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JEE • MATHEMATICS • SEQUENCE OF SERIES

Sequence of series practice · Easy

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481 Easy
481 of 998
Application +4 | -1
An A.P. consists of 2n2 n terms. If two middle terms are α−β\alpha-\beta and α+β\alpha+\beta, then sum of the 2n2 n terms of the A.P. is
View answer and explanation
Correct option: A
2nα2 n \alpha
Option A (2nα2n \alpha) is correct because the sum of the 2n terms of the A.P. is 2nα2n \alpha, given that the two middle terms are α−β\alpha - \beta and α+β\alpha + \beta.
482 Easy
482 of 998
Analyzing +4 | -1
Let SnS_n denote the sum of the first nn terms of an A.P. a1,a2,a3,…,ana_1, a_2, a_3, \ldots, a_n. If a5+a9=1a_5+a_9=1 and S9=6S_9=6, then which of the following is not true?
View answer and explanation
Correct option: B
S6=192S_6=\frac{19}{2}
Option B (S6=192S_6=\frac{19}{2}) is not true because, with the calculated values of a1a_1 and dd, S6S_6 is actually equal to 194\frac{19}{4}.
483 Easy
483 of 998
Application +4 | -1
The value of 2.357‾2.\overline {357} is
View answer and explanation
Correct option: B
2355999\frac{{2355}}{{999}}
Option B (2355999\frac{{2355}}{{999}}) is correct because it represents the fractional equivalent of the repeating decimal 2.357‾2.\overline {357}.
484 Easy
484 of 998
Application +4 | -1
If log⁡102=0.3010,{\log _{10}}2 = 0.3010, then log⁡564={\log _5}64 =
View answer and explanation
Correct option: A
602233\frac{{602}}{{233}}
Option A (602233\frac{{602}}{{233}}) is correct because it is the result of converting the logarithm to base 10 and using the given value of log⁡102{\log _{10}}2.
485 Easy
485 of 998
Application +4 | -1
If the first term of an AP is 3 and the sum of its 25 terms is equal to the sum of its next 15 terms, then the common difference of this AP is
View answer and explanation
Correct option: A
16\frac{1}{6}
Option A (16\frac{1}{6}) is correct because it is the common difference derived from the given conditions about the sum of terms in the arithmetic progression.
486 Easy
486 of 998
Analyzing +4 | -1
If Hn=1+12+13+…+1n  ,{H_n} = 1 + \frac{1}{2} + \frac{1}{3} + \ldots + \frac{1}{n}\;, then the value of Sn=1+32+53+…+2n−1n{S_n} = 1 + \frac{3}{2} + \frac{5}{3} + \ldots + \frac{{2n - 1}}{n} is
View answer and explanation
Correct option: B
2n−Hn2n - {H_n}
Option B (2n−Hn2n - {H_n}) is correct because the series can be rewritten and simplified using the definition of HnH_n.
487 Easy
487 of 998
Application +4 | -1
Let a1,a2,a3,…a_1, a_2, a_3, \ldots be terms of an A.P. If a1+a2+…+apa1+a2+…+aq=p2q2,p≠q\frac{a_1+a_2+\ldots+a_p}{a_1+a_2+\ldots+a_q}=\frac{p^2}{q^2}, p \neq q, then a6a21\frac{a_6}{a_{21}} equals
View answer and explanation
Correct option: D
1141\frac{11}{41}
Option D (11/41) is correct because the ratio a6/a21 is calculated using the given condition and properties of A.P.
488 Easy
488 of 998
Application +4 | -1
If HH is the harmonic mean between PP and Q{\cal Q}, then the value of HP+HQ\frac{H}{P} + \frac{H}{{\cal Q}} is
View answer and explanation
Correct option: A
2
Option A (2) is correct because the harmonic mean formula simplifies to 2 when substituting and simplifying the given expression.
489 Easy
489 of 998
Application +4 | -1
Let a1,  a2,  a3.......{a_1},\,\,{a_2},\,\,{a_3}....... be an A.P. If a1+a2+...+a10a1+a2+...+ap=100p2,p≠10,\frac{{{a_1} + {a_2} + ... + {a_{10}}}}{{{a_1} + {a_2} + ... + {a_p}}} = \frac{{100}}{{{p^2}}},p \ne 10, then a11a10\frac{{{a_{11}}}}{{{a_{10}}}} is equal to
View answer and explanation
Correct option: C
2119\frac{{21}}{{19}}
Option C (2119\frac{{21}}{{19}}) is correct because it is the ratio of a11 to a10, derived from the given condition on the sum of the arithmetic progression.
