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JEE • MATHEMATICS • PAIR OF STRAIGHT LINES

Pair of straight lines practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-201 of 201 questions

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181 Easy
181 of 201
Analyzing +4 | -1
If the pairs of straight lines ax2+2hxy−ay2=0a x^2+2 h x y-a y^2=0 and bx2+2gxy−by2=0b x^2+2 g x y-b y^2=0 be such that each bisects the angles between the other, then
View answer and explanation
Correct option: A
hg+ab=0h g+a b=0
Option A (hg+ab=0h g+a b=0) is correct because it represents the condition where each pair of lines bisects the angles between the other, leading to a specific relationship between their coefficients.
182 Easy
182 of 201
Application +4 | -1
If the angle between the pair of straight lines represented by the equation x2−3xy+λy2+3x−5y+2=0,{x^2} - 3xy + \lambda {y^2} + 3x - 5y + 2 = 0, is tan−1(13)\mathrm{ta}{\mathrm{n}^{ - 1}}\left( {\frac{1}{3}} \right), where 'λ\lambda' is a non-negative real number. Then, λ\lambda is
View answer and explanation
Correct option: A
2
Option A (2) is correct because it satisfies the given condition for the angle between the pair of straight lines after substituting the values into the relevant formula and solving the resulting quadratic equation.
183 Easy
183 of 201
Application +4 | -1
The perpendicular from the origin to a line LL meets it at the point (3,−9)(3,-9), equation of the line LL is
View answer and explanation
Correct option: A
x−3y=30x-3 y=30
Option A (x−3y=30x-3 y=30) is correct because it represents the equation of a line passing through (3,-9) and perpendicular to the line joining the origin and (3,-9).
184 Easy
184 of 201
Analyzing +4 | -1
If aa and bb are positive number ( a<b)a < b), then the range of values of kk for which a real λ\lambda is found such that the equation ax2+2λxy+by2+2k(x+y+1)=0a x^2+2 \lambda x y+b y^2+2 k(x+y+1)=0 represents a pair of straight lines, is
View answer and explanation
Correct option: D
None of these
The correct answer is None of these because the combined equation is 3x2−8xy−3y2−4x+22y−7=03x^2 - 8xy - 3y^2 - 4x + 22y - 7 = 0, which doesn't match any of the options.
185 Easy
185 of 201
Application +4 | -1
If 3x2+xy−y2−3x+6y+k=03{x^2} + xy - {y^2} - 3x + 6y + k = 0 represents a pair of lines, then kk is equal to
View answer and explanation
Correct option: D
-9
Option D (-9) is correct because the condition for a general quadratic equation to represent a pair of lines is applied.
186 Easy
186 of 201
Application +4 | -1
Which of the following second degree equation represented a pair of straight lines
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Correct option: C
4x2−4xy+y2=44 x^2-4 x y+y^2=4
Option C (4x2−4xy+y2=44 x^2-4 x y+y^2=4) is correct because it represents a pair of straight lines when the determinant (Δ\Delta) of the general second-degree equation is zero.
187 Easy
187 of 201
Application +4 | -1
Equation of pair of straight lines drawn through (1,1)(1,1) and perpendicular to the pair of lines 3x2−7xy+2y2=03 x^2-7 x y+2 y^2=0, is
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Correct option: D
None of these
Option D (None of these) is correct because the correct equation of the pair of straight lines drawn through (1,1) and perpendicular to the pair of lines 3x2−7xy+2y2=03 x^2-7 x y+2 y^2=0 is 2(x−1)2+7(x−1)(y−1)+3(y−1)2=02(x-1)^2+7(x-1)(y-1)+3(y-1)^2=0, which is not listed.
188 Easy
188 of 201
Application +4 | -1
If the angle between two lines represented by 2  x2+5  xy+3  y2+7  y+4=02\;{x^2} + 5\;xy + 3\;{y^2} + 7\;y + 4 = 0 is tan⁡−1m,{\tan ^{ - 1}}m, then m =
View answer and explanation
Correct option: A
01-May
Option A (1/5) is correct because it is the value of m calculated using the formula for the angle between two lines represented by a homogeneous equation.
189 Easy
189 of 201
Application +4 | -1
If the lines x+q=0,y−2=0x+q=0, y-2=0 and 3x+2y+5=03 x+2 y+5=0 are concurrent, then value of qq will be
View answer and explanation
Correct option: C
3
Option C (3) is correct because the determinant of the coefficients of the concurrent lines must be zero, leading to q = 3.
190 Easy
190 of 201
Application +4 | -1
The equations of the pairs of opposite sides of a rectangle are x2−7x+6=0x^2-7 x+6=0 and y2−14y+40=0y^2-14 y+40=0, the equation of the diagonal nearer the origin is
View answer and explanation
Correct option: B
6x−5y+14=06 x-5 y+14=0
Option B (6x−5y+14=06 x-5 y+14=0) is correct because it represents the equation of the diagonal AC, which is nearer to the origin compared to diagonal BD.
