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JEE • MATHEMATICS • PERMUTATION AND COMBINATION
Permutation and combination practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 241-270 of 485 questions
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241
Easy
241 of 485
Application
+4 | -1
How many numbers with no more than three digits can be formed using only the digits 1 through 7 with no digit used more than once in a given number?
View answer and explanation
Correct option: A
259
Option A (259) is correct because it sums the number of 1-digit, 2-digit, and 3-digit numbers that can be formed using digits 1 through 7 without repetition.
242
Easy
242 of 485
Application
+4 | -1
The number of integral solutions of , with , is
View answer and explanation
Correct option: C
Option C () is correct because it represents the number of integral solutions of the given equation with the specified constraints, after transforming the variables to non-negative integers.
243
Easy
243 of 485
Analyzing
+4 | -1
The number of different pairs of words that can be made with the letters of the word 'STATICS' is
View answer and explanation
Correct option: B
1260
Option B (10 or 11) is correct because the number of groups is maximized when the group size is closest to half the total number of students.
244
Easy
244 of 485
Application
+4 | -1
In how many ways can 5 boys and 5 girls sit in a circle so that no two boys sit together?
View answer and explanation
Correct option: B
Option B () is correct because it represents the arrangement of girls in a circle and boys in the spaces between them.
245
Easy
245 of 485
Application
+4 | -1
The largest integer such that 33 ! is divisible by is
View answer and explanation
Correct option: B
31
Option B (31) is correct because it represents the largest integer n such that 33! is divisible by 2^n, calculated using Legendre's formula.
246
Easy
246 of 485
Application
+4 | -1
If and satisfy the relation then is equal to
View answer and explanation
Correct option: C
13
Option C (13) is correct because solving the permutation equation leads to a quadratic equation with roots 6 and 7, and their sum is 13.
247
Easy
247 of 485
Application
+4 | -1
If eight persons are to address a meeting, then the number of ways in which a specified speaker is to speak before another specified speaker is
View answer and explanation
Correct option: B
20160
Option B (20160) is correct because in half of the total arrangements, the specified speaker will speak before the other specified speaker.
248
Easy
248 of 485
Application
+4 | -1
A bag contains 2 apples, 3 oranges and 4 bananas. The number of ways in which 3 fruits can be selected, if atleast one banana is always in the combination (assume fruit of same species to be alike) is
View answer and explanation
Correct option: A
6
Option A (6) is correct because it represents the number of ways to select 3 fruits with at least one banana, considering the fruits of the same species to be alike.
249
Easy
249 of 485
Application
+4 | -1
Total number of non-negative integral solutions of is equal to
View answer and explanation
Correct option: C
Option C () is correct because it represents the number of non-negative integral solutions of the given equation using stars and bars method.
250
Easy
250 of 485
Application
+4 | -1
Words with or without meaning are to be formed using all the letters of the word EXAMINATION. The probability that the letter M appears at the fourth position in any such word is
View answer and explanation
Correct option: B
Option B (1/11) is correct because it represents the ratio of favorable arrangements (M at the fourth position) to the total possible arrangements of the letters in EXAMINATION.
251
Easy
251 of 485
Application
+4 | -1
The number of positive integral solutions of the equation is
View answer and explanation
Correct option: A
1875
Option A (1875) is correct because it calculates the number of ways to distribute the prime factors of 420 among the five variables.
252
Easy
252 of 485
Application
+4 | -1
A number of 4 different digits is formed by using the digits such that number formed is multiple of 25 , is , then find the value of value of .
View answer and explanation
Correct option: A
7
Option A (7) is correct because the number of 4-digit multiples of 25 formed using the digits 1 to 7 is 40, and solving 12x + y = 40 gives x + y = 7.
253
Easy
253 of 485
Application
+4 | -1
There are concurrent lines and another line parallel to one of them. The number of different triangles that will be formed by the lines, is
View answer and explanation
Correct option: B
Option B () is correct because it represents the number of ways to choose 2 lines from the concurrent lines to form a triangle with the additional line.
254
Easy
254 of 485
Application
+4 | -1
If the letters of the word "nagpur" are written in all possible ways and then are arranged as in a dictionary, then the rank of the word "nagpur" is:
View answer and explanation
Correct option: B
242
Option B (242) is correct. The rank of the word "nagpur" is determined by arranging the letters alphabetically and counting the words that come before it in the dictionary.
