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JEE • MATHEMATICS • SEQUENCE OF SERIES

Sequence of series practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 998 questions

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271 Easy
271 of 998
Application +4 | -1
The sum of the series 11+2+12+3+13+4+…+1n2−1+n2\frac{1}{{\sqrt 1 + \sqrt 2 }} + \frac{1}{{\sqrt 2 + \sqrt 3 }} + \frac{1}{{\sqrt 3 + \sqrt 4 }} + \ldots + \frac{1}{{\sqrt {{n^2} - 1} + \sqrt {{n^2}} }} equals
View answer and explanation
Correct option: D
n−1n - 1
Option D (n−1n - 1) is correct because the series telescopes, leaving only the last term's square root minus the first term's square root.
272 Easy
272 of 998
Application +4 | -1
GM and HM of two numbers are 10 and 8 respectively. The numbers are
View answer and explanation
Correct option: A
5,20
Option A (5,20) is correct because the numbers 5 and 20 satisfy both the geometric mean (GM) and harmonic mean (HM) conditions.
273 Easy
273 of 998
Analyzing +4 | -1
If 1log⁡3π+1log⁡4π>x,\frac{1}{{{{\log }_3}\mathrm{\pi }}} + \frac{1}{{{{\log }_4}\mathrm{\pi }}} > x, then the greatest integral value of xx is
View answer and explanation
Correct option: A
2
Answer A (2) is correct because by changing the base of the logarithm and simplifying, we find that πx<12\pi^x < 12, and the greatest integer value of x that satisfies this is 2.
274 Easy
274 of 998
Application +4 | -1
If 7th term of an A.P. is 9 and 9th term of the A.P. is 7, then 20th term of the A.P. is
View answer and explanation
Correct option: C
−4-4
Option C (-4) is correct because by finding the common difference and using the properties of arithmetic progressions, the 20th term can be determined.
275 Easy
275 of 998
Application +4 | -1
If sum of the infinite G.P. p+1+1p+1p2+....., (p>2)p + 1 + \frac{1}{p} + \frac{1}{{{p^2}}} + .....,\,\left( {p > 2} \right) is 49/6,49/6, then sum of the 3rd term and the 4th term of the G.P. is
View answer and explanation
Correct option: A
849\frac{8}{49}
Option A (8/49) is correct because by finding the value of p and then calculating the 3rd and 4th terms, their sum is 8/49.
276 Easy
276 of 998
Application +4 | -1
If the sum of the first 20 terms of the series log⁡71/2+log⁡71/3x+log⁡71/4x+…\log _7 1 / 2+\log _7 1 / 3 x+\log _7 1 / 4 x+\ldots is 460 , then xx is equal to
View answer and explanation
Correct option: C
727^2
Option C (727^2) is correct because after simplifying the logarithmic series and solving for x, we find that x equals 49, which is 727^2.
277 Easy
277 of 998
Analyzing +4 | -1
If 1+λ+λ2+...+λn=(1+λ)(1+λ2)(1+λ4)(1+λ8)(1+λ16),1 + \lambda + {\lambda ^2} + ... + {\lambda ^n} = \left( {1 + \lambda } \right)\left( {1 + {\lambda ^2}} \right)\left( {1 + {\lambda ^4}} \right)\left( {1 + {\lambda ^8}} \right)\left( {1 + {\lambda ^{16}}} \right), then the value of nn is (where n∈N)n \in N)
View answer and explanation
Correct option: C
31
Option C (31) is correct because by equating the LHS and RHS after simplification, we find that n = 31.
278 Easy
278 of 998
Application +4 | -1
The digits of a three digit number NN are in A.P. If sum of the digits is 15 and the number obtaind by reversing the digits of the number is 594 less than the original number, then 1000N−252\frac{1000}{N-252} is equal to
View answer and explanation
Correct option: B
5/35 / 3
Option B (5/35 / 3) is correct because by finding the digits of the number and using the given conditions, we can determine the value of the expression.
279 Easy
279 of 998
Analyzing +4 | -1
If the arithmetic progression whose common difference is non-zero, the sum of first 3n3 n terms is equal to the sum of the next nn terms. The ratio of the sum of the first 2n2 n terms to the next 2n2 n terms is
View answer and explanation
Correct option: A
15\frac{1}{5}
Option A (15\frac{1}{5}) is correct because the ratio of the sum of the first 2n2n terms to the next 2n2n terms simplifies to 15\frac{1}{5} using the given conditions.
