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JEE • MATHEMATICS • PROBABILITY

Probability practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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271 Easy
271 of 822
Application +4 | -1
If a bag contains 50 tickets, numbered 1,2,3,…,501,2,3, \ldots, 50 of which five are drawn at random and arranged in ascending order of magnitude (x1<x2<x3<x4<x5)\left( {{x_1} < {x_2} < {x_3} < {x_4} < {x_5}} \right). The probability that x3=30x_3=30, is
View answer and explanation
Correct option: A
20C2×29C250C5\frac{{ }^{20} C_2 \times{ }^{29} C_2}{{ }^{50} C_5}
Option A is correct because the probability is calculated by choosing two numbers less than 30 and two numbers greater than 30, then dividing by the total number of ways to choose five numbers.
272 Easy
272 of 822
Application +4 | -1
The probability that a leap year selected at random will contain either 53 Thursdays or 53 Fridays, is
View answer and explanation
Correct option: A
37\frac{3}{7}
Option A (37\frac{3}{7}) is correct because the probability is calculated by considering the possible pairs of days in a leap year and finding the probability of having either 53 Thursdays or 53 Fridays.
273 Easy
273 of 822
Understanding +4 | -1
If AA and BB are two events, the probability that exactly one of them occurs is not given by
View answer and explanation
Correct option: D
P(Aˉ)+P(Bˉ)−2P(Aˉ∩Bˉ)P(\bar{A})+P(\bar{B})-2 P(\bar{A} \cap \bar{B})
Option D is correct because P(Aˉ)+P(Bˉ)−2P(Aˉ∩Bˉ)P(\bar{A})+P(\bar{B})-2 P(\bar{A} \cap \bar{B}) represents the probability of exactly one of the complements occurring, not exactly one of the original events.
274 Easy
274 of 822
Application +4 | -1
A police-man fires six bullets on a dacoit. The Probability that the dacoit will be killed by one bullet is 0.6 . The Probability that dacoit is still alive is
View answer and explanation
Correct option: B
0.004096
Option B (0.004096) is correct because it represents the probability that the dacoit survives all six shots, calculated as (1 - probability of being killed by one bullet) raised to the power of 6.
275 Easy
275 of 822
Application +4 | -1
Four fair dice D1,D2,D3D_1, D_2, D_3 atd D4D_4, each having six faces numbered 1,2,3,4,5 and 6 are rolled simultaneously. The probability that D4D_4 shows a number on one of D1,D2D_1, D_2 and D3D_3 is
View answer and explanation
Correct option: A
91216\frac{91}{216}
Option A (91/216) is correct because it calculates the probability that D4 shows a number that is present on at least one of the other three dice.
276 Easy
276 of 822
Analyzing +4 | -1
The probability that the 13th day of a randomly chosen month is a Friday, is
View answer and explanation
Correct option: C
184\frac{1}{{84}}
Option C (184\frac{1}{{84}}) is correct because it represents the probability of a randomly chosen month having its 13th day as a Friday, considering the probability of selecting a month and the conditional probability of the 13th being a Friday.
277 Easy
277 of 822
Analyzing +4 | -1
Let AA and BB be two events such that P(B∣A)=25,P(A∣B)=17P(B \mid A)=\frac{2}{5}, P(A \mid B)=\frac{1}{7} and P(A∩B)=19P(A \cap B)=\frac{1}{9}, Consider (S1)P(A′∪B)=56,(S2)P(A′∩B′)=118(S 1) P\left(A^{\prime} \cup B\right)=\frac{5}{6},(S 2) P\left(A^{\prime} \cap B^{\prime}\right)=\frac{1}{18}. Then
View answer and explanation
Correct option: A
Both (S1)(S 1) and (S2)(S 2) are true
Option A (Both (S1) and (S2) are true) is correct because both statements are verified to be true based on the given probabilities and conditional probabilities.
278 Easy
278 of 822
Application +4 | -1
Let A={1,  3,  5,  7,  9},  B={2,  4,  6,  8}.A = \left\{ {1,\;3,\;5,\;7,\;9} \right\},\;B = \left\{ {2,\;4,\;6,\;8} \right\}. If a cartesian product A×BA \times B, if chosen at random, the probability of a+b=9a + b = 9 is
View answer and explanation
Correct option: B
15\frac{1}{5}
Option B (15\frac{1}{5}) is correct because it calculates the probability of a + b = 9 when a Cartesian product A x B is chosen at random.
