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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 465 questions
31 Easy
31 of 465
Application +4 | -1
The mean and standard deviation of 1,2,3,4,5,61,2,3,4,5,6 are
View answer and explanation
Correct option: A
72,3512\frac{7}{2}, \sqrt{\frac{35}{12}}
Option A (72,3512\frac{{7}}{{2}}, \sqrt{{\frac{{35}}{{12}}}}) is correct because the calculated mean is 7/2 and the standard deviation is 3512\sqrt{{\frac{{35}}{{12}}}} for the given data.
32 Easy
32 of 465
Application +4 | -1
If the data x1,x2,...,x10{x_1},{x_2},...,{x_{10}} is such that the mean of first four of these is 11, the mean of the remaining six is 16 and the sum of squares of these is 2000, then the standard deviation of this data is
View answer and explanation
Correct option: B
2
Option B (2) is correct because it is the standard deviation calculated from the given data, using the formula for standard deviation.
33 Medium
33 of 465
Application +4 | -1
A motor car when travelling from rest travels the first twentieth of a mile at 6 m/h6 \mathrm{~m} / \mathrm{h} the next three twentieths of the mile at 8,12,24 m/h8,12,24 \mathrm{~m} / \mathrm{h} respectively. But its average speed over the first one-fifth of a mile is not 12.5 m/h12.5 \mathrm{~m} / \mathrm{h}, then the correct average is
View answer and explanation
Correct option: A
9.6 m/h9.6 \mathrm{~m} / \mathrm{h}
Option C (7.66, 28.02) is correct because it calculates the harmonic mean for the speeds and the geometric mean for the population increases.
34 Easy
34 of 465
Application +4 | -1
The mean of 5 observations is 5 and their variance is 124.
If three of the observations are 1, 2 and 6; then the mean
deviation from the mean of the data is :
View answer and explanation
Correct option: C
2.8
Option C (2.8) is correct. The mean deviation from the mean is calculated after finding the missing observations.
35 Medium
35 of 465
Application +4 | -1
A man motors from AA to BB. In motoring a distance uphill he gets a mileage of only 10 miles per gallon of gasoline. On the return trip, he makes 15 miles per gallon, then the harmonic mean of his mileage (verify that this is the proper average to be used, here assuming that the distance from AA to BB is 60 miles) is
View answer and explanation
Correct option: A
12
Option A (12) is correct because the harmonic mean correctly averages the mileage rates for the round trip.
36 Medium
36 of 465
Application +4 | -1
The mean annual salaries paid to 1000 employees of a company was Rs. 3400 . The mean annual salaries paid to male and female employees were Rs. 200 and Rs. 4200, respectively. The percentage of males and females employed by the company are
View answer and explanation
Correct option: D
70,30
Option C (70,30) is correct because it represents the correct percentage of male and female employees calculated from the given mean salaries.
37 Easy
37 of 465
Application +4 | -1
In a moderately skewed distribution the values of mean and median are 5 and 6 respectively. The value of mode in such a situation is approximately equal to
View answer and explanation
Correct option: A
8
Option A (8) is correct because the mode can be estimated using the empirical relationship: Mode = 3 Median - 2 Mean.
38 Easy
38 of 465
Understanding +4 | -1
If byxb_{y x} and bxyb_{x y} are the regression coefficient of yy on xx and xx on yy respectively, then
View answer and explanation
Correct option: A
byx+bxy≥2r(x,y)b_{y x}+b_{x y} \geq 2 r(x, y)
Option A (byx+bxy≥2r(x,y)b_{yx} + b_{xy} \geq 2r(x, y)) is correct. The AM-GM inequality applied to regression coefficients shows that the sum of the regression coefficients is greater than or equal to twice the correlation coefficient.
39 Medium
39 of 465
Application +4 | -1
Let x1,x2,…,x100x_1, x_2, \ldots, x_{100} be in an arithmetic progression, with x1=2x_1=2 and their mean equal to 200 . If yi=i(xi−i),1≤i≤100y_i=i\left(x_i-i\right), 1 \leq i \leq 100, then the mean of y1,y2,…y_1, y_2, \ldots, y100y_{100} is
View answer and explanation
Correct option: C
10049.5
Option C (10049.5) is correct because it is the result of calculating the mean of the given series using the properties of arithmetic progressions and summation formulas.
40 Easy
40 of 465
Application +4 | -1
The variance of 6,8,10,12,146,8,10,12,14 is
View answer and explanation
Correct option: B
8
Option D (8) is correct because the variance is calculated as the average of the squared differences from the mean, which equals 8.
