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JEE • MATHEMATICS • SEQUENCE OF SERIES

Sequence of series practice · Mixed difficulty

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Showing 271-300 of 998 questions

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271 Easy
271 of 998
Application +4 | -1
If the sum of the first 20 terms of the series log⁡71/2+log⁡71/3x+log⁡71/4x+…\log _7 1 / 2+\log _7 1 / 3 x+\log _7 1 / 4 x+\ldots is 460 , then xx is equal to
View answer and explanation
Correct option: C
727^2
Option C (727^2) is correct because after simplifying the logarithmic series and solving for x, we find that x equals 49, which is 727^2.
272 Medium
272 of 998
Understanding +4 | -1
If the sequence <an>< a_n > is defined by an=3n+2a_n=3 n+2, then difference of any two consecutive terms is
View answer and explanation
Correct option: B
3
Option B (3) is correct because in an arithmetic progression, the difference between consecutive terms is constant and equal to the common difference, which is 3 in this case.
273 Easy
273 of 998
Application +4 | -1
The digits of a three digit number NN are in A.P. If sum of the digits is 15 and the number obtaind by reversing the digits of the number is 594 less than the original number, then 1000N−252\frac{1000}{N-252} is equal to
View answer and explanation
Correct option: B
5/35 / 3
Option B (5/35 / 3) is correct because by finding the digits of the number and using the given conditions, we can determine the value of the expression.
274 Medium
274 of 998
Application +4 | -1
The sum of n terms of the series 1+(1+x)+(1+x+x2)+  ...1 + \left( {1 + x} \right) + \left( {1 + x + {x^2}} \right) + \;... will be
View answer and explanation
Correct option: C
n(1−x)−x(1−xn)(1−x)2\frac{{n\left( {1 - x} \right) - x\left( {1 - {x^n}} \right)}}{{{{\left( {1 - x} \right)}^2}}}
Option C, n(1−x)−x(1−xn)(1−x)2\frac{{n\left( {1 - x} \right) - x\left( {1 - {x^n}} \right)}}{{{{\left( {1 - x} \right)}^2}}}, is correct because it represents the sum of the given series after simplification using the formula for the sum of a geometric progression.
275 Medium
275 of 998
Analyzing +4 | -1
If ax=by=cza^x=b^y=c^z and a,b,ca, b, c are in GP, then x,yx, y and == are in
View answer and explanation
Correct option: C
HP
Option C (HP) is correct because the reciprocals of x, y, and z are in Arithmetic Progression (AP), implying x, y, and z are in Harmonic Progression (HP).
276 Easy
276 of 998
Application +4 | -1
If the sum of first pp terms, first qq terms and first rr terms of an A.P. be x,yx,y and zz respectively. Then, xp(q−r)+yq(r−p)+zr(p−q)\frac{x}{p}\left( {q - r} \right) + \frac{y}{q}\left( {r - p} \right) + \frac{z}{r}\left( {p - q} \right) is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the given expression simplifies to zero using the properties of arithmetic progressions.
277 Medium
277 of 998
Application +4 | -1
The sum of first four terms of a GP is 12(1−5)12(1-\sqrt{5}) If the common ratio is −5-\sqrt{5}, then the first term of a GP is
View answer and explanation
Correct option: B
2
Option B (2) is correct because substituting the common ratio into the sum of the first four terms of a GP allows us to solve for the first term.
278 Medium
278 of 998
Analyzing +4 | -1
If x,y,zx,y,z be three positive prime numbers. The progression in which x,y,z\sqrt x ,\sqrt y ,\sqrt z can be three terms (not necessarily consecutive) is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because if x, y, and z are prime numbers, then the square roots cannot form an arithmetic, geometric, or harmonic progression.
279 Medium
279 of 998
Application +4 | -1
The first and last terms of an AP are 1 and 11 . If the sum of its terms is 36 , then the number of terms will be
View answer and explanation
Correct option: B
6
Option B (6) is correct because it is the number of terms in the arithmetic progression, calculated using the given first term, last term, and sum.
280 Easy
280 of 998
Application +4 | -1
If log⁡(x+z)+log⁡(x−2y+z)=2log⁡(x−z),\log \left( {x + z} \right) + \log \left( {x - 2y + z} \right) = 2\log \left( {x - z} \right), then x,y,zx,y,z are in
View answer and explanation
Correct option: A
H.P.
Option A (H.P.) is correct because the given logarithmic equation leads to a relationship that defines a harmonic progression.
