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JEE • MATHEMATICS • SEQUENCE OF SERIES
Sequence of series practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 691-720 of 998 questions
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691
Easy
691 of 998
Application
+4 | -1
If , then
View answer and explanation
Correct option: B
Option B () is correct because it results from expressing in terms of using change of base formulas.
692
Medium
692 of 998
Analyzing
+4 | -1
Let the sequence, form an AP, then is equal to
View answer and explanation
Correct option: A
Option A is correct because the given expression can be simplified using the properties of arithmetic progressions and factorization.
693
Easy
693 of 998
Application
+4 | -1
Let , and be in GP with common ratio , where and . If 3a, 7b and 15c are the first three terms of an AP, then the 4th term of this AP is
View answer and explanation
Correct option: C
a
Option C (a) is correct because after using the properties of GP and AP, and solving for the common ratio, the 4th term of the AP is found to be a.
694
Easy
694 of 998
Application
+4 | -1
If one geometric mean and two arithmetic means and are inserted between two given quantities, then
View answer and explanation
Correct option: C
Option C () is correct because, by expressing A1 and A2 in terms of a and b, the expression simplifies to ab, which is equal to G squared.
695
Medium
695 of 998
Application
+4 | -1
The number of numbers lying between 100 and 500 that are divisible by 7 but not by 21 , is
View answer and explanation
Correct option: C
38
Option C (38) is correct because it is the number of integers between 100 and 500 divisible by 7 but not by 21, found by subtracting the number divisible by 21 from the number divisible by 7.
696
Easy
696 of 998
Application
+4 | -1
If the value of is
View answer and explanation
Correct option: B
1
Option B (1) is correct because the expression simplifies to 1 due to the properties of logarithms and exponents.
697
Medium
697 of 998
Application
+4 | -1
If and
then equals
then equals
View answer and explanation
Correct option: A
2005
Option A (2005) is correct because by adding the two given series and simplifying, we can solve for x and find that x = 2005.
698
Easy
698 of 998
Application
+4 | -1
The solution of the equation is
View answer and explanation
Correct option: C
4
Option C (4) is correct because substituting x=4 into the equation satisfies the logarithmic conditions and simplifies to a valid solution.
699
Easy
699 of 998
Application
+4 | -1
If are three successive terms of a G.P. with common ratio , the value of for which holds is given by
View answer and explanation
Correct option: C
or
Option C (r>3 or r<1) is correct because it represents the solution set of the inequality derived from the given condition.
700
Easy
700 of 998
Application
+4 | -1
If and are two A.P's such that and , then equals.
View answer and explanation
Correct option: A
2560
Option A (2560) is correct because it is the product of x_5 and h_10, calculated using the properties of arithmetic progressions.
701
Medium
701 of 998
Application
+4 | -1
A polygon has 25 sides, the lengths of which starting from the smallest side are in AP. If the perimeter of the polygon is and the length of the largest side 20 times that of the smallest, then the length of the smallest side and the common difference of an AP are
View answer and explanation
Correct option: A
Option A (8 cm, 6 1/3 cm) is correct because these are the length of the smallest side and the common difference of the AP, calculated using the given perimeter and largest side conditions.
702
Easy
702 of 998
Application
+4 | -1
The value of , where and is
View answer and explanation
Correct option: C
Option C (12.5) is correct because it results from correctly evaluating the expression using logarithm properties.
703
Easy
703 of 998
Application
+4 | -1
After inserting A.Ms between 2 and 38, the sum of the resulting progression is 200. The value of is
View answer and explanation
Correct option: B
8
Option B (8) is correct because the value of n is calculated using the formula for the sum of an arithmetic progression.
704
Medium
704 of 998
Understanding
+4 | -1
is equal to
View answer and explanation
Correct option: C
Option C is correct because the exponent simplifies to log(x) using the Taylor series expansion of log(1+x), and e^(log(x)) equals x.
705
Medium
705 of 998
Application
+4 | -1
Let the sum of the first terms of a non-constant A.P., . be , where is a constant. If is the common difference of this A.P., then the ordered pair is equal to
View answer and explanation
Correct option: A
Option A ((A, 50+46A)) is correct because the common difference and the 50th term of the A.P. are calculated using the given sum of the first n terms.
