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JEE • MATHEMATICS • PAIR OF STRAIGHT LINES

Pair of straight lines practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 264 questions

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61 Medium
61 of 264
Application +4 | -1
If the bisectors of the lines x2−2pxy−y2=0x^2-2 p x y-y^2=0 be x2−2qxy−y2=0x^2-2 q x y-y^2=0, then
View answer and explanation
Correct option: A
pq+1=0p q+1=0
Option A (pq+1=0p q+1=0) is correct because it represents the relationship between p and q when the bisectors of the lines x2−2pxy−y2=0x^2-2 p x y-y^2=0 are x2−2qxy−y2=0x^2-2 q x y-y^2=0.
62 Easy
62 of 264
Application +4 | -1
If the equation 12  x2+7  xy−py2−18  x+qy+6=012\;{x^2} + 7\;xy - p{y^2} - 18\;x + qy + 6 = 0 represents a pair of perpendicular straight lines, then
View answer and explanation
Correct option: A
p=12,q=1p = 12,q = 1
Option A (p=12,q=1p = 12, q = 1) is correct because it satisfies both the condition for perpendicular lines and the general equation for a pair of straight lines.
63 Easy
63 of 264
Application +4 | -1
If the equation λx2+2y2−5xy+5x−7y+3=0\lambda x^2+2 y^2-5 x y+5 x-7 y+3=0 represents two straight lines, then find the value of λ\lambda
View answer and explanation
Correct option: A
2
Option A (2) is correct because it is the value of λ\lambda that makes the given equation represent two straight lines, derived by applying the condition abc+2fgh−af2−bg2−ch2=0abc + 2fgh - af^2 - bg^2 - ch^2 = 0.
64 Easy
64 of 264
Analyzing +4 | -1
If the pair of lines ax2−2xy+by2=0a x^2-2 x y+b y^2=0 and bx2−2xy+ay2=0b x^2-2 x y+a y^2=0 be such that each pair bisects the angle between the other pair, then ∣a−b∣|a-b| equals to
View answer and explanation
Correct option: B
2
Option B (2) is correct because the condition that each pair of lines bisects the angle between the other pair leads to the equation ∣a−b∣=2|a-b|=2.
65 Easy
65 of 264
Application +4 | -1
If the equation 4x2+4xy+y2−6x−3y−4=04 x^2+4 x y+y^2-6 x-3 y-4=0 represents a pair of parallel line, then the distance between these lines is
View answer and explanation
Correct option: B
5\sqrt{5}
Option B (5\sqrt{5}) is correct because it is the calculated distance between the two parallel lines represented by the given equation, using the appropriate formula.
66 Easy
66 of 264
Application +4 | -1
Area of the triangle formed by the lines 3x2−4xy+y2=0,  2x−y=63{x^2} - 4xy + {y^2} = 0,\;2x - y = 6 is
View answer and explanation
Correct option: C
36 sq units
Option C (36 sq units) is correct because the area of the triangle formed by the given lines is calculated using the determinant formula with the intersection points of the lines.
67 Easy
67 of 264
Application +4 | -1
Equation of a straight line passing through the point of intersection of x−y+1=0x-y+1=0 and 3x+y−5=03 x+y-5=0 are perpendicular to one of them is
View answer and explanation
Correct option: B
x+y−3=0x+y-3=0
Option B (x+y−3=0x+y-3=0) is the correct answer because it represents a line passing through the intersection of the given lines and is perpendicular to one of them.
68 Easy
68 of 264
Understanding +4 | -1
The lines represents by ax2+2hxy+by2=0a{x^2} + 2hxy + b{y^2} = 0 are perpendicular to each other, if
View answer and explanation
Correct option: B
a+b=0a + b = 0
Option B (a+b=0a + b = 0) is correct because the sum of the coefficients of x2x^2 and y2y^2 is zero for perpendicular lines.
69 Medium
69 of 264
Application +4 | -1
The sides of a rectangle are x=0,y=0,x=4x=0, y=0, x=4 and y=3y=3. The equation of the straight line having slope 12\frac{1}{2} that divides the rectangle into two equal halves, is
View answer and explanation
Correct option: A
2y=x+12 y=x+1
Option A (2y=x+12y = x + 1) is correct because the line with the given slope passes through the center of the rectangle, dividing it into two equal halves.
70 Easy
70 of 264
Application +4 | -1
The set of values of hh for which the equation 4x2+hxy−3y2=04 x^2+h x y-3 y^2=0 represents a pair of real and distinct lines is
View answer and explanation
Correct option: A
RR
Option A (RR) is correct because the discriminant of the quadratic equation formed by the given equation is always positive, indicating real and distinct lines for all real values of hh.
