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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 465 questions

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181 Medium
181 of 465
Application +4 | -1
If [a×b  b×c  c×a]=λ[a b c]2, [a \times b\,\,b \times c\,\,c \times a] = \lambda {[a\,b\,c]^2},\, then λ\lambda is equal to
View answer and explanation
Correct option: B
1
Option B (1) is correct because, after simplifying the scalar triple product using vector identities, the expression equals [a b c]2, leading to λ = 1.
182 Medium
182 of 465
Application +4 | -1
Mean of a data set is 10 and variance is 4 . If one entry of data set changes from 8 to 12 , then new mean becomes 10.2. Then new variance is:
View answer and explanation
Correct option: B
3.96
Option B (3.96) is correct because the new variance is calculated by considering the change in the data set and applying the variance formula.
183 Easy
183 of 465
Application +4 | -1
If each of n numbers xi=i{x_i} = i is replaced by (i+1)xi,\left( {i + 1} \right){x_i}, then the new mean is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated new mean does not match any of the provided options.
184 Medium
184 of 465
Understanding +4 | -1
Let X‾\overline{\mathrm{X}} and M.D. be the mean and the mean deviation about X‾\overline{\mathrm{X}} of n\mathrm{n} observations x,i=1,2\mathrm{x}, \mathrm{i}=1,2, nn. If each of the observations is increased by 5 , then the new mean and the mean deviation about the new mean, respectively, are:
View answer and explanation
Correct option: B
Xˉ+5,M,D\bar{X}+5, \mathrm{M}, \mathrm{D}.
Option B (Xˉ+5,M,D\bar{X}+5, \mathrm{M}, \mathrm{D}.) is correct because adding a constant to each observation increases the mean by the same constant, but the mean deviation remains unchanged.
185 Medium
185 of 465
Application +4 | -1
The mean and median of 100 items are 50 and 52 , respectively. The value of largest item is 100 . It was later found that it is 110 and not 100 . The true mean and median are
View answer and explanation
Correct option: B
50.10,5250.10,52
Option B (50.10,5250.10,52) is correct because the corrected mean is 50.10, and the median remains the same since the change only affects the largest item.
186 Easy
186 of 465
Application +4 | -1
The first of two samples in a group has 100 items with mean 15 and standard deviation 3. If the whole group has 250 items with mean 15.6 and standard deviation 13.44,\sqrt {13.44} , then the standard deviation of the second sample is
View answer and explanation
Correct option: C
4
Option C (4) is correct because it is the standard deviation calculated using the combined mean and standard deviation formulas, accounting for both samples.
187 Medium
187 of 465
Application +4 | -1
A scientist is weighing each of 30 fishes. Their mean weight worked out is 30gm30 \mathrm{gm} and a standarion deviation of 2gm2 \mathrm{gm}. Later, it was found that the measuring scale was misaligned and always under reported every fish weight by 2gm2 \mathrm{gm}. The correct mean and standard deviation (in gm) of fishes are respectively:
View answer and explanation
Correct option: A
32, 2
Option A (32, 2) is correct. Adding a constant to each observation increases the mean by that constant, but the standard deviation remains unchanged.
188 Easy
188 of 465
Application +4 | -1
The mean and variance of 20 observations are found to be 10 and 4, respectively. On rechecking, it was found that an observation 9 was incorrect and the correct observation was 11. Then the correct variance is
View answer and explanation
Correct option: B
3.99
Option A (1, -1, 1) is correct because it satisfies the equation of the plane found using the midpoint and normal vector.
189 Easy
189 of 465
Understanding +4 | -1
If there exists a linear statistical relationship between two variable x  and  y{x\;and\;y}, then the regression coefficient of y  on    x{y\;on\;\;x} is
View answer and explanation
Correct option: C
cov(x,y)σx2\frac{{cov\left( {x,y} \right)}}{{\sigma _x^2}}
Option C (cov(x,y)σx2\frac{{cov\left( {x,y} \right)}}{{\sigma _x^2}}) is correct because it is the formula for the regression coefficient of y on x.
190 Easy
190 of 465
Understanding +4 | -1
A body is on the point of sliding down an inclined plane under its own weight. If the inclination of the plane to the horizon be 30∘30^{\circ}, the angle of friction will be
View answer and explanation
Correct option: A
30∘30^{\circ}
Option A (30∘30^{\circ}) is correct because when a body is on the point of sliding, the angle of inclination is equal to the angle of friction.
191 Easy
191 of 465
Application +4 | -1
The AM of 2n+1C0,    2n+1C1,  2n+1C2,…,  2n+1Cn^{2n + 1}{C_0},\;{\;^{2n + 1}}{C_1},{\;^{2n + 1}}{C_2}, \ldots ,{\;^{2n + 1}}{C_n} is
View answer and explanation
Correct option: D
22n(n+1)\frac{{{2^{2n}}}}{{\left( {n + 1} \right)}}
Option D (22n(n+1)\frac{{{2^{2n}}}}{{\left( {n + 1} \right)}}) is correct because it represents the arithmetic mean of the given binomial coefficients.
192 Easy
192 of 465
Application +4 | -1
Let a,b∈Ra, b \in {R}. Let the mean and the variance of 6 observations −3,4,7,−6,a,b-3,4,7,-6, a, b be 2 and 23, respectively. The mean deviation about the mean of these 6 observations is:
View answer and explanation
Correct option: A
133\frac{13}{3}
Option A (133\frac{13}{3}) is correct because it calculates the mean deviation about the mean of the given observations after finding the values of a and b.
193 Easy
193 of 465
Understanding +4 | -1
Consider the following statements

