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JEE • MATHEMATICS • SEQUENCE OF SERIES

Sequence of series practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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91 Easy
91 of 998
Application +4 | -1
If ax=by=cz=dw,{a^x} = {b^y} = {c^z} = {d^w}, then log⁡a(bcd){\log _a}\left( {bcd} \right) equals to
View answer and explanation
Correct option: B
x(1y+1z+1w)x\left( {\frac{1}{y} + \frac{1}{z} + \frac{1}{w}} \right)
Option B (x(1y+1z+1w)x\left( {\frac{1}{y} + \frac{1}{z} + \frac{1}{w}} \right)) is correct because by taking logarithms and manipulating the equations, log⁡a(bcd){\log _a}\left( {bcd} \right) can be expressed as x(1y+1z+1w)x\left( {\frac{1}{y} + \frac{1}{z} + \frac{1}{w}} \right).
92 Easy
92 of 998
Analyzing +4 | -1
An A.P., a G.P. and a H.P. have the same first and last terms and the same odd number of terms. The middle terms of the three series are in
View answer and explanation
Correct option: B
G.P.
Option B (G.P.) is correct because the middle terms of A.P., G.P., and H.P. with the same first and last terms are in G.P.
93 Easy
93 of 998
Application +4 | -1
If <an>< {a_n} > is an arithmetic sequence, then Δ  =∣amanapmnp111∣\Delta \; = \left| {\begin{array}{cccccccccccccccccccc} {{a_m}}&{{a_n}}&{{a_p}}\\ m&n&p\\ 1&1&1 \end{array}} \right| equals
View answer and explanation
Correct option: C
0
Option C (0) is correct because the determinant is zero when the first row is a linear combination of the other rows, which is the case for an arithmetic sequence.
94 Easy
94 of 998
Application +4 | -1
If x,  1,  zx,\;1,\;z are in AP and x,  2,  zx,\;2,\;z are in GP, then x,  4,  zx,\;4,\;z will be in
View answer and explanation
Correct option: C
HP
Option C (HP) is correct because given the conditions for AP and GP, the resulting relationship indicates that x, 4, z are in Harmonic Progression.
95 Easy
95 of 998
Application +4 | -1
Let f(x)f(x) be a polynomial of second degree. If f(1)=f(−1)f(1)=f(-1) and a,ba, b, cc are in A.P., then f′(a),f′(b)f^{\prime}(a), f^{\prime}(b) and f′(c)f^{\prime}(c) are in
View answer and explanation
Correct option: B
A.P.
Option B (A.P.) is correct because the derivative of the quadratic function results in a linear function, and since a, b, c are in A.P., their corresponding values in the linear function are also in A.P.
96 Easy
96 of 998
Application +4 | -1
The least value of ' aa ' for which 51+x+51−x,a/2,25x+25−x5^{1+x}+5^{1-x}, a / 2,25^x+25^{-x} are three consecutive terms of an A.P., is
View answer and explanation
Correct option: C
12
Option C (12) is correct because it is the least value of 'a' that satisfies the arithmetic progression condition, obtained by using AM-GM inequality.
97 Easy
97 of 998
Application +4 | -1
The value of the sum ∑r=1n∑s=1nSrs  2r3s,whereSrs=0,  if  r≠s  andSrs=1,    if  r=s,\sum \limits_{r = 1}^n \sum \limits_{s = 1}^n {S_{rs}}\;{2^r}{3^s},\mathrm{where}{S_{rs}} = 0,\;\mathrm{if}\;r \ne s\;\mathrm{and}{S_{rs}} = 1,\;\;\mathrm{if}\;r = s, is
View answer and explanation
Correct option: B
65(6n−1)\frac{6}{5}\left( {{6^n} - 1} \right)
Option B is correct because the sum simplifies to a geometric progression with a common ratio of 6, allowing for direct calculation using the geometric series formula.
98 Easy
98 of 998
Application +4 | -1
If S=1+a+a2+……S=1+a+a^2+\ldots \ldots to ∞(a<1)\infty(a<1), then the value of aa, is
View answer and explanation
Correct option: C
S−1S\frac{S-1}{S}
Option C (S−1S\frac{S-1}{S}) is correct because it is derived directly from the formula for the sum of an infinite geometric series.
99 Easy
99 of 998
Application +4 | -1
If a,b,ca, b, c, dd are H.P., then
View answer and explanation
Correct option: C
ad>bca d>b c
Option C (ad>bca d>b c) is correct because it is derived from the relationship between terms in a harmonic progression, using the properties of geometric and harmonic means.
100 Easy
100 of 998
Application +4 | -1
If ∣x∣<1\left| x \right| < 1 then the sum of the series 1+2x+3x2+4x3+...∞1 + 2x + 3{x^2} + 4{x^3} + ...\infty will be
View answer and explanation
Correct option: D
1(1−x)2\frac{1}{{{{\left( {1 - x} \right)}^2}}}
Option D (1(1−x)2\frac{1}{{{{\left( {1 - x} \right)}^2}}}) is correct because the series can be expressed as the derivative of a geometric series.