280 Easy
280 of 998
Analyzing +4 | -1
Let a,b,ca, b, c be positive integers such that ba\frac{b}{a} is an integer. If a,b,ca, b, c are in geometric progression and the arithmetic mean of a,b,ca, b, c is b+2b+2, then the value of a2+a−14a+1\frac{a^2+a-14}{a+1}, is
View answer and explanation
Correct option: B
4
The correct answer is 4 because by using the given conditions that a, b, c are in GP and their AM is b+2, we can find the value of a and then substitute it into the expression.
281 Easy
281 of 998
Analyzing +4 | -1
If x=log⁡5(1000)x=\log _5(1000) and y=log⁡7(2058),y=\log _7(2058), then
View answer and explanation
Correct option: A
x>yx>y
Option A (x > y) is correct because by comparing the logarithmic expressions after simplification, it's clear that x is greater than y.
282 Easy
282 of 998
Analyzing +4 | -1
If p,q,rp,q,r are in GP and tan⁡−1p,tan⁡−1q,tan⁡−1r{\tan ^{ - 1}}p,{\tan ^{ - 1}}q,{\tan ^{ - 1}}r are in AP, then p,q,rp,q,r satisfies the relation
View answer and explanation
Correct option: A
p=q=rp = q = r
Option A (p=q=rp = q = r) is correct because if p,q,rp, q, r are in both GP and AP, they must be equal.
283 Easy
283 of 998
Application +4 | -1
If the sum of first pp terms, first qq terms and first rr terms of an A.P. be x,yx,y and zz respectively. Then, xp(q−r)+yq(r−p)+zr(p−q)\frac{x}{p}\left( {q - r} \right) + \frac{y}{q}\left( {r - p} \right) + \frac{z}{r}\left( {p - q} \right) is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the given expression simplifies to zero using the properties of arithmetic progressions.
284 Easy
284 of 998
Application +4 | -1
If log⁡(x+z)+log⁡(x−2y+z)=2log⁡(x−z),\log \left( {x + z} \right) + \log \left( {x - 2y + z} \right) = 2\log \left( {x - z} \right), then x,y,zx,y,z are in
View answer and explanation
Correct option: A
H.P.
Option A (H.P.) is correct because the given logarithmic equation leads to a relationship that defines a harmonic progression.
285 Easy
285 of 998
Analyzing +4 | -1
The number of real values of the parameter λ\lambda for which (log⁡16x)2−log⁡16x+log⁡16λ=0\left(\log _{16} x\right)^2-\log _{16} x+\log _{16} \lambda=0 with real coefficients will have exactly one solution is
View answer and explanation
Correct option: B
2
Option B (2) is correct because there are two real values of lambda for which the given equation has exactly one solution.
286 Easy
286 of 998
Application +4 | -1
If the sum of four numbers of APA P is 20 , then which of the following is first term of the given APA P ?
View answer and explanation
Correct option: A
5
Option A (5) is correct because the middle term of the AP is 5 when the sum of four terms is 20.
287 Easy
287 of 998
Application +4 | -1
The sum of three numbers in A.P. is 21. If
the second number is reduced by 1 while third is increased
by 1, three resulting numbers form an increasing G.P., the
common ratio of the G.P. is
View answer and explanation
Correct option: A
2
Option A (2) is correct because after reducing the second number by 1 and increasing the third by 1, the resulting numbers form a G.P. with a common ratio of 2.
288 Easy
288 of 998
Application +4 | -1
If one geometric GG and two arithmetic means A1A_1 and A2A_2 are inserted between two distinct positive
numbers, then (2A1−A2G)(2A2−A1G)\left( {\frac{{2{A_1} - {A_2}}}{G}} \right)\left( {\frac{{2{A_2} - {A_1}}}{G}} \right) is equal to
View answer and explanation
Correct option: B
1
Option B (1) is correct because by expressing A1 and A2 in terms of a and b, the given expression simplifies to 1.
289 Easy
289 of 998
Application +4 | -1
The sum to nn terms of the series 32+54+98+1716+…\frac{3}{2}+\frac{5}{4}+\frac{9}{8}+\frac{17}{16}+\ldots is equal to
View answer and explanation
Correct option: A
n+1−2−nn+1-2^{-n}
Option D (16n(n+1)(n+2)\frac{{1}}{{6}} n(n+1)(n+2)) is correct. By finding the general term and summing the series, we get the result.
290 Easy
290 of 998
Analyzing +4 | -1
In a G.P. of positive terms, any term is equal to the sum of the next two terms. Then, the common ratio of the G.P. is
View answer and explanation
Correct option: A
5−12\frac{\sqrt{5}-1}{2}
Option A (5−12\frac{\sqrt{5}-1}{2}) is correct because it is the positive root of the quadratic equation derived from the given condition that any term equals the sum of the next two terms in the G.P.