71 Easy
71 of 264
Analyzing +4 | -1
The four straight lines given by the equations 12x2+7xy−12y2=012 x^2+7 x y-12 y^2=0 and
12x2+7xy−12y2−x+7y−1=012 x^2+7 x y-12 y^2-x+7 y-1=0 lie along the sides of a
View answer and explanation
Correct option: A
square
Option A (square) is correct because the given equations represent two pairs of parallel lines that are perpendicular to each other, and the distances between the parallel lines are equal.
72 Easy
72 of 264
Application +4 | -1
If the segment of the line between the lines x−y+2=0x-y+2=0 and x+y+4=0x+y+4=0 is bisected at the origin, equation of the line is
View answer and explanation
Correct option: C
y−3x=0y-3 x=0
Option C (y−3x=0y-3 x=0) is correct because it represents the equation of a line passing through the origin and the midpoint of the segment formed by the intersection of the given lines.
73 Easy
73 of 264
Application +4 | -1
Perimeter of the quadrilateral bounded by the coordinate axis and the lines x+y=50x+y=50 and 3x+y=903 x+y=90 is
View answer and explanation
Correct option: C
80+202+101080+20 \sqrt{2}+10 \sqrt{10}
The correct answer is C (80+202+101080+20 \sqrt{2}+10 \sqrt{10}) because it is the sum of the lengths of the sides of the quadrilateral formed by the given lines and axes.
74 Medium
74 of 264
Application +4 | -1
Pair of straight lines perpendicular to each other represented by
View answer and explanation
Correct option: A
2x2=2y(2x+y)2x^2=2y(2x+y)
Option A (2x2=2y(2x+y)2x^2=2y(2x+y)) is correct because it represents a pair of straight lines that are perpendicular to each other, satisfying the condition that the sum of the coefficients of x² and y² is zero.
75 Easy
75 of 264
Application +4 | -1
If the lines 3x−y+1=03 x-y+1=0 and x−2y+3x-2 y+3 =0=0 are equally inclined to the line y=mxy=m x, then the value of mm is given by
View answer and explanation
Correct option: C
7m2−2m−7=07 m^2-2 m-7=0
Option C (7m2−2m−7=07 m^2-2 m-7=0) is correct because it is the equation obtained by equating the tangents of the angles between the line y=mx and the two given lines.
76 Easy
76 of 264
Application +4 | -1
PP is a point on xx-axis, QQ is a point on yy-axis. Both are equidistant from the points (7,6)(7,6) and (3,4)(3,4). Distance between PP and QQ is
View answer and explanation
Correct option: C
155/215 \sqrt{5} / 2
Option C (1552\frac{15 \sqrt{5}}{2}) is correct because it is the distance between P and Q calculated after finding their coordinates using the equidistant condition from the given points.
77 Easy
77 of 264
Application +4 | -1
Distance between the parallel lines 4x2+20xy+25y2+2x+5y−12=04 x^2+20 x y+25 y^2+2 x+5 y-12=0 is
View answer and explanation
Correct option: C
729\frac{7}{\sqrt{29}}
The correct answer is C (729\frac{7}{\sqrt{29}}) because the distance between the parallel lines is calculated using the formula after factoring the given equation.
78 Easy
78 of 264
Analyzing +4 | -1
If two pairs of straight lines having equations y2+xy−12x2=0y^2+x y-12 x^2=0 and ax2+2hxy+by2=0a x^2+2 h x y+b y^2=0 have one line common, then a=a=
View answer and explanation
Correct option: A
−3(2h+3b)-3(2 h+3 b)
Option A (−3(2h+3b)-3(2 h+3 b)) is correct because substituting y=3xy=3x into the second equation and solving for aa yields this result.
79 Easy
79 of 264
Application +4 | -1
If the lengths of the perpendiculars drawn from origin to xsec⁡θ+ycosec⁡θ=ax \sec \theta+y \operatorname{cosec} \theta=a and xcos⁡θ−ysin⁡θ=acos⁡2θx \cos \theta-y \sin \theta=a \cos 2 \theta are pp and p′p^{\prime} respectively, then 4p2+p′2=……4 p^2+p^{\prime 2}=\ldots \ldots
View answer and explanation
Correct option: A
a2a^2
Option A (a2a^2) is correct because the expression 4p2+p′24p^2 + p'^2 simplifies to a2a^2 using trigonometric identities.
80 Medium
80 of 264
Application +4 | -1
Equations of the bisectors of the lines 3x−4y+7=03 x-4 y+7=0 and 12x+5y−2=012 x+5 y-2=0 are given by
View answer and explanation
Correct option: A
21x+77y−101=0,11x−3y+9=021 x+77 y-101=0,11 x-3 y+9=0
Option A (21x+77y−101=0,11x−3y+9=021 x+77 y-101=0,11 x-3 y+9=0) is correct because it represents the equations of the bisectors of the given lines, derived using the angle bisector formula.