279 Easy
279 of 822
Application +4 | -1
Let A=[2,3,4,…,20]{A}=[2,3,4, \ldots, 20]. A number is chosen at random from the set A{A} and it is found to be a prime number. The probability that it is more than 10 is
View answer and explanation
Correct option: C
15\frac{1}{5}
Option C (15\frac{1}{5}) is correct because it represents the conditional probability of selecting a prime number greater than 10, given that a prime number has already been selected from the set A.
280 Easy
280 of 822
Application +4 | -1
A doctor is called to see a sick child. The doctor knows (prior to the visit) that 90%90 \% of the sick children in that neighbourhood are sick with the flue, denoted by FF, while 10%10 \% are sick with the measles, denoted by M. A well-known symptom of measles is a rash, denoted by RR.
The probability of having a rash for a child sick with the measles is 0.950.95. However, occasionally children with the flue also develop a rash with conditional probability 0.080.08. Upon examination the child, the doctor finds a rash, then the probability that the child has the measles, is
View answer and explanation
Correct option: D
95167\frac{95}{167}
Option D (95167\frac{95}{167}) is correct because it is calculated using Bayes' theorem to find the probability of measles given a rash.
281 Easy
281 of 822
Understanding +4 | -1
Write the set A={x:xA=\{x: x is a positive prime <10}< 10\} in the tabular form
View answer and explanation
Correct option: A
{2,3,5,7}\{2,3,5,7\}
Option A ({2,3,5,7}) is correct because these are the only positive prime numbers less than 10.
282 Easy
282 of 822
Application +4 | -1
Let AA and BB be the sets {1,2,…10}\{1,2, \ldots 10\} and {1,2,...20}\{1,2, ...20\} respectively. A function is selected randomly from AA to BB the probability that the function is non-decreasing is
View answer and explanation
Correct option: C
29C19(20)10\frac{{ }^{29} C_{19}}{(20)^{10}}
Option C (29C19(20)10\frac{{ }^{29} C_{19}}{(20)^{10}}) is correct because it represents the ratio of non-decreasing functions to the total number of functions from A to B.
283 Easy
283 of 822
Analyzing +4 | -1
Six teams play a match with each other. The probability that neither a team win all the matches nor a team loose all the matches is
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Correct option: C
175216\frac{175}{216}
Option C (175216\frac{175}{216}) is correct because the probability is calculated by subtracting the probabilities of a team winning all matches or losing all matches from 1.
284 Easy
284 of 822
Application +4 | -1
Three coins are tossed, then what is the probability that at least two heads appears on upper face?
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Correct option: D
None of these
The correct probability is 12\frac{1}{2}, which is not listed in the options. The explanation shows the calculation of this probability by considering all possible outcomes when tossing three coins.
285 Easy
285 of 822
Application +4 | -1
An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours, is
View answer and explanation
Correct option: B
27\frac{2}{7}
Option B (27\frac{2}{7}) is correct because it calculates the probability of drawing three balls of different colors by finding the ratio of favorable outcomes to total possible outcomes.
286 Easy
286 of 822
Application +4 | -1
n(≥3)n(\geq 3) persons are sitting in a row. Two of them are selected at random. The probability that they are not together is
View answer and explanation
Correct option: B
1−2n1-\frac{2}{n}
Option B (1−2n1-\frac{2}{n}) is correct because it represents the probability that two randomly selected persons are not sitting together in a row of n persons.
287 Easy
287 of 822
Analyzing +4 | -1
A die is rolled thrice, the probability of getting a larger number each time than the previous number, is
View answer and explanation
Correct option: A
554\frac{5}{54}
Option A (554\frac{{5}}{{54}}) is correct because it represents the probability calculated by dividing the number of favorable outcomes (increasing numbers) by the total number of possible outcomes when rolling a die thrice.
288 Easy
288 of 822
Application +4 | -1
Entries of a 2×22 \times 2 determinant are chosen from the set {−1,1}\{-1,1\}. The probability that determinant has zero value is
View answer and explanation
Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct because half of the possible 2×22 \times 2 determinants with entries from {−1,1}\{-1, 1\} have a value of zero.
289 Easy
289 of 822
Application +4 | -1
India plays a two ODI matches each with Australia and Pakistan. The probability of India getting points 0, 1, 2 are 0.45, 0.05, 0.50. The probability of India getting at least 7 points in the series is
View answer and explanation
Correct option: C
0.0875
Option C (0.0875) is correct because it calculates the probability of India getting at least 7 points in the series, considering the probabilities of getting 0, 1, or 2 points in each match.
290 Easy
290 of 822
Application +4 | -1
The mean and variance of a random variable XX having a binomial distribution are 4 and 2 respectively, then P(X=1)P\left( {X = 1} \right) is
View answer and explanation
Correct option: A
132\frac{1}{{32}}
Option A (132\frac{1}{{32}}) is correct because it is the result of calculating the binomial probability P(X=1)P(X=1) using the given mean and variance to find nn and pp.
