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JEE • MATHEMATICS • PROBABILITY

Probability practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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511 Easy
511 of 1130
Application +4 | -1
In a multiple choice question, there are five alternative answers of which one or more than one are correct. A candidate will get marks on the question, if he ticks all the correct answers. If he decides to tick answers at random, then the least number of choice should he be allowed so that the probability of his getting marks on the question exceeds 18\frac{1}{8} is
View answer and explanation
Correct option: A
4
Option A (4) is correct because it determines the minimum number of choices needed to exceed a probability of 1/8 by comparing the number of ways to answer the question with the given probability.
512 Easy
512 of 1130
Application +4 | -1
Three persons A,BA, B and CC are to speak at a function along with five others. If they all speak in random order, the probability that AA speaks before BB and BB speaks before C\mathrm{C} is
View answer and explanation
Correct option: B
1/61 / 6
Option B (16\frac{{1}}{{6}}) is correct because it represents the probability of A, B, and C speaking in a specific order out of all possible orders.
513 Easy
513 of 1130
Application +4 | -1
An ordinary cube has four blank faces, one face marked 2 and another marked 3. Then the probability of obtaining 9 in 5 throws, is
View answer and explanation
Correct option: D
51296\frac{5}{{1296}}
Option D (51296\frac{5}{{1296}}) is correct because it calculates the probability of obtaining a sum of 9 in 5 throws of the die.
514 Easy
514 of 1130
Application +4 | -1
There are 4 white and 4 black balls in a bag and 3 balls are drawn at random. If balls of same colour are identical, the probability that none of them is black, is
View answer and explanation
Correct option: A
1/41/4
Option C (5/135/13) is correct because it is calculated using conditional probability, considering that one mango is already known to be good.
515 Medium
515 of 1130
Application +4 | -1
There are 4 white and 3 black balls in a box. In another box there are 3 white and 4 black balls. An unbiased dice is rolled. If it shows a number less than or equal to 3 then a ball is drawn from the first box but if it shows a number more than 3 then a ball is drawn from the second box. If the ball drawn is black then the probability that the ball was drawn from the first box is
View answer and explanation
Correct option: D
3/73 / 7
Option D (3/73 / 7) is correct because it is calculated using Bayes' theorem, considering the probabilities of drawing from each box and the probability of drawing a black ball.
516 Easy
516 of 1130
Application +4 | -1
Two numbers aa and bb are selected at random from 1,2,3,…,1001,2,3, \ldots, 100 and are multiplied. Then, the probability that the product aba b is divisible by 3 , is
View answer and explanation
Correct option: B
83150\frac{83}{150}
Option B (83150\frac{83}{150}) is correct because it represents the probability that the product of two randomly selected numbers from 1 to 100 is divisible by 3.
517 Easy
517 of 1130
Application +4 | -1
Let AA and BB be independent events such that P(A)=pP(A) = p and P(B)=2pP(B) = 2p. The largest value of pp, for which PP (exactly one of AA, BB occurs) 59\frac{5}{9}, is
View answer and explanation
Correct option: D
512\frac{5}{12}
Option D (5/12) is correct because by setting up the probability equation for exactly one event occurring and solving the quadratic equation, we find the largest possible value for p.
518 Easy
518 of 1130
Application +4 | -1
Three numbers are chosen at random without replacement from {1,2,3,…,8}\{1,2,3, \ldots, 8\}. The probability that their minimum is 3 , given that their maximum is 6 , is
View answer and explanation
Correct option: D
15\frac{1}{5}
Option D (15\frac{{1}}{{5}}) is correct because it calculates the conditional probability of the minimum being 3 given that the maximum is 6.
519 Easy
519 of 1130
Application +4 | -1
A wire of length ll is cut into three pieces. What is the probability that the three pieces from a triangle?
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Correct option: B
01-Apr
Option B (01-Apr) is correct because the probability that three pieces of a wire form a triangle is 1/4, derived from geometric probability principles.
520 Easy
520 of 1130
Analyzing +4 | -1
Refer to question 19 above. If the probability that exactly two of the three balls were red, then the first ball being red, is
View answer and explanation
Correct option: B
47\frac{4}{7}
Option B (47\frac{4}{7}) is correct because it represents the conditional probability of the first ball being red given that exactly two of the three balls were red.
521 Easy
521 of 1130
Understanding +4 | -1
If A1,A2,…,AnA_1, A_2, \ldots, A_n are any nn events, then
View answer and explanation
Correct option: C
P(A1∪A2∪…∪An)≤P(A1)+P(A2)+…+P(An)P\left(A_1 \cup A_2 \cup \ldots \cup A_n\right) \leq P\left(A_1\right)+P\left(A_2\right)+\ldots+P\left(A_n\right)
Option C is correct because the probability of the union of multiple events is always less than or equal to the sum of their individual probabilities.
