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JEE • MATHEMATICS • PAIR OF STRAIGHT LINES

Pair of straight lines practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 264 questions

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211 Easy
211 of 264
Application +4 | -1
A line passing through the point P(2,3)P(2,3) meets the lines represented by x2−2xy−y2=0x^2-2 x y-y^2=0 at the points AA and BB such that PA⋅PB=17P A \cdot P B=17, the equation of the line is
View answer and explanation
Correct option: B
y=3y=3
Option D (None of these) is incorrect. Option B (y=3y=3) is correct because it satisfies the condition PA⋅PB=17PA \cdot PB = 17 when the line passes through P(2,3) and intersects the given lines.
212 Easy
212 of 264
Application +4 | -1
A line which makes an acute angle θ\theta with the positive direction of xx-axis is drawn through the point PP (3,4)(3,4) to meet the lines x=6x=6 and y=8y=8 at RR and SS respectively then RS=8−23R S=8-2 \sqrt{3}, if
View answer and explanation
Correct option: C
π/6\pi / 6
Option C (π/6\pi / 6) is correct because substituting this value into the given equation results in the correct relationship between RS and the angle.
213 Easy
213 of 264
Application +4 | -1
The angle between the pair of straight lines x2+4y2−7xy=0x^2+4 y^2-7 x y=0, is
View answer and explanation
Correct option: C
tan⁡−1335\tan ^{-1} \frac{\sqrt{33}}{5}
Option C (tan⁡−1335\tan ^{-1} \frac{\sqrt{33}}{5}) is correct because it is calculated using the formula for the angle between the pair of straight lines.
214 Easy
214 of 264
Analyzing +4 | -1
The straight lines represented by x2+mxy−2y2+3y−1=0x^2+m x y-2 y^2+3 y-1=0 meet at the point
View answer and explanation
Correct option: C
(1/3,2/3)(1 / 3,2 / 3)
Option C (1 / 3, 2 / 3) is correct because it represents the point of intersection found by solving the partial derivative equations of the given equation.
215 Medium
215 of 264
Application +4 | -1
The straight lines 7x−2y+10=07 x-2 y+10=0 and 7x+2y−10=07 x+2 y-10=0 forms and isosceles triangle with the line y=2y=2, area of this triangle is equal to
View answer and explanation
Correct option: B
107\frac{10}{7} squnits
Option C (187\frac{18}{7} sq units) is correct because the area of the isosceles triangle is calculated using the base and height, which are determined by the intersection points of the lines.
216 Easy
216 of 264
Analyzing +4 | -1
The point of intersection of the two lines given by 2x2−5xy+2y2+3x+3y+1=02 x^2-5 x y+2 y^2+3 x+3 y+1=0 is
View answer and explanation
Correct option: C
(3,3)(3,3)
Option D (3,3) is correct because solving the partial derivatives of the given equation yields the intersection point (3,3).
217 Easy
217 of 264
Analyzing +4 | -1
The line y=mxy=m x bisects the angle between the lines ax2+2hxy+by2=0,a x^2+2 h x y+b y^2=0, if
View answer and explanation
Correct option: B
h(m2−1)+m(a−b)=0h\left(m^2-1\right)+m(a-b)=0
Option B (h(m2−1)+m(a−b)=0h\left(m^2-1\right)+m(a-b)=0) is correct because it represents the condition for the line y=mxy=mx to bisect the angle between the lines ax2+2hxy+by2=0a x^2+2 h x y+b y^2=0.
218 Easy
218 of 264
Application +4 | -1
The angle between the pair of straight lines y2sin⁡2θ−xysin⁡2θ+x2(cos⁡2θ−1)=0y^2 \sin ^2 \theta-x y \sin ^2 \theta+x^2\left(\cos ^2 \theta-1\right)=0, is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the angle between the lines is 90 degrees, which is not listed in the options.
219 Easy
219 of 264
Application +4 | -1
The value of 'a' for which the lines represented by ax2+5  xy+2  y2=0a{x^2} + 5\;xy + 2\;{y^2} = 0 are mutually perpendicular is
View answer and explanation
Correct option: B
-2
Option B (-2) is correct because for the lines to be perpendicular, the sum of the coefficients of x² and y² must be zero.
220 Easy
220 of 264
Analyzing +4 | -1
If the line represented by x2−2  pxy−y2=0{x^2} - 2\;pxy - {y^2} = 0 are rotated about the origin through an angle θ\theta, one in clockwise direction and other in anti-clockwise direction, then the equation of the bisectors of the angle between the lines in the new position is
View answer and explanation
Correct option: A
px2+2  xy−py2=0p{x^2} + 2\;xy - p{y^2} = 0
Option D (-1) is correct because when f(f(x))=xf(f(x)) = x, solving for α\alpha gives α=−1\alpha = -1.
