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JEE • MATHEMATICS • STATISTICS

Statistics practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 312 questions

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271 Easy
271 of 312
Application +4 | -1
When a particle be kept at rest under the action of the following forces
View answer and explanation
Correct option: A
↑8N,↑5N,↓13N\uparrow 8 N, \uparrow 5 N, \downarrow 13 N
Option A, ↑8N,↑5N,↓13N\uparrow 8 N, \uparrow 5 N, \downarrow 13 N, is correct because the upward forces sum to equal the downward force, resulting in equilibrium.
272 Easy
272 of 312
Application +4 | -1
The correlation coefficient of two variable xx and yy is 0.8. The regression coefficient of yy on xx is 0.2, than the regression coefficient of xx on yy is
View answer and explanation
Correct option: A
3.23.2
Option A (3.23.2) is correct because it is calculated using the formula relating the correlation coefficient and regression coefficients.
273 Easy
273 of 312
Application +4 | -1
Let σ\sigma be standard deviation of nn observations. Each observation is multiplied by a constant cc. The standard deviation of resulting numbers is
View answer and explanation
Correct option: B
cσc \sigma
Option B (cσc \sigma) is correct because multiplying each observation by a constant multiplies the standard deviation by the absolute value of that constant.
274 Easy
274 of 312
Application +4 | -1
If the heights of 5 persons are 144 cm,153 cm,150 cm,158 cm144 \mathrm{~cm}, 153 \mathrm{~cm}, 150 \mathrm{~cm}, 158 \mathrm{~cm} and 155 cm155 \mathrm{~cm} respectively, then mean height is-
View answer and explanation
Correct option: C
152 cm152 \mathrm{~cm}
Option C (152 cm152 \text{{ cm}}) is correct because the mean height is calculated by summing the heights and dividing by the number of persons.
275 Easy
275 of 312
Application +4 | -1
In an experiment with 15 observations onx, the following results were available ∑x2=2830,  ∑x=170\sum {x^2} = 2830,\;\sum x = 170. One observation that was 20, was found to be wrong and was replaced by the correct value 30. Then, the corrected variance is
View answer and explanation
Correct option: A
78.078.0
Option A (78.078.0) is correct because it is the corrected variance calculated after replacing the incorrect observation with the correct value and using the variance formula.
276 Easy
276 of 312
Application +4 | -1
If the first item is increased by 1, second by 2 and so on, then the new mean is
View answer and explanation
Correct option: C
Xˉ+n+12\bar X + \frac{{n + 1}}{2}
Option C (Xˉ+n+12\bar X + \frac{{n + 1}}{2}) is correct because it represents the new mean after increasing each item by its position in the series.
277 Easy
277 of 312
Application +4 | -1
The quartile deviation of daily wages of 7 persons which are Rs. 12,7,15,10,17,17,25 is
View answer and explanation
Correct option: D
3.5
Option D (3.5) is correct because the quartile deviation is calculated as half the difference between the third and first quartiles.
278 Easy
278 of 312
Application +4 | -1
Coefficient of variance of a distribution is 60%60 \% and the standard deviation is 25 . The arithmetic mean of the distribution is
View answer and explanation
Correct option: C
1253\frac{125}{3}
Option C (1253\frac{125}{3}) is correct because the coefficient of variance is defined as the ratio of the standard deviation to the mean, allowing us to solve for the mean.
279 Easy
279 of 312
Application +4 | -1
If the frequencies of first four numbers out of 1,2,4,6,81,2,4,6,8 are 2 , 3,3,23,3,2, respectively, then the frequency of 8 , if their AM is 5 , is
View answer and explanation
Correct option: C
6
Option C (6) is correct because it is the frequency of 8 that results in the given arithmetic mean of 5.
