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JEE • MATHEMATICS • PROBABILITY

Probability practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 661-690 of 822 questions

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661 Easy
661 of 822
Analyzing +4 | -1
The probability that the triangle formed by choosing any three vertices from the vertices of a cube is equilateral is
View answer and explanation
Correct option: D
17\frac{1}{7}
Option D (1/7) is correct because it represents the probability of forming an equilateral triangle by choosing three vertices of a cube.
662 Easy
662 of 822
Application +4 | -1
A die is thrown. Let AA be the event that the number obtained is greater than 3. Let BB be the event that the number obtained is less than 5. Then P(A∪B)P\left( {A \cup B} \right) is
View answer and explanation
Correct option: D
1
Option D (1) is correct because the union of the two events covers all possible outcomes when rolling a die.
663 Easy
663 of 822
Application +4 | -1
Given P(A)=0.5,  P(B)=0.4,  P(A∩B)=0.3,P\left( A \right) = 0.5,\;P\left( B \right) = 0.4,\;P\left( {A \cap B} \right) = 0.3, then P(A′B′)P\left( {\frac{{A'}}{{B'}}} \right) is equal to
View answer and explanation
Correct option: C
23\frac{2}{3}
Option C (2/3) is correct because it correctly applies the conditional probability formula and De Morgan's Law.
664 Easy
664 of 822
Application +4 | -1
Two dice are thrown. The Probability that the number appeared have a sum 8 if it is known that the second dice always exhibits 4 , is
View answer and explanation
Correct option: B
16\frac{1}{6}
Option B (16\frac{1}{6}) is correct because, given the second die shows 4, only one outcome results in a sum of 8 (4,4).
665 Easy
665 of 822
Application +4 | -1
A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is
View answer and explanation
Correct option: A
328\frac{3}{28}
Option A (328\frac{3}{28}) is correct because it is the probability of drawing 2 green balls and 1 blue ball without replacement, considering all possible orders.
666 Easy
666 of 822
Application +4 | -1
Six boys and six girls sit in a row randomly. The probability that all the six girls sit together is
View answer and explanation
Correct option: A
1132\frac{1}{132}
Option A (1132\frac{1}{132}) is correct because it represents the probability of all six girls sitting together, calculated by treating the group of girls as one unit and dividing the number of favorable arrangements by the total possible arrangements.
667 Easy
667 of 822
Application +4 | -1
The probability that the two digit number formed by digit 1, 2, 3, 4, 5, is divisible by 4 (while repetition of digit is allowed), is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the actual probability is 1/5, which is not among the given options. The probability is calculated by dividing the number of two-digit numbers divisible by 4 by the total number of two-digit numbers.
668 Easy
668 of 822
Analyzing +4 | -1
A number nn is chosen at random from S={1,  2,  3,  …,  50}.S = \left\{ {1,\;2,\;3,\; \ldots ,\;50} \right\}.
Let A={n∈S:n+50n>27},  B={n∈S:n  is  a  prime}A = \left\{ {n \in S:n + \frac{{50}}{n} > 27} \right\},\;B = \left\{ {n \in S:n\;\mathrm{is\;a\;prime}} \right\} and C={n∈S:n  is  a  square}.  C = \left\{ {n \in S:n\;\mathrm{is\;a\;square}} \right\}.\mathrm{\;}Then, correct order of their probabilities is
View answer and explanation
Correct option: B
P(A)>P(B)>P(C)P\left( A \right) > P\left( B \right) > P\left( C \right)
Option B (P(A)>P(B)>P(C)P(A) > P(B) > P(C)) is correct because it accurately compares the probabilities of the defined sets A, B, and C within the given sample space S.
669 Easy
669 of 822
Understanding +4 | -1
A letter is chosen at random from the word 'ASSASSINATION'.

I. The probability that letter is a vowel is 613\frac{6}{13}.

II. The probability that letter is a consonant is 713\frac{7}{13}.
View answer and explanation
Correct option: B
Both I and II are correct
Option B (Both I and II are correct) is correct because there are 6 vowels and 7 consonants in the word 'ASSASSINATION', leading to probabilities of 6/13 and 7/13 respectively.
670 Easy
670 of 822
Application +4 | -1
One of the two events must happen. Given that the chance of one is two-third of the other, the odds in favour of the other are
View answer and explanation
Correct option: C
3:23: 2
Option C (3:23:2) is correct because it represents the odds in favor of the other event, given that one event's chance is two-thirds of the other's.
