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JEE • MATHEMATICS • PERMUTATION AND COMBINATION
Permutation and combination practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 91-120 of 742 questions
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91
Medium
91 of 742
Application
+4 | -1
The number of ways in which things of which are alike, can be arranged in a circular order, is
View answer and explanation
Correct option: A
Option A () is correct because it accounts for the circular arrangement and the identical objects.
92
Medium
92 of 742
Application
+4 | -1
A student is allowed to select atmost books from a collection of books. If the number of ways in which he can do this, is 64, then the value of is
View answer and explanation
Correct option: C
3
Option C (3) is correct because the sum of binomial coefficients from 0 to n equals half of the total sum, which is used to solve for n.
93
Medium
93 of 742
Analyzing
+4 | -1
The number of triangles whose vertices are at the vertices of an octagon but none of whose sides happen to come from the octagon, is
View answer and explanation
Correct option: A
16
Option A (16) is correct because it represents the number of triangles that can be formed from the vertices of an octagon without sharing any sides with the octagon itself.
94
Easy
94 of 742
Application
+4 | -1
The number of four-letter words that can be formed (the words need not be meaningful) using the letters of the word MEDITERRANEAN such that the first letter is E and the last letter is , is
View answer and explanation
Correct option: B
59
Option B (59) is correct because it is the total number of four-letter words formed with E as the first and R as the last letter, considering repetitions of letters in MEDITERRANEAN.
95
Medium
95 of 742
Application
+4 | -1
The sum of 4 digited numbers formed by using the digits without repetition is
View answer and explanation
Correct option: A
545958
Option A (545958) is correct because it uses the formula for the sum of 4-digit numbers formed by the given digits, considering the zero.
96
Easy
96 of 742
Application
+4 | -1
A man invites 10 friends for a dinner party. In how many they can be seated around a circular table so that two particular friends on either side of man?
View answer and explanation
Correct option: D
!
Option D () is correct because the two friends and the man are considered a single unit, leaving 8 other friends to arrange, and the two friends can switch places.
97
Easy
97 of 742
Application
+4 | -1
The number of ways of permuting the letters of the word DEVIL so that neither D is the first letter nor is the last letter is
View answer and explanation
Correct option: D
78
Option D (78) is correct because it accurately calculates the number of permutations of the word DEVIL where 'D' is not the first letter and 'L' is not the last letter using inclusion-exclusion principle.
98
Easy
98 of 742
Understanding
+4 | -1
The number of combinations of 4 different objects , taken 2 at a time is
View answer and explanation
Correct option: A
6
Option A (6) is correct because there are 6 ways to choose 2 objects from 4 distinct objects without regard to order.
99
Easy
99 of 742
Application
+4 | -1
The letters of the word 'HOSTEL' are arranged so that vowels occupy the end places. Then the number of arrangements is
View answer and explanation
Correct option: A
48
Option A (48) is correct because the 2 vowels can be arranged in the end places in 2! ways, and the remaining 4 letters can be arranged in 4! ways.
100
Medium
100 of 742
Application
+4 | -1
All words, with or without meaning, are made using all the letters of the word MONDAY. These words are written as in a dictionary with serial numbers. The serial number of the word MONDAY is
View answer and explanation
Correct option: A
327
Option A (327) is correct because calculating the rank of the word MONDAY involves finding the number of words that come before it in lexicographical order, which results in 327.
101
Easy
101 of 742
Application
+4 | -1
The number of ways to 16 different things to three persons so that gets one more than and gets two more than , is
View answer and explanation
Correct option: A
Option A () is correct because it represents the number of ways to divide 16 distinct items into groups of 4, 5, and 7.
102
Easy
102 of 742
Understanding
+4 | -1
The set to be partitioned into three sets of equal size. Thus,
. The number of ways to partition , is
. The number of ways to partition , is
View answer and explanation
Correct option: C
The correct answer is C () because it represents the number of ways to divide 12 distinct objects into 3 groups of 4, where the order of the groups doesn't matter.
103
Easy
103 of 742
Application
+4 | -1
The number of ways in which ten candidates can be arranged in a row "If are sit together in a specified order is
View answer and explanation
Correct option: C
8 !
Option C (8 !) is correct because treating A1, A2, and A3 as one unit reduces the problem to arranging 8 entities.
104
Easy
104 of 742
Application
+4 | -1
The number of divisors a number 38808 can have, excluding 1 and the number itself is
View answer and explanation
Correct option: A
70
Option A (70) is correct because it calculates the total number of divisors excluding 1 and the number itself.
105
Medium
105 of 742
Analyzing
+4 | -1
The number of permutations of the letters of the word 'HINDUSTAN' such that neither the pattern 'HIN' nor 'DUS' nor 'TAN' appear, are
View answer and explanation
Correct option: B
169194
Option D (None of these) is correct because the number of primes in the list is zero, as each term is divisible by a number between 2 and p.