281 Easy
281 of 998
Application +4 | -1
If the sum of four numbers of APA P is 20 , then which of the following is first term of the given APA P ?
View answer and explanation
Correct option: A
5
Option A (5) is correct because the middle term of the AP is 5 when the sum of four terms is 20.
282 Easy
282 of 998
Application +4 | -1
The sum of three numbers in A.P. is 21. If
the second number is reduced by 1 while third is increased
by 1, three resulting numbers form an increasing G.P., the
common ratio of the G.P. is
View answer and explanation
Correct option: A
2
Option A (2) is correct because after reducing the second number by 1 and increasing the third by 1, the resulting numbers form a G.P. with a common ratio of 2.
283 Easy
283 of 998
Application +4 | -1
If one geometric GG and two arithmetic means A1A_1 and A2A_2 are inserted between two distinct positive
numbers, then (2A1−A2G)(2A2−A1G)\left( {\frac{{2{A_1} - {A_2}}}{G}} \right)\left( {\frac{{2{A_2} - {A_1}}}{G}} \right) is equal to
View answer and explanation
Correct option: B
1
Option B (1) is correct because by expressing A1 and A2 in terms of a and b, the given expression simplifies to 1.
284 Easy
284 of 998
Application +4 | -1
The sum to nn terms of the series 32+54+98+1716+…\frac{3}{2}+\frac{5}{4}+\frac{9}{8}+\frac{17}{16}+\ldots is equal to
View answer and explanation
Correct option: A
n+1−2−nn+1-2^{-n}
Option D (16n(n+1)(n+2)\frac{{1}}{{6}} n(n+1)(n+2)) is correct. By finding the general term and summing the series, we get the result.
285 Medium
285 of 998
Application +4 | -1
The sum of the first 20 terms of the series 5+11+5+11+ 19+29+41+…19+29+41+\ldots is
View answer and explanation
Correct option: A
3520
Option A (3520) is the correct answer because the sum of the first 20 terms of the given series is calculated to be 3520 using the formula for the sum of n terms of a series.
286 Easy
286 of 998
Application +4 | -1
If the sum of nn terms of a AP is nA+n2B,nA + {n^2}B, where AA and BB are constants, then its common difference will be
View answer and explanation
Correct option: D
2  B2\;B
Option D (2B2B) is correct because the common difference of the AP is derived from the given sum formula by finding the difference between consecutive terms.
287 Medium
287 of 998
Remembering +4 | -1
If aa and bb are two positive numbers, then
View answer and explanation
Correct option: D
AM≥GM≥HMA M \geq G M \geq H M
Option D (AM≥GM≥HMA M \geq G M \geq H M) is correct because for any two positive numbers, the Arithmetic Mean is always greater than or equal to the Geometric Mean, which is greater than or equal to the Harmonic Mean.
288 Easy
288 of 998
Application +4 | -1
If 4log⁡93+9log⁡24=10log⁡x83,{4^{{{\log }_9}3}} + {9^{{{\log }_2}4}} = {10^{{{\log }_x}83}}, then x=x =
View answer and explanation
Correct option: D
10
Option D (10) is correct because it satisfies the equation after simplifying the logarithmic and exponential terms.
289 Easy
289 of 998
Understanding +4 | -1
1+(log⁡en)22!+(log⁡en)44!+...1 + \frac{{{{\left( {{{\log }_e}n} \right)}^2}}}{{2!}} + \frac{{{{\left( {{{\log }_e}n} \right)}^4}}}{{4!}} + ... is equal to
View answer and explanation
Correct option: C
12(n+n−1)\frac{1}{2}\left( {n + {n^{ - 1}}} \right)
Option C (12(n+n−1)\frac{1}{2}\left( {n + {n^{ - 1}}} \right)) is correct because the given series is the expansion of elog⁡n+e−log⁡n2\frac{e^{\log n} + e^{-\log n}}{2}.
290 Medium
290 of 998
Application +4 | -1
If the sum of first nn terms of a series is 5n2+2n5 n^2+2 n, then its second term is
View answer and explanation
Correct option: B
17
Option B (17) is correct because the second term is the difference between the sum of the first two terms and the sum of the first term.
291 Easy
291 of 998
Application +4 | -1
The first two terms of a geometric progression add upto 12 the sum of the third and the fourth terms is 48 , if the terms of the geometric progression are alternately positive and negative, then the first term is
View answer and explanation
Correct option: A
-12
Option A (-12) is correct because it is the first term of the geometric progression, calculated using the given conditions and the fact that the terms are alternately positive and negative.
292 Medium
292 of 998
Analyzing +4 | -1
If log⁡2a+log⁡4b+log⁡4c=2{\log _2}a + {\log _4}b + {\log _4}c = 2

