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JEE • MATHEMATICS • STATISTICS

Statistics practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-141 of 141 questions
121 Medium
121 of 141
Application +4 | -1
Mean and variance of 10 positive observations is 7 and 8. If we add 5 to each number then sum of mean
and variance of new data is
View answer and explanation
Correct option: B
20
Option B (20) is correct because adding a constant to each observation increases the mean by that constant, while the variance remains unchanged. Therefore, the sum of the new mean and variance is 7 + 5 + 8 = 20.
122 Medium
122 of 141
Application +4 | -1
The mean of observations is 4.4 and the variance is 8.24 . If three of the five observations are 1,2 and 6 , then find the other two observations.
View answer and explanation
Correct option: A
9,4
Option A (9,4) is correct because these values satisfy both the mean and variance equations derived from the given data.
123 Medium
123 of 141
Application +4 | -1
For a set of 100 observations, taking assumed mean as 4 , the sum of the deviations is −11 cm-11 \mathrm{~cm}, and the sum of the squares of these deviations is 275 cm2275 \mathrm{~cm}^2. The coefficient of variation is
View answer and explanation
Correct option: A
41.13%41.13 \%
Option A (41.13 %) is correct because the coefficient of variation is calculated correctly using the given data and the assumed mean.
124 Medium
124 of 141
Application +4 | -1
If two lines of regression are3xˉ−2yˉ+1=0  and  2xˉ−yˉ−2=03\bar x - 2\bar y + 1 = 0\;and\;2\bar x - \bar y - 2 = 0, then (xˉ,  yˉ)(\bar x,\;\bar y) is
View answer and explanation
Correct option: B
(5,8)\left( {5,8} \right)
Option B ((5,8)\left( {5,8} \right)) is correct because it is the solution to the system of equations formed by the two regression lines.
125 Medium
125 of 141
Application +4 | -1
The average weight of a class of 14 students is 42 kg42 \mathrm{~kg}. If the teacher is included then average weight increases by 400 g400 \mathrm{~g}, then weight of teacher is
View answer and explanation
Correct option: B
48
Option B (48) is correct because the teacher's weight is calculated by considering the increase in the average weight when the teacher is included.
126 Medium
126 of 141
Application +4 | -1
If the regression coefficient of XX on YY and YY on XX are -0.4 and -0.9 respectively, then the correlation coefficient between X{X} and Y{Y} is
View answer and explanation
Correct option: A
-0.6
Option A (-0.6) is correct because the correlation coefficient is the square root of the product of the regression coefficients, and it has the same sign as the regression coefficients.
127 Medium
127 of 141
Analyzing +4 | -1
Statement-1: The variance of first nn even natural numbers is n2−14\frac{n^2-1}{4}.

Statement-2 : The sum of first nn natural numbers is n(n+1)2\frac{n(n+1)}{2} and the sum of squares of first nn natural numbers is n(n+1)(2n+1)6\frac{n(n+1)(2 n+1)}{6}.
View answer and explanation
Correct option: C
Statement- 1 is false, Statement- 2 is true.
Statement-1 is false and Statement-2 is true, therefore option C is the correct answer.
128 Medium
128 of 141
Application +4 | -1
The quartile deviation of daily wages (in Rs.) of 7 persons given below is
12,7,15,10,17,17,2512,7,15,10,17,17,25
View answer and explanation
Correct option: B
2.5
Option B (2.5) is correct because it is the quartile deviation calculated as half the difference between the third and first quartiles.
129 Medium
129 of 141
Application +4 | -1
The mean and standard deviation of the marks of 20 students were found to be 40 and 15 respectively. Later, it was discovered that a score of 60 was wrongly read as 40 , then the correct variance will be
View answer and explanation
Correct option: D
244
Option D (244) is correct because it calculates the corrected variance after accounting for the error in the student's score.
130 Medium
130 of 141
Application +4 | -1
The average rate of (i) motion in the case of a person who rides the first mile at 10 m/h10 \mathrm{~m} / \mathrm{h}, the next mile at 8 m/h8 \mathrm{~m} / \mathrm{h} and the third mile at 6 m/h6 \mathrm{~m} / \mathrm{h} (ii) increase in population which is the first decade has increased 20%20 \% in the next 25%25 \% and in the third 44%44 \% are (where, log⁡20=1.3010\log 20=1.3010, log⁡25=1.3979,log⁡28.02=1.4475\log 25=1.3979, \log 28.02=1.4475, log⁡44=1.6435\log 44=1.6435 )
View answer and explanation
Correct option: C
7.66,28.027.66,28.02
Option C (7.66, 28.02) is correct because it calculates the harmonic mean for the speeds and the geometric mean for the population increases.
131 Medium
131 of 141
Application +4 | -1
Mean of 5 observations is 7 . If four of these observations are 6,7,8,106,7,8,10 and one is missing then the variance of all the five observations is :
View answer and explanation
Correct option: D
2
Option D (2) is correct. The variance is calculated after finding the missing observation using the given mean.
132 Medium
132 of 141
Application +4 | -1
The mean deviation about the median of the series of batsman in ten innings 34,38,42,44,46,48,54,55,56,7634,38,42,44,46,48,54,55,56,76 is
View answer and explanation
Correct option: A
8.5
Option A (8.5) is correct because it is the mean deviation calculated about the median of the given series.
133 Medium
133 of 141
Application +4 | -1
The mean deviation from mean of observations a,a+d,a+2d,…..,a+2nda, a+d, a+2 d, \ldots . ., a+2 n d is
View answer and explanation
Correct option: D
n(n+1)2n+1∣d∣\frac{n(n+1)}{2 n+1}|d|
Option D (n(n+1)2n+1∣d∣\frac{{n(n+1)}}{{2 n+1}}|d|) is correct because it represents the mean deviation from the mean of an arithmetic progression.
134 Medium
134 of 141
Analyzing +4 | -1
A data consists of n\mathrm{n} observations:

x1,x2,…,xn. If ∑i=1n(xi+1)2=9n and ∑i=1n(xi−1)2=5nx_1, x_2, \ldots, x_{\mathrm{n}} \text {. If } \sum_{i=1}^{\mathrm{n}}\left(x_i+1\right)^2=9 \mathrm{n} \text { and } \sum_{i=1}^{\mathrm{n}}\left(x_i-1\right)^2=5 \mathrm{n}

then the standard deviation of this data is:
View answer and explanation
Correct option: B
5\sqrt{5}
Option B (5\sqrt{5}) is correct because the standard deviation is calculated using the given summations and the formula for variance.
135 Medium
135 of 141
Remembering +4 | -1
The mean of discrete observations y1,y2,y3,…,yn{y}_1, {y}_2, {y}_3, \ldots, {y}_{{n}} is given by
View answer and explanation
Correct option: A
∑i=1nYin\frac{{\sum\limits_{i = 1}^n {{Y_i}} }}{n}
Option A (∑i=1nYin\frac{{\sum\limits_{i = 1}^n {{Y_i}} }}{n}) is correct because it represents the formula for the mean of discrete observations.
136 Medium
136 of 141
Application +4 | -1
A factory is operating in two shifts, day and night, with 70 and 30 workers respectively. If per day mean wage of the day shift workers is ₹54₹ 54 and per day mean wage of all the workers is ₹60₹ 60, then per day mean wage of the night shift workers (in ₹₹ ) is :
View answer and explanation
Correct option: C
74
Option C (74) is correct. The mean wage of the night shift workers is calculated using the weighted average formula.
137 Medium
137 of 141
Application +4 | -1
A car owner buys petrol at Rs. 7.50 , Rs. 8.00 and Rs. 8.50 per litre for 3 successive years. If he spends Rs. 4000 each year, then the average cost per litre of petrol is
View answer and explanation
Correct option: C
Rs. 7.98
Option C (Rs. 7.98) is correct because it represents the average cost per litre of petrol calculated using the harmonic mean.
138 Medium
138 of 141
Understanding +4 | -1
If xˉ1\bar{x}_1 and xˉ2\bar{x}_2 are means to two distributions such that xˉ1<xˉ2\bar{x}_1 < \bar{x}_2 and xˉ\bar{x} is the mean of the combined distribution, then
View answer and explanation
Correct option: D
xˉ1<xˉ<xˉ2\bar{x}_1 < \bar{x} < \bar{x}_2
Option D (xˉ1<xˉ<xˉ2\bar{x}_1 < \bar{x} < \bar{x}_2) is correct because the mean of the combined distribution must lie between the means of the individual distributions.
139 Medium
139 of 141
Application +4 | -1
If the standard deviation of the numbers 2, 3, aa and 11 is 3.5, then which of the following is true?
View answer and explanation
Correct option: B
3a2−32a+84=03{a^2} - 32a + 84 = 0
Option B (3a2−32a+84=03{a^2} - 32a + 84 = 0) is correct because it is the equation derived from the given standard deviation of the numbers.
140 Medium
140 of 141
Understanding +4 | -1
The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observations of
the set is increased by 2, then the median of the new set
View answer and explanation
Correct option: C
Remains the same as that of the original set
Option C (Remains the same as that of the original set) is correct because the median is the middle value, and increasing the largest values doesn't affect the middle value.
141 Medium
141 of 141
Application +4 | -1
If z=ax+byz=a x+b y and rr is the correlation coefficient between xx and yy, then σz2\sigma_z^2 is equal to
View answer and explanation
Correct option: B
a2σx2+b2σy2−2abrσxσya^2 \sigma_x^2+b^2 \sigma_y^2-2 a b r \sigma_x \sigma_y
Option C (a2σx2+b2σy2+2abrσxσya^2 \sigma_x^2+b^2 \sigma_y^2+2 a b r \sigma_x \sigma_y) is correct because it represents the variance of the linear combination of two variables, including the covariance term.
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