522 Easy
522 of 1130
Application +4 | -1
If XX has binomial distribution with mean npnp and variance npq,npq, then P(X=k)P(X=k−1)\frac{{P\left( {X = k} \right)}}{{P\left( {X = k - 1} \right)}} is equal to
View answer and explanation
Correct option: B
n−k+1k.pq\frac{{n - k + 1}}{k}.\frac{p}{q}
Option B (n−k+1k.pq\frac{{n - k + 1}}{k}.\frac{p}{q}) is correct because it correctly applies the formula for the ratio of probabilities in a binomial distribution.
523 Easy
523 of 1130
Analyzing +4 | -1
If 15 boys of different ages are distributed into 3 groups of 4, 5, and 6 boys randomly then the probability that three youngest boys are in different groups is
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Correct option: A
2491\frac{24}{91}
Option A (2491\frac{24}{91}) is correct because the probability that the three youngest boys are in different groups is calculated by considering the total number of ways to distribute the boys and the number of ways to distribute them with the youngest in different groups.
524 Easy
524 of 1130
Application +4 | -1
A book writer writes a good book with probability 12\frac{1}{2}. If it is a good book, the probability that it will be published is 23\frac{2}{3}, otherwise it is 14\frac{1}{4}. If he writes 2 books, the probability that at least one book will be published is
View answer and explanation
Correct option: A
407576\frac{407}{576}
Option A (407576\frac{407}{576}) is correct because it calculates the probability of at least one book being published out of two, considering the probabilities of writing a good book and its subsequent publication.
525 Easy
525 of 1130
Application +4 | -1
Probability P(A)=45,P(B′)=25P\left( A \right) = \frac{4}{5},P\left( {B'} \right) = \frac{2}{5} and P(A∩B)=12,P\left( {A \cap B} \right) = \frac{1}{2}, then P(A∩B′)P\left( {A \cap B'} \right) is equal to
View answer and explanation
Correct option: A
310\frac{3}{{10}}
Option A (3/10) is correct because it correctly uses the probabilities and the formula for the union of events to find the desired probability.
526 Easy
526 of 1130
Analyzing +4 | -1
The probabilities of three events A,BA, B and CC are given P(A)=0.6,P(B)=0.4P(A)=0.6, P(B)=0.4 and P(C)=0.5P(C)=0.5. If P(A∪B)=0.8P(A \cup B)=0.8, P(A∩C)=0.3,P(A∩B∩C)=0.2,P(B∩C)=βP(A \cap C)=0.3, \quad P(A \cap B \cap C)=0.2, \quad P(B \cap C)=\beta \quad and P(A∪B∪C)=αP(A \cup B \cup C)=\alpha, where 0.85≤α≤0.950.85 \leq \alpha \leq 0.95, then β\beta lies in the interval
View answer and explanation
Correct option: C
[0.25,0.35][0.25,0.35]
Option C ([0.25,0.35][0.25,0.35]) is correct because it represents the interval in which the probability of the intersection of events B and C lies, derived from the given probabilities and the properties of probability.
527 Easy
527 of 1130
Application +4 | -1
Probability that A speaks truth is 4/54 / 5. A coin is tossed. A reports that a head appears. The probability that actually there was head is
View answer and explanation
Correct option: A
45\frac{4}{5}
Option A (45\frac{4}{5}) is correct because it represents the probability that a head actually appeared given that A reported a head.
528 Easy
528 of 1130
Application +4 | -1
Numbers are selected at random one at a time, from the numbers 00,01,02,…,9900,01,02, \ldots, 99 with replacement. An event EE occurs if and only if the product of the two digits of a selected number is 18 . If four numbers are selected, then the probability that E{E} occurs at least 3 times, is
View answer and explanation
Correct option: A
97390625\frac{97}{390625}
Option A (97390625\frac{97}{390625}) is correct because it calculates the probability of event E occurring at least 3 times out of 4 selections using binomial probability.
529 Easy
529 of 1130
Application +4 | -1
A coin is tossed 10 times. The probability of getting exactly six heads, is
View answer and explanation
Correct option: B
105512\frac{{105}}{{512}}
Option B (105512\frac{{105}}{{512}}) is correct because it is calculated using the binomial probability formula with n=10, k=6, and p=0.5.
