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JEE • MATHEMATICS • SEQUENCE OF SERIES

Sequence of series practice · Mixed difficulty

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151 Easy
151 of 998
Analyzing +4 | -1
If 4a2+9b2+16c2=2(3ab+6bc+4ca)4{a^2} + 9{b^2} + 16{c^2} = 2\left( {3ab + 6bc + 4ca} \right), where a,b,ca,b,c are non-zero numbers, then a,b,ca,b,c are in
View answer and explanation
Correct option: C
HP
Option C (HP) is correct because the given equation can be rearranged to show that 2a=3b=4c2a = 3b = 4c, which implies that a,b,ca, b, c are in Harmonic Progression.
152 Easy
152 of 998
Application +4 | -1
The coefficient of x4{x^4} in the expansion of 1−2x−x2e−x\frac{{1 - 2x - {x^2}}}{{{e^{ - x}}}} is
View answer and explanation
Correct option: A
1−k−k2k!\frac{{1 - k - {k^2}}}{{k!}}
Option C is correct because by substituting the given value of x and applying the properties of logarithms, the expression simplifies to -6.
153 Easy
153 of 998
Application +4 | -1
A man saves ₹200₹ 200 in each of the first three months of his service. In each of the subsequent months his saving increases by ₹40₹ 40 more than the saving of immediately previous month. His total saving from the start of service will be ₹ 11040 after
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Correct option: C
21 months
Option C (21 months) is correct because it is the total number of months required to reach the total savings of ₹ 11040, considering the initial constant savings and the subsequent increasing savings.
154 Easy
154 of 998
Application +4 | -1
If the first, second and the last terms of an A.P. are a,ba, b, c respectively, then the sum of the A.P. is
View answer and explanation
Correct option: C
(a+c)(b+c−2a)2(b−a)\frac{(a+c)(b+c-2 a)}{2(b-a)}
Option C is correct because the sum of the A.P. is calculated using the first, second, and last terms.
155 Easy
155 of 998
Application +4 | -1
The value of (0.16)log⁡2.5(13+132+133+…∞){\left( {0.16} \right)^{{{\log }_{2.5}}\left( {\frac{1}{3} + \frac{1}{{{3^2}}} + \frac{1}{{{3^3}}} + \ldots \infty } \right)}} , is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the expression simplifies to 4 after evaluating the infinite geometric series and applying logarithmic properties.
156 Medium
156 of 998
Application +4 | -1
If the sum of any number of terms in a sequence is always three times the squared number of these terms, then the sequence is
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Correct option: A
an AP
Option A (an AP) is correct because if the sum of any number of terms in a sequence is three times the squared number of these terms, the sequence is an arithmetic progression.
157 Easy
157 of 998
Application +4 | -1
If the (p+q)\left( {p + q} \right)th term of a geometric series is mm and the (p−q)\left( {p - q} \right)th term is n, then the ppth term is
View answer and explanation
Correct option: A
(mn)1/2{\left( {mn} \right)^{1/2}}
Option A ((mn)1/2{( {mn} )}^{1/2}) is correct because it is derived by multiplying the two given terms and taking the square root.
158 Medium
158 of 998
Application +4 | -1
Let a1,a2,…,a10a_1, a_2, \ldots, a_{10} be in AP and h1,h2,…,h10h_1, h_2, \ldots, h_{10} be in HP. If a1=h1=2a_1=h_1=2 and a10=h10=3a_{10}=h_{10}=3, then a4h7a_4 h_7 is
View answer and explanation
Correct option: D
6
Option D (6) is correct because by using the properties of AP and HP, we can find the values of a_4 and h_7 and then calculate their product.
159 Easy
159 of 998
Application +4 | -1
Let a1,a2,a3,…{a_1},{a_2},{a_3}, \ldots be terms of an AP. If a1+a2+…+apa1+a2+…+aq=p2q2,  p≠q\frac{{{a_1} + {a_2} + \ldots + {a_p}}}{{{a_1} + {a_2} + \ldots + {a_q}}} = \frac{{{p^2}}}{{{q^2}}},\;p \ne q, then a6a21\frac{{{a_6}}}{{{a_{21}}}} equals
View answer and explanation
Correct option: C
1141\frac{{11}}{{41}}
Option C is correct because by using the given ratio of sums and properties of arithmetic progressions, we can find the ratio of the 6th term to the 21st term.
160 Medium
160 of 998
Application +4 | -1
The sum to 10 terms of the series 11+12+14+21+22+24+31+32+34+…\frac{1}{1+1^{2}+1^{4}}+\frac{2}{1+2^{2}+2^{4}}+\frac{3}{1+3^{2}+3^{4}}+\ldots is
View answer and explanation
Correct option: C
55111\frac{55}{111}
The correct answer is C (55111\frac{55}{111}) because the sum to 10 terms of the given series is correctly calculated using telescoping series method.
