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JEE • MATHEMATICS • PROBABILITY

Probability practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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511 Easy
511 of 822
Application +4 | -1
A man is known to speak truth 3 out of 4
times. He takes out a card at random from a well shuffled
pack of 52 playing cards, and reports it is a king. The
probability that its actually a king is
View answer and explanation
Correct option: D
15\frac{1}{5}
Option D (15\frac{1}{5}) is correct because it uses Bayes' theorem to calculate the probability that the card is actually a king, given that the man reports it is a king, considering his truth-telling probability.
512 Easy
512 of 822
Analyzing +4 | -1
A book contains 1000 pages. A page is chosen at random. The probability that the sum of the digits of the marked number on the page is equal to 9 , is
View answer and explanation
Correct option: B
11200\frac{11}{200}
Option B (11200\frac{11}{200}) is correct because it represents the ratio of favorable outcomes (sum of digits equals 9) to the total possible outcomes (1000 pages).
513 Easy
513 of 822
Application +4 | -1
There are 4 envelopes corresponding to 4 letters. If the letters are placed in the envelopes at random. The probability that all the letters are not placed in the right envelopes, is
View answer and explanation
Correct option: B
2324\frac{23}{24}
Option B (23/24) is correct because it calculates the probability that not all letters are placed in the right envelopes by subtracting the probability that all letters are in the correct envelopes from 1.
514 Easy
514 of 822
Understanding +4 | -1
If E‾\overline{{E}} and F‾\overline{{F}} are the complementary events of events E{E} and F{F} respectively and if 0<P(F)<10 < {P}({F}) < 1, then
View answer and explanation
Correct option: A
P(E∣F)+P(E‾∣F)=1{P}({E} \mid {F})+{P}(\overline{{E}} \mid {F})=1
Option A (P(E∣F)+P(E‾∣F)=1{P}({E} \mid {F})+{P}(\overline{{E}} \mid {F})=1) is correct because given event F, either E occurs or its complement E‾\overline{E} occurs, and the sum of their conditional probabilities is 1.
515 Easy
515 of 822
Application +4 | -1
A bag contain 5 black balls, 4 white balls and 3 red balls. If a ball is selected randomly, the probability that it is a black or red ball, is
View answer and explanation
Correct option: D
02-Mar
Option D (2/3) is correct because it calculates the probability of selecting a black or red ball by summing the individual probabilities and dividing by the total.
516 Easy
516 of 822
Application +4 | -1
Six faces of an unbiased die are numbered with 2, 3, 5, 7, 11 and 13. If two such dice are thrown, then the probability that the sum on the uppermost faces of the dice is an odd number, is
View answer and explanation
Correct option: A
518\frac{5}{{18}}
Option A (5/18) is correct because the sum is odd only when one die shows an odd number and the other shows an even number.
517 Easy
517 of 822
Application +4 | -1
A man is known to speak the truth 3 out of 4 times. He throws a die and reports that it is a six. The probability that it is actually a six, is
View answer and explanation
Correct option: A
3/83 / 8
Option A (3/83 / 8) is correct because it uses Bayes' theorem to find the probability that it was actually a six, given the man reported it was a six.
518 Easy
518 of 822
Application +4 | -1
If events are independent and P(A)=13,  P(B)=13,  P(C)=14,  P\left( A \right) = \frac{1}{3},\;P\left( B \right) = \frac{1}{3},\;P\left( C \right) = \frac{1}{4},\; then P(A′∩B′∩C′)\mathrm{P}\left( {A' \cap B' \cap C'} \right) is equal to
View answer and explanation
Correct option: C
13\frac{1}{3}
Option C (1/3) is correct because the probability of independent events is calculated by multiplying the probabilities of the complements of each event.
519 Easy
519 of 822
Analyzing +4 | -1
One Indian and four American men and their wives are to be seated randomly around a circular table. The conditional probability that the Indian man is seated adjacent to his wife given that each American man is seated adjacent to his wife, is
View answer and explanation
Correct option: C
25\frac{2}{5}
Option C (25\frac{{2}}{{5}}) is correct because it represents the conditional probability of the Indian man sitting next to his wife given that each American man is seated next to his wife around the circular table.
520 Easy
520 of 822
Analyzing +4 | -1
If two squares are chosen at random on a chess board, the probability that they have a side in common is
View answer and explanation
Correct option: B
Jan-18
The correct answer is Jan-18 (118\frac{1}{18}) because it calculates the probability of two randomly chosen squares on a chessboard sharing a side.
