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JEE • MATHEMATICS • PERMUTATION AND COMBINATION

Permutation and combination practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 250 questions

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181 Medium
181 of 250
Application +4 | -1
The sum of all that can be formed with the digits 2,3,4,5 taken all at a time is
View answer and explanation
Correct option: A
93324
Option A (93324) is correct because the sum of all numbers formed is calculated using the formula (sum of digits) * (n-1)! * (1111... n times).
182 Medium
182 of 250
Analyzing +4 | -1
The number of distinct rational numbers xx such that 0<x<10 < x < 1 and x=pqx=\frac{p}{q}, where p,q∈{1,2,3,4,5,6}p, q \in\{1,2,3,4,5,6\} is
View answer and explanation
Correct option: D
11
Option D (11) is correct because it represents the number of distinct rational numbers between 0 and 1 that can be formed using the given set of numbers, after removing duplicates.
183 Medium
183 of 250
Application +4 | -1
A class has nn students. We have to form a team of the students including atleast two students and also excluding atleast two students. The number of ways of forming the team is
View answer and explanation
Correct option: B
2n−2n−22^n-2 n-2
Option C (2n−2n−42^n-2 n-4) is correct because it represents the total number of subsets minus the subsets with fewer than two students and the subsets with fewer than two students excluded.
184 Medium
184 of 250
Application +4 | -1
The total number of flags with three horizontal strips, in order that can be formed using 2 identical red, 2 identical green and 2 identical white strips, is equal to
View answer and explanation
Correct option: A
4!
Option A (4!) is correct because the total number of flags is calculated by considering all possible arrangements of the colored strips.
185 Medium
185 of 250
Application +4 | -1
Letter of the word 'WATER' is arranged in all possible ways and written as dictionary then rank of the word 'WATER' is
View answer and explanation
Correct option: C
101
Option C (101) is correct because it calculates the number of words preceding 'WATER' in the dictionary by considering the alphabetical order of the letters.
186 Medium
186 of 250
Application +4 | -1
A boat is to be managed by eight men of whom 2 can only row on bow side and 3 can only row on stroke side, the number of ways in which the crew can be arranged, is
View answer and explanation
Correct option: B
5760
Option B (5760) is correct because it calculates the number of ways to arrange the crew, considering the restrictions on who can row on the bow and stroke sides.
187 Medium
187 of 250
Application +4 | -1
Five digit number divisible by 3 is formed using 0,1,2,3,40,1,2,3,4, 6 and 7 without repetition. Total number of such numbers are
View answer and explanation
Correct option: D
216
The correct answer is D (216) because it calculates the total number of 5-digit numbers divisible by 3 formed using the given digits without repetition.
188 Medium
188 of 250
Application +4 | -1
The sum of all four digit numbers that can be med using the digits 1,2,3,41,2,3,4, when repetition of digits is not allowed, is
View answer and explanation
Correct option: D
66660
Option D (66660) is correct because the sum is calculated by summing the digits, multiplying by (n-1)!, and then multiplying by (10^n - 1)/9.
189 Medium
189 of 250
Understanding +4 | -1
The value of (2n)!n!\frac{(2 n) !}{n !} is
View answer and explanation
Correct option: A
{1⋅3⋅5…(2n−1)}2n\{1 \cdot 3 \cdot 5 \ldots(2 n-1)\} 2^n
Option A ({1 · 3 · 5 …(2 n-1)} 2^n) is correct because it correctly represents the simplification of the given factorial expression.
190 Medium
190 of 250
Application +4 | -1
An nn-digit number is a positive number with exactly nn digits. Nine hundred distinct nn-digit numbers are to be formed using only the three digits 2, 5 and 7. The smallest value of nn for which this is possible, is
View answer and explanation
Correct option: B
7
Option B (7) is correct because it is the smallest number of digits needed to form at least 900 distinct numbers using only the digits 2, 5, and 7.
