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JEE • MATHEMATICS • STATISTICS

Statistics practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 141 questions

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61 Medium
61 of 141
Application +4 | -1
Forces MM and NN acting at a point OO make an angle 150∘150^{\circ}. Their resultant acts at OO has magnitude 2 unit and is perpendicular to MM. Then, in the same unit, the magnitudes of MM and NN are
View answer and explanation
Correct option: A
23,42 \sqrt{3}, 4
Option A, 23,42 \sqrt{3}, 4, is correct because these magnitudes satisfy the conditions that the resultant is 2 units and perpendicular to M with an angle of 150° between M and N.
62 Medium
62 of 141
Application +4 | -1
The mean and SD of 63 children in an arithmetic test are respectively 27.6 and 7.1. They are added to a new group of 26 who had less training and whose mean is 19.2 and SD 6.2. The values of the combined group of the mean and SD are
View answer and explanation
Correct option: A
25.1,7.825.1,7.8
Option A (25.1, 7.8) is correct because it accurately calculates the combined mean and standard deviation of the two groups using the provided data.
63 Medium
63 of 141
Understanding +4 | -1
Consider any set of 201 observations x1,x2,  …x200,x201{x_1},{x_2},\; \ldots {x_{200}},{x_{201}}. It is given that x1<x2<…<x200<x201{x_1} < {x_2} < \ldots < {x_{200}} < {x_{201}}. Then, the mean deviation of this set of observations about a point kk is minimum when kk equals
View answer and explanation
Correct option: C
x101{x_{101}}
Option C (x101{x_{101}}) is correct because the mean deviation is minimized when calculated about the median, and in this ordered set, the median is the 101st observation.
64 Medium
64 of 141
Application +4 | -1
If SD of XX is s, then SD of the variableμ=aX+bc\mathrm{\mu } = \frac{{aX + b}}{c}, where a,  b,  ca,\;b,\;c are constants, is
View answer and explanation
Correct option: B
∣ac∣σ\left| {\frac{a}{c}} \right|\mathrm{\sigma }
Option B (∣ac∣σ\left| {\frac{a}{c}} \right|\mathrm{\sigma }) is correct because the standard deviation scales linearly with the coefficient of X and inversely with the divisor.
65 Medium
65 of 141
Application +4 | -1
If σx=3,σy=4\sigma_x=3, \sigma_y=4 and σx+y=7\sigma_{x+y}=7, then r(x,y)r(x, y) is
View answer and explanation
Correct option: A
1
Option A (1) is correct because the correlation coefficient is calculated using the covariance and standard deviations, resulting in 1.
66 Medium
66 of 141
Application +4 | -1
The average salary of male employees in a firm was
Rs 5200 and that of females was 4200. The mean salary of all the employees was Rs 5000. The percentage
of male employees is
View answer and explanation
Correct option: A
80
Option A (80) is correct because, by setting up an equation for the mean salary and solving for the ratio of male to female employees, we can find the percentage of male employees.
67 Medium
67 of 141
Application +4 | -1
The arithmetic mean of a set of observations is Xˉ{\bar X}. If each observation is divided by α and then is increased by 10, then the mean of the new series is
View answer and explanation
Correct option: C
Xˉ+10  αα\frac{{\bar X + 10\;\alpha }}{\alpha }
Option C (Xˉ+10;αα\frac{{\bar X + 10\\;\alpha }}{\alpha }) is correct because each observation is divided by α and increased by 10, so the mean is also affected accordingly.
68 Medium
68 of 141
Analyzing +4 | -1
If a linear relation aX+bY+c=0a X+b Y+c=0 exists between the variables XX and YY and ab<0a b < 0, then coefficient of correlation between XX and YY, is
View answer and explanation
Correct option: A
1
Option A (1) is correct because a linear relation with ab<0ab < 0 implies a perfect correlation between X and Y.
69 Medium
69 of 141
Application +4 | -1
The mean square deviation of a set of nn observations x1,x2,…,xnx_1, x_2, \ldots, x_n about a point cc is defined as
1n∑i=1n(xi−c)2\frac{1}{n} \sum\limits_{{i=1}}^n\left(x_i-c\right)^2

