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JEE • MATHEMATICS • STRAIGHT LINES

Straight lines practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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331 Easy
331 of 555
Analyzing +4 | -1
For a>0,b>0,c>0a>0, b>0, c>0, the distance between (1,1)(1,1) and the point of intersection of the lines ax+by+c=0a x+b y+c=0 and bx+ay+c=0b x+a y+c=0 is less than 222 \sqrt{2}. Then,
View answer and explanation
Correct option: A
a+b−c>0a + b - c > 0
Option A (a+b−c>0a + b - c > 0) is correct because it is derived from the distance condition between the point of intersection and (1,1) being less than 222\sqrt{2}.
332 Medium
332 of 555
Application +4 | -1
The measure of the angle between the lines xcos⁡β+ysin⁡β=5π2x \cos \beta+y \sin \beta=\frac{5 \pi}{2} and xcos⁡α+ysin⁡α=π2x \cos \alpha+y \sin \alpha=\frac{\pi}{2} is
View answer and explanation
Correct option: D
∣β−α∣|\beta-\alpha|
Option D (∣β−α∣|\beta-\alpha|) is correct because it represents the absolute difference between the angles, which gives the acute angle between the lines.
333 Easy
333 of 555
Application +4 | -1
The number of integer values of mm for which the xx-coordinate of the point of intersection of the lines 3x+4y=93 x+4 y=9 and y=mx+1y=m x+1 is also an integer; is
View answer and explanation
Correct option: A
2
Option A (2) is correct because there are two integer values of m that make the x-coordinate of the intersection point an integer.
334 Easy
334 of 555
Application +4 | -1
The straight line whose sum of the intercepts on the axes is equal to half of the product of the intercepts, passes through the points
View answer and explanation
Correct option: B
(2, 2)
Option B ((4,2)) is correct because it satisfies the conditions of the right-angled triangle ABC, where A and B are given, and BC = 5 units.
335 Medium
335 of 555
Application +4 | -1
If P=(1,0),Q=(−1,0)P=(1,0), Q=(-1,0) and R=(2,0)R=(2,0) are three given points, then locus of the point SS satisfying the relation SQ2+SR2=2SP2S Q^2+S R^2=2 S P^2, is
View answer and explanation
Correct option: D
a straight line parallel to YY-axis
Option D (a straight line parallel to YY-axis) is correct because the locus simplifies to an equation of the form x=cx = c, which represents a vertical line.
336 Medium
336 of 555
Analyzing +4 | -1
The value of λ\lambda for which the lines joining the point of intersection of curves C1C_1 and C2C_2 to the origin are equally inclined to the XX-axis, where C1:λx2+3y2−2λxy+9x=0C_1: \lambda x^2+3 y^2-2 \lambda x y+9 x=0 and C2:3x2−4y2+8xy−3x=0C_2: 3 x^2-4 y^2+8 x y-3 x=0, is
View answer and explanation
Correct option: B
12
Option B (12) is correct because it is the value of λ\lambda that makes the lines joining the intersection points of the curves to the origin equally inclined to the X-axis.
337 Easy
337 of 555
Analyzing +4 | -1
If the quadrilateral formed by the lines ax+by+c=0,a′x+b′y+c=0,ax+by+c′=0a x+b y+c=0, a^{\prime} x+b^{\prime} y+c=0, a x+b y+c^{\prime}=0,
a′x+b′y+c′=0a^{\prime} x+b^{\prime} y+c^{\prime}=0 have perpendicular diagonals, then
View answer and explanation
Correct option: C
a2+b2=a′2+b′2{a^2} + {b^2} = {a'^2} + {b'^2}
Option C (a2+b2=a′2+b′2{a^2} + {b^2} = {a'^2} + {b'^2}) is correct because the quadrilateral is a rhombus, implying equal distances between parallel sides.
338 Medium
338 of 555
Application +4 | -1
The image of the point (4,-3) with respect to the line y=x is
View answer and explanation
Correct option: D
(−3,  4)\left( { - 3,\;4} \right)
Option D ((-3,4)) is correct because it represents the reflection of the point (4,-3) across the line y=x.
339 Easy
339 of 555
Application +4 | -1
If a,ba, b and cc are any three terms of an AP, then the ax+by+c=0a x+b y+c=0
View answer and explanation
Correct option: B
always passes through a fixed point