(1) Mode can be computed from histogram

(2) Median is not independent of change of scale

(3) Variance is independent of change of origin and scale

Which of these is/are correct?
View answer and explanation
Correct option: C
Only (1) and (2)
Option C (Only (1) and (2)) is correct because mode can be computed from a histogram, and the median is not independent of a change of scale. Variance is dependent on the change of scale.
194 Medium
194 of 465
Application +4 | -1
The resultant of two forces acting on a particle is at right angles to one of them and its magnitude is one third of the magnitude of the other. The ratio of the larger force to the smaller is
View answer and explanation
Correct option: A
3:223: 2 \sqrt{2}
Option A, 3:223: 2 \sqrt{2}, is correct because it represents the ratio of the larger force to the smaller force, derived from the given conditions using trigonometric relationships.
195 Easy
195 of 465
Analyzing +4 | -1
Suppose values taken by a variable xx are such that a≤xi≤ba \leq x_i \leq b, where xix_i denotes the value of xx in the ii th case for i=1,2,3,…,ni=1,2,3, \ldots, n. Then,
View answer and explanation
Correct option: D
(b−a)2≥Var⁡(x)(b-a)^2 \geq \operatorname{Var}(x)
Option D ((b−a)2≥Var⁡(x)(b-a)^2 \geq \operatorname{{Var}}(x)) is correct because the variance is always less than or equal to the square of the range.
196 Medium
196 of 465
Application +4 | -1
The average marks of 10 students in a class is 60 with standard deviation 4 while the average marks of other 10 students is 40 with standard deviation 6 . If all the 20 students are taken together, their standard deviation will be
View answer and explanation
Correct option: D
126\sqrt{126}
Option D (126\sqrt{126}) is correct because it's calculated by combining the data from both groups of students, finding the overall mean, and then calculating the combined standard deviation.
197 Hard
197 of 465
Application +4 | -1
In a set of 2n2 \mathrm{n} observations, half of them are equal to ' a\mathrm{a} ' and the remaining half are equal to '- a′\mathrm{a}^{\prime}. If the standard deviation of all the observations is 2 ; then the value of ∣a∣|a| is :
View answer and explanation
Correct option: A
2
Option A (2) is correct. The standard deviation is calculated using the given information about the observations.
198 Easy
198 of 465
Application +4 | -1
The variance of first n numbers is
View answer and explanation
Correct option: B
n2−112\frac{{{n^2} - 1}}{{12}}
Option B (n2−112\frac{{{n^2} - 1}}{{12}}) is correct because it is the standard formula for the variance of the first n natural numbers.
199 Easy
199 of 465
Understanding +4 | -1
The standard deviation of certain data is 4 . Then, their variance is
View answer and explanation
Correct option: B
16
Option B (16) is correct because variance is the square of the standard deviation, so 42=164^2 = 16.
200 Medium
200 of 465
Application +4 | -1
You are provided with the following raw data of two variable xx and yy.

