel lines) is correct because the equation represents a family of lines with the same slope 'm' but different y-intercepts.
134 Easy
134 of 555
Remembering +4 | -1
Consider the following statements.

I. The distance between two points (x1,y1)\left(x_1, y_1\right) and (x2,y2)\left(x_2, y_2\right) is given by
(x2−x1)2+(y2−y1)2\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

II. The coordinates of the mid-point of the line segment joining the points (x1,y1)\left(x_1, y_1\right) and (x2,y2)\left(x_2, y_2\right)
is (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Choose the correct option.
View answer and explanation
Correct option: C
Both are true
Option C (Both are true) is correct because both the distance formula and the midpoint formula are stated accurately.
135 Easy
135 of 555
Application +4 | -1
Locus of the centroid of the triangle whose vertices are (acos⁡t,asin⁡t),(bsin⁡t,−bcos⁡t)(a \cos t, a \sin t),(b \sin t,-b \cos t) and (1,0)(1,0), where tt is aa parameter, is
View answer and explanation
Correct option: C
(3x−1)2+(3y)2=a2+b2(3 x-1)^2+(3 y)^2=a^2+b^2
Option C ((3x−1)2+(3y)2=a2+b2(3 x-1)^2+(3 y)^2=a^2+b^2) is correct because it represents the locus of the centroid of the triangle with the given vertices.
136 Easy
136 of 555
Application +4 | -1
The family of lines making an angle 30∘{30^ \circ } with the line 3y=x+1\sqrt 3 y = x + 1 is
View answer and explanation
Correct option: C
y=3x+λy = \sqrt 3 x + \lambda
Option C (y=3x+λy = \sqrt 3 x + \lambda) is correct because it represents a line making a 30-degree angle with the given line.
137 Medium
137 of 555
Application +4 | -1
The locus of a point P which divides the line joining (1,0) and (2cos⁡θ,  2sin⁡θ)\left( {2\cos \theta ,\;2\sin \theta } \right) internally in the ratio 2∶3 for all θ\theta, is a
View answer and explanation
Correct option: B
Circle
Option B (Circle) is correct because the locus of point P, which divides the line segment in a given ratio, forms a circle.
138 Easy
138 of 555
Application +4 | -1
The centroid of a triangle lies at the origin and the coordinates of its two vertices are (−8,0)(-8,0) and (9,11)(9,11), the area of the triangle in sq. units is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated area of the triangle with vertices (-8, 0), (9, 11), and (-1, -11) is 66, which is not among the given options.
139 Medium
139 of 555
Analyzing +4 | -1
If A(sin⁡α,12)A\left(\sin \alpha, \frac{1}{\sqrt{2}}\right) and B(12,cos⁡α),−π≤α≤πB\left(\frac{1}{\sqrt{2}}, \cos \alpha\right),-\pi \leq \alpha \leq \pi, are two points on the same side of the line x−y=0x-y=0, then α\alpha belongs to the interval
View answer and explanation
Correct option: A
(−π4,π4)∪(π4,3π4)\left(-\frac{\pi}{4}, \frac{\pi}{4}\right) \cup\left(\frac{\pi}{4}, \frac{3 \pi}{4}\right)
Option A ((−π4,π4)∪(π4,3π4)\left(-\frac{\pi}{4}, \frac{\pi}{4}\right) \cup\left(\frac{\pi}{4}, \frac{3 \pi}{4}\right)) is correct because it represents the interval where both points A and B lie on the same side of the line x-y=0.
140 Medium
140 of 555
Analyzing +4 | -1
For a>b>c>0,a>b>c>0, the distance between (1,1)(1,1) and the point of intersection of the lines ax+by+c=0a x+b y+c=0 and bx+ay+c=0b x+a y+c=0 is less than 22.2 \sqrt{2}. Then
View answer and explanation
Correct option: A
a+b−c>0a+b-c>0
Option A (a+b−c>0a+b-c>0) is correct because it is derived from the distance formula and the given condition that the distance between (1,1) and the intersection point is less than 222\sqrt{2}.
141 Medium
141 of 555
Analyzing +4 | -1
The equation of the lines through the points (2,3)(2,3) and making an intercept of length 2 units between the lines y+2x=3y+2 x=3 and y+2x=5y+2 x=5, are
View answer and explanation
Correct option: C
x−2=0,3x+4y=18x-2=0,3 x+4 y=18
Option C (x−2=0,3x+4y=18x-2=0,3 x+4 y=18) is correct because these lines satisfy the given conditions of passing through (2,3) and intercepting a length of 2 units between the given lines.
142 Easy
142 of 555
Application +4 | -1
The members of the family of lines (λ+μ)x+(2λ+−μ)y=λ+2  μ,\left( {\lambda + \mu } \right)x + \left( {2\lambda + - \mu } \right)y = \lambda + 2\;\mu , where λ≠0,μ≠0,\lambda \ne 0,\mu \ne 0, pass through the point
View answer and explanation
Correct option: A
(3,−1)\left( {3, - 1} \right)
Option A ((3, -1)) is correct because the family of lines passes through the intersection of the two lines formed by separating the lambda and mu terms.
143 Easy
143 of 555
Application +4 | -1
The lines parallel to the x-axis and passing through the intersection of the lines ax+2by+3b=0ax + 2by + 3b = 0 and bx−2ay−3a=0,bx - 2ay - 3a = 0, where (a,  b)≠(0,0)\left( {a,\;b} \right) \ne \left( {0,0} \right) is
View answer and explanation
Correct option: D
Below the x-axis at a distance of (3/2) from it
Option D (Below the x-axis at a distance of (3/2) from it) is correct because the equation of the line parallel to the x-axis is y = -3/2.
144 Medium
144 of 555
Application +4 | -1
Joint equation of pair of lines through (3,  −2)\left( {3,\; - 2} \right) and parallel to x2−4xy+3y2=0{x^2} - 4xy + 3{y^2} = 0 is
View answer and explanation
Correct option: A
x2+3y2−4xy−14x+24y+45=0{x^2} + 3{y^2} - 4xy - 14x + 24y + 45 = 0
Option A (x2+3y2−4xy−14x+24y+45=0{x^2} + 3{y^2} - 4xy - 14x + 24y + 45 = 0) is correct because it represents the joint equation of the pair of lines passing through (3, -2) and parallel to the given equation.
145 Easy
145 of 555
Application +4 | -1
If the system of following equations in x & yx \,\&\, y