221 Easy
221 of 264
Application +4 | -1
The distance between the parallel lines 9x2−6xy+y2+18x−6y+8=0,9{x^2} - 6xy + {y^2} + 18x - 6y + 8 = 0, is
View answer and explanation
Correct option: B
210\frac{2}{{\sqrt {10} }}
Option B (210\frac{2}{{\sqrt {10} }}) is correct because the distance between parallel lines is calculated using the formula involving coefficients and constants.
222 Medium
222 of 264
Application +4 | -1
If the lines x=k;k=1,2…,nx=k ; k=1,2 \ldots, n meet the line y=3x+4y=3 x+4 at the points Ak(xk,yk),k=1,2,…,nA_k\left(x_k, y_k\right), k=1,2, \ldots, n then the ordinate of the centre of Mean position of the points AkA_k, k=1,2,…,nk=1,2, \ldots, n is
View answer and explanation
Correct option: B
3n+112\frac{3 n+11}{2}
Option B (3n+112\frac{{3 n+11}}{{2}}) is correct because it represents the ordinate of the center of the mean position of the points AkA_k, calculated using the summation of the ordinates divided by nn.
223 Easy
223 of 264
Application +4 | -1
If the slope of one of the lines represented by ax2+a x^2+ (3a+1)xy+3y2=0(3 a+1) x y+3 y^2=0 be reciprocal of the slope of the other, then the slopes of the lines are
View answer and explanation
Correct option: D
−1/3,−3-1 / 3,-3
Option D (-1/3, -3) is correct because if the slopes are reciprocals, their product is 1. Solving for 'a' and substituting back into the equation allows us to find the slopes.
224 Medium
224 of 264
Application +4 | -1
The equation of the lines which are passing through the origin and which are perpendicular to the pair of straight lines x2−3xy+2y2=0x^2-3 x y+2 y^2=0 is
View answer and explanation
Correct option: C
2x2+3xy+y2=02 x^2+3 x y+y^2=0
Option C (2x2+3xy+y2=02 x^2+3 x y+y^2=0) is correct because it represents the equation of the lines passing through the origin and perpendicular to the given pair of straight lines.
225 Easy
225 of 264
Application +4 | -1
The equation 3ax2+9xy+(a2−2)y2=03 a x^2+9 x y+\left(a^2-2\right) y^2=0 represents two perpendicular straight lines for
View answer and explanation
Correct option: C
for only two values of aa
The correct answer is C (for only two values of aa) because for the lines to be perpendicular, the sum of the coefficients of x2x^2 and y2y^2 must be zero, leading to a quadratic equation with two solutions for aa.
226 Easy
226 of 264
Application +4 | -1
The angle between the pair of lines given by 3x2+5xy−2y2+x+9y−4=03 x^2+5 x y-2 y^2+x+9 y-4=0
View answer and explanation
Correct option: A
tan⁡−17\tan ^{-1} 7
Option A (tan⁡−17\tan ^{-1} 7) is correct because using the formula for the angle between a pair of lines, the angle is calculated to be tan⁡−17\tan^{-1} 7.
227 Easy
227 of 264
Analyzing +4 | -1
The equation x3+y3=0x^3+y^3=0 represents
View answer and explanation
Correct option: D
None of these.
Option D (None of these) is correct because the equation x3+y3=0x^3+y^3=0 represents one real straight line and two imaginary straight lines.
228 Easy
228 of 264
Application +4 | -1
The equation of the line whose perpendicular distance from the origin is 3 units and the angle which the normal makes with the positive direction of xx-axis is 30∘30^{\circ} is
View answer and explanation
Correct option: B
3x+y=6\sqrt{3} x+y=6
Option B (3x+y=6\sqrt{3} x+y=6) is correct because it is the equation of the line in normal form with the given perpendicular distance and angle.
229 Easy
229 of 264
Application +4 | -1
The combined equation of the pair of lines through the point (1, 0) and parallel to the lines represented by 2x2−xy−y2=02{x^2} - xy - {y^2} = 0 is
View answer and explanation
Correct option: C
2x2−xy−y2−4x+y+2=02{x^2} - xy - {y^2} - 4x + y + 2 = 0
Option C (2x2−xy−y2−4x+y+2=02{x^2} - xy - {y^2} - 4x + y + 2 = 0) is correct because it represents the combined equation of the pair of lines parallel to the given lines and passing through the point (1,0).
230 Easy
230 of 264
Application +4 | -1
If θ\theta is the acute angle between the lines given by x2−2pxy+y2=0x^2-2 p x y+y^2=0, then
View answer and explanation
Correct option: C
sec⁡θ=p\sec \theta=p
Option C (sec⁡θ=p\sec \theta=p) is correct because using the formula for the angle between the lines and trigonometric identities leads to sec⁡θ=p\sec \theta = p.
