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JEE • MATHEMATICS • SCALAR TRIPLE PRODUCT

Scalar triple product practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Hard
1 of 3
Application +4 | -1
Let a⃗=i^−2j^+3k^,  b⃗=3i^+3j^−k^\vec a = \hat i - 2\hat j + 3\hat k,\;\vec b = 3\hat i + 3\hat j - \hat k and c⃗=di^+j^+(2d−1)k^\vec c = d\hat i + \hat j + \left( {2d - 1} \right)\hat k. If c⃗{\vec c} is parallel to the plane of the vectors a⃗{\vec a} and b⃗{\vec b}, then 11d=11d =
View answer and explanation
Correct option: C
−1- 1
Option C (-1) is correct because the condition for a vector to be parallel to the plane of two other vectors is correctly applied using the scalar triple product.
2 Hard
2 of 3
Application +4 | -1
A vector n\mathbf{n} of magnitude 8 units is inclined to xx-axis at 45∘,y45^{\circ}, y-axis at 60∘60^{\circ} and an acute angle with zz-axis. If a plane passes through a point (2,−1,1)(\sqrt{2},-1,1) and is normal to n\mathbf{n}, then its equation in vector form is
View answer and explanation
Correct option: B
r⋅(2i+j+k)=2\mathbf{r} \cdot(\sqrt{2} \mathbf{i}+\mathbf{j}+\mathbf{k})=2
Option B (r⋅(2i+j+k)=2\mathbf{r} \cdot(\sqrt{2} \mathbf{i}+\mathbf{j}+\mathbf{k})=2) is correct because it is the equation of the plane passing through the given point and normal to the vector n\mathbf{n}.
3 Hard
3 of 3
Application +4 | -1
A unit vector coplanar with \widehat \mathbf{i} + \widehat \mathbf{j} + 2\mathbf{\hat k}\widehat \mathbf{i} + \widehat \mathbf{j} + 2\mathbf{\hat k} and \widehat \mathbf{i} + 2\widehat \mathbf{j} + \mathbf{\hat k}\widehat \mathbf{i} + 2\widehat \mathbf{j} + \mathbf{\hat k}, and perpendicular to \widehat \mathbf{i} + \widehat \mathbf{j} + \mathbf{\hat k}\widehat \mathbf{i} + \widehat \mathbf{j} + \mathbf{\hat k} is
View answer and explanation
Correct option: A
\left( {\frac{{\widehat \mathbf{j} - \mathbf{\hat k}}}{{\sqrt 2 }}} \right)\left( {\frac{{\widehat \mathbf{j} - \mathbf{\hat k}}}{{\sqrt 2 }}} \right)
Option A (\left( {\frac{{\widehat \mathbf{j} - \mathbf{\hat k}}}{{\sqrt 2 }}} \right)\left( {\frac{{\widehat \mathbf{j} - \mathbf{\hat k}}}{{\sqrt 2 }}} \right)) is correct because it is a unit vector that is coplanar with the given vectors and perpendicular to \widehat \mathbf{i} + \widehat \mathbf{j} + \mathbf{\hat k}\widehat \mathbf{i} + \widehat \mathbf{j} + \mathbf{\hat k}.
Revision notes and key takeaways

Review SCALAR TRIPLE PRODUCT in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 3 single-correct-answer MCQs on SCALAR TRIPLE PRODUCT.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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