101 Easy
101 of 998
Understanding +4 | -1
Consider the following statements

I. If a1,a2,…,an…{a}_1, {a}_2, \ldots, {a}_{{n}} \ldots is a sequence, then the expression a1+a2+…+an+…a_1+a_2+\ldots+a_n+\ldots is called a series.

II. Those sequences whose terms follow certain patterns are called progressions.

Choose the correct option.
View answer and explanation
Correct option: D
Both are true
Option D (Both are true) is correct because both statements accurately describe the definition of a series and a progression.
102 Easy
102 of 998
Application +4 | -1
Suppose all the terms of an arithmetic progression (A.P.) are natural numbers. If the ratio of the sum of the first seven terms to the sum of the first eleven terms is 6:116: 11 and the seventh term lies in between 130 and 140, then the common difference of this A.P. is
View answer and explanation
Correct option: D
9
Option D (9) is correct because the common difference is found by using the given ratio of sums and the condition on the seventh term.
103 Easy
103 of 998
Application +4 | -1
If 3+log⁡5x=2log⁡25y,3 + {\log _5}x = 2{\log _{25}}y,then xx equals to
View answer and explanation
Correct option: A
y125\frac{y}{{125}}
Option A (y125\frac{y}{{125}}) is correct because by using logarithm properties, the equation can be simplified to express x in terms of y.
104 Easy
104 of 998
Application +4 | -1
If A1,A2A_1, A_2 be two A.M.'s and G1,G2G_1, G_2 be two G.M.'s between aa and bb, then A1+A2G1G2\frac{A_1+A_2}{G_1 G_2} is equal to
View answer and explanation
Correct option: C
a+bab\frac{a+b}{a b}
Option C (a+bab\frac{a+b}{ab}) is correct because, after calculating A1+A2 and G1G2, their ratio simplifies to (a+b)/ab.
105 Easy
105 of 998
Application +4 | -1
Let aa be a positive number such that the arithmetic mean of aa and 2 exceeds their geometric mean by 1. Then, the value of aa is
View answer and explanation
Correct option: D
8
Option D (8) is correct because solving the equation a+22=2a+1\frac{{a + 2}}{2} = \sqrt {2a} + 1 leads to a=8a = 8.
106 Easy
106 of 998
Analyzing +4 | -1
Let bi>1b_i>1 for i=1,2,…,101i=1,2, \ldots, 101. Suppose log⁡eb1\log _e b_1, log⁡eb2,…,log⁡eb101\log _e b_2, \ldots, \log _e b_{101} are in Arithmetic Progression (A.P) with the common differencelog⁡e2{\log _e}2 . Suppose a1,a2,…,a101a_1, a_2, \ldots, a_{101} are in A.P. such that a1=b1a_1=b_1 and a51=b51a_{51}=b_{51}. If t=b1+b2+…+b51t=b_1+b_2+\ldots+b_{51} and s=a1+a2+…+a51s=a_1+a_2+\ldots+a_{51}, then
View answer and explanation
Correct option: B
s>ts>t and a101<b101a_{101} < b_{101}
Option B (s>ts>t and a101<b101a_{101} < b_{101}) is correct because the sum of the arithmetic progression is greater than the sum of the geometric progression, while the 101st term of the arithmetic progression is less than the 101st term of the geometric progression.
107 Easy
107 of 998
Application +4 | -1
If 1+cos⁡α+cos⁡2α+...∞=2−2,1 + \cos \alpha + {\cos ^2}\alpha + ...\infty = 2 - \sqrt 2 , then α,  (0<α<π)\alpha ,\;(0 < \alpha < \pi ) is
View answer and explanation
Correct option: D
3π4\frac{{3\pi }}{4}
Option D (3π4\frac{{3\pi }}{{4}}) is correct because it is the value of α\alpha that satisfies the given infinite geometric series equation.
108 Easy
108 of 998
Analyzing +4 | -1
If d,  e,  fd,\;e,\;f are in G.P. and the two quadratic equations ax2+2  bx+c=0a{x^2} + 2\;bx + c = 0 and dx2+2  ex+f=0d{x^2} + 2\;ex + f = 0 have a common root, then
View answer and explanation
Correct option: A
da,eb,fc\frac{d}{a},\frac{e}{b},\frac{f}{c} are in H.P.
Option A (da,eb,fc\frac{d}{a},\frac{e}{b},\frac{f}{c} are in H.P.) is correct because the common root condition and the G.P. condition for d,e,fd, e, f lead to the conclusion that da,eb,fc\frac{d}{a},\frac{e}{b},\frac{f}{c} are in H.P.
109 Easy
109 of 998
Analyzing +4 | -1
If pth,qth p^{t h}, q^{\text {th }} and rth r^{\text {th }} terms of A.P. a1,a2,a3a_1, a_2, a_3, are in G.P., then ap:aq=a_p: a_q=
View answer and explanation
Correct option: C
q−pr−q\frac{q-p}{r-q}
Option C (q−pr−q\frac{q-p}{r-q}) is correct because, by using the properties of arithmetic and geometric progressions, we can derive that apaq=q−pr−q\frac{a_p}{a_q} = \frac{q-p}{r-q}.