671 Easy
671 of 822
Application +4 | -1
A boy is throwing stones at a target. The probability of hitting the target at any trial is 1/21 / 2. The probability of hitting the target 5th time at the 10th throw is
View answer and explanation
Correct option: B
63/2963 / 2^9
Option B (63 / 29) is correct because it calculates the probability of hitting the target 4 times in the first 9 throws and then hitting it on the 10th throw.
672 Easy
672 of 822
Application +4 | -1
A die has four blank faces and two faces marked 3. The change of getting a total of 12 in 5 throws is
View answer and explanation
Correct option: A
5C4(13)4(23)^5{C_4}{\left( {\frac{1}{3}} \right)^4}\left( {\frac{2}{3}} \right)
Option A (5C4(13)4(23)^5{C_4}{\left( {\frac{1}{3}} \right)^4}\left( {\frac{2}{3}} \right)) is correct because it calculates the probability of getting exactly four 3's in 5 throws, which results in a total of 12.
673 Easy
673 of 822
Application +4 | -1
The probability that a man who is 85 years old will die before attaining the age of 90 is 1/31 / 3. Four persons A1,A2,A3A_1, A_2, A_3 and A4A_4 are 85 years old. The probability that A1A_1 will die before attaining the age of 90 and will be the first to die is
View answer and explanation
Correct option: C
65324\frac{65}{324}
Option C (65324\frac{65}{324}) is correct because it is the probability that A1A_1 dies before attaining the age of 90 and is the first to die among the four persons.
674 Easy
674 of 822
Application +4 | -1
Four persons independently solve a certain problem correctly with probabilities 12,34,14,18\frac{1}{2}, \frac{3}{4}, \frac{1}{4}, \frac{1}{8}. Then the probability that the problem is solved correctly by at least one of them is
View answer and explanation
Correct option: A
235256\frac{235}{256}
Option A (235256\frac{{235}}{{256}}) is correct because it calculates the probability of at least one person solving the problem by subtracting the probability that none of them solve it from 1.
675 Easy
675 of 822
Application +4 | -1
Two friends AA and BB have equal number of daughters. There are three cinema tickets which are to be distributed among the daughters of AA and BB. The probability that all the tickets got to daughters of AA is 1/20. The number of daughters each of them have is
View answer and explanation
Correct option: D
3
Option D (3) is correct because it solves the probability equation to find the number of daughters each friend has.
676 Easy
676 of 822
Application +4 | -1
A box contains 4 white and 5 black balls. AA ball is drawn at random and its colour is noted. A ball is then put back in the box along with two additional balls of its opposite colour. If a ball is drawn again from the box, then the probability that the ball drawn now is black, is
View answer and explanation
Correct option: C
5399\frac{53}{99}
Option C (5399\frac{53}{99}) is correct because it uses the law of total probability to calculate the probability of drawing a black ball.
677 Easy
677 of 822
Application +4 | -1
AA and BB toss a coin alternately till one of them tosses heads and wins the game, their respective probability of winning are
View answer and explanation
Correct option: C
13  and  23\frac{1}{3}\,\,\mathrm{and}\,\,\frac{2}{3}
Option C (13 and 23\frac{1}{3}\,\mathrm{and}\,\frac{2}{3}) is correct because it represents the probabilities of A and B winning, calculated by summing the probabilities of winning on each turn.
678 Easy
678 of 822
Application +4 | -1
In a binomial distribution B(n,p=1/4)B(n, p=1 / 4) If the probability of at least one success is greater than or equal to 9/109 / 10, then nn is greater than
View answer and explanation
Correct option: A
1log⁡104−log⁡103\frac{1}{\log _{10} 4-\log _{10} 3}
The correct answer is 1log⁡104−log⁡103\frac{1}{\log _{10} 4-\log _{10} 3} because it represents the lower bound for n, given the probability condition.
679 Easy
679 of 822
Application +4 | -1
nn persons are seated on nn chairs at a round table. The probability that two specified persons are sitting next to each other, is
View answer and explanation
Correct option: B
2n−1\frac{2}{n-1}
Option B (2n−1\frac{2}{n-1}) is correct because it represents the probability of two specific people sitting next to each other at a round table.
680 Easy
680 of 822
Application +4 | -1
Two cards are drawn successively with replacement from a well shuffled deck of 52 cards. Let XX denote the random variable of number of aces obtained in the two drawn cards. Then, P(X=1)+P(X=2)P(X = 1) + P(X = 2) equals
View answer and explanation
Correct option: A
25169\frac{{25}}{{169}}
Option A (25/169) is correct because it is the sum of probabilities of getting exactly one ace and two aces in two draws with replacement.
