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JEE • MATHEMATICS • SEQUENCE OF SERIES

Sequence of series practice · Easy

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211 Easy
211 of 998
Analyzing +4 | -1
The sum of the series 12+2.22+32+2.42+52+2.62+….+2(2m)21^{2}+2.2^{2}+3^{2}+2.4^{2}+5^{2}+2.6^{2}+\ldots .+2(2 m)^{2} is
View answer and explanation
Correct option: A
m(2m+1)2m(2 m+1)^{2}
Option A (m(2m+1)²) is correct because the sum of the series can be simplified and expressed as m(2m+1)².
212 Easy
212 of 998
Application +4 | -1
If one A.M. ' aa ' and two G.M.'s pp and qq be inserted between any two numbers, then the value of p3+q3p^3+q^3 is
View answer and explanation
Correct option: B
$2 apq$
Option B ($2 apq$) is correct because it correctly relates the arithmetic mean 'a' and the two geometric means 'p' and 'q' inserted between two numbers.
213 Easy
213 of 998
Analyzing +4 | -1
If ∑k=1n(∑m=1km2)=an4+bn3+cn2+dn+e\sum\limits_{{k=1}}^n\left(\sum\limits_{{m=1}}^k m^2\right)=a n^4+b n^3+c n^2+d n+e, then
View answer and explanation
Correct option: A
a=112a=\frac{1}{12}
Option A (112\frac{1}{12}) is correct because it is the coefficient of n4n^4 after expanding and simplifying the given summation.
214 Easy
214 of 998
Analyzing +4 | -1
If log⁡ab−c=log⁡bc−a=log⁡ca−b,\frac{{\log a}}{{b - c}} = \frac{{\log b}}{{c - a}} = \frac{{\log c}}{{a - b}}, then aabbcc={a^a}{b^b}{c^c} =
View answer and explanation
Correct option: B
1
Option B (1) is correct because when log⁡ab−c=log⁡bc−a=log⁡ca−b=λ\frac{{\log a}}{{b - c}} = \frac{{\log b}}{{c - a}} = \frac{{\log c}}{{a - b}} = \lambda, then aabbcc=1{a^a}{b^b}{c^c} = 1.
215 Easy
215 of 998
Analyzing +4 | -1
If ax3+bx2+cx+da x^3+b x^2+c x+d is divisible by ax2+ca x^2+c, then a,b,c,da, b, c, d are in
View answer and explanation
Correct option: B
G.P.
Option B (G.P.) is correct because the divisibility condition implies that a,b,c,da, b, c, d are in geometric progression, satisfying the relation bc=adbc = ad.
216 Easy
216 of 998
Application +4 | -1
The nth and 10th10 t h terms of aGPa G P 5,25,125,…5,25,125, \ldots, are respectively
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Correct option: C
5n,5105^n, 5^{10}
Option C (5n,5105^n, 5^{10}) is correct because the nth term of the GP is 5n5^n and the 10th term is 5105^{10}.
217 Easy
217 of 998
Analyzing +4 | -1
Let A1,A2,A3,…{A_1},{A_2},{A_3}, \ldots be an increasing geometric progression of positive real numbers. If A1A3A5A7=11296{A_1}{A_3}{A_5}{A_7} = \frac{1}{{1296}} and A2+A4=736,{A_2} + {A_4} = \frac{7}{{36}}, then, the value of A6+A8+A10{A_6} + {A_8} + {A_{10}} is equal to
View answer and explanation
Correct option: C
43
Option C (43) is correct because it is obtained by solving the geometric progression equations and finding the sum of the specified terms.
218 Easy
218 of 998
Application +4 | -1
If sum of the series ∑n=0∞rn=S\sum \limits_{n = 0}^\infty {r^n} = S for ∣r∣<1\left| r \right| < 1, then sum of the series ∑n=0∞r2n\sum \limits_{n = 0}^\infty {r^{2n}} , is
View answer and explanation
Correct option: D
S22S−1\frac{{{S^2}}}{{2S - 1}}
Option D (S22S−1\frac{{{S^2}}}{{2S - 1}}) is correct because by substituting the expression for r in terms of S, we find the sum of the series to be S22S−1\frac{{{S^2}}}{{2S - 1}}.
219 Easy
219 of 998
Application +4 | -1
Let {an}n=0∞\left\{a_n\right\}_{n=0}^{\infty} be a sequence such that a0=a1=0a_0=a_1=0 and an+2=2an+1−an+1a_{n+2}=2 a_{n+1}-a_n+1 for all n≥0n \geq 0.
Then ∑n=2∞an7n\sum\limits_{n=2}^{\infty} \frac{a_n}{7^n} is equal to :
View answer and explanation
Correct option: B
7216\frac{7}{216}
Option B (7216\frac{7}{216}) is correct because it is the result of solving the recurrence relation and summing the infinite series.
