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JEE • MATHEMATICS • PERMUTATION AND COMBINATION
Permutation and combination practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 211-240 of 742 questions
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211
Easy
211 of 742
Application
+4 | -1
Let be a set of distinct elements. The number of triplets of the set in which atleast two coordinates are equal to
View answer and explanation
Correct option: B
Option B () is correct because it calculates the total number of triplets minus the number of triplets with all distinct elements.
212
Easy
212 of 742
Application
+4 | -1
Out of 18 points in a plane no three are in the same straight line except five points which are collinear. The number of straight lines that can be formed joining them is
View answer and explanation
Correct option: B
144
Option B (144) is correct because it calculates the total number of lines minus the extra lines counted due to collinearity, plus one for the single line formed by the collinear points.
213
Easy
213 of 742
Application
+4 | -1
Let be the number of all possible triangles formed by joining vertices of an -sided regular polygon. If , the value of is
View answer and explanation
Correct option: A
5
Option A (5) is correct because the equation simplifies to , which is satisfied when n = 5.
214
Easy
214 of 742
Application
+4 | -1
A seven-digit number made up of all distinct digits and is divisible by 3. Then, possible number of order pair is
View answer and explanation
Correct option: B
8
Option B (8) is correct because there are 8 possible ordered pairs (x, y) that make the seven-digit number divisible by 3.
215
Easy
215 of 742
Application
+4 | -1
If are prime numbers and are the positive integers such that LCM of is , then the number of ordered pairs is
View answer and explanation
Correct option: C
225
Option C (225) is correct because the number of ordered pairs (p, q) is found by considering all possible combinations of the prime factors' exponents in the LCM.
216
Easy
216 of 742
Application
+4 | -1
How many numbers greater than 40000 can be formed from the digits 2, 4, 5, 5, 7?
View answer and explanation
Correct option: D
48
Option D (48) is correct because it is calculated by subtracting the number of arrangements with 2 at the first place from the total number of arrangements.
217
Easy
217 of 742
Application
+4 | -1
How many words can be made from the letters of the word ‘COMMITTEE’?
View answer and explanation
Correct option: B
Option B () is correct because it accounts for the repeated letters (M, T, E) in the word COMMITTEE.
218
Easy
218 of 742
Application
+4 | -1
Every one of the 10 available lamps can be switched on to illuminate certain Hall. The total number of ways in which the hall can be illuminated, is
View answer and explanation
Correct option: B
Option B, , is correct because each lamp can be either on or off, giving possibilities, but we must subtract 1 for the case where all lamps are off.
219
Medium
219 of 742
Application
+4 | -1
Sixteen men compete with one another in running swimming and riding. How many prize lists could be made if there were altogether 6 prizes of different values, one for running, 2 for swimming and 3 for riding?
View answer and explanation
Correct option: B
Option B () is correct because it represents the product of the number of ways to award each prize.
220
Medium
220 of 742
Application
+4 | -1
A person predicts the outcome of 20 cricket matches of his home team. Each match can result either in a win, loss or tie for the home team. Total number of ways in which he can make the predictions, so that exactly 10 predictions are correct, is equal to
View answer and explanation
Correct option: A
Option A () is correct because it represents choosing the 10 correct matches and then the possibilities for the incorrect ones.
221
Easy
221 of 742
Application
+4 | -1
A four digit number of distinct digits is formed by using the digits . The number of such numbers which are divisible by 25, is
View answer and explanation
Correct option: B
40
Option B (40) is correct because it considers the two possible endings (25 and 75) and calculates the permutations for the remaining digits.
222
Easy
222 of 742
Application
+4 | -1
The least positive integer for which is
View answer and explanation
Correct option: A
14
Option A (14) is correct because it is the smallest positive integer that satisfies the inequality , which simplifies to n > 13.
223
Easy
223 of 742
Application
+4 | -1
The exponent of 3 in 100 !, is
View answer and explanation
Correct option: C
48
Option A (72) is correct because it calculates the number of words formed with at least one vowel.
224
Medium
224 of 742
Application
+4 | -1
Number of ways is which 50 identical books can be distributed in 100 students if each student can get atmost one book is
View answer and explanation
Correct option: A
Option A ((51)(52)...(100)/50!) is correct because it represents the number of ways to choose 50 students out of 100 to receive the books.
225
Easy
225 of 742
Understanding
+4 | -1
There are 10 true-false questions. The number of ways, in which they can be answered is
View answer and explanation
Correct option: B
Option B () is correct because each of the 10 questions can be answered in 2 ways (true or false), leading to total possibilities.