Σx=235,Σy=250,Σx2=6750,Σy2=6840\Sigma x=235, \Sigma y=250, \Sigma x^2=6750, \Sigma y^2=6840

Ten pairs of values are included in the survey. The standard deviation are
View answer and explanation
Correct option: A
11.08,7.6811.08,7.68
Option A (11.08,7.68) is correct because it represents the standard deviations of x and y calculated from the given data.
201 Easy
201 of 465
Application +4 | -1
The standard deviations of two sets containing 10 and 20 members are 2 and 3 , respectively measured from their common mean 5 . The SD for the whole set of 30 members is
View answer and explanation
Correct option: C
223\sqrt{\frac{22}{3}}
Option C (223\sqrt{\frac{22}{3}}) is correct because it is the standard deviation calculated using the formula for combined standard deviation.
202 Medium
202 of 465
Application +4 | -1
If ∑i=118(xi−8)=9\sum\limits_{{i=1}}^{18}\left(x_i-8\right)=9 and ∑i=118(xi−8)2=45\sum\limits_{{i=1}}^{18}\left(x_i-8\right)^2=45 then the standard deviation of the observations x1,x2,…−x18x_1, x_2, \ldots-x_{18} is
View answer and explanation
Correct option: C
3/23 / 2
Option C (3 / 2) is correct because the standard deviation is calculated using the given sums and the formula for standard deviation.
203 Easy
203 of 465
Application +4 | -1
The variance of 15 observations was found to be 8 . If each observation is multiplied by 4 , the new variance of the series is
View answer and explanation
Correct option: D
128
Option D (128) is correct because multiplying each observation by a constant multiplies the variance by the square of that constant.
204 Easy
204 of 465
Application +4 | -1
In a class of 50 students, 10 have failed and their average marks are 28. The total marks obtained by the entire class are 2800. The average marks of those who have passed, are
View answer and explanation
Correct option: C
63
The correct answer is C (63) because it is calculated by subtracting the total marks of failed students from the total marks of all students, then dividing by the number of passed students.
205 Easy
205 of 465
Application +4 | -1
If the sum of 11 consecutive natural numbers is 2761, then the middle number is
View answer and explanation
Correct option: C
251
Option C (251) is correct because when the sum of consecutive numbers is known, dividing the sum by the number of terms gives the middle term directly when the number of terms is odd.
206 Hard
206 of 465
Application +4 | -1
The regression coefficient of yy on x is 2/3 and that of xx on yy is 4/3 .The acute angle between the two regression lines is tan⁡−1k,  {\tan ^{ - 1}}k,\; where kk is equal to
View answer and explanation
Correct option: C
1/181/18
Option C (1/18) is correct because the acute angle between the regression lines is calculated using the given regression coefficients.
207 Easy
207 of 465
Application +4 | -1
If n=10,xˉ=12n=10, \bar{x}=12 and Σx2=1530\Sigma x^2=1530, then coefficient of variation is
View answer and explanation
Correct option: C
25
Option C (25) is correct because the coefficient of variation is calculated using the formula C.V = 100 * (standard deviation / mean).
208 Easy
208 of 465
Understanding +4 | -1
The standard deviation of the wages of 85 employees is ₹ 15.40. After one year, each of them is given an increment of ₹ 25 . The standard deviation of new wages (in ₹ˉ\bar{₹} ) is
View answer and explanation
Correct option: A
15.4
Option A (15.4) is correct because the standard deviation is independent of the change of origin (adding a constant to each value).
209 Easy
209 of 465
Application +4 | -1
The mean deviation from the mean of the series a,  a+d,a+2  d,…,a+2nd,\mathrm{a},\mathrm{\;}a + d,a + 2\;d, \ldots ,a + 2nd, is
View answer and explanation
Correct option: B
n(n+1)d2  n+1\frac{{n\left( {n + 1} \right)d}}{{2\;n + 1}}
Option B (n(n+1)d2;n+1\frac{{n\left( {n + 1} \right)d}}{{2\\;n + 1}}) is correct because it represents the mean deviation from the mean of the given arithmetic series.
210 Easy
210 of 465
Application +4 | -1
Harmonic mean of 2,4,52,4,5 is.....
View answer and explanation
Correct option: B
3.16
Option B (3.16) is correct because it is the result of calculating the harmonic mean of the given numbers 2, 4, and 5.
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