521 Easy
521 of 822
Application +4 | -1
A multiple choice examination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get 4 or more correct answers just by guessing is
View answer and explanation
Correct option: C
1135\frac{{11}}{{{3^5}}}
Option C (1135\frac{{11}}{{{3^5}}}) is correct because it calculates the probability of getting 4 or more correct answers by guessing using the binomial distribution formula.
522 Easy
522 of 822
Application +4 | -1
AA and BB toss a coin alternatively till one of them gets a head and wins the game. If AA begins the game, the probability BB wins the game is
View answer and explanation
Correct option: B
13\frac{1}{3}
Option B (13\frac{{1}}{{3}}) is correct because it is calculated by summing the probabilities of B winning on their first, second, third, etc. turns, which forms a geometric series.
523 Easy
523 of 822
Application +4 | -1
If the probability for AA to fail in an examination is 0.2 and that for BB is 0.3, then the probability that either AA or BB fails, is
View answer and explanation
Correct option: B
0.44
Option B (0.44) is correct because it calculates the probability of either A or B failing by considering the probabilities of A failing, B failing, and both failing.
524 Easy
524 of 822
Application +4 | -1
Two numbers a and b are chosen at random from the set of first 30 natural numbers. The probability that a2−b2{a^2} - {b^2} is divisible by 3 is
View answer and explanation
Correct option: D
4787\frac{{47}}{{87}}
Option D (4787\frac{{47}}{{87}}) is correct because it calculates the probability that a2−b2{a^2} - {b^2} is divisible by 3 when a and b are chosen from the first 30 natural numbers.
525 Easy
525 of 822
Application +4 | -1
The records of a hospital show that 10% of the cases of a certain disease are fatal. If 6 patients are suffering from the disease, then the probability that only three will die, is
View answer and explanation
Correct option: B
1458×10−51458 \times {10^{ - 5}}
Option A (8748×10−58748 \times {10^{ - 5}}) is incorrect. The correct answer is B (1458×10−51458 \times {10^{ - 5}}) because it represents the probability of exactly three patients dying out of six, calculated using the binomial probability formula.
526 Easy
526 of 822
Application +4 | -1
A fair coin is tossed a fixed number of times. If the probability of getting 4 heads equals the probability of getting 7 heads, then the probability of getting 2 heads is
View answer and explanation
Correct option: A
552048\frac{{55}}{{2048}}
Option A (552048\frac{{55}}{{2048}}) is correct because it is the probability of getting 2 heads when the number of tosses is 11, derived from the given condition P(4 heads) = P(7 heads).
527 Easy
527 of 822
Application +4 | -1
A die is loaded so that the probability of face ii is proportional to i,i=1,2,…,6i, i=1,2, \ldots, 6. The probability of an even number occuring when the die is rolled, is
View answer and explanation
Correct option: B
47\frac{4}{7}
Option B (4/7) is correct because it calculates the probability of an even number occurring by summing the probabilities of the even faces, given that the probability of each face is proportional to its number.
528 Easy
528 of 822
Analyzing +4 | -1
AA is the set of all four digit natural numbers which has exactly one digit ' 7 '. A number is chosen at random from the set AA. The probability that the chosen number when divided by 5 leaves the remainder 2 , is
View answer and explanation
Correct option: A
97297\frac{97}{297}
Option A (97297\frac{{97}}{{297}}) is correct because it represents the probability calculated by dividing the number of favorable outcomes (numbers divisible by 5 with remainder 2) by the total number of four-digit numbers with exactly one digit '7'.
529 Easy
529 of 822
Application +4 | -1
The letters of the word 'ARTICLE' are arranged at random. The Probability that the vowels may occupy the even places, is
View answer and explanation
Correct option: A
135\frac{1}{35}
Option A (135\frac{1}{35}) is correct because it represents the probability of arranging the letters in 'ARTICLE' such that the vowels occupy the even places.
530 Easy
530 of 822
Application +4 | -1
Two numbers xx and yy are chosen at random from the set {1,2,3,…,30}\{1,2,3, \ldots, 30\}. The probability that x2−y2x^2-y^2 is divisible by 3 is
View answer and explanation
Correct option: D
none of these
Option D (none of these) is correct because the probability that x2−y2x^2-y^2 is divisible by 3 is 4787\frac{47}{87}, which is not among the given options.