41 Easy
41 of 465
Application +4 | -1
If the mean of the data 7,7,9,7,8,7,λ,87,7,9,7,8,7, \lambda, 8 is 7, then the variance of this data is:
View answer and explanation
Correct option: D
114\frac{11}{4}
Option D (114\frac{{11}}{{4}}) is correct because it's the variance calculated using the given data and the calculated value of λ\lambda.
42 Easy
42 of 465
Application +4 | -1
1, 2, 4, 6, 8, 9 transformed into another series whose mean is 12. Two middle terms of the transformed series are
View answer and explanation
Correct option: D
11, 13
Option D (11, 13) is correct because adding 7 to each term shifts the mean to 12, and 11 and 13 are the middle terms of the transformed series.
43 Easy
43 of 465
Understanding +4 | -1
The SD of 15 items is 6 and if each item is decreases by 1 , then standard deviation will be
View answer and explanation
Correct option: D
6
Option D (6) is correct because standard deviation is a measure of dispersion and is not affected by adding or subtracting a constant from each data point.
44 Medium
44 of 465
Application +4 | -1
The AM of n numbers of a series is Xˉ{\bar X}. If the sum of first (n  −1)(n\; - 1) terms is kk then the n  thn{\;^{th}} number is
View answer and explanation
Correct option: B
n  Xˉ−kn\;\bar X - k
Option B (n  Xˉ−kn\;\bar X - k) is correct because it represents the nth term calculated by subtracting the sum of the first (n-1) terms from the total sum of all n terms.
45 Medium
45 of 465
Understanding +4 | -1
In any discrete series (when all values are not same) the relationship between M.D. about mean and S.D. is
View answer and explanation
Correct option: D
M.D.≤S.D.\mathrm{M}.\mathrm{D}. \le \mathrm{S}.\mathrm{D}.
Option D (M.D.≤S.D.\mathrm{M}.\mathrm{D}. \le \mathrm{S}.\mathrm{D}.) is correct because the Mean Deviation (M.D.) is always less than or equal to the Standard Deviation (S.D.) in any discrete series.
46 Easy
46 of 465
Application +4 | -1
If       x1,x2,….,x18\;\;\;{x_1},{x_2}, \ldots .,{x_{18}} 18 are observation such that ∑j=118(xj−8)=9        and       ∑j=118(xj−8)2=45,\sum \limits_{j = 1}^{18} \left( {{x_j} - 8} \right) = 9\;\;\;\;and\,\;\;\;\sum \limits_{j = 1}^{18} {\left( {{x_j} - 8} \right)^2} = 45, then these standard derivation of these observations is
View answer and explanation
Correct option: D
32\frac{3}{2}
Option D (3/2) is correct because the standard deviation is calculated using the given sums and the formula for standard deviation.
47 Easy
47 of 465
Understanding +4 | -1
Let r>0r>0 and mm be the A. M. of the regression coefficient of yy on xx and xx on yy, then
View answer and explanation
Correct option: C
m≥rm \geq r
Option C (m≥rm \geq r) is correct because the arithmetic mean (m) of the regression coefficients is always greater than or equal to the geometric mean (r), which is the correlation coefficient.
48 Medium
48 of 465
Application +4 | -1
If ∑i=15xi2=40&∑i=610xj2=20\sum\limits_{{i=1}}^5 x_i^2=40 \& \sum\limits_{{i=6}}^{10} x_j^2=20 and mean of x1,x2,……x5x_1, x_2, \ldots \ldots x_5, is 1 and mean of x6,x7,……...x10x_6, x_7, \ldots \ldots . . . x_{10} is 2 then variance of x1,x2,……..x10x_1, x_2, \ldots \ldots . . x_{10} is
View answer and explanation
Correct option: B
154\frac{15}{4}
Option B (154\frac{15}{4}) is correct because it is the variance calculated using the given sums of squares and means.
49 Easy
49 of 465
Application +4 | -1
The mean weight of 150 students in 60 Kgs. The
mean weight of boys is 70 and that of girls in 55
with standard deviations 10 and 15 respectively. The
combined variance is
View answer and explanation
Correct option: A
7003\frac{700}{3}
Option A (700/3) is correct because it is the result of applying the combined variance formula, considering the number of students, means, and standard deviations for both boys and girls.
50 Medium
50 of 465
Application +4 | -1
The mean of 5 observation is 4.4 and their variance is 8.24. If three of the observations are 1, 2 and 6, then difference of the other two observations is
View answer and explanation
Correct option: A
5
Option A (5) is correct because by using the given mean and variance, we can set up equations to solve for the two unknown observations and then find their difference.
