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JEE • MATHEMATICS • SEQUENCE OF SERIES

Sequence of series practice · Mixed difficulty

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751 Easy
751 of 998
Application +4 | -1
The value of 7 log⁡1615+5log⁡2524+3log⁡8180,\log \frac{{16}}{{15}} + 5\log \frac{{25}}{{24}} + 3\log \frac{{81}}{{80}},, is
View answer and explanation
Correct option: A
log⁡2\log 2
Option A log⁡2\log 2 is correct because it is obtained by simplifying the logarithmic expression using logarithmic properties.
752 Easy
752 of 998
Application +4 | -1
Three positive numbers form an increasing G.P. If the middle term in this G.P. is tripled, the new numbers are in A.P. Then the common ratio of G.P.is:
View answer and explanation
Correct option: A
3+223+2 \sqrt{2}
Option A (3+223+2 \sqrt{{2}}) is correct because by tripling the middle term and setting up an A.P., we can solve for the common ratio of the G.P.
753 Easy
753 of 998
Application +4 | -1
In a G.P. with alternatively positive and negative terms, any term is the A.M. of the next two terms. Then, the common ratio of the G.P. is
View answer and explanation
Correct option: C
−2- 2
Option C (-2) is correct because setting up the A.M. equation and solving the quadratic results in a common ratio of -2.
754 Medium
754 of 998
Understanding +4 | -1
If three numbers be in G.P., then their logarithms will be in
View answer and explanation
Correct option: A
A.P.
Option B (nn+1\frac{n}{n+1}) is correct because the series can be expressed as a telescoping sum, where each term is of the form 1k(k+1)=1k−1k+1\frac{1}{k(k+1)} = \frac{1}{k} - \frac{1}{k+1}, leading to the result nn+1\frac{n}{n+1}.
755 Easy
755 of 998
Understanding +4 | -1
If Sn=13+23+...+n3{S_n} = {1^3} + {2^3} + ... + {n^3} and Tn=1+2+...+n{T_n} = 1 + 2 + ... + n, then
View answer and explanation
Correct option: C
Sn=Tn2{S_n} = T_n^2
Option C is correct because the sum of cubes of first n natural numbers is equal to the square of the sum of first n natural numbers.
756 Easy
756 of 998
Application +4 | -1
H.M. between 128\frac{1}{28} and 110\frac{1}{10} is
View answer and explanation
Correct option: A
119\frac{1}{19}
Option A is correct because the harmonic mean between two numbers is calculated using the formula 2ab/(a+b).
757 Easy
757 of 998
Application +4 | -1
The value of alog⁡b(log⁡bx)log⁡ba,{a^{\frac{{{{\log }_b}\left( {{{\log }_b}x} \right)}}{{{{\log }_b}a}}}}, is
View answer and explanation
Correct option: B
log⁡bx{\log _b}x
Option B (log⁡bx{\log _b}x) is correct because the expression simplifies using properties of logarithms and exponents.
758 Easy
758 of 998
Application +4 | -1
The sum of a GP with common ratio 3 is 364 and last term is 243, then the number of terms is
View answer and explanation
Correct option: A
6
Option A (6) is correct because it is the number of terms that satisfies the given conditions for the geometric progression.
759 Easy
759 of 998
Application +4 | -1
If 2/3, kk, 5/8 are in AP, then value of kk is
View answer and explanation
Correct option: D
31/4831/48
Option D (31/4831/48) is correct because in an arithmetic progression, the middle term is the average of the first and third terms.
760 Easy
760 of 998
Application +4 | -1
Which of the following sequences is an A.P. with common difference 3?
View answer and explanation
Correct option: B
an=3n+5a_n=3 n+5
Option B (an=3n+5a_n=3n+5) is correct because it represents a linear expression in 'n' with a coefficient of 3, indicating an arithmetic progression with a common difference of 3.
761 Medium
761 of 998
Application +4 | -1
If log⁡aab=x,{\log _a}ab = x, then the value of log⁡bab{\log _b}ab is
View answer and explanation
Correct option: B
xx−1\frac{x}{{x - 1}}
Option B (xx−1\frac{x}{{x - 1}}) is correct because it is the correct expression for log⁡bab{\log _b}ab in terms of xx, derived from the given equation log⁡aab=x{\log _a}ab = x.