The correct answer is that the line always passes through a fixed point because the coefficients satisfy the condition for an arithmetic progression, allowing us to find a point that always satisfies the equation.
340 Easy
340 of 555
Application +4 | -1
The equation of the straight lines passing through the point (4, 3) and making intercepts on the coordinate axes whose sum is -1, is
View answer and explanation
Correct option: D
x2−y3=1  \frac{x}{2} - \frac{y}{3} = 1\; and x−2+y1=1\frac{x}{{ - 2}} + \frac{y}{1} = 1
The correct answer is x2−y3=1  \frac{x}{2} - \frac{y}{3} = 1\; and x−2+y1=1\frac{x}{{ - 2}} + \frac{y}{1} = 1 because these are the equations of lines passing through (4, 3) with intercepts summing to -1.
341 Easy
341 of 555
Application +4 | -1
The equation of the line ABA B is y=xy=x. If AA and BB lie on
the same side of the line mirror 2x−y=12 x-y=1, then the equation of the
image of ABA B, is
View answer and explanation
Correct option: C
7x−y−6=07 x-y-6=0
Option C (7x−y−6=07 x-y-6=0) is correct because it represents the image of the line AB after reflection across the line mirror 2x-y=1.
342 Medium
342 of 555
Application +4 | -1
If x2−y2+2hxy+2gx+2fy+c=0x^2-y^2+2 h x y+2 g x+2 f y+c=0 is the locus of a point, which moves such that it is always equidistant from the lines x+2y+7=0x+2 y+7=0 and 2x−y+8=02 x-y+8=0, then the value of g+c+h−fg+c+h-f equals
View answer and explanation
Correct option: C
14
Option C (14) is correct because it involves finding the equation of the angle bisectors, comparing it to the given equation, and then calculating g+c+h-f.
343 Easy
343 of 555
Application +4 | -1
The centroid of the triangle formed by the pair of straight lines 12x2−20xy+7y2=012{x^2} - 20xy + 7{y^2} = 0 and the line 2x−3y+4=02x - 3y + 4 = 0 is
View answer and explanation
Correct option: C
(83,83)\left( {\frac{8}{3},\frac{8}{3}} \right)
Option C ((83,83)\left( {\frac{8}{3},\frac{8}{3}} \right)) is correct because it is the centroid calculated from the vertices of the triangle formed by the intersection of the given lines.
344 Easy
344 of 555
Analyzing +4 | -1
If a≠b≠c,a \ne b \ne c, then the equations (b−c)x+(c−a)y+(a−b)=0\left( {b - c} \right)x + \left( {c - a} \right)y + \left( {a - b} \right) = 0 and, (b3−c3)x+(c3−a3)y+(a3−b3)=0\left( {{b^3} - {c^3}} \right)x + \left( {{c^3} - {a^3}} \right)y + \left( {{a^3} - {b^3}} \right) = 0
will represent the same line, if
View answer and explanation
Correct option: D
a+b+c=0a + b + c = 0
Option D (a+b+c=0a + b + c = 0) is correct because it's the condition that makes the two given equations represent the same line.
345 Easy
345 of 555
Application +4 | -1
Area of the parallelogram formed by the lines y=mx,y=mx+1,y=nxy=m x, y=m x+1, y=n x and y=nx+1y=n x+1 equals
View answer and explanation
Correct option: D
1∣m−n∣\frac{1}{|m-n|}
Option D (1∣m−n∣\frac{{1}}{{|m-n|}}) is correct because the area of a parallelogram formed by given lines is calculated using the formula involving the determinant of the coefficients.
346 Easy
346 of 555
Application +4 | -1
If the three points (3q,0),(0,3p)\left( {3q,0} \right),\left( {0,3p} \right) and (1,1)\left( {1,1} \right) are collinear then which one is true?
View answer and explanation
Correct option: C
1p+1q=3\frac{1}{p} + \frac{1}{q} = 3
Option C 1p+1q=3\frac{1}{p} + \frac{1}{q} = 3 is correct because it is the condition derived from the collinearity of the three points.
347 Medium
347 of 555
Application +4 | -1
The acute angle formed between the lines joining the origin to the points of intersection of the curves x2+y2−2x−1=0x^2+y^2-2 x-1=0 and x+y=1x+y=1, is
View answer and explanation
Correct option: B
tan⁡−12\tan ^{-1} 2
Option B (tan⁡−12\tan ^{-1} 2) is correct because it is calculated by homogenizing the equation and then applying the formula for the angle between the lines.
348 Easy
348 of 555
Application +4 | -1
A rectangle ABCD,A≡(0,0),B≡(4,0),C≡(4,2)A B C D, A \equiv(0,0), B \equiv(4,0), C \equiv(4,2) and D≡(0,2)D \equiv(0,2) undergoes the following transformations successively:

(i) f1(x,y)→(y,x)f_1(x, y) \rightarrow(y, x)

(ii) f2(x,y)→(x+3y,y)f_2(x, y) \rightarrow(x+3 y, y)

(iii) f3(x,y)→(x−y2,x+y2)f_3(x, y) \rightarrow\left(\frac{x-y}{2}, \frac{x+y}{2}\right)

The final figure will be
View answer and explanation
Correct option: D
a parallelogram
The final figure will be a parallelogram because after the transformations, opposite sides remain parallel, but the angles are no longer right angles.
349 Easy
349 of 555
Analyzing +4 | -1
Given four lines whose equations are x+2y−3=0,  2x+3y−4=0,3x+4y−7=0x + 2y - 3 = 0,\;2x + 3y - 4 = 0,3x + 4y - 7 = 0 and 4x+5y−6=0,4x + 5y - 6 = 0, then the lines are
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because only three of the four lines are concurrent.
350 Easy
350 of 555
Application +4 | -1
Coordinate of the foot of the perpendicular drawn from (0, 0) to the line joining (a  cosα,  asin⁡α)(a\mathrm{\;cos\alpha },\mathrm{\;}a\sin \mathrm{\alpha }) and (acos⁡β,  asin⁡β)  (a\cos \mathrm{\beta },\mathrm{\;}a\sin \mathrm{\beta })\; are
View answer and explanation
Correct option: B
[a2(cos⁡α+cos⁡β),a2(sin⁡α+sin⁡β)]\left[ {\frac{a}{2}(\cos \mathrm{\alpha } + \cos \mathrm{\beta }),\frac{a}{2}(\sin \mathrm{\alpha } + \sin \mathrm{\beta })} \right]
Option B [a2(cos⁡α+cos⁡β),a2(sin⁡α+sin⁡β)]\left[ {\frac{a}{2}(\cos \mathrm{\alpha } + \cos \mathrm{\beta }),\frac{a}{2}(\sin \mathrm{\alpha } + \sin \mathrm{\beta })} \right] is correct because it represents the coordinates of the foot of the perpendicular from (0,0) to the line joining the two given points.
351 Easy
351 of 555
Application +4 | -1
The equation of the bisector of the acute angle between the lines 2x−y+4=02 x-y+4=0 and x−2y=1x-2 y=1, is
View answer and explanation
Correct option: B
x−y+1=0x-y+1=0
Option B is correct. The equation of the bisector of the acute angle between the lines 2x−y+4=02x-y+4=0 and x−2y=1x-2y=1 is x−y+1=0x-y+1=0.
352 Medium
352 of 555
Application +4 | -1
Let AA be the point of intersection of the lines 3x+2y=14,5x−y=63 x+2 y=14,5 x-y=6 and BB be the point of intersection of the lines 4x+3y=8,6x+y=54 x+3 y=8,6 x+y=5. The distance of the point P(5,−2)P(5,-2) from the line ABA B is
View answer and explanation
Correct option: C
6
The correct answer is C (6) because it is the perpendicular distance of the point P(5,-2) from the line AB, calculated using the distance formula.
353 Easy
353 of 555
Application +4 | -1
The angle between the straight line x−y3=5x - y\sqrt 3 = 5 and 3x+y=7\sqrt 3 x + y = 7 is
View answer and explanation
Correct option: A
90∘90^\circ
Option A (90∘90^\circ) is correct because the dot product of the direction vectors of the two lines is zero, indicating perpendicularity.
354 Easy
354 of 555
Application +4 | -1
The lines ax+by+c=0,  bx+cy+a=0ax + by + c = 0,\;bx + cy + a = 0 and cx+ay+b=0cx + ay + b = 0 (a≠b≠c)\left( {a \ne b \ne c} \right) are concurrent, if
View answer and explanation
Correct option: C
a+b+c=0a + b + c = 0
Option C (a+b+c=0a + b + c = 0) is correct because the determinant of the coefficients must be zero for concurrency, which simplifies to a+b+c=0a + b + c = 0 given a≠b≠ca \ne b \ne c.
355 Medium
355 of 555
Application +4 | -1
Coordinates of the foot of the perpendicular drawn from (0, 0) to the line joining (acos⁡α,asin⁡α(a\cos \mathrm{\alpha },a\sin \mathrm{\alpha }) and (acos⁡β,asin⁡βa\cos \mathrm{\beta },a\sin \mathrm{\beta }) are
View answer and explanation
Correct option: B
(a2(cos⁡α+cos⁡β),a2(sin⁡α+sin⁡β))\left( {\frac{a}{2}\left( {\cos \mathrm{\alpha } + \cos \mathrm{\beta }} \right),\frac{a}{2}\left( {\sin \mathrm{\alpha } + \sin \mathrm{\beta }} \right)} \right)
Option B is correct because it involves finding the equation of the perpendicular from the origin to the line joining the two given points and then solving for the point of intersection.
356 Easy
356 of 555
Analyzing +4 | -1
Consider three points

