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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 465 questions
1 Easy
1 of 465
Application +4 | -1
If the mean of a set of observations x1,x2,…,xn{x_1},{x_2}, \ldots ,{x_n} is Xˉ,\bar X, then the mean of the observationsxi+2  i;i=1,  2,…,n{x_i} + 2\;i;i = 1,\;2, \ldots ,n is
View answer and explanation
Correct option: C
Xˉ+(n+1)\bar X + \left( {n + 1} \right)
Option C (Xˉ+(n+1)\bar X + (n + 1)) is correct because adding 2i to each observation increases the mean by the average of 2i, which is n+1.
2 Easy
2 of 465
Application +4 | -1
The sum of 10 items is 12 and sum of their squares is 18 , then standard deviation will be
View answer and explanation
Correct option: D
3/53 / 5
Option D (3/53 / 5) is correct because the standard deviation is calculated using the given sums and the formula, resulting in 3/5.
3 Easy
3 of 465
Application +4 | -1
In a family, there are 8 men, 7 women and 5 children whose mean ages separately are respectively 24,20 and 6 years. The mean age of the family is
View answer and explanation
Correct option: B
18.1 years
Option B (18.1 years) is correct because it is the weighted average age of the family, considering the number of men, women, and children.
4 Easy
4 of 465
Application +4 | -1
The mean and variance of seven observations are 8 and 16, respectively. If 5 of the observations are 2, 4, 10, 12, 14, then the product of the remaining two observations is
View answer and explanation
Correct option: C
48
Option C (48) is correct because it accurately calculates the product of the remaining two observations based on the given mean and variance.
5 Medium
5 of 465
Application +4 | -1
1,3,5,x,y1,3,5, x, y are 5 observations. Mean of these observations is 5 and variance is 8. Sum of the cubes of the two missing number equals:
View answer and explanation
Correct option: A
1072
Option A (1072) is correct because after calculating the missing numbers using the mean and variance, the sum of their cubes is 1072.
6 Medium
6 of 465
Application +4 | -1
If s.d. of a set of observations is 8 and if each observation is divided by −2,-2, the s.d. of the new set of observations will be
View answer and explanation
Correct option: D
4
Option D (4) is correct because dividing each observation by -2 divides the standard deviation by the absolute value of -2, which is 2.
7 Easy
7 of 465
Application +4 | -1
The geometric mean of 5,8,10,15,20,25,305,8,10,15,20,25,30 is
View answer and explanation
Correct option: B
10(9)1/710(9)^{1 / 7}
Option B (10(9)1/710(9)^{{1/7}}) is correct because it represents the geometric mean of the given numbers.
8 Medium
8 of 465
Application +4 | -1
The mean of the distribution, in which the values of XX are 1,2,.....n,1,2,.....n, the frequency of each being unity is:
View answer and explanation
Correct option: C
n+12\frac{{n + 1}}{2}
Option C (n+12\frac{{n + 1}}{2}) is correct because the mean of the distribution is the sum of the values divided by the number of values.
9 Medium
9 of 465
Application +4 | -1
If a variable takes values 0,  1,2,..,n0,\;1,2,..,n with frequencies qn,  nC1qn−1p,  nC2qn−2p2,…  nCnpn,{q^n},{\;^n}{C_1}{q^{n - 1}}p,{\;^n}{C_2}{q^{n - 2}}{p^2}, \ldots {\;^n}{C_n}{p^n}, where p+q=1,p + q = 1, then the mean is
View answer and explanation
Correct option: A
npnp
Option A (npnp) is correct because the given distribution is a binomial distribution, and the mean of a binomial distribution is npnp.
10 Easy
10 of 465
Application +4 | -1
If the S.D.\mathrm{S}.\mathrm{D}. of a variate XX is σ\sigma, then the S.D.\mathrm{S}.\mathrm{D}. of a  X+ba\;X + b is
View answer and explanation
Correct option: A
∣a∣    σ\left| a \right|\;\;\sigma
Option A (∣a∣  σ\left| a \right|\;\sigma) is correct because the standard deviation of aX + b is the absolute value of a times the standard deviation of X.