531 Easy
531 of 822
Application +4 | -1
Suppose an unbiased die has nn sides numbered i=1,2i=1,2, .... nn. The die is tossed nn times (assume independence) and a "match" is defined to be the occurrence of side ii on the its roll. The probability of at least one match is
View answer and explanation
Correct option: C
1−(1−1n)n1-\left(1-\frac{1}{n}\right)^n
Option C (1-(1-1/n)^n) is correct because it calculates the probability of at least one match by finding the complement of the probability of no matches.
532 Easy
532 of 822
Understanding +4 | -1
What is the probability that when one die is thrown, the number appearing on top is even?
View answer and explanation
Correct option: C
1/21/2
Option C (12\frac{1}{2}) is correct because there are 3 even numbers (2, 4, 6) on a standard die, and 3/6 simplifies to 1/2.
533 Easy
533 of 822
Application +4 | -1
A fair die is rolled repeatedly. The probability that 1 occurs for the first time at the even throw is
View answer and explanation
Correct option: B
511\frac{5}{11}
Option B (5/11) is correct because it represents the sum of probabilities of the first 1 occurring at the 2nd, 4th, 6th, ... throws, forming a geometric series.
534 Easy
534 of 822
Application +4 | -1
The probability of choosing randomly a number cc from the set {1, 2, 3, ….., 9} such that the quadratic equation x2+4x+c=0{x^2} + 4x + c = 0 has real roots is
View answer and explanation
Correct option: D
49\frac{4}{9}
Option D (49\frac{4}{9}) is correct because it represents the probability of choosing a number c such that the quadratic equation has real roots, calculated by finding the values of c that satisfy the discriminant condition.
535 Easy
535 of 822
Application +4 | -1
A die is thrown 5 times. Getting an odd number is consider a success. The variance of the distribution is
View answer and explanation
Correct option: D
54\frac{5}{4}
Option D (5/4) is correct because the variance of a binomial distribution is calculated as npq, where n=5 and p=1/2.
536 Easy
536 of 822
Application +4 | -1
If 4P(A)=6P(B)=10P(A∩B)=1,4P\left( A \right) = 6P\left( B \right) = 10P\left( {A \cap B} \right) = 1, then P(BA)P\left( {\frac{B}{A}} \right) is equal to
View answer and explanation
Correct option: A
25\frac{2}{5}
Option A (25\frac{2}{5}) is correct because it is calculated by using the conditional probability formula P(B/A)=P(A∩B)P(A)P(B/A) = \frac{P(A \cap B)}{P(A)}.
537 Easy
537 of 822
Application +4 | -1
Three six-faced dice are thrown together. The probability that the sum of the numbers appearing on the dice is k(9≤k≤14)k(9 \leq k \leq 14) is
View answer and explanation
Correct option: A
21k−k2−83216\frac{21 k-k^2-83}{216}
Option A (21k−k2−83216\frac{{21 k-k^2-83}}{{216}}) is correct because it calculates the probability by considering the coefficient of xk−3x^{k-3} in the expansion of (1−x6)3(1−x)−3(1-x^6)^3(1-x)^{-3} for the given range of k.
538 Easy
538 of 822
Application +4 | -1
A dice is thrown two times. If getting the odd number is considered as success, then the probability of two successes is
View answer and explanation
Correct option: D
14\frac{1}{4}
Option D (14\frac{1}{4}) is correct because the probability of getting an odd number on a dice is 1/2, and since the dice are thrown twice, the probability of two successes is (1/2)*(1/2).
539 Easy
539 of 822
Application +4 | -1
A man takes a step forward with probability 0.4 and back-ward with probability 0.6. The probability that at the end of eleven steps he is one step away from the starting point is
View answer and explanation
Correct option: A
  11C6(0.24)5{\;^{11}}{C_6}{\left( {0.24} \right)^5}
Option A (  11C6(0.24)5{\;^{11}}{C_6}{\left( {0.24} \right)^5}) is correct because it accounts for the probability of ending one step away by moving either one step forward or one step backward.
540 Easy
540 of 822
Analyzing +4 | -1
In x=33n,nx = {33^n},n is a positive integral value, then what is the probability that xx will have 3 at its units place?
View answer and explanation
Correct option: B
01-Apr
Option B, 01-Apr, is correct because the probability that 33n33^n has 3 at its units place is 1/4, as the units digit cycles through 3, 9, 7, and 1.
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