255
Easy
255 of 485
Application
+4 | -1
If , then equals:
View answer and explanation
Correct option: A
Option A () is correct because by using the property , we can rewrite the sum and solve for the desired expression.
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256
Easy
256 of 485
Analyzing
+4 | -1
Number of points having position vector , where such that is divisible by 4 , is
View answer and explanation
Correct option: A
70
The correct answer is A (70) because by analyzing the divisibility rule of 4 for the expression , we find that there are 70 possible combinations of and that satisfy the condition.
257
Easy
257 of 485
Application
+4 | -1
The number of even divisors of 10800 is
View answer and explanation
Correct option: D
48
Option D (48) is correct because it accurately calculates the number of even divisors by considering at least one factor of 2 in the divisors.
258
Easy
258 of 485
Application
+4 | -1
If denotes the number of permutations of things taken all at a time, the number of permutations of things taken 11 at a time and the number of permutations of things taken all at a time such that , the value of is
View answer and explanation
Correct option: B
12
Option D (18) is correct because it solves for x using the given permutation equation.
259
Easy
259 of 485
Application
+4 | -1
A set containing elements. A subset of is chosen. The set is reconstructed by replacing the element of . A subset of is again chosen the number of ways of choosing and , so that , is
View answer and explanation
Correct option: D
Option D () is correct because for each element in the set A, there are three possibilities: it belongs to P, it belongs to Q, or it belongs to neither, given that P and Q are disjoint.
260
Easy
260 of 485
Application
+4 | -1
The sides of a have 3, 4, 5 interior points, respectively on them. Total number of triangles that can be formed using these points as vertices, is equal to
View answer and explanation
Correct option: D
205
Option D (205) is correct because the total number of triangles is calculated by subtracting the number of collinear points from the total number of ways to choose 3 points from the 12 interior points: .
261
Easy
261 of 485
Analyzing
+4 | -1
In word 'ENGINEERING', E's and N's come alternately
View answer and explanation
Correct option: C
Option C () is correct because it arranges the G's, I's, and R, then places the E's and N's alternately.
262
Easy
262 of 485
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: A
100
Option A (100) is correct because solving the equation by finding a common denominator and simplifying leads to x = 100.
263
Easy
263 of 485
Application
+4 | -1
If , then is
View answer and explanation
Correct option: D
Option D ((10,3)) is correct because it solves for n and r using the given permutation and combination values.
264
Easy
264 of 485
Application
+4 | -1
If stands for , then is equal to
View answer and explanation
Correct option: D
Option D () is correct because the given sum simplifies to (n+1)!.
265
Easy
265 of 485
Understanding
+4 | -1
white counters and red counters are arranged in a straight line with counters on each side of a central mark. The number of ways of arranging the counters, so that the arrangements are symmetrical with respect to the central mark, is
View answer and explanation
Correct option: A
Option A () is correct because it represents the number of ways to arrange m white and n red counters on one side of the central mark, determining the entire symmetrical arrangement.
266
Easy
266 of 485
Application
+4 | -1
Number of ways of selection of 4 letters of the word "PERFECT" is
View answer and explanation
Correct option: C
Option C (25) is correct because it correctly counts the number of ways to select 4 letters from the word \"PERFECT\", considering the repeated letter E.
267
Easy
267 of 485
Analyzing
+4 | -1
The value of is
View answer and explanation
Correct option: A
Option A () is correct because the expression can be manipulated to match the factorial form.
268
Easy
268 of 485
Application
+4 | -1
There are stalls for 10 animals in a ship. The number of ways the shipload can be made if there are cows, calves and horses to be transported, animals of each kind being not less than 10 , is
View answer and explanation
Correct option: A
59049
Option A (59049) is correct because each stall can be filled in 3 ways, and there are 10 stalls, resulting in 3 to the power of 10.
269
Easy
269 of 485
Analyzing
+4 | -1
The number of ways of arranging numbers out of , so that maximum is and minimum is 2 (repetitions of numbers is allowed) such that maximum and minimum both occur exactly once , is
View answer and explanation
Correct option: C
Option C () is correct because it represents the number of ways to arrange numbers with the given constraints, considering the positions of the minimum and maximum values and the choices for the remaining numbers.
270
Easy
270 of 485
Understanding
+4 | -1
The number of ways in which 10 candidates , can be ranked so that is always above , is
View answer and explanation
Correct option: B
The correct answer is B () because half of the total permutations will have above , and the other half will have above .
Revision notes and key takeaways
Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.
Showing 241-270 of 485 questions