280 Easy
280 of 312
Application +4 | -1
The mean marks of 120 students is 20. It was later
discovered that two marks were wrongly taken as 50
and 80 instead of 15 and 18. The correct mean of
marks is
View answer and explanation
Correct option: A
19.19
Option A (19.19) is correct because it represents the corrected mean after accounting for the wrongly taken marks.
281 Easy
281 of 312
Application +4 | -1
The mean and the standard deviation (s.d.) of 10 observations are 20 and 2 respectively. Each of these 10 observations is multiplied by pp and then reduced by q,q, where p≠0p \ne 0 and q≠0.q \ne 0. If the new mean and new s.d. become half of their original values, then qq is equal to
View answer and explanation
Correct option: D
-20
Option D (-20) is correct because it is the value of q that satisfies the given conditions for the new mean and standard deviation.
282 Easy
282 of 312
Application +4 | -1
The mean age of a combined group of men and women is 25 yr. If the mean age of the group of men is 26 yr and that of the group of women is 21 yr, then the percentage of men and women in the group are respectively
View answer and explanation
Correct option: B
80, 20
Option B (80, 20) is correct because the percentages of men and women are calculated using the combined mean formula.
283 Easy
283 of 312
Application +4 | -1
The mean of 6 distinct observation is 6.5 and their variance is 10.25. if 4 out of 6 observations are 2, 4, 5 and 7, then the remaining two observations are
View answer and explanation
Correct option: A
10, 11
Option A (10, 11) is correct because it satisfies both the mean and variance conditions given the other four observations.
284 Easy
284 of 312
Application +4 | -1
The median of the following items 25,15,23,40,27,25,23,2525,15,23,40,27,25,23,25 and 20 is
View answer and explanation
Correct option: C
25
Option C (25) is correct because it is the middle value when the data is arranged in ascending order.
285 Easy
285 of 312
Application +4 | -1
The S.D. of the series a,  a+d,a+2  d,…,a+2nd,\mathrm{a},\mathrm{\;}a + d,a + 2\;d, \ldots ,a + 2nd, is
View answer and explanation
Correct option: B
n(n+1)3d\sqrt {\frac{{n\left( {n + 1} \right)}}{3}} d
Option B (n(n+1)3d\sqrt {\frac{{n\left( {n + 1} \right)}}{3}} d) is correct because it's the correct formula for the standard deviation of an arithmetic series.
286 Easy
286 of 312
Application +4 | -1
The geometric mean of the series 1,2,4,…,2∗1,2,4, \ldots, 2^*, is
View answer and explanation
Correct option: B
2(x+I/22^{(x+\mathrm{I} / 2}
Option B (2n+122^{{\frac{{n+1}}{{2}}}}) is correct because it represents the geometric mean of the given series.
287 Easy
287 of 312
Application +4 | -1
The average of the squares of the numbers 0,  1,  2,  3,4,  ...,  n,0,\;1,\;2,\;3,4,\;...,\;n, is
View answer and explanation
Correct option: B
16n(2n+1)\frac{1}{6}n\left( {2n + 1} \right)
Option B (16n(2n+1)\frac{1}{6}n(2n + 1)) is correct because it is the average of the squares of the numbers from 0 to n.
288 Easy
288 of 312
Analyzing +4 | -1
The mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of correct and incorrect observations is 70. If the correct mean is 16, then the correct variance is equal to:
View answer and explanation
Correct option: C
43
Option C (43) is correct because it represents the correct variance after adjusting for the incorrect observation and the correct mean.
289 Easy
289 of 312
Application +4 | -1
If 25%25 \% of items are less than 10 and 25%25 \% are more than 40 , then coefficient of quartile deviation is
View answer and explanation
Correct option: D
3/53 / 5
Option D (3/53 / 5) is correct because the coefficient of quartile deviation is calculated as (Q3-Q1)/(Q3+Q1) = (40-10)/(40+10) = 3/5.