762 Easy
762 of 998
Understanding +4 | -1
∑n=0∞(log⁡ex)nn  !  is  equal  to\sum \limits_{n = 0}^\infty \frac{{{{\left( {{{\log }_e}x} \right)}^n}}}{{n\;!}}\;\mathrm{is\;equal\;to}
View answer and explanation
Correct option: B
xx
Option B (xx) is correct because the given series is the Taylor series expansion of eye^y where y=log⁡exy = \log_e x.
763 Easy
763 of 998
Analyzing +4 | -1
If a1,a2,…an{a_1},{a_2}, \ldots {a_n} are in arithmetic progression, where a1>0{a_1} > 0 for all ii.

Then, 1a1+a2+1a2+a3+...+1an−1+an\frac{1}{{\sqrt {{a_1}} + \sqrt {{a_2}} }} + \frac{1}{{\sqrt {{a_2}} + \sqrt {{a_3}} }} + ... + \frac{1}{{\sqrt {{a_{n - 1}}} + \sqrt {{a_n}} }} is equal to
View answer and explanation
Correct option: B
n−1a1+an\frac{{n - 1}}{{\sqrt {{a_1}} + \sqrt {{a_n}} }}
Option B (n−1a1+an\frac{{n - 1}}{{\sqrt {{{{a_1}}}} + \sqrt {{{{a_n}}}} }}) is the correct answer. The sum telescopes after rationalizing each term, and the common difference allows simplification to the final expression.
764 Easy
764 of 998
Application +4 | -1
If the ratio of nth n^{\text {th }} terms of two A.P.S is (2n+8):(5n−3)(2 n+8):(5 n-3), then the ratio of the sums of their nn terms is
View answer and explanation
Correct option: C
(2n+18):(5n−1)(2 n+18):(5 n-1)
Option C ((2n+18):(5n−1)(2n+18):(5n-1)) is correct because the ratio of the sums of their n terms is obtained by replacing n by (n+1)/2 in the given ratio.
765 Easy
765 of 998
Application +4 | -1
If the sum of three numbers in A.P. is 24 and their product is 440, then common difference of the A.P. can be
View answer and explanation
Correct option: A
3
Option A (3) is correct because by setting up equations based on the given sum and product, we can solve for the common difference.
766 Easy
766 of 998
Application +4 | -1
If xlog⁡x(x2−4x+5)=(x−1),{x^{{{\log }_x}\left( {{x^2} - 4x + 5} \right)}} = \left( {x - 1} \right), then x=x =
View answer and explanation
Correct option: B
2
Option B (2) is correct because substituting x=2 into the equation satisfies the given condition.
767 Easy
767 of 998
Application +4 | -1
Let Sn{S_n} denote the sum of the first nn terms of an AP. If S4=16{S_4} = 16 and S6=− 48{S_6} = - \,48 then S10{S_{10}} is equal to
View answer and explanation
Correct option: C
-320
Option C (-320) is correct because it is the sum of the first 10 terms of the arithmetic progression, calculated using the given sums of the first 4 and 6 terms.
768 Easy
768 of 998
Application +4 | -1
If 2log⁡8a=x,log⁡22a=y2{\log _8}a = x,{\log _2}2a = y and y−x=4,y - x = 4, then x=x =
View answer and explanation
Correct option: D
6
Option D (6) is correct because solving the system of logarithmic equations leads to x = 6.
769 Easy
769 of 998
Application +4 | -1
The sum of first two terms of an infinite G.P. is 1 and every term is twice the sum of the successive terms. Its first term is
View answer and explanation
Correct option: C
3/43/4
Option C 3/43/4 is correct because it is found by setting up equations based on the given information and solving for the first term.
770 Easy
770 of 998
Application +4 | -1
If log⁡303=x,log⁡305=y,{\log _{30}}3 = x,{\log _{30}}5 = y, then log⁡308={\log _{30}}8 =
View answer and explanation
Correct option: A
3(1−x−y)3\left( {1 - x - y} \right)
Option A, 3(1−x−y)3(1 - x - y), is correct because it is derived by expressing log⁡308{\log_{30}}8 in terms of log⁡303{\log_{30}}3 and log⁡305{\log_{30}}5.
771 Easy
771 of 998
Application +4 | -1
If an APA P is given by 3,a2,…,203, a_2, \ldots, 20, then which of the following is the sum of second and second last terms?
View answer and explanation
Correct option: C
23
Option C (23) is correct because the sum of the second and second-to-last terms in an AP is equal to the sum of the first and last terms.