2x+3y+4=0;3x+5y+6=0;2x2+6xy+5y2+8x+12y+1=t\begin{aligned} & 2 x+3 y+4=0 ; 3 x+5 y+6=0 ; \\ & 2 x^2+6 x y+5 y^2+8 x+12 y+1=t \end{aligned}

consists of a solution. Then find the numeric value of t4t^4.
View answer and explanation
Correct option: A
2401
The correct answer is A (2401) because it is the value of t4t^4 after solving the system of equations and finding t.
146 Medium
146 of 555
Application +4 | -1
The equation of the lines through the point (3, 2) which makes an angle of 45∘45^\circ with the line x−2y=3x - 2y = 3 , are
View answer and explanation
Correct option: A
3x−y=73x - y = 7 and x+3y=9x + 3y = 9
The correct answer is A (3x - y = 7 and x + 3y = 9) because the equations of lines passing through (3, 2) and making an angle of 45 degrees with the line x - 2y = 3 are found using the angle between two lines formula.
147 Easy
147 of 555
Application +4 | -1
If the line y=mx meets the lines x+2  y−1=0x + 2\;y - 1 = 0 and 2  x−y+3=02\;x - y + 3 = 0 at the same point, then m is equal to
View answer and explanation
Correct option: B
-1
The correct answer is B (-1) because this value of m makes the line y=mx pass through the intersection point of the other two lines.
148 Easy
148 of 555
Analyzing +4 | -1
If the straight lines, ax+amy+1=0,a x+a m y+1=0, bx+(m+1)by+1=0b x+(m+1) b y+1=0 and cx+(m+2)cy+1=0,m≠0c x+(m+2) c y+1=0, m \neq 0 are concurrent, then a,b,ca, b, c are in
View answer and explanation
Correct option: D
HP for all mm
Option D (HP for all mm) is correct because the condition for concurrency leads to a relationship between a, b, and c that satisfies the definition of a Harmonic Progression.
149 Medium
149 of 555
Application +4 | -1
If Y-intercept of a line is 8 more than its X-intercept and it passes through (5,−3)(5,-3), then the equation of the line is
View answer and explanation
Correct option: C
x10+y2=−1\frac{x}{10}+\frac{y}{2}=-1 and x4+y12=1\frac{x}{4}+\frac{y}{12}=1
Option C (x10+y2=−1\frac{{x}}{{10}}+\frac{{y}}{{2}}=-1 and x4+y12=1\frac{{x}}{{4}}+\frac{{y}}{{12}}=1) is correct because these are the equations of the lines that satisfy the given conditions.
150 Easy
150 of 555
Analyzing +4 | -1
Consider the straight lines
L1:x−y=1L2:x+y=1L3:2x+2y=5L4:2x−2y=7\begin{array}{l} L_{1}: x-y=1 \\ L_{2}: x+y=1 \\ L_{3}: 2 x+2 y=5 \\ L_{4}: 2 x-2 y=7 \end{array}

The correct statement is
View answer and explanation
Correct option: D
L1⊥L2,L1⊥L3,L2L_{1} \perp L_{2}, L_{1} \perp L_{3}, L_{2} intersect L4L_{4}.
Option D (L1⊥L2,L1⊥L3,L2L_{1} \perp L_{2}, L_{1} \perp L_{3}, L_{2} intersect L4L_{4}) is correct because it accurately describes the relationships between the given lines based on their slopes and intersection points.
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