490 Easy
490 of 998
Application +4 | -1
If x,2x+2,3x+3x, 2 x+2,3 x+3 are in G.P., then the fourth term is
View answer and explanation
Correct option: D
-13.5
Option D (-13.5) is correct because after finding the possible values of x, the common ratio is calculated and used to find the fourth term of the G.P.
491 Easy
491 of 998
Application +4 | -1
If first term of a GP is aa, third term is bb and (n+1)(n+1) th term is cc. The (2n+1)(2 n+1) th term of a GP is
View answer and explanation
Correct option: D
c2a\frac{c^2}{a}
Option D (c2a\frac{c^2}{a}) is correct because using the properties of a GP, we can express the (2n+1)(2n+1)th term in terms of a, b, and c.
492 Easy
492 of 998
Application +4 | -1
If log⁡10{98+x2−12x+36}=2,{\log _{10}}\left\{ {98 + \sqrt {{x^2} - 12x + 36} } \right\} = 2, then x=x =
View answer and explanation
Correct option: D
4,  84,\;8
Option D (4, 8) is correct because both values satisfy the given logarithmic equation after considering the absolute value.
493 Easy
493 of 998
Application +4 | -1
If A1,A2;G1,G2{A_1},{A_2};{G_1},{G_2} and H1,H2{H_1},{H_2} be two AM’s, GM’s and HM’s between two quantities, then the value of G1G2H1+H2\frac{{{G_1}{G_2}}}{{{H_1} + {H_2}}}
View answer and explanation
Correct option: A
A1+A2H1+H2\frac{{{A_1} + {A_2}}}{{{H_1} + {H_2}}}
Option A (A1+A2H1+H2\frac{{{A_1} + {A_2}}}{{{H_1} + {H_2}}}) is correct because, by defining the AM, GM, and HM between two quantities and using their relationships, the expression simplifies to the given form.
494 Easy
494 of 998
Analyzing +4 | -1
If x,y,zx, y, z are in GP are tan⁡−1x,tan⁡−1y,tan⁡−1z\tan ^{-1} x, \tan ^{-1} y, \tan ^{-1} z are in A.P., then
View answer and explanation
Correct option: C
x=y=zx=y=z, but their common value is not necessarily zero
Option C (x=y=zx=y=z, but their common value is not necessarily zero) is correct because the given conditions imply that x, y, and z must be equal, but not necessarily zero.
495 Easy
495 of 998
Analyzing +4 | -1
The number of solution(s) for the equation 2log⁡xa+log⁡axa+3log⁡a2xa=0,2 \log _x a+\log _{a x} a+3 \log _{a^2 x} a=0, is
View answer and explanation
Correct option: B
Two
Option B (Two) is correct because solving the equation results in two valid solutions for x after considering the domain restrictions.
496 Easy
496 of 998
Analyzing +4 | -1
If a,b,ca, b, c are in GP, then the equations ax2+2bx+c=0a x^2+2 b x+c=0 and dx2+2ex+f=0d x^2+2 e x+f=0 have a common root, if da,eb,fc\frac{d}{a}, \frac{e}{b}, \frac{f}{c} are in
View answer and explanation
Correct option: A
AP
Option A (AP) is correct because if a, b, c are in GP, the quadratic equation has a repeated root, and for the two quadratics to have a common root, d/a, e/b, f/c must be in AP.
497 Easy
497 of 998
Application +4 | -1
If the 10th term of an A.P is 120\frac{1}{{20}} and its 20th term is 110\frac{1}{{10}}, then the sum of its first 200 terms is
View answer and explanation
Correct option: D
100  12100\,\,\frac{1}{2}
Option D (100 12100\,\frac{1}{2}) is correct because the sum of the first 200 terms is calculated using the A.P. formula with the derived values of 'a' and 'd'.
498 Easy
498 of 998
Application +4 | -1
If a,b,c,da,b,c,d are in H.P., then ab+bc+cd=ab + bc + cd =
View answer and explanation
Correct option: C
3ad3ad
Option C (3ad3ad) is correct because, given that a, b, c, d are in H.P., the expression ab + bc + cd simplifies to 3ad.
499 Easy
499 of 998
Analyzing +4 | -1
The value of alog⁡b(log⁡bN)log⁡baa^{\frac{\log _b\left(\log _b N\right)}{\log _b a}} is
View answer and explanation
Correct option: B
log⁡bN\log _b N
Option B (log⁡bN\log _b N) is correct because by using the change of base formula and simplifying, the expression reduces to log_b(N).