161 Easy
161 of 998
Application +4 | -1
If x>0x > 0, and
log⁡2x+log⁡2(x)+\log _2 x+\log _2(\sqrt{x})+ log⁡2(x4)+log⁡2(x8)+log⁡2(x16)+…=4\log _2(\sqrt[4]{x})+\log _2(\sqrt[8]{x})+\log _2(\sqrt[16]{x})+\ldots=4
then xx equals
View answer and explanation
Correct option: C
4
Option C (4) is correct because simplifying the logarithmic expression using properties of logarithms and geometric series leads to x=4.
162 Medium
162 of 998
Application +4 | -1
The first term of a G.P of real numbers given by b1,b2,b3,………b_1, b_2, b_3, \ldots \ldots \ldots. is Unity. Then the minimum value of 4b2+5b34 b_2+5 b_3 is …\ldots.
View answer and explanation
Correct option: B
−4/5-4 / 5
Option B (-4/5) is correct because it represents the minimum value of the quadratic expression 5r2+4r5r^2 + 4r obtained by completing the square or using the vertex formula.
163 Easy
163 of 998
Application +4 | -1
Let 1x1,1x2,1x3,….,(xi≠0\frac{1}{x_{1}}, \frac{1}{x_{2}}, \frac{1}{x_{3}}, \ldots .,\left(x_{i} \neq 0\right. for i=1,2,…,n)\left.i=1,2, \ldots, n\right) be in A.P. such that x1=4x_{1}=4 and x21=20x_{21}=20. If nn is the least positive integer for which xn>50x_{n}>50, then ∑i=1n(1xi)\sum_{i=1}^{n}\left(\frac{1}{x_{i}}\right) is equal to.
View answer and explanation
Correct option: C
134\frac{13}{4}
Option C (13/4) is correct because it is the sum of the reciprocals of the first n terms of the A.P., where n is the least positive integer for which x_n > 50.
164 Easy
164 of 998
Analyzing +4 | -1
If a,b,ca,b,c are in G.P. and log⁡ca,log⁡bc,log⁡ab{\log _c}a,{\log _b}c,{\log _a}b are in A.P., then the common difference of the A.P. is
View answer and explanation
Correct option: B
3/23/2
Option B (3/2) is correct because, given the conditions, the common difference of the arithmetic progression formed by the logarithms is calculated to be 3/2.
165 Easy
165 of 998
Application +4 | -1
If a,b,ca, b, c are in AP and (a+2b−c)(2b+c−a)(c+a−b)(a+2 b-c)(2 b+c-a)(c+a-b) =λabc=\lambda a b c, then λ\lambda is
View answer and explanation
Correct option: C
4
Option C (16) is correct because the minimum value of the expression is 16, obtained by applying AM-GM inequality.
166 Easy
166 of 998
Analyzing +4 | -1
The series expansion of log⁡{(1+x)1+x(1−x)1−x},\log \left\{ {{{\left( {1 + x} \right)}^{1 + x}}{{\left( {1 - x} \right)}^{1 - x}}} \right\}, is
View answer and explanation
Correct option: A
2{x21⋅2+x43⋅4+x65⋅6+…}2\left\{ {\frac{{{x^2}}}{{1 \cdot 2}} + \frac{{{x^4}}}{{3 \cdot 4}} + \frac{{{x^6}}}{{5 \cdot 6}} + \ldots } \right\}
Option A (2{x21⋅2+x43⋅4+x65⋅6+…}2\left\{ {\frac{{{x^2}}}{{1 \cdot 2}} + \frac{{{x^4}}}{{3 \cdot 4}} + \frac{{{x^6}}}{{5 \cdot 6}} + \ldots } \right\}) is correct because it is the series expansion of log⁡{(1+x)1+x(1−x)1−x}\log \left\{ {\left( {1 + x} \right)^{1 + x} {\left( {1 - x} \right)^{1 - x}}} \right\} after simplification.
167 Easy
167 of 998
Application +4 | -1
If log⁡7{log⁡5(x+5+x)}=0{\log _7}\left\{ {{{\log }_5}\left( {\sqrt {x + 5} + \sqrt x } \right)} \right\} = 0 then x=x =
View answer and explanation
Correct option: B
4
Option B (4) is correct because solving the logarithmic equation leads to x = 4 after simplification and squaring.
168 Easy
168 of 998
Application +4 | -1
If 2,a,23,b2, a, 2^3, b and 252^5 are in GPG P, then aba b is
View answer and explanation
Correct option: B
64
Option B (64) is correct because in a GP, the product of terms equidistant from the beginning and end is constant, so ab=2×25=64ab = 2 \times 2^5 = 64.
169 Easy
169 of 998
Application +4 | -1
Fifth term of a G.P. is 2, then the product of its 9 terms is
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Correct option: B
512
Option B (512) is correct because the product of 9 terms in a GP with the fifth term being 2 is equal to 2 raised to the power of 9, which is 512.