772 Medium
772 of 998
Application +4 | -1
If a,ba, b and cc are the sides of a △ABC\triangle A B C are in AP, then cot⁡C2\cot \frac{C}{2} is equal to
View answer and explanation
Correct option: A
3tan⁡A23 \tan \frac{A}{2}
Option A (3tan⁡A23 \tan \frac{A}{2}) is correct because, given that a, b, and c are in AP, we can express cot⁡C2\cot \frac{C}{2} in terms of tan⁡A2\tan \frac{A}{2} using trigonometric identities.
773 Medium
773 of 998
Application +4 | -1
If Sn=∑r=1n1+2+22+… upto r terms 2rS_n=\sum\limits_{{r=1}}^n \frac{1+2+2^2+\ldots \text { upto } r \text { terms }}{2^r}, then SnS_n is equal to
View answer and explanation
Correct option: C
n−1+12nn-1+\frac{1}{2^n}
Option C (n−1+12nn-1+\frac{1}{2^n}) is correct because the sum of the geometric series is calculated and simplified correctly.
774 Easy
774 of 998
Application +4 | -1
If the interior angles of a polygon are in A.P. with common difference 5∘5^\circ and smallest angle is 120∘,120^\circ , then the number of sides of the polygon is
View answer and explanation
Correct option: B
9
Option B (9) is correct because solving the quadratic equation for the number of sides results in two possible values, but only one is valid given the constraint on the largest angle.
775 Easy
775 of 998
Application +4 | -1
∑k=1513+23+...+k31+3+5+...+(2k−1)\sum \limits_{k = 1}^5 \frac{{{1^3} + {2^3} + ... + {k^3}}}{{1 + 3 + 5 + ... + \left( {2k - 1} \right)}} is equal to
View answer and explanation
Correct option: A
22.522.5
Option A (22.5) is correct because it is the result of simplifying the summation and calculating the sum of the series.
776 Medium
776 of 998
Application +4 | -1
If the ratio of AM between two positive real numbers aa and bb to their HM is m:n,m:n, then a:ba:b is equal to
View answer and explanation
Correct option: C
m+m−nm−m−n\frac{{\sqrt m + \sqrt {m - n} }}{{\sqrt m - \sqrt {m - n} }}
Option C (m+m−nm−m−n\frac{{\sqrt m + \sqrt {m - n} }}{{\sqrt m - \sqrt {m - n} }}) is correct because it is derived by solving for the two numbers a and b using the given ratio of AM to HM.
777 Easy
777 of 998
Application +4 | -1
If x,  y,  zx,\;y,\;z are in HP, then the value of expression log⁡(x+z)+log⁡(x−2y+z)  \log \left( {x + z} \right) + \log \left( {x - 2y + z} \right)\; will be
View answer and explanation
Correct option: B
2log⁡(x−z)2\log \left( {x - z} \right)
Option B (2log⁡(x−z)2\log \left( {x - z} \right)) is correct because the given expression simplifies to 2log⁡(x−z)2\log(x-z) when x, y, and z are in Harmonic Progression (HP).
778 Easy
778 of 998
Application +4 | -1
If the sum of the series 20+1935+1915+1845+….20+19 \frac{3}{5}+19 \frac{1}{5}+18 \frac{4}{5}+\ldots .. upto nn terms is 488 and the nth n^{\text {th }} term is negative, then the value of nth n^{\text {th }} term is
View answer and explanation
Correct option: B
−4-4
The correct answer is -4 because it is the negative nth term of the series that satisfies the given sum of 488.
779 Easy
779 of 998
Application +4 | -1
In aGPa G P, if {an},a1=3,an=96\left\{a_n\right\}, a_1=3, a_n=96 and Sn=189S_n=189, then the value of rr is
View answer and explanation
Correct option: B
2
Option B (2) is correct because the common ratio 'r' is correctly calculated using the formula for the sum of a geometric progression.
780 Easy
780 of 998
Application +4 | -1
If (1−p)(1+2x+4x2+8x3+16x4+32x5)=1−p6,p≠1\left( {1 - p} \right)\left( {1 + 2x + 4{x^2} + 8{x^3} + 16{x^4} + 32{x^5}} \right) = 1 - {p^6},p \ne 1 then a value of p/xp/x is
View answer and explanation
Correct option: B
2
Option B (2) is correct because by simplifying the given equation, we find that p = 2x, hence p/x = 2.
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