500 Easy
500 of 998
Application +4 | -1
The sum of six arithmetic means between 2 and 23 is
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Correct option: D
75
Option D (75) is correct because it is the sum of the six arithmetic means calculated using the formula for the sum of an arithmetic series.
501 Easy
501 of 998
Application +4 | -1
If a,b,c,da, b, c, d are positive real numbers such that a+b+c+d=2a+b+c+d=2, then m=(a+b)(c+d)m=(a+b)(c+d) satisfies the relation
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Correct option: A
0<m≤10 < m \leq 1
Option A (0<m≤10 < m \leq 1) is correct because, by AM-GM inequality, the maximum value of (a+b)(c+d) is 1 when a+b = c+d = 1, and since a,b,c,d are positive, m > 0.
502 Easy
502 of 998
Analyzing +4 | -1
A G.P. consists of 2n2 n terms. If the sum of the terms occupying the odd places is S1S_1, and that of the terms in the even places is S2S_2, then S2/S1S_2 / S_1, is
View answer and explanation
Correct option: D
dependent on rr
Option D (dependent on rr) is correct because the ratio S2/S1S_2 / S_1 simplifies to rr, which is the common ratio of the G.P.
503 Easy
503 of 998
Understanding +4 | -1
The mean of the series a,a+nd,a+2nda, a+n d, a+2 n d is
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Correct option: B
a+nda+n d
Option B (a+nda+nd) is correct because the mean of the series is calculated by summing the terms and dividing by the number of terms, resulting in a+nda+nd.
504 Easy
504 of 998
Analyzing +4 | -1
If in an increasing G.P., the sum of second and sixth term is 252\frac{25}{2} and the product of third and fifth term is 25 , then the sum of fourth, sixth and 8th 8^{\text {th }} term is
View answer and explanation
Correct option: A
35
The correct answer is 35 because, by solving the given equations for the increasing G.P., we find the first term and common ratio, and then calculate the sum of the fourth, sixth, and eighth terms.
505 Easy
505 of 998
Application +4 | -1
The cost and revenue functions of aa product are given by C(x)=2x+80C(x)=2 x+80 and R(x)=5x+20R(x)=5 x+20 respectively, where xx is the number of items produced by the manufacture. How many items the manufacturer must sell to realize some profit?
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Correct option: A
more than 20
The correct answer is A (more than 20) because the manufacturer needs to sell more than 20 items to ensure that the revenue exceeds the cost, resulting in a profit.
506 Easy
506 of 998
Analyzing +4 | -1
If log (x−y)−log⁡5−12log⁡x−12log⁡y=0,\left( {x - y} \right) - \log 5 - \frac{1}{2}\log x - \frac{1}{2}\log y = 0, then xy+yx=\frac{x}{y} + \frac{y}{x} =
View answer and explanation
Correct option: C
27
Option C (27) is correct because by simplifying the logarithmic equation, we can express the relationship between x and y, leading to the value of xy+yx=27\frac{x}{y} + \frac{y}{x} = 27.
507 Easy
507 of 998
Application +4 | -1
The sum of the series 5.05 +1.212+029088+...∞+ 1.212 + 029088 + ...\infty is
View answer and explanation
Correct option: D
6.644746.64474
Option D (6.64474) is correct because it is the sum of the infinite GP calculated using the formula S = a / (1 - r).
508 Easy
508 of 998
Application +4 | -1
If the sum of nn terms of the series 23+43+63+...{2^3} + {4^3} + {6^3} + ... is 3528, then nn equals to
View answer and explanation
Correct option: D
6
Option D (6) is correct because it is the value of n that satisfies the given sum of the series.
509 Easy
509 of 998
Application +4 | -1
A person is to count 4500 currency notes. Let ana_n denotes the number of notes he counts in the nnth minute. If a1=a2=…=a10=150a_1=a_2=\ldots=a_{10}=150 and a10,a11,…a_{10}, a_{11}, \ldots are in AP with common difference −2-2, then the time taken by him to count all notes is
View answer and explanation
Correct option: A
34 min34 \mathrm{~min}
Option A (34 min) is correct because it represents the total time taken to count all the notes, considering the initial constant rate and the subsequent arithmetic progression.
510 Easy
510 of 998
Analyzing +4 | -1
13!+25!+37!+…\frac{1}{{3!}} + \frac{2}{{5!}} + \frac{3}{{7!}} + \ldots is equal to
View answer and explanation
Correct option: A
e−12\frac{{{e^{ - 1}}}}{2}
The correct answer is A (e−12\frac{{{e^{ - 1}}}}{2}) because the given series can be expressed as a difference of factorials, leading to a form related to the exponential function.
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