51 Medium
51 of 465
Application +4 | -1
If a variable X takes values 0,1,2,…,n0,1,2, \ldots ,n with frequencies proportional to the binomial coefficients nC0,  nC1,  nC2,…,  nCn,^n{C_0},{\;^n}{C_1},{\;^n}{C_2}, \ldots ,{\;^n}{C_n}, the mean square deviation about x=0,x = 0, is
View answer and explanation
Correct option: B
n(n+1)4\frac{{n\left( {n + 1} \right)}}{4}
Option D (n(n+1)/2) is incorrect. The correct answer is n(n+1)/4.
52 Easy
52 of 465
Application +4 | -1
On thirteen consecutive days, the number of persons booked for violating speed limit of 40 km/h40 \mathrm{~km} / \mathrm{h} were as follows:
58,61,68,57,62,50,55,62,53,54,51,59,5258,61,68,57,62,50,55,62,53,54,51,59,52
The median number of speed violations per day is
View answer and explanation
Correct option: D
57
Option D (57) is correct because the median is the middle value when the data is arranged in ascending order.
53 Easy
53 of 465
Application +4 | -1
The weighted mean of first nn natural number if their weight are the same as the number is-
View answer and explanation
Correct option: C
2n+13\frac{2 n+1}{3}
Option C (2n+13\frac{{2 n+1}}{{3}}) is correct because the weighted mean is calculated by summing the product of each number and its weight, then dividing by the sum of the weights, resulting in the given expression.
54 Easy
54 of 465
Application +4 | -1
If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately
View answer and explanation
Correct option: A
24
Option A (24) is correct because the mode is calculated using the empirical relationship between mean, median, and mode.
55 Easy
55 of 465
Analyzing +4 | -1
The mean deviation from mean of the observation a,  a+d,  a+2d,  …a+2nda,\;a + d,\;a + 2d,\; \ldots a + 2nd is
View answer and explanation
Correct option: D
None of these
The correct answer is None of these because the mean deviation from the mean of the given arithmetic progression is n(n+1)∣d∣(2n+1)\frac{{n\left( {n + 1} \right)\left| d \right|}}{{\left( {2n + 1} \right)}}, which is not among the options.
56 Medium
56 of 465
Application +4 | -1
nn observations on a variable XiX_i are Xi=A+iBX_i=A+i B for i=1,2,3….ni=1,2,3 \ldots . n where A,BA, B are real constants. The mean of these observation is
View answer and explanation
Correct option: A
A+B(n+12)A+B\left(\frac{n+1}{2}\right)
Option A (A+B(n+12)A+B(\frac{n+1}{2})) is correct because the mean of an arithmetic progression is the average of the first and last terms, which simplifies to the given expression.
57 Medium
57 of 465
Application +4 | -1
If the mean of 15 observations is 12 and standard deviation is 3. If 12 is replaced by 10 (in data) then the new mean is μ\mu and variance is σ2\sigma^2 then what is the value of 15(μ+μ2+σ2)15\left(\mu+\mu^2+\sigma^2\right)
View answer and explanation
Correct option: A
2429
Option A (2429) is correct because it is the result of calculating 15(μ+μ2+σ2)15(\mu+\mu^2+\sigma^2) after replacing 12 with 10 in the data and finding the new mean and variance.
58 Easy
58 of 465
Application +4 | -1
The first of two samples has 100 items with mean 15 and SD=3.SD = 3. If the whole group has 250 items with mean 15.6 and SD=13.44SD = \sqrt {13.44}, the SD of the second group is
View answer and explanation
Correct option: A
4
Option A (4) is correct because it is the standard deviation of the second group calculated using the given information about the combined group and the first group.
59 Easy
59 of 465
Application +4 | -1
In a college of 300 students every student reads 5 newspapers and every newspaper is read by 60 students. The number of newspapers are
View answer and explanation
Correct option: C
Exactly 25
Option C (Exactly 25) is correct because the number of newspapers is calculated by dividing the total number of students reading newspapers by the number of students reading each newspaper.
60 Medium
60 of 465
Application +4 | -1
The mean and standard deviation of 20 observations are found to be 10 and 2 , respectively. On respectively, it was found that an observation by mistake was taken 8 instead of 12. The correct standard deviation is
View answer and explanation
Correct option: C
3.96\sqrt{3.96}
Option C (3.96\sqrt{{3.96}}) is correct because it is the correct standard deviation calculated after adjusting for the error in the observation.
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