231 Easy
231 of 264
Application +4 | -1
The angle between the lines x2+4xy+y2=0{x^2} + 4xy + {y^2} = 0 is
View answer and explanation
Correct option: A
60∘60^\circ
Option A (60∘60^\circ) is correct because it is the angle calculated using the formula for the angle between a pair of straight lines represented by a homogeneous equation of degree 2.
232 Medium
232 of 264
Application +4 | -1
The area of the triangle formed by the lines 4x2−9xy−9y2=04 x^2-9 x y-9 y^2=0 and x=2x=2 is equal to
View answer and explanation
Correct option: C
103\frac{10}{3} sq units
Option C (103\frac{10}{3} sq units) is correct because it is the area of the triangle formed by the given lines, calculated using the intersection points.
233 Medium
233 of 264
Analyzing +4 | -1
If the pairs of lines x2+2xy+λy2=0x^2+2 x y+\lambda y^2=0 and λx2+2xy+y2=0\lambda x^2+2 x y+y^2=0 have exactly one line in common, then the joint equation of the other two lines is given by
View answer and explanation
Correct option: B
3x2+10xy+3y2=03 x^2+10 x y+3 y^2=0
Option B (3x2+10xy+3y2=03 x^2+10 x y+3 y^2=0) is correct because it represents the joint equation of the other two lines after finding the common line and the value of λ.
234 Easy
234 of 264
Application +4 | -1
If the distance between the parallel lines 3x+4y+7=03 x+4 y+7=0 and ax+y+b=0a x+y+b=0 is 1 , the integral value of bb is
View answer and explanation
Correct option: C
3
Option C (3) is correct because it is the only integral value of b that satisfies the distance formula between parallel lines.
235 Medium
235 of 264
Analyzing +4 | -1
If the straight lines ax2+2hxy+by2a x^2+2 h x y+b y^2 +2gx+2fy+c=0+2 g x+2 f y+c=0 intersect on the XX-axis, then
View answer and explanation
Correct option: C
af=gha f=g h
Option C (af=gha f=g h) is correct because it represents the condition when the lines intersect on the X-axis.
236 Easy
236 of 264
Application +4 | -1
The equation of the bisector of the acute angle between the line 3x−4y+7=03x - 4y + 7 = 0 and 12x+5y−2=012x + 5y - 2 = 0 is
View answer and explanation
Correct option: C
21x+77y−101=021x + 77y - 101 = 0
Option A (in AP) is correct because if the line always passes through (1,-2), then the coefficients a, b, and c must satisfy the condition a - 2b + c = 0, which implies that a, b, c are in AP.
237 Medium
237 of 264
Application +4 | -1
Two lines represented by the equation x2−y2−2x+1=0x^2-y^2-2 x+1=0 are rotated about the point (1,0)(1,0), the line making the bigger angle with the positive direction of the xx-axis being turned by 45∘45^{\circ} in the clockwise sense and the other line being turned by 15∘15^{\circ} in the anticlockwise sense. The combined equation of the pair of lines in their new position, is
View answer and explanation
Correct option: B
3x2−xy−23x+y+3=0\sqrt{3} x^2-x y-2 \sqrt{3} x+y+\sqrt{3}=0
Option B (3x2−xy−23x+y+3=0\sqrt{3} x^2-x y-2 \sqrt{3} x+y+\sqrt{3}=0) is correct because it represents the combined equation of the rotated lines after adjusting their angles with the x-axis.
238 Easy
238 of 264
Application +4 | -1
The angle θ\theta between the pairs of straight lines represented by 6x2−xy−12y2−8x+29y−14=06 x^2-x y-12 y^2-8 x+29 y-14=0 is such that tan⁡θ\tan \theta equals
View answer and explanation
Correct option: C
17/617 / 6
Option C (17 / 6) is correct because it is the value of tan⁡θ\tan \theta calculated using the formula involving the coefficients of the given equation.
239 Medium
239 of 264
Application +4 | -1
The equation x2−3xy+λy2+3x−5y+2=0x^2-3 x y+\lambda y^2+3 x-5 y+2=0 when λ\lambda is a real number, represents a pair of straight lines. If θ\theta is the angle between the lines, then cosec⁡2θ=\operatorname{cosec}^2 \theta=
View answer and explanation
Correct option: C
10
Option C (10) is correct because by substituting λ = 2 into the equation and using the formula for the angle between lines, we find that cosec⁡2θ=10\operatorname{cosec}^2 \theta = 10.
240 Easy
240 of 264
Analyzing +4 | -1
If the pairs of straight lines ax2+2hxy−ay2=0a x^2+2 h x y-a y^2=0 and bx2+2gxy−by2=0b x^2+2 g x y-b y^2=0 be such that each bisects the angles between the other, then
View answer and explanation
Correct option: A
hg+ab=0h g+a b=0
Option A (hg+ab=0h g+a b=0) is correct because it represents the condition where each pair of lines bisects the angles between the other, leading to a specific relationship between their coefficients.
Revision notes and key takeaways

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