11 Easy
11 of 465
Application +4 | -1
The weighted mean of first nn natural numbers whose weights are equal is given by
View answer and explanation
Correct option: B
(n+1)/2(n+1) / 2
Option B ((n+1)2\frac{(n+1)}{2}) is correct because the weighted mean of the first n natural numbers with equal weights simplifies to the arithmetic mean.
12 Medium
12 of 465
Application +4 | -1
Let sets AA and BB have 5 elements each. Let the mean of the elements in sets AA and BB 5 and 8 respectively and the variance of the elements in sets AA and BB be 12 and 20 respectively. A new set CC of 10 elements is formed by subtracting 3 from each element of AA and adding 2 to each element of BB. Then the sum of the mean and variance of the elements of CC is
View answer and explanation
Correct option: C
38
Option C (38) is correct because it is the sum of the combined mean (6) and combined variance (32) of the new set C.
13 Easy
13 of 465
Application +4 | -1
For a bivariate distribution (x,y)(x, y) if
∑x=50,∑y=60,∑xy=350,xˉ=5,yˉ=6.\sum x=50, \sum y=60, \sum x y=350, \bar{x}=5, \bar{y}=6 .

Variance of xx is 4 , variance of yy is 9 , then rxyr_{x y} equals
View answer and explanation
Correct option: C
56\frac{5}{6}
Option C (56\frac{5}{6}) is correct because it is the calculated correlation coefficient using the given data.
14 Easy
14 of 465
Application +4 | -1
If the variable takes the values 0,1,2,….n,  0,\mathrm{ }1,\mathrm{ }2,\mathrm{ } \ldots .n,\; with frequencies proportional to the binomial coefficients C(n,0),C(n,1),C(n,2),…..,C(n,n)C\left( {n,0} \right),C\left( {n,1} \right),C\left( {n,2} \right), \ldots ..,C\left( {n,n} \right) respectively, then the variance of the distribution is
View answer and explanation
Correct option: D
n4\frac{n}{4}
Option D (n/4) is correct because the variance of the distribution is calculated to be n/4 using binomial coefficients.
15 Easy
15 of 465
Understanding +4 | -1
The standard deviation is not affected by the change of
View answer and explanation
Correct option: A
Origin
Option A (Origin) is correct because the standard deviation is not affected by a change of origin.
16 Easy
16 of 465
Application +4 | -1
For a series, the information available is n=10n=10, Σx=60\Sigma x=60 and Σx2=1000\Sigma x^2=1000. The standard deviation is
View answer and explanation
Correct option: A
8
Option A (8) is correct because the standard deviation is calculated using the formula and given values, resulting in 8.
17 Medium
17 of 465
Application +4 | -1
Coefficient of variation of two distributions are 50 and 60 and their arithmetic means are 30 and 25, respectively. Then, difference of their standard deviations is
View answer and explanation
Correct option: A
0
Option A (0) is correct because by using the formula for the coefficient of variation and the given values, we find that both standard deviations are equal, resulting in a difference of 0.
18 Easy
18 of 465
Application +4 | -1
Mean marks scored by the students of a class is 53. The mean marks of the girls is 55 and the mean marks of the boys is 50. What is the percentage of girls in the class?
View answer and explanation
Correct option: A
60%60\%
Option A (60%60\%) is correct because it is derived from setting up an equation based on the weighted average of the mean marks of boys and girls.
19 Easy
19 of 465
Understanding +4 | -1
If the median of 21 observations is 40 and if the observations greater than the median are increased by 6 then the median of the new data will be
View answer and explanation
Correct option: A
40
Option A (40) is correct because the median is the middle value, and increasing values above the median does not change the position of the middle value.
20 Hard
20 of 465
Analyzing +4 | -1
The mean square deviation of a set of m\mathrm{m} observations y1,y2….ymy_1, y_2 \ldots . y_m about a point KK is defined as 1m∑i=1m(yi−k)2\frac{1}{m} \sum\limits_{{i=1}}^{m}\left(y_i-k\right)^2. The mean square deviation about -3 and 3 are 16 and 8 respectively, then standard deviation of this set of observation?
View answer and explanation
Correct option: A
233\frac{\sqrt{23}}{3}
Option A (233\frac{\sqrt{23}}{3}) is correct because it is the standard deviation calculated from the given mean square deviations about -3 and 3.