220 Easy
220 of 998
Analyzing +4 | -1
If three unequal numbers p,  q,  rp,\;q,\;r are in HP and their squares are in AP, then the ratio p  :q  :rp\;:q\;:r is
View answer and explanation
Correct option: D
1∓3  :−2  :1±31 \mp \sqrt 3 \;: - 2\;:1 \pm \sqrt 3
Option D (1∓3  :−2  :1±31 \mp \sqrt 3 \;:- 2\;:1 \pm \sqrt 3) is correct because it represents the ratio of p:q:rp:q:r when p,q,rp, q, r are in HP and their squares are in AP.
221 Easy
221 of 998
Application +4 | -1
The sum of nn terms of an A.P. is 3n2+5.3{n^2} + 5. The number of term which equals 159 is
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Correct option: C
27
Option C (27) is correct because the nth term of the A.P. is derived from the sum of n terms, and solving for n when the term equals 159 yields 27.
222 Easy
222 of 998
Analyzing +4 | -1
For three positive integers p,q,r,xpq2=yqr=zp2rp, q, r, x^{p q^{2}}=y^{q r}=z^{p^{2} r} and r=pq+1r=p q+1 such that 3,3log⁡yx,3log⁡zy,7log⁡x3,3 \log _{y} x, 3 \log _{z} y, 7 \log _{x} zz are in A.P with common difference 12\frac{1}{2}. Then r−p−r-p- qq is equal to
View answer and explanation
Correct option: B
2
Option B (2) is correct because it is obtained by solving the given equations and the arithmetic progression conditions to find the values of p, q, and r.
223 Easy
223 of 998
Understanding +4 | -1
If a1,a2,a3,…,an{a_1},{a_2},{a_3}, \ldots ,{a_n} are the nn arithmetic means between aa and bb, then 2∑i=1nai2\sum \limits_{i = 1}^n {a_i} equals
View answer and explanation
Correct option: B
n(a+b)n\left( {a + b} \right)
Option B (n(a+b)n\left( {a + b} \right)) is correct because the sum of n arithmetic means between a and b is n times the average of a and b.
224 Easy
224 of 998
Analyzing +4 | -1
Let a, b, c, d and p be any non-zero distinct real numbers such that (a2+b2+c2)p2−2(ab+bc+cd)p+(b2+c2+d2)=0.({a^2} + {b^2} + {c^2}){p^2} - 2(ab + bc + cd)p + ({b^2} + {c^2} + {d^2}) = 0. Then,
View answer and explanation
Correct option: C
a, b, c, d are in GP
Option C (a, b, c, d are in GP) is correct because the given equation leads to the condition that the ratio between consecutive terms is constant, indicating a geometric progression.
225 Easy
225 of 998
Application +4 | -1
The value of log⁡2log⁡2log⁡4256+2log⁡22,{\log _2}{\log _2}{\log _4}256 + 2{\log _{\sqrt 2 }}2, is
View answer and explanation
Correct option: C
5
Option C (5) is correct because by simplifying the logarithmic expression step-by-step, the final result is 5.
226 Easy
226 of 998
Application +4 | -1
For x∈R, let[x]x \in R,\,\mathrm{let}\left[ x \right] denote the greatest integer ≤x\le x, then the sum of the series
[−13]+[−13−1100]+[−13−2100]+...+[−13−99100]\left[ { - \frac{1}{3}} \right] + \left[ { - \frac{1}{3} - \frac{1}{{100}}} \right] + \left[ { - \frac{1}{3} - \frac{2}{{100}}} \right] + ... + \left[ { - \frac{1}{3} - \frac{{99}}{{100}}} \right] is
View answer and explanation
Correct option: B
−133- 133
Option B (-133) is correct because it is the sum of the series after evaluating the greatest integer function for each term.
227 Easy
227 of 998
Application +4 | -1
If log⁡42+log⁡44+log⁡416+log⁡4x=6,{\log _4}2 + {\log _4}4 + {\log _4}16 + {\log _4}x = 6, then x=x =
View answer and explanation
Correct option: C
32
Option C (32) is correct because by using logarithm properties and solving the resulting equation, x is found to be 32.
228 Easy
228 of 998
Application +4 | -1
Suppose for each n∈N,14+24+34+…+n4=an5+bn4+cn3+dn2+en+fn \in \mathbf{N}, 1^4+2^4+3^4+\ldots+n^4=a n^5+b n^4+c n^3+d n^2+e n+f, then value of bb is
View answer and explanation
Correct option: B
1/21 / 2
Option B (1/2) is correct because by comparing coefficients after subtracting the sum of powers formula for n and n+1, we can determine the value of b to be 1/2.
229 Easy
229 of 998
Application +4 | -1
The number of solutions of log⁡2(x−1)=2log⁡2(x−3){\log _2}\left( {x - 1} \right) = 2{\log _2}\left( {x - 3} \right) is
View answer and explanation
Correct option: B
1
Option B (1) is correct because solving the logarithmic equation yields two possible solutions, but only one satisfies the domain restrictions of the logarithms.