log⁡9a+log⁡3b+log⁡9c=2{\log _9}a + {\log _3}b + {\log _9}c = 2

log⁡16a+log⁡16b+log⁡4c=2{\log _{16}}a + {\log _{16}}b + {\log _4}c = 2 then
View answer and explanation
Correct option: A
a=23,b=278,c=323a = \frac{2}{3},b = \frac{{27}}{8},c = \frac{{32}}{3}
Option A (a=23,b=278,c=323a = \frac{2}{3},b = \frac{{27}}{8},c = \frac{{32}}{3}) is correct because solving the system of logarithmic equations leads to these values for a, b, and c.
293 Medium
293 of 998
Understanding +4 | -1
The arithmetic mean, geometric mean and harmonic mean between two positive real quantities are themselves in
View answer and explanation
Correct option: B
GP
Option B (GP) is correct because the arithmetic mean (A), geometric mean (G), and harmonic mean (H) between two positive real quantities satisfy the relation G2 = AH, indicating they are in geometric progression.
294 Easy
294 of 998
Application +4 | -1
If nn is even, then the sum of nn terms of the series 12−22+32−42+52−62+……1^2-2^2+3^2-4^2+5^2-6^2+\ldots \ldots, is
View answer and explanation
Correct option: A
−n(n+1)2-\frac{n(n+1)}{2}
Option A (−n(n+1)2-\frac{n(n+1)}{2}) is correct because the sum of the series, when n is even, can be simplified by pairing terms and summing the resulting arithmetic progression.
295 Easy
295 of 998
Application +4 | -1
The series of natural numbers is divided into groups (1),(2,3,4),(5,6,7,8,9)(1), (2,3,4),(5,6,7,8,9), and so on. The sum of first and last term of the nnth group is
View answer and explanation
Correct option: A
2(n2−n+1)2\left(n^2-n+1\right)
Option A (2(n2−n+1)2(n^2-n+1)) is correct because the sum of the first and last term of the nth group is 2(n2−n+1)2(n^2 - n + 1).
296 Easy
296 of 998
Application +4 | -1
(a−ba)+12(a−ba)2+13(a−ba)3+…=\left(\frac{a-b}{a}\right)+\frac{1}{2}\left(\frac{a-b}{a}\right)^2+\frac{1}{3}\left(\frac{a-b}{a}\right)^3+\ldots= ?
View answer and explanation
Correct option: B
log⁡a(ab)\log _a\left(\frac{a}{b}\right)
Option B (log_a(a/b)) is correct because the given series is a logarithmic series and can be simplified to log_e(a/b).
297 Easy
297 of 998
Application +4 | -1
If f(x)f(x) is a function satisfying f(x+y)=f(x)f(y)f(x+y)=f(x) f(y) for all x,y∈Nx, y \in N such that f(1)=3f(1)=3 and ∑x=1nf(x)=120\sum\limits_{x=1}^n f(x)=120. Then, the value of nn is
View answer and explanation
Correct option: A
4
Option A (4) is correct because it satisfies the given functional equation and the sum condition, leading to the correct value of n.
298 Easy
298 of 998
Application +4 | -1
Suppose A.M. of two positive numbers be 7 and G.M. between them be 5. The A.M. between their squares is
View answer and explanation
Correct option: B
73
Option B (73) is correct because it is calculated by using the given A.M. and G.M. to find the A.M. of the squares of the two numbers.
299 Easy
299 of 998
Application +4 | -1
If H.M. : G.M. =4:5=4: 5 for the two positive numbers, then the ratio of the numbers is
View answer and explanation
Correct option: A
4:14: 1
Option A (4:14: 1) is correct because it is derived from the given ratio of H.M. to G.M. by using componendo and dividendo.
300 Easy
300 of 998
Application +4 | -1
The solution of the equation log⁡π(log⁡2(log⁡7x))=0,{\log _\mathrm{\pi }}\left( {{{\log }_2}\left( {{{\log }_7}x} \right)} \right) = 0, is
View answer and explanation
Correct option: A
72{7^2}
Option A (72{7^2}) is correct because, by solving the logarithmic equation step-by-step, we find that x = 72.
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