681 Easy
681 of 822
Application +4 | -1
Three integers are chosen at random without replacement from the first 20 integers. The probability that their product is even is
View answer and explanation
Correct option: C
17/1917 / 19
Option C (17 / 19) is correct because it is calculated by finding the probability that the product is odd and subtracting it from 1.
682 Easy
682 of 822
Application +4 | -1
An experiment succeeds twice as often as it fails. The probability that in the next six trials there are at least 4 successes, is
View answer and explanation
Correct option: A
496729\frac{496}{729}
Option A (496729\frac{496}{729}) is correct because it's the probability of at least 4 successes, calculated by summing the probabilities of 4, 5, and 6 successes.
683 Easy
683 of 822
Application +4 | -1
In a series of three trials the probability of exactly two successes in nine times as large as the probability of three successes. Then, the probability of success in each trial is
View answer and explanation
Correct option: C
01-Apr
Option D (01-Apr) is correct because the probability of success is calculated by setting up an equation based on the given relationship between the probabilities of two and three successes.
684 Easy
684 of 822
Understanding +4 | -1
A,B,CA,B,C are any three events. If P(S)P\left( S \right) denotes the probability of SS happening, then P(A∩(B∪C))=P\left( {A \cap \left( {B \cup C} \right)} \right) =
View answer and explanation
Correct option: C
P(A∩B)+P(A∩C)−P(A∩B∩C)P\left( {A \cap B} \right) + P\left( {A \cap C} \right) - P\left( {A \cap B \cap C} \right)
Option C (P(A∩B)+P(A∩C)−P(A∩B∩C)P\left( {A \cap B} \right) + P\left( {A \cap C} \right) - P\left( {A \cap B \cap C} \right)) is correct because it correctly applies the distributive property and the inclusion-exclusion principle for probabilities.
685 Easy
685 of 822
Application +4 | -1
Let XX have a binomial distribution B(n,p)B(n, p) such that the sum and the product of the mean and variance of XX are 24 and 128 respectively. If P(X>n−3)=P(X>n-3)= k2n\frac{k}{2^n}, then kk is equal to :
View answer and explanation
Correct option: B
529
Option B (529) is correct because it is the sum of the probabilities P(X=n-2), P(X=n-1), and P(X=n) for a binomial distribution with n=32 and p=1/2.
686 Easy
686 of 822
Application +4 | -1
In a group of people, if 4 are selected at a random, the probability that the any two of the four do not have same month of birth is pp then 96p11\frac{96 p}{11} is equal to
View answer and explanation
Correct option: A
5
Option A (5) is correct because the probability that no two of the four selected people have the same month of birth is 55/96, and (96p)/11 equals 5.
687 Easy
687 of 822
Application +4 | -1
A bag contains 100 tickets numbered 1 to 100. If one ticket is picked up at random, then the probability that the number is divisible by 3 or 5 is
View answer and explanation
Correct option: A
0.47
Option A (0.47) is correct because it is calculated by finding the probability of a number being divisible by 3, the probability of being divisible by 5, and subtracting the probability of being divisible by both (15).
688 Easy
688 of 822
Application +4 | -1
A 7-digit number is formed using the digit 4 three times, digit 5 two times and digit 3 two times. A number is chosen at random, the probability that the chosen mumber is even, is
View answer and explanation
Correct option: C
37\frac{3}{7}
Option D (37\frac{3}{7}) is correct because it calculates the probability of the chosen number being even by considering the arrangements where the last digit is 4.
689 Easy
689 of 822
Application +4 | -1
If the mean and variance of a variate XX having a binomial distribution are 6 and 4 respectively. then the number of values of the variate in the distribution is
View answer and explanation
Correct option: D
18
Option D (18) is correct because the number of trials n in a binomial distribution can be found using the mean (np) and variance (npq).
690 Easy
690 of 822
Application +4 | -1
If X{X} follows a binomial distribution with parameters nn =8=8 and p=1/2p=1 / 2, then P(∣X−4∣≤2)={P}(|{X}-4| \leq 2)=
View answer and explanation
Correct option: A
119128\frac{119}{128}
Option A (119/128) is correct because it calculates the probability of X being between 2 and 6 inclusive, given a binomial distribution with n=8 and p=1/2.
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