291 Easy
291 of 822
Application +4 | -1
A draws two cards at random from a pack of 52 cards. After returning them to the pack and shuffling it, B draws two cards at random. The probability that their draws contain exactly one common cards is
View answer and explanation
Correct option: B
50663\frac{50}{663}
Option B (50663\frac{50}{663}) is correct because it calculates the probability that two draws of two cards each contain exactly one common card.
292 Easy
292 of 822
Understanding +4 | -1
Five horses are in a race. Mr. A selects two of the horses at random and bets on them. The probability that Mr. A selected the winning horse is
View answer and explanation
Correct option: A
25\frac{2}{5}
Option A (2/5) is correct because it represents the probability that at least one of the two horses Mr. A selected is the winning horse.
293 Easy
293 of 822
Application +4 | -1
In a college, 25% of the boys and 10% of the girls offer Mathematics. The girls constitute 60% of the total number of students. If a student is selected at random and is found to be studying Mathematics. The probability that the student is a girl is
View answer and explanation
Correct option: B
03-Aug
The correct answer is B (03-Aug), which represents 3/8. This is calculated using conditional probability, considering the proportion of girls and boys studying mathematics.
294 Easy
294 of 822
Application +4 | -1
A card is drawn from a pack of 52 playing cards. The card is replaced and the pack is reshuffled. If this is done six times, the probability that 2 hearts, 2 diamonds and 2 black cards are drawn is
View answer and explanation
Correct option: C
90×(12)1090 \times\left(\frac{1}{2}\right)^{10}
The correct answer is 90×(12)1090 \times\left(\frac{1}{2}\right)^{10} because it calculates the probability of drawing 2 hearts, 2 diamonds, and 2 black cards in 6 draws with replacement.
295 Easy
295 of 822
Analyzing +4 | -1
Let A, B, C be three mutually independent events.

Consider the two statements S1\mathrm{S}_1 and S2\mathrm{S}_2

S1:A\mathrm{S}_1: \mathrm{A} and B∪CB \cup C are independent

S2:A\mathrm{S}_2: \mathrm{A} and B∩CB \cap C are independent, then
View answer and explanation
Correct option: A
Both S1S_1 and S2S_2 are true
The correct answer is A (Both S1S_1 and S2S_2 are true) because if A, B, and C are mutually independent, then A is independent of any boolean expression involving only B and C.
296 Easy
296 of 822
Application +4 | -1
If birth to male child and birth to female child are equal-probable, then what is the probability that at least one of the three children born to a couple is male?
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Correct option: B
78\frac{7}{8}
Option B (78\frac{7}{8}) is correct because it calculates the probability of at least one male child by finding the complement of all female children.
297 Easy
297 of 822
Application +4 | -1
If AA and BB are two independent events, the probability that both AA and BB occur is 1/81/8 and the probability that neither of them occurs is 3/8.3/8. The probability of the occurrence of AA, is
View answer and explanation
Correct option: A
12,  14\frac{1}{2},\,\,\frac{1}{4}
Option C (0.0875) is correct because it calculates the probability of India getting at least 7 points in the series based on the given probabilities.
298 Easy
298 of 822
Analyzing +4 | -1
Three different numbers are selected at random from the set A={1,2,3,…,10}A=\{1,2,3, \ldots, 10\}. The probability that the product of two of the numbers is equal to third, is
View answer and explanation
Correct option: B
140\frac{1}{40}
Option B (140\frac{1}{40}) is correct because it represents the ratio of favorable outcomes (product of two numbers equals the third) to the total possible outcomes when selecting three numbers.
299 Easy
299 of 822
Application +4 | -1
If AA and BB are mutually exclusive events with P(A)=12×P(B)P\left( A \right) = \frac{1}{2} \times P\left( B \right) and A∪B=S,A \cup B = S, (total sample space) then P(A)P\left( A \right) is equal to
View answer and explanation
Correct option: B
13\frac{1}{3}
Option B (13\frac{1}{3}) is correct because it uses the properties of mutually exclusive events and the given relationship between P(A) and P(B) to find P(A).
300 Easy
300 of 822
Application +4 | -1
AA and BB are the independent events. The probability that both occur simultaneously is 16\frac{1}{6} and the probability that neither occur is 13\frac{1}{3}. The probability of occurrence of the events AA and BB is
View answer and explanation
Correct option: B
12,  13\frac{1}{2},\,\,\frac{1}{3}
Option B (12,13\frac{1}{2}, \frac{1}{3}) is correct because solving the probability equations derived from the given conditions yields these probabilities for events A and B.
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