P=(−sin⁡(β−α),  −cos⁡β)P = \left( { - \sin \left( {\mathrm{\beta } - \mathrm{\alpha }} \right),\mathrm{\;} - \cos \mathrm{\beta }} \right)

Q=(cos⁡(β−α),  sin⁡β){\cal Q} = \left( {\cos \left( {\mathrm{\beta } - \mathrm{\alpha }} \right),\mathrm{\;}\sin \mathrm{\beta }} \right)

And R=(cos⁡(β−α+θ),  sin⁡(β−θ))R = \left( {\cos \left( {\mathrm{\beta } - \mathrm{\alpha } + \mathrm{\theta }} \right),\mathrm{\;}\sin (\mathrm{\beta } - \mathrm{\theta }} \right)),

Where 0<α,  β,  θ<π40 < \alpha ,\;\beta ,\;\theta < \frac{\pi }{4}. Then,
View answer and explanation
Correct option: D
P,  Q,  RP,\;{\cal Q},\;R are non-collinear
Option D (P,  Q,  RP,\;{\cal Q},\;R are non-collinear) is correct because the determinant formed by the coordinates of the points is non-zero, indicating non-collinearity.
357 Easy
357 of 555
Understanding +4 | -1
Consider the following statements.

I. Centroid of a triangle is a point where angle bisectors meet.

II. If value of area after calculations is negative then we take its negative value.

Choose the correct option.
View answer and explanation
Correct option: C
Both are false
Option C is correct because both statements are false; the centroid is where medians meet, and area is taken as an absolute value.
358 Easy
358 of 555
Application +4 | -1
A triangle ABC, right angled at A, has points A and B as (2,3) and (0,-1) respectively. If BC=5 units, then the point C, is
View answer and explanation
Correct option: B
(4,2)
Option C (θ\theta) is correct because it is the acute angle between the pair of straight lines represented by the given equation, derived using the formula involving the coefficients of the equation.
359 Medium
359 of 555
Analyzing +4 | -1
Family of lines λx+3y−6=0(λ\lambda x+3 y-6=0(\lambda is a real parameter )) intersect the lines x−2y+3=0x-2 y+3=0 and x−y+1=0x-y+1=0 in PP and QQ, then locus of the middle point of PQP Q is
View answer and explanation
Correct option: D
4x+3y=44 x+3 y=4
The correct answer is D (4x+3y=44x+3y=4) because the locus of the midpoint of PQ is found by using the equation of the chord with a given midpoint and the fact that the family of lines passes through a fixed point.
360 Easy
360 of 555
Application +4 | -1
The coordinates of the incentre of the triangle having sides

3x−4y=0,  5x+12y=03x - 4y = 0,\;5x + 12y = 0

and y−15=0y - 15 = 0 are
View answer and explanation
Correct option: A
−1,  8- 1,\;8
Option A ( - 1, 8) is correct because it is the incentre calculated using the formula with the vertices and side lengths of the triangle.
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