170 Easy
170 of 998
Application +4 | -1
If a,b,ca, b, c, are in A.P. and p,p′p, p^{\prime} are respectively A.M. and GM. between aa and bb while q,q′q, q^{\prime} are respectively AM and GM\mathrm{GM}, between b\mathrm{b} and c\mathrm{c}, then
View answer and explanation
Correct option: C
p2−q2=p′2−q′2p^2-q^2=p^{\prime 2}-q^{\prime 2}
Option A (1) is correct because the sum of the solutions for x divided by pi equals 1, after solving the given equation involving cosine.
171 Medium
171 of 998
Understanding +4 | -1
In an AP the sum of any two terms, such that the distance of one of them from the beginning is same as that of the other from the end, is
View answer and explanation
Correct option: B
Sum of first and last terms
Option B is correct because in an arithmetic progression, the sum of terms equidistant from the beginning and end is constant and equal to the sum of the first and last terms.
172 Easy
172 of 998
Understanding +4 | -1
The sum of nn arithmetic means between aa and bb is
View answer and explanation
Correct option: A
n(a+b)2\frac{n(a+b)}{2}
Option A (n(a+b)2\frac{n(a+b)}{2}) is correct because the sum of nn arithmetic means between aa and bb is given by nn times the average of aa and bb, which is n(a+b)2\frac{n(a+b)}{2}.
173 Easy
173 of 998
Application +4 | -1
Let a1,a2,…,a10a_1, a_2, \ldots, a_{10} be in AP and h1,h2,…,h10h_1, h_2, \ldots, h_{10} be in HP. If a1=h1=2a_1=h_1=2 and a10=h10=3a_{10}=h_{10}=3, then a4h7a_4 h_7 is
View answer and explanation
Correct option: D
6
Option D (6) is correct because it is the product of the 4th term of the AP and the 7th term of the HP, calculated using the given conditions.
174 Easy
174 of 998
Application +4 | -1
If a1,a2,a3,…a_1, a_2, a_3, \ldots are in GP with first term aa and common ratio rr, then a1a2a12−a22+a2a3a22−a32+a3a4a32−a42+…+an−1anan−12−an2\frac{a_1 a_2}{a_1^2-a_2^2}+\frac{a_2 a_3}{a_2^2-a_3^2}+\frac{a_3 a_4}{a_3^2-a_4^2}+\ldots+\frac{a_{n-1} a_n}{a_{n-1}^2-a_n^2} is equal to
View answer and explanation
Correct option: B
(n−1)r1−r2\frac{(n-1) r}{1-r^2}
Option C (4) is correct because the given condition a,b,ca, b, c are in AP leads to the simplification of the expression to 4abc4abc, thus λ=4\lambda = 4.
175 Easy
175 of 998
Application +4 | -1
The first 3 terms of the sequence which is defined by an=nn2+1a_n=\frac{n}{n^2+1}, are
View answer and explanation
Correct option: B
12,25,310\frac{1}{2}, \frac{2}{5}, \frac{3}{10}
Option B (12,25,310\frac{1}{2}, \frac{2}{5}, \frac{3}{10}) is correct because these are the first three terms obtained by substituting n=1,2,3n=1, 2, 3 into the given sequence formula.
176 Easy
176 of 998
Application +4 | -1
The value of ∑r=1630(r+2)(r−3)\sum_{\mathrm{r}=16}^{30}(\mathrm{r}+2)(\mathrm{r}-3) is equal to :
View answer and explanation
Correct option: A
7770
Option A (7770) is correct because it is the result of correctly summing the given series.
177 Easy
177 of 998
Understanding +4 | -1
If aa and bb are two different positive real numbers, then which of the following statements is true?
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Correct option: B
2ab<a+b2\sqrt {ab} < a + b
Option B is correct because for two different positive real numbers, the Arithmetic Mean is always greater than the Geometric Mean.
178 Medium
178 of 998
Application +4 | -1
The sum of the series 1.32+2.52+3.72+  ...{1.3^2} + {2.5^2} + {3.7^2} + \;... upto 20 terms is
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Correct option: A
188090
Option A is correct because by finding the general term of the series and summing up to 20 terms, the sum is calculated to be 188090.
179 Easy
179 of 998
Application +4 | -1
The first and second terms of a G.P. are x−4x^{-4} and xnx^n respectively. If x52x^{52} is the eight th term of the same progression, then nn is equal to
View answer and explanation
Correct option: B
4
Option B (4) is correct because solving the G.P. equation yields n=4.
180 Easy
180 of 998
Application +4 | -1
The value of log⁡0.524,\sqrt {\log _{0.5}^24} , is
View answer and explanation
Correct option: A
−2- 2
Option A (-2) is correct because the expression simplifies to the logarithm of 4 to the base 0.5, which equals -2.
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