191 Medium
191 of 250
Application +4 | -1
Two teams are to play a series of 5 matches between them. A match ends in a win or loss or draw for a team. A number of people forecast the result of each match and no two people make the same forecast for the series of matches. The smallest group of people in which one person forecasts correctly for all the matches will contain nn people, where nn is
View answer and explanation
Correct option: B
243
Option B (243) is correct because the total number of possible forecasts is calculated as 3 raised to the power of the number of matches (5), resulting in 243.
192 Medium
192 of 250
Application +4 | -1
The number of arrangements that can be formed out of GANESHPURI so that "The vowels are always together is
View answer and explanation
Correct option: C
7!4!7 ! 4 !
Option C (7!4!7 ! 4 !) is correct because the vowels are treated as a single unit, and then arranged with the consonants, followed by arranging the vowels within their unit.
193 Medium
193 of 250
Application +4 | -1
The number of integers, greater than 7000 that can
be formed, using the digits 3, 5, 6, 7, 8 without
repetition, is
View answer and explanation
Correct option: B
168
Option B (168) is correct because it involves counting permutations of numbers greater than 7000 using the given digits.
194 Medium
194 of 250
Application +4 | -1
If n=210032n=2^{100} 3^2 and {d1,d2,…dk}\left\{d_1, d_2, \ldots d_k\right\} is the set of all divisors of nn, then ∑j=1k1dj\sum\limits_{{j=1}}^k \frac{1}{d_j} equals
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the sum of reciprocals of divisors is calculated using the formula and the result doesn't match any of the given options.
195 Medium
195 of 250
Application +4 | -1
The total number of four-digit numbers having all different digits is equal to
View answer and explanation
Correct option: A
4536
Option A (4536) is correct because it calculates the number of four-digit numbers with all different digits.
196 Medium
196 of 250
Understanding +4 | -1
If n=2p−1(2p−1)n=2^{p-1}\left(2^p-1\right), where 2p−12^p-1 is a prime, then the sum of the divisors of nn is equal to
View answer and explanation
Correct option: B
2n2 \mathrm{n}
Option B is correct because the sum of divisors of n, where n is in the given form, is equal to 2n.
197 Medium
197 of 250
Understanding +4 | -1
Two players P1P_1 and P2P_2 play a series of '2n2 n' games. Each game can result in either a win or loss for P1P_1. Total number of ways in which P1P_1 can win the series of these games, is equal to
View answer and explanation
Correct option: A
12(22n−2nCn)\frac{1}{2}\left(2^{2 n}-{ }^{2 n} C_n\right)
Option A (12(22n−2nCn)\frac{1}{2}\left(2^{2 n}-{ }^{2 n} C_n\right)) is correct because it represents the sum of ways P1P_1 can win more than n games, which is half of the total ways minus the ways to win exactly n games.
198 Medium
198 of 250
Application +4 | -1
15 identical balls have to be put in 5 different boxes. Each box can contain any number of balls. Total number of ways of putting the balls into box, so that each box contains atleast 2 balls, is equal to
View answer and explanation
Correct option: A
9C4{ }^9 C_4
Option A (9C4{ }^9 C_4) is correct because it represents the number of ways to distribute the balls after giving each box the minimum required number of balls.
199 Medium
199 of 250
Application +4 | -1
number of ways in which 15 indistinguishable oranges can be distributed in 3 different boxes so that every has atmost 8 oranges is
View answer and explanation
Correct option: A
52
Option A (52) is correct because it represents the number of ways to distribute 15 indistinguishable oranges into 3 distinct boxes with a maximum of 8 oranges per box, calculated using stars and bars with inclusion-exclusion.
200 Medium
200 of 250
Application +4 | -1
Total number of 6 digit numbers in which all the odd digits and only odd digits appear is
View answer and explanation
Correct option: A
52∠6\frac{5}{2} \angle 6
Option A (52∠6\frac{{5}}{{2}} \angle 6) is correct because it represents the number of 6-digit numbers with only odd digits, where one odd digit is repeated.