110 Easy
110 of 998
Analyzing +4 | -1
The value of ∑r=1∞(4r+5)5−rr(5r+5)\sum\limits_{r = 1}^\infty {\frac{{(4r + 5){5^{ - r}}}}{{r(5r + 5)}}} is
View answer and explanation
Correct option: A
15\frac{1}{5}
Option A (15\frac{{1}}{{5}}) is correct because it is the value obtained after evaluating the infinite series by using partial fraction decomposition and telescoping the series.
111 Easy
111 of 998
Analyzing +4 | -1
Let a1,a2,a3,...{a_1},{a_2},{a_3},... be an AP with a6=2{a_6} = 2. Then, the common difference of this AP, which maximizes the product a1,a4,a5,{a_1},{a_4},{a_5}, is
View answer and explanation
Correct option: A
85\frac{8}{5}
Option A (8/5) is correct because the common difference that maximizes the product is found by differentiating the product with respect to the common difference and setting it to zero.
112 Easy
112 of 998
Application +4 | -1
The third term of a geometric progression is 4 . The product of the first five terms is
View answer and explanation
Correct option: B
454^5
Option B (454^5) is correct because the product of the first five terms of a GP with the third term being 4 is 454^5.
113 Easy
113 of 998
Application +4 | -1
The arithmetic mean between two numbers is AA, and SS is the sum of nn arithmetic means between these mumbers, then
View answer and explanation
Correct option: A
S=nAS=n A
Option A (S=nAS=n A) is correct because the sum of n arithmetic means between two numbers is n times the arithmetic mean of the two numbers.
114 Easy
114 of 998
Application +4 | -1
The sum to infinity of the series, 1+2(1−1n)+3(1−1n)2+…1+2\left(1-\frac{1}{n}\right)+3\left(1-\frac{1}{n}\right)^2+\ldots is
View answer and explanation
Correct option: A
n2n^2
Option A (n2n^2) is correct because it represents the sum to infinity of the given series, derived using the formula for the sum of an infinite geometric progression.
115 Easy
115 of 998
Application +4 | -1
Let TrT_r be the rth r^{\text {th }} term of an A.P. whose first term is a and common difference is dd. If for some positive integers m,nm, n, m≠n,Tm=1nm \neq n, T_m=\frac{1}{n} and Tn=1mT_n=\frac{1}{m}, then a−da-d equals
View answer and explanation
Correct option: D
0
Option D (0) is correct because a-d equals 0 when solving the equations derived from the given conditions of the arithmetic progression.
116 Easy
116 of 998
Analyzing +4 | -1
If x=log⁡a(bc),y=log⁡b(ca)x = {\log _a}\left( {bc} \right),y = {\log _b}\left( {ca} \right) and z=log⁡c(ab),z = {\log _c}\left( {ab} \right), then which of the following is correct?
View answer and explanation
Correct option: B
11+x+11+y+11+z=1\frac{1}{{1 + x}} + \frac{1}{{1 + y}} + \frac{1}{{1 + z}} = 1
Option B (11+x+11+y+11+z=1\frac{1}{{1 + x}} + \frac{1}{{1 + y}} + \frac{1}{{1 + z}} = 1) is correct because it simplifies to a logarithmic identity equal to 1.
117 Easy
117 of 998
Analyzing +4 | -1
Let S=2+67+1272+2073+3074+…S = 2 + \frac{6}{7} + \frac{{12}}{{{7^2}}} + \frac{{20}}{{{7^3}}} + \frac{{30}}{{{7^4}}} + \ldots Then 4S4 S is equal to
View answer and explanation
Correct option: C
(73)3{\left( {\frac{7}{3}} \right)^3}
The correct answer is C ((73)3{\left( {\frac{7}{3}} \right)^3}) because it is the value of 4S calculated by manipulating the series and using the formula for the sum of an infinite geometric series.
118 Easy
118 of 998
Application +4 | -1
If a,b,ca, b, c are in H.P. then a−b2,b2,c−b2a-\frac{b}{2}, \frac{b}{2}, c-\frac{b}{2} are in
View answer and explanation
Correct option: B
G.P.
Option B (G.P.) is correct because the product of the first and third terms equals the square of the second term, satisfying the condition for a geometric progression.
119 Easy
119 of 998
Application +4 | -1
If a is positive and if AA and GG are the arithmetic mean and the geometric mean of the roots of x2−2ax+a2=0{x^2} - 2ax + {a^2} = 0 respectively, then
View answer and explanation
Correct option: A
A=GA = G
Option A (A=GA = G) is correct because the arithmetic mean and geometric mean of the roots of the given equation are equal, as the roots are equal.
120 Easy
120 of 998
Application +4 | -1
Three numbers are in AP such that their sum is 18 and sum of their squares is 158. The greatest number among them is
View answer and explanation
Correct option: B
11
Option B (11) is correct because by setting up the equations based on the given conditions for an AP, we find the greatest number to be 11.
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