290 Easy
290 of 312
Application +4 | -1
The mean and variance of 7 observations are 8 and 16, respectively. If five observations are 2, 4, 10, 12, 14, then the absolute difference of the remaining two observations is
View answer and explanation
Correct option: D
2
The correct answer is D (2) because it is the absolute difference between the two remaining observations, calculated using the given mean and variance.
291 Easy
291 of 312
Application +4 | -1
The two lines of regression are x+2y−5=0x+2 y-5=0 and x+3y−8=0x+3 y-8=0. The coefficient of correlation between xx and yy is
View answer and explanation
Correct option: A
-0.82
Option A (9.6 m/h) is correct because the average speed is calculated using the harmonic mean of the given speeds.
292 Easy
292 of 312
Application +4 | -1
The standard deviation of n observations x1,x2,…..,xn  {x_1},{x_2}, \ldots ..,{x_n}\; is 2. If   ∑i=1nxi=20  and  ∑i=1nxi2=100\;\sum \limits_{i = 1}^n {x_i} = 20\;and\;\sum \limits_{i = 1}^n x_i^2 = 100, then n is
View answer and explanation
Correct option: C
5  or  205\;\mathrm{ }or\;\mathrm{ }20
Option C (5 or 20) is correct because these are the possible values of n that satisfy the given conditions for the standard deviation and sums.
293 Easy
293 of 312
Application +4 | -1
The mean of 18 observations is 7 and if in each observation 5 is added, then the new mean will be
View answer and explanation
Correct option: B
12
Option B (12) is correct because adding a constant to each observation increases the mean by the same constant.
294 Easy
294 of 312
Application +4 | -1
The median of 19 observations of a group is 30. If two observations with values 8 and 32 are further included, then the median of the new group of 21 observations will be
View answer and explanation
Correct option: B
30
Option B (30) is correct because adding two observations, one smaller and one larger than the median, does not change the position of the middle element in the ordered set.
295 Easy
295 of 312
Understanding +4 | -1
The mode of a set of observations 7,12,8,5,6,4,97,12,8,5,6,4,9, 10,8,9,7,9,6,5,910,8,9,7,9,6,5,9 is
View answer and explanation
Correct option: C
9
Option C (9) is correct because 9 appears most frequently in the given set of observations.
296 Easy
296 of 312
Application +4 | -1
The standard deviation of the numbers 31, 32, 33,…., 46, 47 is
View answer and explanation
Correct option: C
262\sqrt 6
Option C (262\sqrt 6) is correct because it represents the standard deviation of the given series of consecutive integers.
297 Easy
297 of 312
Application +4 | -1
For a series, the value of mean deviation is 15 . The most likely value of its quartile deviation is
View answer and explanation
Correct option: A
12.5
Option A (12.5) is correct because it is the most likely value of quartile deviation given the mean deviation is 15, using the relationship between MD, QD, and SD.
298 Easy
298 of 312
Application +4 | -1
The two lines of regression are 8x−10y=668 x-10 y=66 and 40x−18y=21440 x-18 y=214 and variance of xx is 9 . The standard deviation of yy series is
View answer and explanation
Correct option: C
4
Option A (b1−a\frac{{b}}{{1-a}} or β1−α\frac{{\beta}}{{1-\alpha}}) is correct because the mean of x and y series is found by solving the regression equations with the condition that the means are equal.
299 Easy
299 of 312
Application +4 | -1
Combined mean of two series x1x_1 and x2x_2, when Σx1=210,Σx2=150,n1=50,n2=100\Sigma x_1=210, \Sigma x_2=150, n_1=50, n_2=100 is
View answer and explanation
Correct option: C
170
Option D (170) is correct because the combined mean is calculated using the formula for combined mean.
300 Easy
300 of 312
Understanding +4 | -1
The arithmetic mean of first nn odd natural numbers is
View answer and explanation
Correct option: A
nn
Option A (nn) is correct because the sum of the first n odd natural numbers is n2n^2, and dividing by n gives the mean as n.
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