81 Easy
81 of 264
Application +4 | -1
The distance between the pair of lines represented by the equation x2−6xy+9y2+3x−9y−4=0{x^2} - 6xy + 9{y^2} + 3x - 9y - 4 = 0 is
View answer and explanation
Correct option: C
52\sqrt {\frac{5}{2}}
Option C (52\sqrt {\frac{5}{2}}) is correct because the distance between the parallel lines is calculated using the formula involving the coefficients of the equation.
82 Medium
82 of 264
Application +4 | -1
The combined equation of the pair of lines through the origin and perpendicular to the pair of lines given by ax2+2hxy+by2=0a x^2+2 h x y+b y^2=0, is
View answer and explanation
Correct option: C
bx2−2hxy+ay2=0b x^2-2 h x y+a y^2=0
Option C (bx2−2hxy+ay2=0b x^2-2 h x y+a y^2=0) is correct because it represents the combined equation of the pair of lines through the origin and perpendicular to the pair of lines given by ax2+2hxy+by2=0a x^2+2 h x y+b y^2=0.
83 Easy
83 of 264
Application +4 | -1
Separate equations of lines for a pair of lines whose equation is x2+xy−12y2=0{x^2} + xy - 12{y^2} = 0, are
View answer and explanation
Correct option: D
x+4y=0x + 4y = 0 and x−3y=0x - 3y = 0
Option D (x+4y=0x + 4y = 0 and x−3y=0x - 3y = 0) is correct because these are the separate equations obtained by factoring the given homogeneous equation.
84 Easy
84 of 264
Analyzing +4 | -1
If the equation of the pair of straight lines passing through the point (1,1)(1,1), one making an angle θ\theta with the positive direction of the XX-axis and the other making the same angle with the positive direction of the YY-axis, is x2−(a+2)xy+y2+a(x+y−1)=0,a≠−2x^2-(a+2) x y+y^2+a(x+y-1)=0, a \neq-2, then the value of sin⁡2θ\sin 2 \theta is
View answer and explanation
Correct option: C
2(a+2)\frac{2}{(a+2)}
Option C (2(a+2)\frac{{2}}{{(a + 2)}}) is correct because comparing the given equation with the joint equation of the lines leads to the relation sin⁡2θ=2(a+2)\sin 2\theta = \frac{{2}}{{(a + 2)}}.
85 Easy
85 of 264
Application +4 | -1
The distance between the pair of parallel lines x2+4xy+4y2+3x+6y−4=0{x^2} + 4xy + 4{y^2} + 3x + 6y - 4 = 0 is
View answer and explanation
Correct option: A
5\sqrt 5
Option A (5\sqrt{5}) is correct because it is the distance between the parallel lines calculated using the appropriate formula.
86 Easy
86 of 264
Analyzing +4 | -1
If the equation x2+(λ+μ)xy+λμy2+x+μy=0x^2+(\lambda+\mu) x y+\lambda \mu y^2+x+\mu y=0 represents two parallel straight lines, then
View answer and explanation
Correct option: C
λ=μ\lambda=\mu
Option C (λ=μ\lambda=\mu) is correct because it is the condition that makes the given equation represent two parallel straight lines, which requires the discriminant to be zero.
87 Easy
87 of 264
Application +4 | -1
If ax2−y2+4x−y=0a{x^2} - {y^2} + 4x - y = 0 represents a pair of lines, then aa is equal to
View answer and explanation
Correct option: B
16
The correct answer is B (16) because the condition for a general second-degree equation to represent a pair of straight lines is applied, and the value of 'a' is calculated.
88 Easy
88 of 264
Application +4 | -1
The difference of the tangents of the angles which the lines x2(sec⁡2−sin⁡2θ)−2xytan⁡θ+y2sin⁡2θ=0x^2\left(\sec ^2-\sin ^2 \theta\right)-2 x y \tan \theta+y^2 \sin ^2 \theta=0 make with X\mathrm{X}-axis, is
View answer and explanation
Correct option: B
2
Option B (2) is correct because the difference of the tangents is calculated using the formula involving the coefficients of the given equation and trigonometric identities.
89 Easy
89 of 264
Application +4 | -1
The lines joining the points of intersection of line x+y=1x+y=1 and curve x2+y2−2y+λ=0x^2+y^2-2 y+\lambda=0 to the origin are perpendicular, then the value of λ\lambda will be
View answer and explanation
Correct option: D
0
Option D (0) is correct because after homogenizing the equation and applying the perpendicularity condition (A+B=0), the value of lambda is found to be 0.
90 Easy
90 of 264
Application +4 | -1
If the slope of one line in the pair ax2+4xy+y2=0a x^2+4 x y+y^2=0 is three times the other, then a=a=
View answer and explanation
Correct option: A
3
Option A (3) is correct because it is the value of 'a' that satisfies the condition where one slope is three times the other for the given equation.
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