530 Easy
530 of 1130
Application +4 | -1
A random variable XX takes the values 0,1,2,30,1,2,3 and its mean is 1.3. If P(X=3)=2P(X=1)P(X=3)=2 P(X=1) and P(X=2)=0.3,P(X=2)=0.3, then P(X=0),P(X=0), is
View answer and explanation
Correct option: D
0.40.4
Option D (0.4) is correct because it's the probability calculated using the given mean and probabilities of the random variable X.
531 Easy
531 of 1130
Application +4 | -1
Let A={1,2,3,4}A=\{1,2,3,4\} and B={a,b}B=\{a, b\}. A function f:A→Bf: A \rightarrow B is selected randomly. Probability that function is an onto function is
View answer and explanation
Correct option: C
78\frac{7}{8}
Option C (78\frac{7}{8}) is correct because it calculates the probability that the function is onto by subtracting the probability of the function not being onto from 1.
532 Medium
532 of 1130
Application +4 | -1
If P(A∪B)=0.8P\left( {A \cup B} \right) = 0.8 and P(A∩B)=0.3,P\left( {A \cap B} \right) = 0.3, then P(A′)+P(B′)P\left( {A'} \right) + P\left( {B'} \right) equals to
View answer and explanation
Correct option: D
0.9
Option D (0.9) is correct because it is calculated using the properties of probability and De Morgan's laws.
533 Easy
533 of 1130
Application +4 | -1
A coin is tossed and a die is rolled. The probability that the coin shows the head and the die shows 6 is
View answer and explanation
Correct option: B
112\frac{1}{12}
Option B (112\frac{{1}}{{12}}) is correct because the probability of independent events is the product of their individual probabilities.
534 Easy
534 of 1130
Application +4 | -1
A coin is tossed nn times. The probability of getting head at least once is greater than 0.8, then the least value of nn is
View answer and explanation
Correct option: B
3
Option B (3) is correct because it is the smallest integer value of n that satisfies the inequality 2n≥52^n \ge 5.
535 Easy
535 of 1130
Application +4 | -1
In a simultaneous throw of three coins, what is the probability of getting at least 2 tails
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Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct. With three coins, there are 23 = 8 possible outcomes. The outcomes with at least 2 tails are TTH, THT, HTT, and TTT, so the probability is 4/8 = 1/2.
536 Easy
536 of 1130
Application +4 | -1
In an entrance test there are multiple choice questions. There are four possible answers to each question,of which one is correct. The probability that a student knows the answer to a question is 90%. If be gets the correct answer to a question, then the probability that he was guessing, is
View answer and explanation
Correct option: B
137\frac{1}{{37}}
Option B (137\frac{1}{{37}}) is correct because it uses Bayes' theorem to calculate the probability that the student was guessing, given that they got the correct answer.
537 Easy
537 of 1130
Analyzing +4 | -1
Let NN be the sum of the numbers appeared when two fair dice are rolled and let the probability that N−2,3N,N+2N-2, \sqrt{3 N}, N+2 are in geometric progression be k48\frac{k}{48}. Then the value of kk is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the probability that N−2,3N,N+2N-2, \sqrt{3N}, N+2 are in geometric progression is 112\frac{1}{12}, which simplifies to 448\frac{4}{48}, thus k=4.
538 Medium
538 of 1130
Application +4 | -1
A person throws two dice, one the common cube and the other regular tetrahedron with numbers 1,2,3,41,2,3,4 on its faces, the number on the lowest face being taken in the case of a tetrahedron. The chance that the sum of numbers thrown is not less than 5 is
View answer and explanation
Correct option: B
34\frac{3}{4}
Option B (34\frac{{3}}{{4}}) is correct because the probability that the sum is not less than 5 is 18/24, which simplifies to 3/4.
539 Easy
539 of 1130
Understanding +4 | -1
If two events are independent, then
View answer and explanation
Correct option: D
None of the above is correct
Option D (None of the above is correct) is correct because independent events are not necessarily mutually exclusive, and the sum of their probabilities does not have to be 1.
540 Hard
540 of 1130
Analyzing +4 | -1
Out of 3n3n consecutive natural numbers, 3 natural numbers are chosen at random without replacement. The probability that the sum of the chosen numbers is divisible by 3, is
View answer and explanation
Correct option: C
(3n2−3n+2)(3n−1)(3n−2)\frac{{\left( {3{n^2} - 3n + 2} \right)}}{{\left( {3n - 1} \right)\left( {3n - 2} \right)}}
Option B ((3n2−3n+2)2(3n−1)(3n−2)\frac{{\left( {3{n^2} - 3n + 2} \right)}}{{2\left( {3n - 1} \right)\left( {3n - 2} \right)}}) is correct because it represents the probability that the sum of three randomly chosen numbers from 3n consecutive natural numbers is divisible by 3.
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