291 Easy
291 of 998
Analyzing +4 | -1
For any three positive real numbers a,ba, b and cc, 9(25a2+b2)+25(c2−3ac)=15b(3a+c)9\left(25 a^2+b^2\right)+25\left(c^2-3 a c\right)=15 b(3 a+c). Then,
View answer and explanation
Correct option: D
b,cb, c and aa are in A.P.
Option D (b,cb, c and aa are in A.P.) is correct because the given equation implies a specific relationship between a,b,a, b, and cc, which leads to b,c,b, c, and aa being in A.P.
292 Easy
292 of 998
Application +4 | -1
If the sum of nn terms of a AP is nA+n2B,nA + {n^2}B, where AA and BB are constants, then its common difference will be
View answer and explanation
Correct option: D
2  B2\;B
Option D (2B2B) is correct because the common difference of the AP is derived from the given sum formula by finding the difference between consecutive terms.
293 Easy
293 of 998
Application +4 | -1
If 4log⁡93+9log⁡24=10log⁡x83,{4^{{{\log }_9}3}} + {9^{{{\log }_2}4}} = {10^{{{\log }_x}83}}, then x=x =
View answer and explanation
Correct option: D
10
Option D (10) is correct because it satisfies the equation after simplifying the logarithmic and exponential terms.
294 Easy
294 of 998
Application +4 | -1
7th 7^{\text {th }} term of an A.P. is 40 , then the sum of first 13 terms is
View answer and explanation
Correct option: B
520
Option B (520) is correct because the sum of the first 13 terms of an A.P. can be found by multiplying the 7th term by 13, given that the 7th term is the middle term.
295 Easy
295 of 998
Application +4 | -1
If a=0.2,b=5a=0.2, b=\sqrt{5} and x=14+18+116+…∞x=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\ldots \infty, then alog⁡bx=a^{\log _b x}=
View answer and explanation
Correct option: C
4
Option C (4) is correct because simplifying the expression using logarithm properties and the sum of an infinite geometric series results in 4.
296 Easy
296 of 998
Understanding +4 | -1
1+(log⁡en)22!+(log⁡en)44!+...1 + \frac{{{{\left( {{{\log }_e}n} \right)}^2}}}{{2!}} + \frac{{{{\left( {{{\log }_e}n} \right)}^4}}}{{4!}} + ... is equal to
View answer and explanation
Correct option: C
12(n+n−1)\frac{1}{2}\left( {n + {n^{ - 1}}} \right)
Option C (12(n+n−1)\frac{1}{2}\left( {n + {n^{ - 1}}} \right)) is correct because the given series is the expansion of elog⁡n+e−log⁡n2\frac{e^{\log n} + e^{-\log n}}{2}.
297 Easy
297 of 998
Analyzing +4 | -1
If x18=y21=z28,{x^{18}} = {y^{21}} = {z^{28}}, then 3,3log⁡yx,  3log⁡zy,  7log⁡xz3,3{\log _y}x,\;3{\log _z}y,\;7{\log _x}z are in
View answer and explanation
Correct option: A
A.P.
Option A (A.P.) is correct because the given terms form an arithmetic progression with a common difference of 0.5.
298 Easy
298 of 998
Application +4 | -1
The first two terms of a geometric progression add upto 12 the sum of the third and the fourth terms is 48 , if the terms of the geometric progression are alternately positive and negative, then the first term is
View answer and explanation
Correct option: A
-12
Option A (-12) is correct because it is the first term of the geometric progression, calculated using the given conditions and the fact that the terms are alternately positive and negative.
299 Easy
299 of 998
Analyzing +4 | -1
The sequence S=i+2i2+3i3+….S=i+2 i^2+3 i^3+\ldots .. upto 100 terms simplifies to where i=−1\mathrm{i}=\sqrt{-1}
View answer and explanation
Correct option: A
50(1−i)50(1-i)
Option A (50(1-i)) is correct because after multiplying the series by i and subtracting, the resulting geometric series simplifies to 50(1-i).
300 Easy
300 of 998
Application +4 | -1
If nn is even, then the sum of nn terms of the series 12−22+32−42+52−62+……1^2-2^2+3^2-4^2+5^2-6^2+\ldots \ldots, is
View answer and explanation
Correct option: A
−n(n+1)2-\frac{n(n+1)}{2}
Option A (−n(n+1)2-\frac{n(n+1)}{2}) is correct because the sum of the series, when n is even, can be simplified by pairing terms and summing the resulting arithmetic progression.
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