201 Medium
201 of 250
Application +4 | -1
The number of ordered pairs (m,n)(m, n), m,n∈{1,2,…,100}m, n \in\{1,2, \ldots, 100\} such that 7m+7n7^m+7^n is divisible by 5, is
View answer and explanation
Correct option: C
2500
Option C (2500) is correct because it represents the number of ordered pairs (m, n) such that 7^m + 7^n is divisible by 5, which is determined by analyzing the cyclical pattern of the last digit of 7^r.
202 Medium
202 of 250
Application +4 | -1
The number of word formed by using all letter of word 'RANDOM' in which vowels are in alphabetical order is
View answer and explanation
Correct option: B
360
Option B (360) is correct because it divides the total permutations by the number of ways to arrange the vowels to ensure alphabetical order.
203 Medium
203 of 250
Application +4 | -1
In a single correct match the column question, column I contain 10 questions and Column II contain 10 answers written in some arbitrary order. If the number ways a student can answer this question so that exactly 6 of his matching are correct is k\mathrm{k}, then (sum of digits of k) /2/ 2 is equal to
View answer and explanation
Correct option: A
9
Option A (9) is correct because the sum of digits of k (1890) divided by 2 is equal to 9.
204 Medium
204 of 250
Application +4 | -1
Let a be a factor of 120 . Then the number of positive integral solutions of x1,x2,x3=a\mathrm{x}_1, \mathrm{x}_2, \mathrm{x}_3=\mathrm{a} is k\mathrm{k} then k80\frac{\mathrm{k}}{80} is
View answer and explanation
Correct option: A
4
Option A (4) is correct because the number of positive integral solutions of x1, x2, x3 = a is found to be 320, and then k/80 = 320/80 = 4.
205 Medium
205 of 250
Application +4 | -1
The number of ways in which the sum of upper faces of four distinct dices can be six, is
View answer and explanation
Correct option: A
10
Option A (10) is correct because it represents the number of ways to distribute the sum of 6 among four distinct dice, each having a minimum value of 1.
206 Medium
206 of 250
Application +4 | -1
The number of ways in which 3 children can distribute 10 tickets out of 15 consecutively numbered tickets themselves such that they get consecutive blocks of 5, 3 and 2 tickets is
View answer and explanation
Correct option: C
8C5(3!)2{ }^8 {C}_5(3 !)^2
Option B (π+1\pi+1) is correct because it maximizes the sum of the inverse trigonometric functions by considering the range of each function and the given domain.
207 Medium
207 of 250
Application +4 | -1
In how many ways can 10 examination paper be arranged, so that the best and the worst papers never come together?
View answer and explanation
Correct option: B
8⋅9!8 \cdot 9 !
Option B (8⋅9!8 \cdot 9 !) is correct because it calculates the number of arrangements where the best and worst papers are not together by subtracting the arrangements where they are together from the total arrangements.
208 Medium
208 of 250
Application +4 | -1
The number of natural numbers less than 1000, in which no two digits are replaced, is
View answer and explanation
Correct option: A
738
Option A (738) is correct because it sums the number of 1-digit, 2-digit, and 3-digit numbers with no repeated digits.
209 Medium
209 of 250
Application +4 | -1
No. of ways to give 16 different things to A,B,CA, B, C so that BB gets 1 more than AA and CC gets 2 more than BB, is
View answer and explanation
Correct option: A
16!4!5!7!\frac{16 !}{4 ! 5 ! 7 !}
Option A (16!4!5!7!\frac{{16 !}}{{4 ! 5 ! 7 !}}) is correct because it represents the number of ways to distribute 16 different things to A, B, and C such that B gets 1 more than A and C gets 2 more than B.
210 Medium
210 of 250
Application +4 | -1
The number of ways such that 6 persons can be selected from 4 officers and 8 constables, if at least one officer is to be included, is
View answer and explanation
Correct option: A
896
Option D (3π4\frac{{3 \pi}}{{4}}) is correct because it is the simplified value of the given expression using trigonometric identities.
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