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226
Easy
226 of 742
Understanding
+4 | -1
The value of , when numerator and denominator takes their greatest value, is
View answer and explanation
Correct option: A
Option A () is correct because it is the simplified ratio of the two binomial coefficients.
227
Easy
227 of 742
Application
+4 | -1
If all permutations of the letters of the word PENCIL are arranged as in a dictionary, then 413th word is
View answer and explanation
Correct option: D
LICPEN
Option D (LICPEN) is correct because after arranging the permutations of the letters in the word PENCIL in dictionary order, the 413th word is LICPEN.
228
Easy
228 of 742
Application
+4 | -1
A seven-digit numbers divisible by 9 is to be formed by using 7 out of numbers . The number of ways in which this can be done, is
View answer and explanation
Correct option: D
Option D () is correct because there are 4 pairs of digits that can be excluded to make the sum of the remaining 7 digits divisible by 9, and each set of 7 digits can be arranged in 7! ways.
229
Easy
229 of 742
Application
+4 | -1
How many four digit numbers can be formed using the digits 1, 2, 3, 4, 5 such that at least one of the digit is repeated?
View answer and explanation
Correct option: D
Option D () is correct because it subtracts the number of four-digit numbers with no repetition from the total number of four-digit numbers that can be formed.
230
Easy
230 of 742
Application
+4 | -1
A dictionary is printed consisting of 7 letters words only that can be made with a letters of the word CRICKET. If the words are printed at the alphabetical order as in an ordinary dictionary, then the number of words before the word CRICKET is
View answer and explanation
Correct option: A
530
Option A (530) is correct because it calculates the number of words before \"CRICKET\" by considering alphabetical order and accounting for repeated letters.
231
Easy
231 of 742
Application
+4 | -1
The number of six-digit numbers that can be formed from the digits 1, 2, 3, 4, 5, 6 and 7, so that digits do not repeat and the terminal digits are even, is
View answer and explanation
Correct option: D
720
The correct answer is D (720) because it correctly calculates the number of six-digit numbers with even terminal digits from the given digits without repetition.
232
Medium
232 of 742
Application
+4 | -1
The number of words of four letters containing equal number of vowels and consonants, repetition allowed, is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated number of words does not match any of the given options.
233
Medium
233 of 742
Application
+4 | -1
The number of words which can be formed the letters of the word MAXIMUM, if two consonants cannot occur together, is
View answer and explanation
Correct option: A
4!
Option A (4!) is correct because the vowels must occupy alternate positions, and the consonants can then be arranged in the remaining spaces.
234
Easy
234 of 742
Application
+4 | -1
The number of ways in which positive and negative signs may be placed in a row so that no two negative signs shall be together is
View answer and explanation
Correct option: A
Option A () is correct because it represents the number of ways to place negative signs such that no two are together.
235
Easy
235 of 742
Analyzing
+4 | -1
The number of 6 digits numbers that can be formed using the digits 0, 1, 2, 5, 7 and 9 which are divisible by 11 and no digit is repeated, is
View answer and explanation
Correct option: A
60
Option A (60) is correct because it is the total number of 6-digit numbers that can be formed using the given digits, divisible by 11, with no repetition.
236
Easy
236 of 742
Understanding
+4 | -1
Let be the set of all functions from the set to the set . If , then is
View answer and explanation
Correct option: B
Option B () is correct because each of the k elements in A can be mapped to any of the k elements in A.
237
Easy
237 of 742
Application
+4 | -1
If then is equal to
View answer and explanation
Correct option: C
8, 9, 10
Option C (8, 9, 10) is correct because these values of r satisfy the inequality after simplification.
238
Easy
238 of 742
Application
+4 | -1
If and , then is equal to
View answer and explanation
Correct option: A
6
Option A (6) is correct because solving the given ratio of permutations leads to the equation 2x-1=11, which gives x=6.
239
Easy
239 of 742
Application
+4 | -1
A basket ball team consists of 12 pairs of twin brothers. On the first day of training, all 24 players stand in a circle in such a way that all pairs of twin brothers are neighbours. Number of ways this can be done is :
View answer and explanation
Correct option: B
Option B () is correct because there are 11! ways to arrange the 12 pairs in a circle, and each pair can be arranged in 2 ways.
240
Medium
240 of 742
Application
+4 | -1
A variable name in certain computer language must be either an alphabet or an alphabet followed by a decimal digit. The total number of different variable names that can exist in that language is equal to
View answer and explanation
Correct option: C
286
Option C (286) is correct because it correctly calculates the total number of variable names by considering alphabets and alphabets followed by digits.
Revision notes and key takeaways
Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.
Showing 211-240 of 742 questions