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106
Easy
106 of 742
Application
+4 | -1
Eleven animals of a circus have to be placed in eleven cages one in each cage. If 4 of the cages are too small for 6 of the animals, then the number of ways of caging the animals is
View answer and explanation
Correct option: C
604800
Option C (604800) is correct because it represents the total number of ways to cage the animals, considering the size constraints.
107
Medium
107 of 742
Analyzing
+4 | -1
If the number of ways of selecting cards out of unlimited number of cards bearing the number
2, 3, 4 so that they can not be used to write the number 423 is 93. Then is equal to
2, 3, 4 so that they can not be used to write the number 423 is 93. Then is equal to
View answer and explanation
Correct option: B
5
Option B (5) is correct because the number of ways to select cards such that they cannot be used to write 423 is 93, which leads to the equation 3 * 2^m - 3 = 93, solving for m gives m=5.
108
Medium
108 of 742
Application
+4 | -1
5- digit numbers are to be formed using without repeating the digits. If be the number of such numbers that exceed 20000 and be the number of those that lie between 30000 and 90000 , then is :
View answer and explanation
Correct option: D
Option D (5:3) is correct because the ratio of numbers greater than 20000 to those between 30000 and 90000 is 120:72, which simplifies to 5:3.
109
Easy
109 of 742
Application
+4 | -1
The number of numbers greater than 50,000 that can be formed by using the digits is
View answer and explanation
Correct option: B
48
Option A (3265920) is correct because we calculate the number of 8-digit numbers with distinct digits, considering that the first digit cannot be 0.
110
Medium
110 of 742
Application
+4 | -1
6 white and 6 black balls are distributed among ten identical urns, so that there is atleast one ball in each urn. Balls are all alike except for the colour and each box can hold any number of balls. The number of different distributions of the balls is:
View answer and explanation
Correct option: D
10
Option D (10) is correct because there are 10 distinct ways to distribute the balls among the urns, considering the constraints.
111
Easy
111 of 742
Application
+4 | -1
The number of ways that 8 beads of different colures be string as a necklace, is
View answer and explanation
Correct option: A
2520
Option A (2520) is correct because it applies the formula for circular permutations with the correction for flipping the necklace.
112
Easy
112 of 742
Application
+4 | -1
The number of ways in which the six faces of a cube is painted with six different colours, is
View answer and explanation
Correct option: D
None of the above
The correct answer is None of the above because the number of ways to paint the cube is 30, not 1.
113
Easy
113 of 742
Application
+4 | -1
There are 6 letters and 3 post-boxes. The number of ways in which these letters can be posted, is
View answer and explanation
Correct option: B
Option B () is correct because each of the 6 letters can be posted in any of the 3 post-boxes, leading to possibilities.
114
Medium
114 of 742
Application
+4 | -1
There are 20 persons among whom two are brothers. The number of ways in which we can arrange them around a circle so that there is exactly one person between the brothers is
View answer and explanation
Correct option: B
!
Option B () is correct because it accounts for arranging the remaining people and the two possible arrangements of the brothers.
115
Easy
115 of 742
Analyzing
+4 | -1
How many different words can be formed by Jumbling the letters in the word MISSISSIPPI in which no two S's are adjacent?
View answer and explanation
Correct option: C
Option A () is correct because it calculates the number of arrangements where no two S's are adjacent by first arranging the other letters and then placing the S's in the gaps.
116
Easy
116 of 742
Application
+4 | -1
The total number of words which can be formed out of the letters taken 3 together, such that each word contains at least one vowel, is
View answer and explanation
Correct option: C
96
Option C (96) is correct because it calculates the number of 3-letter words with at least one vowel from the given letters.
117
Easy
117 of 742
Application
+4 | -1
There are 5 letters and 5 different envelopes. The number of ways in which all the letters can be put in wrong envelope, is
View answer and explanation
Correct option: B
44
Option B (44) is correct because it uses the derangement formula to calculate the number of ways to put all letters in the wrong envelopes.
118
Easy
118 of 742
Application
+4 | -1
The letters of the word 'MEERUT' are arranged in all possible ways as in a dictionary, then the rank of the word 'MEERUT' is
View answer and explanation
Correct option: D
122
Option D (122) is correct because it is the sum of the number of words starting with letters before M, plus the number of words starting with MEERUT.
119
Easy
119 of 742
Application
+4 | -1
Number of numbers between 5000 and 10000 by using the digits without repetition is equal to
View answer and explanation
Correct option: B
72
Option B (72) is correct because there are 3 choices for the first digit (5, 7, or 9) and then 4! ways to arrange the remaining 4 digits.
120
Easy
120 of 742
Application
+4 | -1
8 different persons are sitting around a table. Numbers of ways in which we can select 3 of them so that no two are consecutive is
View answer and explanation
Correct option: B
16
Option B (16) is correct because it represents the number of ways to select 3 non-consecutive persons around a circular table.
Revision notes and key takeaways
Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.
Showing 91-120 of 742 questions