191 Easy
191 of 201
Application +4 | -1
If the coordinate axes are the bisectors of the angles between the pair of lines ax2+2hxy+by2=0,ax^2+2 h x y+b y^2=0, then
View answer and explanation
Correct option: B
h=0h=0
Option B (h=0h=0) is correct because if the coordinate axes are the bisectors, the xyxy term must vanish, implying h=0h=0.
192 Easy
192 of 201
Application +4 | -1
The product of perpendiculars drawn from the origin to the lines represented by the equation ax2+2hxy+by2+2gx+2fy+c=0a x^2+2 h x y+b y^2+2 g x+2 f y+c=0, will be
View answer and explanation
Correct option: D
c(a−b)2+4h2\frac{c}{\sqrt{(a-b)^2+4 h^2}}
Option D (c(a−b)2+4h2\frac{c}{\sqrt{(a-b)^2+4 h^2}}) is correct because it represents the product of the perpendiculars from the origin to the lines represented by the given equation.
193 Easy
193 of 201
Understanding +4 | -1
The equation ax2+2hxy+by2=0a x^2+2 h x y+b y^2=0 represents a pair of perpendicular lines if
View answer and explanation
Correct option: D
a=11,b=−11a=11, b=-11
Option D (a=11,b=−11a=11, b=-11) is correct because the equation represents a pair of perpendicular lines if the sum of the coefficients of x2x^2 and y2y^2 is zero (a + b = 0).
194 Easy
194 of 201
Application +4 | -1
If one of the lines given by 6x2−xy+4cy2=06{x^2} - xy + 4c{y^2} = 0 is 3x+4y=0,3x + 4y = 0, then c equals
View answer and explanation
Correct option: D
-3
Option D (-3) is correct because substituting the slope of the given line into the equation allows us to solve for c.
195 Easy
195 of 201
Application +4 | -1
The length of the perpendicular from the origin, on the normal to the curve, x2+2xy−3y2=0{x^2} + 2xy - 3{y^2} = 0 at the point (2, 2) is
View answer and explanation
Correct option: B
222\sqrt 2
Option B (222\sqrt 2) is correct because the length of the perpendicular from the origin to the normal at (2,2) is the distance between (0,0) and (2,2).
196 Easy
196 of 201
Application +4 | -1
The slopes of the lines represented by x2+2hxy+2y2=0{x^2} + 2hxy + 2{y^2} = 0 are in the ratio 1 : 2, then hh equals
View answer and explanation
Correct option: B
±32\pm \frac{3}{2}
Option B (±32\pm \frac{3}{2}) is correct because the ratio of slopes is used to find a relationship between h and the slopes, which then leads to the value of h.
197 Easy
197 of 201
Application +4 | -1
For what value of kk is 4  x2+8  xy+ky2=94\;{x^2} + 8\;xy + k{y^2} = 9 the equation of a pair of straight lines?
View answer and explanation
Correct option: B
4
Option B (4) is correct because when k=4, the given equation represents a pair of straight lines as the determinant condition is satisfied.
198 Easy
198 of 201
Application +4 | -1
If the angle between the lines represented by 2x2+5xy+3y2+6x+7y+4=02{x^2} + 5xy + 3{y^2} + 6x + 7y + 4 = 0 is tan⁡−1(m),{\tan ^{ - 1}}\left( m \right), then mm is equal to
View answer and explanation
Correct option: A
01-May
Option A (0.2) is correct because it is the absolute value of the tangent of the angle between the lines, calculated using the formula involving the coefficients of the quadratic equation.
199 Easy
199 of 201
Analyzing +4 | -1
The points A(0,−1),B(2,1),C(0,3)A(0,-1), B(2,1), C(0,3) and D(−2,1)D(-2,1) are the vertices of a
View answer and explanation
Correct option: A
square
Option A (square) is correct because all sides are equal in length, and the diagonals are perpendicular, indicating 90-degree angles.
200 Easy
200 of 201
Application +4 | -1
A ray of light travels along the line 2x−3y+5=02 x-3 y+5=0 and strikes a plane mirror lying along the line x+y=2x+y=2. The equation of the straight line containing the reflected ray is
View answer and explanation
Correct option: B
3x−2y+3=03 x-2 y+3=0
Option B (3x−2y+3=03 x-2 y+3=0) is correct because it represents the equation of the reflected ray, calculated by finding the intersection point and using the angle of incidence equals angle of reflection principle.
201 Easy
201 of 201
Analyzing +4 | -1
The equation x3+x2y−xy2−y3=0x^3+x^2 y-x y^2-y^3=0 represents three straight lines passing through the origin such that
View answer and explanation
Correct option: A
Two of them are coincident and two of them are perpendicular
Option A (Two of them are coincident and two of them are perpendicular) is correct because the equation x3+x2y−xy2−y3=0x^3+x^2 y-x y^2-y^3=0 represents three straight lines, where two are coincident and two are perpendicular.
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