The mean square deviation about −2-2 and 22 are 18 and 10 respectively, then standard deviation of this set of observation is
View answer and explanation
Correct option: A
3
Option A (3) is correct because, by using the given mean square deviations about -2 and 2, we can find the mean and then the standard deviation of the set of observations.
70 Medium
70 of 141
Application +4 | -1
If [a×b  b×c  c×a]=λ[a b c]2, [a \times b\,\,b \times c\,\,c \times a] = \lambda {[a\,b\,c]^2},\, then λ\lambda is equal to
View answer and explanation
Correct option: B
1
Option B (1) is correct because, after simplifying the scalar triple product using vector identities, the expression equals [a b c]2, leading to λ = 1.
71 Medium
71 of 141
Application +4 | -1
Mean of a data set is 10 and variance is 4 . If one entry of data set changes from 8 to 12 , then new mean becomes 10.2. Then new variance is:
View answer and explanation
Correct option: B
3.96
Option B (3.96) is correct because the new variance is calculated by considering the change in the data set and applying the variance formula.
72 Medium
72 of 141
Understanding +4 | -1
Let X‾\overline{\mathrm{X}} and M.D. be the mean and the mean deviation about X‾\overline{\mathrm{X}} of n\mathrm{n} observations x,i=1,2\mathrm{x}, \mathrm{i}=1,2, nn. If each of the observations is increased by 5 , then the new mean and the mean deviation about the new mean, respectively, are:
View answer and explanation
Correct option: B
Xˉ+5,M,D\bar{X}+5, \mathrm{M}, \mathrm{D}.
Option B (Xˉ+5,M,D\bar{X}+5, \mathrm{M}, \mathrm{D}.) is correct because adding a constant to each observation increases the mean by the same constant, but the mean deviation remains unchanged.
73 Medium
73 of 141
Application +4 | -1
The mean and median of 100 items are 50 and 52 , respectively. The value of largest item is 100 . It was later found that it is 110 and not 100 . The true mean and median are
View answer and explanation
Correct option: B
50.10,5250.10,52
Option B (50.10,5250.10,52) is correct because the corrected mean is 50.10, and the median remains the same since the change only affects the largest item.
74 Medium
74 of 141
Application +4 | -1
A scientist is weighing each of 30 fishes. Their mean weight worked out is 30gm30 \mathrm{gm} and a standarion deviation of 2gm2 \mathrm{gm}. Later, it was found that the measuring scale was misaligned and always under reported every fish weight by 2gm2 \mathrm{gm}. The correct mean and standard deviation (in gm) of fishes are respectively:
View answer and explanation
Correct option: A
32, 2
Option A (32, 2) is correct. Adding a constant to each observation increases the mean by that constant, but the standard deviation remains unchanged.
75 Medium
75 of 141
Application +4 | -1
The resultant of two forces acting on a particle is at right angles to one of them and its magnitude is one third of the magnitude of the other. The ratio of the larger force to the smaller is
View answer and explanation
Correct option: A
3:223: 2 \sqrt{2}
Option A, 3:223: 2 \sqrt{2}, is correct because it represents the ratio of the larger force to the smaller force, derived from the given conditions using trigonometric relationships.
76 Medium
76 of 141
Application +4 | -1
The average marks of 10 students in a class is 60 with standard deviation 4 while the average marks of other 10 students is 40 with standard deviation 6 . If all the 20 students are taken together, their standard deviation will be
View answer and explanation
Correct option: D
126\sqrt{126}
Option D (126\sqrt{126}) is correct because it's calculated by combining the data from both groups of students, finding the overall mean, and then calculating the combined standard deviation.
77 Medium
77 of 141
Application +4 | -1
You are provided with the following raw data of two variable xx and yy.

Σx=235,Σy=250,Σx2=6750,Σy2=6840\Sigma x=235, \Sigma y=250, \Sigma x^2=6750, \Sigma y^2=6840

Ten pairs of values are included in the survey. The standard deviation are
View answer and explanation
Correct option: A
11.08,7.6811.08,7.68
Option A (11.08,7.68) is correct because it represents the standard deviations of x and y calculated from the given data.
78 Medium
78 of 141
Application +4 | -1
If ∑i=118(xi−8)=9\sum\limits_{{i=1}}^{18}\left(x_i-8\right)=9 and ∑i=118(xi−8)2=45\sum\limits_{{i=1}}^{18}\left(x_i-8\right)^2=45 then the standard deviation of the observations x1,x2,…−x18x_1, x_2, \ldots-x_{18} is
View answer and explanation
Correct option: C
3/23 / 2
Option C (3 / 2) is correct because the standard deviation is calculated using the given sums and the formula for standard deviation.
79 Medium
79 of 141
Application +4 | -1
The mean life of a sample of 60 bulbs was 650 h650 \mathrm{~h} and the standard deviation was 8h. A second sample of 80 bulbs has a mean life of 660 h660 \mathrm{~h} and standard deviation 7 h7 \mathrm{~h}. Find the overall standard deviation.
View answer and explanation
Correct option: C
8.94
Option C (8.94) is correct because it is the overall standard deviation calculated using the combined standard deviation formula.
80 Medium
80 of 141
Application +4 | -1
For the given data, the calculation corresponding to all values of variates (x,y)\left( {x,y} \right) is following   ∑(x−xˉ)2=36,  ∑(y−yˉ)2=25,  ∑(x−xˉ)(y−yˉ)=20\;\sum {\left( {x - \bar x} \right)^2} = 36,\;\sum {\left( {y - \bar y} \right)^2} = 25,\;\sum \left( {x - \bar x} \right)\left( {y - \bar y} \right) = 20. The Karl Pearson&rsquo;s correlation coefficient is
View answer and explanation
Correct option: C
0.66
Option C (0.66) is correct because it is the calculated Karl Pearson's correlation coefficient using the given data.
81 Medium
81 of 141
Application +4 | -1
Let xˉ,M\bar{x}, M and σ2\sigma^2 be respectively the mean, mode and variance of nn observations x1,x2,…,xn\mathrm{x}_1, \mathrm{x}_2, \ldots, \mathrm{x}_{\mathrm{n}} and di=−xi−a\mathrm{d}_{\mathrm{i}}=-\mathrm{x}_{\mathrm{i}}-\mathrm{a}, i=1,2,…,n\mathrm{i}=1,2, \ldots, \mathrm{n}, where a\mathrm{a} is any number.