230 Easy
230 of 998
Analyzing +4 | -1
Let a1,a2,……,a30\mathrm{a}_{1}, \mathrm{a}_{2}, \ldots \ldots, \mathrm{a}_{30} be an A.P., S=∑i=130ai\mathrm{S}=\sum_{i=1}^{30} \mathrm{a}_{i} and T=∑i=115a(2i−1)\mathrm{T}=\sum_{i=1}^{15} \mathrm{a}_{(2 i-1)}
If a5=27\mathrm{a}_{5}=27 and S−2T=75\mathrm{S}-2 \mathrm{T}=75, then a10\mathrm{a}_{10} is equal to:
View answer and explanation
Correct option: A
52
The correct answer is 52 because by using the properties of arithmetic progressions and the given equations, we can find the value of a10a_{10}.
231 Easy
231 of 998
Application +4 | -1
If 2x,x+8,3x+12 x, x+8,3 x+1 are in AP, then the value of xx will be
View answer and explanation
Correct option: C
5
Option C (5) is correct because if 2x,x+8,3x+12x, x+8, 3x+1 are in AP, then 2(x+8)=2x+3x+12(x+8) = 2x + 3x + 1, which simplifies to x=5x=5.
232 Easy
232 of 998
Application +4 | -1
The number of terms in an A.P. is even; the sum of the odd terms in it is 24 and that the even terms is 30 . If the last term exceeds the first term by 101210 \frac{1}{2}, then the number of terms in the A.P. is:
View answer and explanation
Correct option: B
8
Option B (8) is correct because it is the number of terms that satisfies the given conditions for the arithmetic progression.
233 Easy
233 of 998
Application +4 | -1
If the sum of the first 2n2 n terms of 2,5,8…2,5,8 \ldots is equal to the sum of the first nn terms of 57,59,61…57,59,61 \ldots. , then nn is equal to
View answer and explanation
Correct option: C
11
Option C (11) is correct because by equating the sum of the first 2n terms of the first A.P. to the sum of the first n terms of the second A.P., we can solve for n and find it to be 11.
234 Easy
234 of 998
Analyzing +4 | -1
If x,y,zx,y,z are in AP, then 1x+y,1z+x,1y+z\frac{1}{{\sqrt x + \sqrt y }},\frac{1}{{\sqrt z + \sqrt x }},\frac{1}{{\sqrt y + \sqrt z }} are in
View answer and explanation
Correct option: A
AP
Option A (AP) is correct because if x, y, z are in AP, then the reciprocals with the given square roots are also in AP.
235 Easy
235 of 998
Understanding +4 | -1
If a,  b,  c,  d,  e,  f  a,\;b,\;c,\;d,\;e,\;f\; are in AP, then the value of e−ce - c will be
View answer and explanation
Correct option: B
2 (d−c)\left( {d - c} \right)
Option D (d−cd - c) is incorrect. The correct answer is 2(d−cd - c). Since a,b,c,d,e,f are in A.P. e-c = 2(d-c)
236 Easy
236 of 998
Analyzing +4 | -1
The number of roots of the equation xlog⁡x(x+3)2=16x^{\log _x(x+3)^2}=16 is
View answer and explanation
Correct option: B
0
Option B (0) is correct because solving the equation leads to values of x that do not satisfy the domain restrictions of the logarithmic function.
237 Easy
237 of 998
Application +4 | -1
0.5737373⋯=0.5737373 \cdots=
View answer and explanation
Correct option: C
568990\frac{568}{990}
Option C (568990\frac{568}{990}) is correct because the repeating decimal can be expressed as a fraction by summing a geometric series.
238 Easy
238 of 998
Analyzing +4 | -1
If log⁡0.3(x−1)<log⁡0.09(x−1),\log _{0.3}(x-1)<\log _{0.09}(x-1), then xx lies in the interval
View answer and explanation
Correct option: C
(2,∞)(2, \infty)
Option C ((2, ∞)) is correct because solving the logarithmic inequality leads to x > 2, which corresponds to the interval (2, infinity).
239 Easy
239 of 998
Analyzing +4 | -1
If the sum of an infinitely decreasing G.P. is 3, and the sum of the squares of its terms is 9/2,9/2, the sum of the cubes of the terms is
View answer and explanation
Correct option: B
10813\frac{{108}}{{13}}
Option B (108/13) is correct because it is derived by finding the first term and common ratio of the G.P. and then calculating the sum of the cubes of the terms.
240 Easy
240 of 998
Understanding +4 | -1
If a,b,c,d,e,fa, b, c, d, e, f are in AP\mathrm{AP}, then the value of e−ce-c will be
View answer and explanation
Correct option: C
2(d−c)2(d-c)
Option C (2(d−c)2(d-c)) is correct because in an arithmetic progression, the difference between consecutive terms is constant, so e−c=2(d−c)e-c = 2(d-c).
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