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JEE • MATHEMATICS • PROPERTIES OF TRIANGLES
Properties of triangles practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 91-120 of 434 questions
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91
Easy
91 of 434
Application
+4 | -1
In a , equals
View answer and explanation
Correct option: C
Option C () is correct because the given expression can be simplified using the semi-perimeter formula and trigonometric identities to obtain .
92
Easy
92 of 434
Application
+4 | -1
In a triangle . if , then the area of the triangle (in square unit) is
View answer and explanation
Correct option: B
Option B () is correct because if , then the triangle is equilateral, and the area can be calculated using the side length .
93
Easy
93 of 434
Application
+4 | -1
Consider a and let and denote the lengths of the sides opposite to vertices and , respectively. Suppose and the area of the triangle is . If is obtuse and if denotes the radius of the incircle of the triangle, then is equal to
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Correct option: A
3
Option A (3) is correct because by using the area of the triangle and the given side lengths, we can find the third side and then calculate the inradius and .
94
Medium
94 of 434
Analyzing
+4 | -1
In a is equal to
View answer and explanation
Correct option: D
Option D () is correct because after simplification using trigonometric identities, the expression reduces to this form.
95
Easy
95 of 434
Application
+4 | -1
If , then the value of is
View answer and explanation
Correct option: C
Option C () is correct because it is the result of correctly applying the double angle formula for sine, , after finding and using the given side lengths.
96
Easy
96 of 434
Analyzing
+4 | -1
If the sides of a triangle are , where , then the largest angle is
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Correct option: D
Option A (120°) is correct because by using the cosine rule, the largest angle opposite the largest side is found to be 120 degrees.
97
Easy
97 of 434
Application
+4 | -1
In a , if , then the value of in terms of the sides is
View answer and explanation
Correct option: B
Option B () is correct because it is derived from trigonometric identities and the given condition B = 90°.
98
Easy
98 of 434
Analyzing
+4 | -1
If in a , then
View answer and explanation
Correct option: C
Option C () is correct because the given equation simplifies to , implying .
99
Easy
99 of 434
Application
+4 | -1
In is equal to
View answer and explanation
Correct option: A
Option A () is correct because by using trigonometric identities and the area of a triangle formula, the expression simplifies to this form.
100
Easy
100 of 434
Application
+4 | -1
Three poles whose feet lie on a circle subtend angle respectively at the centre of the circle. If the height of the poles are in A.P. then are in
View answer and explanation
Correct option: C
H.P.
Option C (H.P.) is correct because if the heights are in A.P., then their cotangents are in H.P. due to the relationship between height, radius, and angle.
101
Easy
101 of 434
Application
+4 | -1
If be the areas of the incircle and excircles, then is equal to
View answer and explanation
Correct option: A
Option A is correct because it is derived from the relationship between the inradius, exradii, and the area of the triangle.
102
Easy
102 of 434
Application
+4 | -1
In a is equal to
View answer and explanation
Correct option: B
Option B () is correct because by simplifying the trigonometric expression and using the Law of Cosines, we can show that .
103
Easy
103 of 434
Application
+4 | -1
If , then
View answer and explanation
Correct option: A
No triangle is possible
Option A (No triangle is possible) is correct because the calculated value of sin B is greater than 1, which is not possible.
104
Easy
104 of 434
Application
+4 | -1
In a , if and , then the value of is
View answer and explanation
Correct option: A
Option A () is correct because by using the formula for and comparing it with the given equation, we find that .
105
Easy
105 of 434
Application
+4 | -1
The radii of escribed circles of the are in HP. If its area is and its perimeter is , then the lengths of its sides are
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Correct option: C
Option C (6,8,10) is correct because these side lengths form an arithmetic progression and satisfy the area and perimeter conditions.
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106
Easy
106 of 434
Application
+4 | -1
In a triangle is equal to
View answer and explanation
Correct option: C
Option C () is correct because using Napier's analogy, , and since , .
107
Easy
107 of 434
Understanding
+4 | -1
If in , then the triangle is
View answer and explanation
Correct option: A
Isosceles
Option A (Isosceles) is correct because if a sin A = b sin B, then by the sine rule, a²k = b²k, implying a = b, which defines an isosceles triangle.
108
Medium
108 of 434
Application
+4 | -1
In a triangle
View answer and explanation
Correct option: A
Option A () is correct because the expression can be rewritten in terms of the inradius and circumradius as .
109
Easy
109 of 434
Application
+4 | -1
In a and , the
View answer and explanation
Correct option: A
Option A () is correct because by applying the sine rule and trigonometric identities, we find that A = 90 degrees.
110
Medium
110 of 434
Analyzing
+4 | -1
If in a , , then is equal to
View answer and explanation
Correct option: A
Option A () is correct because the given equation implies that the triangle is right-angled and isosceles, leading to the specified side ratio.
111
Medium
111 of 434
Application
+4 | -1
The area of the triangle inscribed in a circle of radius of 4 and the measures of whose angles are in the ratio is
View answer and explanation
Correct option: A
Option A () is correct because the area of the triangle can be calculated using the formula after finding the angles and sides.
112
Medium
112 of 434
Application
+4 | -1
In a is equal to
View answer and explanation
Correct option: B
Option B () is correct because it simplifies to using projection formulas after substituting the cosine values.
113
Easy
113 of 434
Analyzing
+4 | -1
In a , if
View answer and explanation
Correct option: C
Option C () is correct because it is derived from the trigonometric identity relating the given expression to and the range of cosine squared.
114
Easy
114 of 434
Application
+4 | -1
In a . Then, relation between angles of the triangle is
View answer and explanation
Correct option: C
Option C () is correct because by using the cosine rule, we find that cos(C) = cos(2A), which implies C = 2A.
115
Easy
115 of 434
Application
+4 | -1
The sides of a triangle are three consecutive natural numbers and its largest angle is twice the smallest one. Then, the sides of the triangle are
View answer and explanation
Correct option: D
4, 5, 6
Option D (4, 5, 6) is correct because by using the sine rule and the given condition C = 2A, we can derive a relationship between the sides and solve for the consecutive natural numbers.
116
Medium
116 of 434
Application
+4 | -1
In a are given and are two values of the third side . The sum of the areas of two triangles with sides and is
View answer and explanation
Correct option: A
Option A () is correct because the sum of the areas can be expressed in terms of and using trigonometric identities.
117
Easy
117 of 434
Application
+4 | -1
In a if and , then
View answer and explanation
Correct option: C
Option C (48) is correct because by using the cosine rule to find c and then using Heron's formula to find the area, can be calculated as .
118
Easy
118 of 434
Application
+4 | -1
In a , if are in AP, then the value of is
View answer and explanation
Correct option: B
Option B is correct because it is the simplified value of the given expression using the sine rule and the condition that a, b, c are in AP.
119
Easy
119 of 434
Application
+4 | -1
In triangle ABC, the value of is
View answer and explanation
Correct option: D
Option D () is correct because simplifying the given expression using trigonometric identities and half-angle formulas leads to the result , where is the semi-perimeter of the triangle, which is equal to .
120
Easy
120 of 434
Application
+4 | -1
The angle of a right angled triangle are in A.P. The ratio of the in-radius and the perimeter is
View answer and explanation
Correct option: A
Option A () is correct because the ratio of the in-radius and the perimeter of the right-angled triangle with angles in A.P. is .
Revision notes and key takeaways
Review PROPERTIES OF TRIANGLES in your textbook or class notes, then use this set to check your understanding.
Showing 91-120 of 434 questions