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706
Medium
706 of 998
Application
+4 | -1
The value of
View answer and explanation
Correct option: A
Option A () is correct because, after rationalizing the denominator and summing the terms, the expression simplifies to this result.
707
Easy
707 of 998
Application
+4 | -1
A man saves ₹ 200 in each of the first three months of his service. In each of the subsequent months his saving increases by ₹ 40 more than the saving in the immediately previous month. His total savings from the start of service will be after
View answer and explanation
Correct option: D
21 months
Option D (21 months) is correct because by setting up an equation representing the total savings as an arithmetic progression and solving the resulting quadratic, we find the number of months to be 21.
708
Medium
708 of 998
Application
+4 | -1
If the sum of terms of an is , then the common difference is
View answer and explanation
Correct option: D
6
Option D (6) is correct because the common difference of an AP with sum is .
709
Medium
709 of 998
Analyzing
+4 | -1
If then
View answer and explanation
Correct option: A
Option A () is correct because the sum is always less than , as each term in the series is overestimated by replacing fractions with larger values.
710
Medium
710 of 998
Analyzing
+4 | -1
If are in G.P. and and are in H.P., then is equal to
View answer and explanation
Correct option: B
0
Option B (0) is correct because the given conditions lead to the equation .
711
Medium
711 of 998
Application
+4 | -1
Suppose are distinct positive real numbers such that are in A.P. and are in G.P. The common ratio of G.P. is
View answer and explanation
Correct option: C
Option C (1/3) is correct because by using the conditions for arithmetic and geometric progressions, we can derive a relationship between a and c, leading to the common ratio of 1/3.
712
Medium
712 of 998
Application
+4 | -1
If one geometric mean and two arithmetic means and are inserted between two numbers, then is equal to
View answer and explanation
Correct option: B
Option B ((2p-q)(2q-p)) is correct because it represents the square of the geometric mean in terms of the arithmetic means.
713
Easy
713 of 998
Application
+4 | -1
The sum of 7 terms of a GP is
View answer and explanation
Correct option: C
381
Option C (381) is correct because the sum of the first 7 terms of the GP is 381.
714
Easy
714 of 998
Application
+4 | -1
Given an A.P. whose terms are all positive integers. The sum of its first nine terms is greater than 200 and less than 220. If the second term in it is 12 , then its term is:
View answer and explanation
Correct option: C
20
Option C (20) is correct because it is the 4th term of the A.P. that satisfies the given conditions where the sum of the first nine terms is between 200 and 220, and the second term is 12.
715
Easy
715 of 998
Application
+4 | -1
The value of , is
View answer and explanation
Correct option: B
Option B (2) is correct because the expression simplifies to after evaluating the infinite series in the exponent.
716
Medium
716 of 998
Application
+4 | -1
The four numbers are in AP, such that their sum is 50 and greatest of them is 4 times the least, are
View answer and explanation
Correct option: C
Option C () is correct because these four numbers are in AP, their sum is 50, and the greatest is 4 times the least.
717
Easy
717 of 998
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
Option C () is correct because solving the infinite geometric series and then finding the sine inverse gives these two solutions within the specified range.
718
Easy
718 of 998
Analyzing
+4 | -1
Let and be roots of and let and be the roots of where form an increasing GP Then the ratio of is equal to
View answer and explanation
Correct option: C
Option C () is correct because the ratio is derived from the relationships between the roots of the quadratic equations and the geometric progression.
719
Easy
719 of 998
Understanding
+4 | -1
Statement I: If '' is the first term and '' is the common difference of an A.P., then its term is given by
Statement II: The sum of terms of an A.P. with first term '' and common difference '' is given by
Choose the correct option.
Statement II: The sum of terms of an A.P. with first term '' and common difference '' is given by
Choose the correct option.
View answer and explanation
Correct option: B
Only II is true
Option B (Only II is true) is correct because statement I has an incorrect sign, while statement II correctly states the sum of n terms of an A.P.
720
Easy
720 of 998
Application
+4 | -1
If are in AP, then shall be in
View answer and explanation
Correct option: B
GP
Option B (GP) is correct because if a, b, c are in AP, then 3^a, 3^b, 3^c are in GP.
Revision notes and key takeaways
Review SEQUENCE OF SERIES in your textbook or class notes, then use this set to check your understanding.
Showing 691-720 of 998 questions