21 Medium
21 of 465
Application +4 | -1
The mean of 10 numbers is 12.5 ; the mean of the first six is 15 and the last five is 10 . The sixth number is
View answer and explanation
Correct option: A
15
Option A (15) is correct because it calculates the sixth number by using the combined mean formula and solving for the unknown.
22 Easy
22 of 465
Application +4 | -1
If x=X−Mx,y=Y−Myx=X-M_x, y=Y-M_y and Σxy=40,Σx2=80\Sigma x y=40, \Sigma x^2=80, Σy2=20\Sigma y^2=20. Then, coefficient of correlation between XX and YY is
View answer and explanation
Correct option: D
1
Option D (1) is correct because the correlation coefficient is calculated using the given sums of squares and cross-products, resulting in 1.
23 Easy
23 of 465
Application +4 | -1
Mean of 100 observations is 45 . It was later found that the two observations 19 and 31 were incorrectly recorded as 91 and 13 . The correct mean is
View answer and explanation
Correct option: B
44.46
Option B (44.46) is correct because it accurately adjusts the initial mean based on the corrected observations.
24 Easy
24 of 465
Application +4 | -1
For two data sets, each of size 5, the variance are given to be 4 and 5 and the corresponding means are given to be 2 and 4, respectively. The variance of the combined data set is
View answer and explanation
Correct option: B
112\frac{{11}}{2}
The correct answer is B (112\frac{{11}}{2}) because it is the variance of the combined data set calculated using the given variances and means.
25 Easy
25 of 465
Application +4 | -1
The standard deviation of a variable x  is  10{x\;is\;10}. Then, the standard deviation of 50+5x50 + 5x is
View answer and explanation
Correct option: A
50
Option D (50) is correct because multiplying a variable by a constant multiplies the standard deviation by the same constant, while adding a constant does not change the standard deviation.
26 Easy
26 of 465
Application +4 | -1
The mean of the data set comprising of 16 observation is 16. If one of the observation valued 16 is deleted and three new observations valued 3, 4 and 5 are added to the data, then the mean of the resultant data is
View answer and explanation
Correct option: D
14
Option D (14) is correct because the new mean is calculated by subtracting the deleted value and adding the new values, then dividing by the new number of observations.
27 Easy
27 of 465
Analyzing +4 | -1
Statement 1: The variance of first nn odd natural numbers is n2−13\frac{n^2-1}{3}

Statement 2: The sum of first nn odd natural number is n2n^2 and the sum of square of first nn odd natural numbers is n(4n2+1)3\frac{n\left(4 n^2+1\right)}{3}.
View answer and explanation
Correct option: A
Statement 1 is true, Statement 2 is false.
Statement 1 is true and Statement 2 is false, therefore option A is the correct answer.
28 Easy
28 of 465
Understanding +4 | -1
The median of a set of 9 distinct observations is 20.5. if each of the largest 4 observations of the set is increased by 2, then the median of the new set
View answer and explanation
Correct option: D
Remains the same as that of the original set
Option D (Remains the same as that of the original set) is correct because the median is the middle value, and changing the largest 4 values doesn't affect the middle value in a set of 9 distinct observations.
29 Medium
29 of 465
Application +4 | -1
Three rotten apples are mixed accidently with seven good apples and four apples are drawn one by one without replacement. Let the random variable XX denote the number of rotten apples. If μ\mu and σ2\sigma^{2} represent mean and variance of XX, respectively, then 10(μ2+σ2)10\left(\mu^{2}+\sigma^{2}\right) is equal to
View answer and explanation
Correct option: D
20
Option D (20) is correct because the calculated value of 10(μ2+σ2)10(\mu^2 + \sigma^2) based on the mean and variance of the number of rotten apples drawn is 20.
30 Medium
30 of 465
Application +4 | -1
Let x1,x2,…..,xx  {x_1},{x_2}, \ldots ..,{x_x}\; be n observations such that ∑xi2=400    and      ∑xi=80\sum x_i^2 = 400\;\;and\;\;\;\sum {x_i} = 80. Then a possible value of n among the following is
View answer and explanation
Correct option: C
18
Option C (18) is correct because the condition for variance being non-negative leads to n >= 16, and 18 is the only option satisfying this.
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Key Takeaways

  • ✓ This set contains 465 single-correct-answer MCQs on STATISTICS.
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