Statement I: Variance of d1,d2,…dnd_1, d_2, \ldots d_n is σ2\sigma^2.

Statement II: Mean and mode of d1, d2,…dn\mathrm{d}_1, \mathrm{~d}_2, \ldots \mathrm{d}_{\mathrm{n}} are −x‾−a-\overline{\mathrm{x}}-\mathrm{a} and −M−a-\mathrm{M}-\mathrm{a}, respectively.
View answer and explanation
Correct option: B
Statement I and Statement II are both true
Option B (Statement I and Statement II are both true) is correct. Shifting the data by a constant affects the mean and mode but not the variance.
82 Medium
82 of 141
Application +4 | -1
Let xi(1≤ i ≤ 10){x_i}(1 \le \,i\, \le \,10) be ten observations of a random variable X. If ∑i=i10(xi−p) = 3 and ∑i=i10(xi−p)2 = 9  X.\,\mathrm{If}\,\sum\limits_{i = i}^{10} {({x_i} - p)} \, = \,3\,\mathrm{and}\,\sum\limits_{i = i}^{10} {{{({x_i} - p)}^2}\, = \,9\,\,} pp where 0≠ p∈R,\mathrm{0} \ne \,p \in R, then the standard deviation of these observation is
View answer and explanation
Correct option: A
910\frac{9}{{10}}
Option A (910\frac{9}{{10}}) is correct because it is the standard deviation calculated from the given summations.
83 Medium
83 of 141
Application +4 | -1
If the regression coefficients are 0.8 and 0.2, then the value of coefficient of correlation is
View answer and explanation
Correct option: B
0.4
Option B (0.4) is correct because the coefficient of correlation is the square root of the product of the regression coefficients.
84 Medium
84 of 141
Understanding +4 | -1
Statement-I: The series having greater CV is said to be
less variable than the other.

Statement-II: The series having lesser CV is said to be
more consistent than the other.
View answer and explanation
Correct option: B
Only Statement II is true
Option B (Only Statement II is true) is correct because a lower coefficient of variation indicates more consistency, not less variability.
85 Medium
85 of 141
Application +4 | -1
The variates xx and uu are related by hu=x−ah u=x-a, then correct relation between σx\sigma_x and σa\sigma_{\mathrm{a}} is
View answer and explanation
Correct option: A
σx=hσa\sigma_x=h \sigma_a
Option A (σx=hσu\sigma_x=h \sigma_u) is correct because it represents the correct relationship between the standard deviations of x and u, given the linear transformation hu = x - a.
86 Medium
86 of 141
Analyzing +4 | -1
The correlation between xx and a−xa-x is
View answer and explanation
Correct option: A
-1
Option A (-1) is correct because the correlation between x and a-x is always -1, indicating a perfect negative linear relationship.
87 Medium
87 of 141
Application +4 | -1
If the standard deviation of x1,x2,…x{x_1},{x_2}, \ldots x is 3.5, then the standard deviation of −2x1−3,  −2x2−3,  …,−2xn−3- 2{x_1} - 3,\; - 2{x_2} - 3,\; \ldots , - 2{x_n} - 3 is
View answer and explanation
Correct option: C
77
Option C (77) is correct because the standard deviation is affected by the absolute value of the scaling factor, which is 2 in this case.
88 Medium
88 of 141
Application +4 | -1
If the resultant of two forces of magnitude PP and 2P2 P is perpendicular to PP, then the angle between the forces is
View answer and explanation
Correct option: A
2π/32 \pi / 3
Option A, 2π3\frac{2 \pi}{3}, is correct because it is the angle between the forces that satisfies the condition that the resultant is perpendicular to P.
89 Medium
89 of 141
Application +4 | -1
If the standard deviation of a variable xx is σ\sigma, then the standard deviation of another variable ax+bc\frac{{ax + b}}{c} is
View answer and explanation
Correct option: B
σac\frac{{\sigma a}}{c}
The correct answer is B (σac\frac{{\sigma a}}{c}) because standard deviation is affected by scaling but not by translation.
90 Medium
90 of 141
Analyzing +4 | -1
Let the mean and standard deviation of marks of class AA of 100 students be respectively 40 and α\alpha (>0)(> 0), and the mean and standard deviation of marks of class BB of nn students be respectively 55 and 30−α30-\alpha. If the mean and variance of the marks of the combined class of 100+n100+n students are respectively 50 and 350, then the sum of variances of classes AA and BB is:
View answer and explanation
Correct option: D
500
Option D (500) is correct because, after setting up equations for the means and variances of the two classes and the combined class, solving for the unknowns yields the sum of the variances of classes A and B as 500.
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